Mysterious Journey across Black river. [closed]












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When sarah rowed down black river with the current, she took 1 hr to go 4 miles. When she rowed back the same distance, at the same rowing speed, but against the current, her trip required 2 hrs. What is the speed in mph, of the current in black river?










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closed as off-topic by Noah Schweber, Gibbs, Shailesh, Leucippus, Lord Shark the Unknown Feb 2 at 7:53


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Noah Schweber, Gibbs, Shailesh, Leucippus, Lord Shark the Unknown

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    What have you tried? Where did you get stuck? Please don't just ask us to do your homework for you. (Also, algebraic geometry isn't just any problem involving algebra and geometry)
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    – Noah Schweber
    Feb 1 at 22:34
















-1












$begingroup$


When sarah rowed down black river with the current, she took 1 hr to go 4 miles. When she rowed back the same distance, at the same rowing speed, but against the current, her trip required 2 hrs. What is the speed in mph, of the current in black river?










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$endgroup$



closed as off-topic by Noah Schweber, Gibbs, Shailesh, Leucippus, Lord Shark the Unknown Feb 2 at 7:53


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Noah Schweber, Gibbs, Shailesh, Leucippus, Lord Shark the Unknown

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    What have you tried? Where did you get stuck? Please don't just ask us to do your homework for you. (Also, algebraic geometry isn't just any problem involving algebra and geometry)
    $endgroup$
    – Noah Schweber
    Feb 1 at 22:34














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-1


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$begingroup$


When sarah rowed down black river with the current, she took 1 hr to go 4 miles. When she rowed back the same distance, at the same rowing speed, but against the current, her trip required 2 hrs. What is the speed in mph, of the current in black river?










share|cite|improve this question











$endgroup$




When sarah rowed down black river with the current, she took 1 hr to go 4 miles. When she rowed back the same distance, at the same rowing speed, but against the current, her trip required 2 hrs. What is the speed in mph, of the current in black river?







algebra-precalculus






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edited Feb 1 at 22:34









saulspatz

17.2k31435




17.2k31435










asked Feb 1 at 22:25









Danielle SilveroDanielle Silvero

1




1




closed as off-topic by Noah Schweber, Gibbs, Shailesh, Leucippus, Lord Shark the Unknown Feb 2 at 7:53


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Noah Schweber, Gibbs, Shailesh, Leucippus, Lord Shark the Unknown

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by Noah Schweber, Gibbs, Shailesh, Leucippus, Lord Shark the Unknown Feb 2 at 7:53


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Noah Schweber, Gibbs, Shailesh, Leucippus, Lord Shark the Unknown

If this question can be reworded to fit the rules in the help center, please edit the question.












  • $begingroup$
    What have you tried? Where did you get stuck? Please don't just ask us to do your homework for you. (Also, algebraic geometry isn't just any problem involving algebra and geometry)
    $endgroup$
    – Noah Schweber
    Feb 1 at 22:34


















  • $begingroup$
    What have you tried? Where did you get stuck? Please don't just ask us to do your homework for you. (Also, algebraic geometry isn't just any problem involving algebra and geometry)
    $endgroup$
    – Noah Schweber
    Feb 1 at 22:34
















$begingroup$
What have you tried? Where did you get stuck? Please don't just ask us to do your homework for you. (Also, algebraic geometry isn't just any problem involving algebra and geometry)
$endgroup$
– Noah Schweber
Feb 1 at 22:34




$begingroup$
What have you tried? Where did you get stuck? Please don't just ask us to do your homework for you. (Also, algebraic geometry isn't just any problem involving algebra and geometry)
$endgroup$
– Noah Schweber
Feb 1 at 22:34










1 Answer
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Let $s$ be her speed in still water and $r$ the speed of the river. Going upstream, her speed relative to the bank is $s- r= 4/2= 2$ mph. Going downstream relative to the bank is $s+ r= 4/1= 4$ mph.
Can you solve the two equations, $s- r= 2$ and $s+ r= 4$ for $s$ and $r$?






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$endgroup$




















    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1












    $begingroup$

    Let $s$ be her speed in still water and $r$ the speed of the river. Going upstream, her speed relative to the bank is $s- r= 4/2= 2$ mph. Going downstream relative to the bank is $s+ r= 4/1= 4$ mph.
    Can you solve the two equations, $s- r= 2$ and $s+ r= 4$ for $s$ and $r$?






    share|cite|improve this answer











    $endgroup$


















      1












      $begingroup$

      Let $s$ be her speed in still water and $r$ the speed of the river. Going upstream, her speed relative to the bank is $s- r= 4/2= 2$ mph. Going downstream relative to the bank is $s+ r= 4/1= 4$ mph.
      Can you solve the two equations, $s- r= 2$ and $s+ r= 4$ for $s$ and $r$?






      share|cite|improve this answer











      $endgroup$
















        1












        1








        1





        $begingroup$

        Let $s$ be her speed in still water and $r$ the speed of the river. Going upstream, her speed relative to the bank is $s- r= 4/2= 2$ mph. Going downstream relative to the bank is $s+ r= 4/1= 4$ mph.
        Can you solve the two equations, $s- r= 2$ and $s+ r= 4$ for $s$ and $r$?






        share|cite|improve this answer











        $endgroup$



        Let $s$ be her speed in still water and $r$ the speed of the river. Going upstream, her speed relative to the bank is $s- r= 4/2= 2$ mph. Going downstream relative to the bank is $s+ r= 4/1= 4$ mph.
        Can you solve the two equations, $s- r= 2$ and $s+ r= 4$ for $s$ and $r$?







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Feb 2 at 1:24









        AryanSonwatikar

        471114




        471114










        answered Feb 1 at 22:34









        user247327user247327

        11.6k1516




        11.6k1516















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