How to save each loop to a new file with python
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I trying to get a json response and save it as a new file.
To do that am I trying to loop a request through a range, then I want to save each json result as a new file
I managed to pull the request through the loop but I don't know how to save it each output in new file.
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
python range output
add a comment |
I trying to get a json response and save it as a new file.
To do that am I trying to loop a request through a range, then I want to save each json result as a new file
I managed to pull the request through the loop but I don't know how to save it each output in new file.
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
python range output
2
Shouldn't there be an indentation at json.dump ?
– Melon
Jan 3 at 12:10
Im new to it all. Sorry but I don't know what you mean by "indentation"
– those44244
Jan 3 at 12:13
don't even start the war: spaces or tabs?
– naivepredictor
Jan 3 at 12:14
trying to use tabs
– those44244
Jan 3 at 12:24
I get it, thanks and it worked!
– those44244
Jan 3 at 13:18
add a comment |
I trying to get a json response and save it as a new file.
To do that am I trying to loop a request through a range, then I want to save each json result as a new file
I managed to pull the request through the loop but I don't know how to save it each output in new file.
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
python range output
I trying to get a json response and save it as a new file.
To do that am I trying to loop a request through a range, then I want to save each json result as a new file
I managed to pull the request through the loop but I don't know how to save it each output in new file.
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
python range output
python range output
edited Jan 3 at 12:08


Rakesh
41.6k134276
41.6k134276
asked Jan 3 at 12:07
those44244those44244
125
125
2
Shouldn't there be an indentation at json.dump ?
– Melon
Jan 3 at 12:10
Im new to it all. Sorry but I don't know what you mean by "indentation"
– those44244
Jan 3 at 12:13
don't even start the war: spaces or tabs?
– naivepredictor
Jan 3 at 12:14
trying to use tabs
– those44244
Jan 3 at 12:24
I get it, thanks and it worked!
– those44244
Jan 3 at 13:18
add a comment |
2
Shouldn't there be an indentation at json.dump ?
– Melon
Jan 3 at 12:10
Im new to it all. Sorry but I don't know what you mean by "indentation"
– those44244
Jan 3 at 12:13
don't even start the war: spaces or tabs?
– naivepredictor
Jan 3 at 12:14
trying to use tabs
– those44244
Jan 3 at 12:24
I get it, thanks and it worked!
– those44244
Jan 3 at 13:18
2
2
Shouldn't there be an indentation at json.dump ?
– Melon
Jan 3 at 12:10
Shouldn't there be an indentation at json.dump ?
– Melon
Jan 3 at 12:10
Im new to it all. Sorry but I don't know what you mean by "indentation"
– those44244
Jan 3 at 12:13
Im new to it all. Sorry but I don't know what you mean by "indentation"
– those44244
Jan 3 at 12:13
don't even start the war: spaces or tabs?
– naivepredictor
Jan 3 at 12:14
don't even start the war: spaces or tabs?
– naivepredictor
Jan 3 at 12:14
trying to use tabs
– those44244
Jan 3 at 12:24
trying to use tabs
– those44244
Jan 3 at 12:24
I get it, thanks and it worked!
– those44244
Jan 3 at 13:18
I get it, thanks and it worked!
– those44244
Jan 3 at 13:18
add a comment |
4 Answers
4
active
oldest
votes
not sure why Milad suggested using a write()
— your code is basically fine, it just needs the indentation being done correctly. you can either do:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
note the extra spaces at the beginning of the last line, they are important and is what people are referring to with indentation. reading some Python tutorials might help
making this code slightly nicer, you could use more of the requests
interface by doing:
import requests
import json
for page in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore', params={
'country_code': 'dk',
'currency_code': 'DKK',
'grape_filter': 'varietal',
'min_rating': 1,
'page': page,
'wine_type_ids': [1, 2],
})
# raise an exception if this request wasn't successful
vino.raise_for_status()
data = vino.json()
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile)
if you're going to be reading the output yourself I'd "pretty print" the output with something like:
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
finally, if you're using a recent version of Python3, I'd also use the the new "format strings":
with open(f'data{page}.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
as it tends to result in easier to read code…
Thank you so much. I understod how the indentation caused the problem. I'm on my 20th hour with python and first time coding. Thanks a lot Sam!
– those44244
Jan 3 at 13:28
add a comment |
do it this way:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
outfile.write(data)
Im getting outfile.write(data) TypeError: expected a character buffer object
– those44244
Jan 3 at 12:24
add a comment |
The response from the website already contains json data, but as a string. If you want to save it to the file, you can just save that string, no need to call the json()
function on the response object. json()
method will parse this data to python objects (dicts and lists).
You can use that after to fiddle with the data. If you just want to save it, this is not needed.
This will work:
import requests
for i in range(1, 5):
resp = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = resp.text
with open("data-{}.json".format(i), 'w') as outfile:
outfile.write(data)
add a comment |
Try this
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
not sure why Milad suggested using a write()
— your code is basically fine, it just needs the indentation being done correctly. you can either do:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
note the extra spaces at the beginning of the last line, they are important and is what people are referring to with indentation. reading some Python tutorials might help
making this code slightly nicer, you could use more of the requests
interface by doing:
import requests
import json
for page in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore', params={
'country_code': 'dk',
'currency_code': 'DKK',
'grape_filter': 'varietal',
'min_rating': 1,
'page': page,
'wine_type_ids': [1, 2],
})
# raise an exception if this request wasn't successful
vino.raise_for_status()
data = vino.json()
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile)
if you're going to be reading the output yourself I'd "pretty print" the output with something like:
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
finally, if you're using a recent version of Python3, I'd also use the the new "format strings":
with open(f'data{page}.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
as it tends to result in easier to read code…
Thank you so much. I understod how the indentation caused the problem. I'm on my 20th hour with python and first time coding. Thanks a lot Sam!
– those44244
Jan 3 at 13:28
add a comment |
not sure why Milad suggested using a write()
— your code is basically fine, it just needs the indentation being done correctly. you can either do:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
note the extra spaces at the beginning of the last line, they are important and is what people are referring to with indentation. reading some Python tutorials might help
making this code slightly nicer, you could use more of the requests
interface by doing:
import requests
import json
for page in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore', params={
'country_code': 'dk',
'currency_code': 'DKK',
'grape_filter': 'varietal',
'min_rating': 1,
'page': page,
'wine_type_ids': [1, 2],
})
# raise an exception if this request wasn't successful
vino.raise_for_status()
data = vino.json()
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile)
if you're going to be reading the output yourself I'd "pretty print" the output with something like:
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
finally, if you're using a recent version of Python3, I'd also use the the new "format strings":
with open(f'data{page}.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
as it tends to result in easier to read code…
Thank you so much. I understod how the indentation caused the problem. I'm on my 20th hour with python and first time coding. Thanks a lot Sam!
– those44244
Jan 3 at 13:28
add a comment |
not sure why Milad suggested using a write()
— your code is basically fine, it just needs the indentation being done correctly. you can either do:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
note the extra spaces at the beginning of the last line, they are important and is what people are referring to with indentation. reading some Python tutorials might help
making this code slightly nicer, you could use more of the requests
interface by doing:
import requests
import json
for page in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore', params={
'country_code': 'dk',
'currency_code': 'DKK',
'grape_filter': 'varietal',
'min_rating': 1,
'page': page,
'wine_type_ids': [1, 2],
})
# raise an exception if this request wasn't successful
vino.raise_for_status()
data = vino.json()
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile)
if you're going to be reading the output yourself I'd "pretty print" the output with something like:
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
finally, if you're using a recent version of Python3, I'd also use the the new "format strings":
with open(f'data{page}.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
as it tends to result in easier to read code…
not sure why Milad suggested using a write()
— your code is basically fine, it just needs the indentation being done correctly. you can either do:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
note the extra spaces at the beginning of the last line, they are important and is what people are referring to with indentation. reading some Python tutorials might help
making this code slightly nicer, you could use more of the requests
interface by doing:
import requests
import json
for page in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore', params={
'country_code': 'dk',
'currency_code': 'DKK',
'grape_filter': 'varietal',
'min_rating': 1,
'page': page,
'wine_type_ids': [1, 2],
})
# raise an exception if this request wasn't successful
vino.raise_for_status()
data = vino.json()
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile)
if you're going to be reading the output yourself I'd "pretty print" the output with something like:
with open('data' + str(page) + '.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
finally, if you're using a recent version of Python3, I'd also use the the new "format strings":
with open(f'data{page}.json', 'w') as outfile:
json.dump(data, outfile, sort_keys=True,
indent=4, separators=(',', ': '))
as it tends to result in easier to read code…
answered Jan 3 at 12:53
Sam MasonSam Mason
3,36811331
3,36811331
Thank you so much. I understod how the indentation caused the problem. I'm on my 20th hour with python and first time coding. Thanks a lot Sam!
– those44244
Jan 3 at 13:28
add a comment |
Thank you so much. I understod how the indentation caused the problem. I'm on my 20th hour with python and first time coding. Thanks a lot Sam!
– those44244
Jan 3 at 13:28
Thank you so much. I understod how the indentation caused the problem. I'm on my 20th hour with python and first time coding. Thanks a lot Sam!
– those44244
Jan 3 at 13:28
Thank you so much. I understod how the indentation caused the problem. I'm on my 20th hour with python and first time coding. Thanks a lot Sam!
– those44244
Jan 3 at 13:28
add a comment |
do it this way:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
outfile.write(data)
Im getting outfile.write(data) TypeError: expected a character buffer object
– those44244
Jan 3 at 12:24
add a comment |
do it this way:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
outfile.write(data)
Im getting outfile.write(data) TypeError: expected a character buffer object
– those44244
Jan 3 at 12:24
add a comment |
do it this way:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
outfile.write(data)
do it this way:
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
outfile.write(data)
answered Jan 3 at 12:15
Milad KhMilad Kh
347313
347313
Im getting outfile.write(data) TypeError: expected a character buffer object
– those44244
Jan 3 at 12:24
add a comment |
Im getting outfile.write(data) TypeError: expected a character buffer object
– those44244
Jan 3 at 12:24
Im getting outfile.write(data) TypeError: expected a character buffer object
– those44244
Jan 3 at 12:24
Im getting outfile.write(data) TypeError: expected a character buffer object
– those44244
Jan 3 at 12:24
add a comment |
The response from the website already contains json data, but as a string. If you want to save it to the file, you can just save that string, no need to call the json()
function on the response object. json()
method will parse this data to python objects (dicts and lists).
You can use that after to fiddle with the data. If you just want to save it, this is not needed.
This will work:
import requests
for i in range(1, 5):
resp = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = resp.text
with open("data-{}.json".format(i), 'w') as outfile:
outfile.write(data)
add a comment |
The response from the website already contains json data, but as a string. If you want to save it to the file, you can just save that string, no need to call the json()
function on the response object. json()
method will parse this data to python objects (dicts and lists).
You can use that after to fiddle with the data. If you just want to save it, this is not needed.
This will work:
import requests
for i in range(1, 5):
resp = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = resp.text
with open("data-{}.json".format(i), 'w') as outfile:
outfile.write(data)
add a comment |
The response from the website already contains json data, but as a string. If you want to save it to the file, you can just save that string, no need to call the json()
function on the response object. json()
method will parse this data to python objects (dicts and lists).
You can use that after to fiddle with the data. If you just want to save it, this is not needed.
This will work:
import requests
for i in range(1, 5):
resp = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = resp.text
with open("data-{}.json".format(i), 'w') as outfile:
outfile.write(data)
The response from the website already contains json data, but as a string. If you want to save it to the file, you can just save that string, no need to call the json()
function on the response object. json()
method will parse this data to python objects (dicts and lists).
You can use that after to fiddle with the data. If you just want to save it, this is not needed.
This will work:
import requests
for i in range(1, 5):
resp = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = resp.text
with open("data-{}.json".format(i), 'w') as outfile:
outfile.write(data)
answered Jan 3 at 12:59
iborkoiborko
514
514
add a comment |
add a comment |
Try this
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
add a comment |
Try this
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
add a comment |
Try this
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
Try this
import requests
import json
for i in range(1, 5):
vino = requests.get('https://www.vivino.com/api/explore/explore?country_code=dk¤cy_code=DKK&grape_filter=varietal&merchant_id=&min_rating=1&order_by=&order=desc&page='+str(i)+'&price_range_max=2500&price_range_min=0&wine_type_ids=1&wine_type_ids=2')
data = vino.json()
with open('data' + str(i) + '.json', 'w') as outfile:
json.dump(data, outfile)
answered Jan 3 at 13:03
Allef MizaelAllef Mizael
112
112
add a comment |
add a comment |
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2
Shouldn't there be an indentation at json.dump ?
– Melon
Jan 3 at 12:10
Im new to it all. Sorry but I don't know what you mean by "indentation"
– those44244
Jan 3 at 12:13
don't even start the war: spaces or tabs?
– naivepredictor
Jan 3 at 12:14
trying to use tabs
– those44244
Jan 3 at 12:24
I get it, thanks and it worked!
– those44244
Jan 3 at 13:18