Mixing
Ngrx: Is it possible partially using async pipe?
I am wondering if it's possible partially using async pipe while I use ngrx stroe.
For example,
// ts file
this.name$ = this.store.pipe(
select(SOME.STATE),
map((item) => {
return item.name;
})
)
// html file
<p>{{name$ | async}}</p>
It's simple, but what if I need
// ts file
this.store.pipe(
select(SOME.STATE),
)
.subscribe(item => {
this.name = item.name;
this.age = item.age // <-
})
someMethod() {
const age = this.age;
// ...some processes using 'age' data which from store
}
// html file
<p>{{name}}</p>
Like above, if I have multiple data and I have to do some post-process( such as someMethod() ), I am not sure how to handle async pipe.
No more async pipe means also I have to unsubscribe manually which make more verbose code.
I have tried the below
// ts file
this.name$ = this.store.pipe(
select(SOME.STATE),
map((item) => {
return item.name;
})
)
this.store.pipe(
select(SOME.STATE),
)
.subscribe(item => {
this.age = item.age
})
someMethod() {
const age = this.age;
// ...some processes using 'age' data which from store
}
// html file
<p>{{name$ | async}}</p>
Working but I am wondering if there is better way.
Thanks.
angular ngrx ngrx-store asked Jan 2 at 23:11
TéwaTéwa
1571316
add a comment |
I am wondering if it's possible partially using async pipe while I use ngrx stroe.
For example,
// ts file
this.name$ = this.store.pipe(
select(SOME.STATE),
map((item) => {
return item.name;
})
)
// html file
<p>{{name$ | async}}</p>
It's simple, but what if I need
// ts file
this.store.pipe(
select(SOME.STATE),
)
.subscribe(item => {
this.name = item.name;
this.age = item.age // <-
})
someMethod() {
const age = this.age;
// ...some processes using 'age' data which from store
}
// html file
<p>{{name}}</p>
Like above, if I have multiple data and I have to do some post-process( such as someMethod() ), I am not sure how to handle async pipe.
No more async pipe means also I have to unsubscribe manually which make more verbose code.
I have tried the below
// ts file
this.name$ = this.store.pipe(
select(SOME.STATE),
map((item) => {
return item.name;
})
)
this.store.pipe(
select(SOME.STATE),
)
.subscribe(item => {
this.age = item.age
})
someMethod() {
const age = this.age;
// ...some processes using 'age' data which from store
}
// html file
<p>{{name$ | async}}</p>
Working but I am wondering if there is better way.
Thanks.
angular ngrx ngrx-store asked Jan 2 at 23:11
TéwaTéwa
1571316
Do you intend to do some process onagefor example and show it in the template?
– jal
Jan 2 at 23:14
In your examples you only usenamein the template. Can you clarify?
– jal
Jan 2 at 23:25
.subscribe(value => this.value = value)is never a good thing.
– cgTag
Jan 3 at 3:44
add a comment |
I am wondering if it's possible partially using async pipe while I use ngrx stroe.
For example,
// ts file
this.name$ = this.store.pipe(
select(SOME.STATE),
map((item) => {
return item.name;
})
)
// html file
<p>{{name$ | async}}</p>
It's simple, but what if I need
// ts file
this.store.pipe(
select(SOME.STATE),
)
.subscribe(item => {
this.name = item.name;
this.age = item.age // <-
})
someMethod() {
const age = this.age;
// ...some processes using 'age' data which from store
}
// html file
<p>{{name}}</p>
Like above, if I have multiple data and I have to do some post-process( such as someMethod() ), I am not sure how to handle async pipe.
No more async pipe means also I have to unsubscribe manually which make more verbose code.
I have tried the below
// ts file
this.name$ = this.store.pipe(
select(SOME.STATE),
map((item) => {
return item.name;
})
)
this.store.pipe(
select(SOME.STATE),
)
.subscribe(item => {
this.age = item.age
})
someMethod() {
const age = this.age;
// ...some processes using 'age' data which from store
}
// html file
<p>{{name$ | async}}</p>
Working but I am wondering if there is better way.
Thanks.
angular ngrx ngrx-store asked Jan 2 at 23:11
TéwaTéwa
1571316
I am wondering if it's possible partially using async pipe while I use ngrx stroe.
For example,
// ts file
this.name$ = this.store.pipe(
select(SOME.STATE),
map((item) => {
return item.name;
})
)
// html file
<p>{{name$ | async}}</p>
It's simple, but what if I need
// ts file
this.store.pipe(
select(SOME.STATE),
)
.subscribe(item => {
this.name = item.name;
this.age = item.age // <-
})
someMethod() {
const age = this.age;
// ...some processes using 'age' data which from store
}
// html file
<p>{{name}}</p>
Like above, if I have multiple data and I have to do some post-process( such as someMethod() ), I am not sure how to handle async pipe.
No more async pipe means also I have to unsubscribe manually which make more verbose code.
I have tried the below
// ts file
this.name$ = this.store.pipe(
select(SOME.STATE),
map((item) => {
return item.name;
})
)
this.store.pipe(
select(SOME.STATE),
)
.subscribe(item => {
this.age = item.age
})
someMethod() {
const age = this.age;
// ...some processes using 'age' data which from store
}
// html file
<p>{{name$ | async}}</p>
Working but I am wondering if there is better way.
Thanks.
angular ngrx ngrx-store angular ngrx ngrx-store asked Jan 2 at 23:11
TéwaTéwa
1571316
asked Jan 2 at 23:11
TéwaTéwa
1571316
asked Jan 2 at 23:11
TéwaTéwa
1571316
asked Jan 2 at 23:11
TéwaTéwa
1571316
asked Jan 2 at 23:11
TéwaTéwa
1571316
1571316
Do you intend to do some process onagefor example and show it in the template?
– jal
Jan 2 at 23:14
In your examples you only usenamein the template. Can you clarify?
– jal
Jan 2 at 23:25
.subscribe(value => this.value = value)is never a good thing.
– cgTag
Jan 3 at 3:44
add a comment |
Do you intend to do some process onagefor example and show it in the template?
– jal
Jan 2 at 23:14
In your examples you only usenamein the template. Can you clarify?
– jal
Jan 2 at 23:25
.subscribe(value => this.value = value)is never a good thing.
– cgTag
Jan 3 at 3:44
Do you intend to do some process on
age for example and show it in the template?– jal
Jan 2 at 23:14
Do you intend to do some process on
age for example and show it in the template?– jal
Jan 2 at 23:14
In your examples you only use
name in the template. Can you clarify?– jal
Jan 2 at 23:25
In your examples you only use
name in the template. Can you clarify?– jal
Jan 2 at 23:25
.subscribe(value => this.value = value) is never a good thing.– cgTag
Jan 3 at 3:44
.subscribe(value => this.value = value) is never a good thing.– cgTag
Jan 3 at 3:44
add a comment |
1 Answer
1
active
oldest
votes
Use the tap operator to do that instead of subscribing.
this.name$ = this.store.pipe(
select(SOME.STATE),
tap(item => this.age = item.age),
map((item) => {
return item.name;
}));
There's still really no reason to do it this way though. Instead you should simply have another observable for example age$.
answered Jan 3 at 4:23
ChristianChristian
1,168714
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use the tap operator to do that instead of subscribing.
this.name$ = this.store.pipe(
select(SOME.STATE),
tap(item => this.age = item.age),
map((item) => {
return item.name;
}));
There's still really no reason to do it this way though. Instead you should simply have another observable for example age$.
answered Jan 3 at 4:23
ChristianChristian
1,168714
add a comment |
Use the tap operator to do that instead of subscribing.
this.name$ = this.store.pipe(
select(SOME.STATE),
tap(item => this.age = item.age),
map((item) => {
return item.name;
}));
There's still really no reason to do it this way though. Instead you should simply have another observable for example age$.
answered Jan 3 at 4:23
ChristianChristian
1,168714
add a comment |
Use the tap operator to do that instead of subscribing.
this.name$ = this.store.pipe(
select(SOME.STATE),
tap(item => this.age = item.age),
map((item) => {
return item.name;
}));
There's still really no reason to do it this way though. Instead you should simply have another observable for example age$.
answered Jan 3 at 4:23
ChristianChristian
1,168714
Use the tap operator to do that instead of subscribing.
this.name$ = this.store.pipe(
select(SOME.STATE),
tap(item => this.age = item.age),
map((item) => {
return item.name;
}));
There's still really no reason to do it this way though. Instead you should simply have another observable for example age$.
answered Jan 3 at 4:23
ChristianChristian
1,168714
answered Jan 3 at 4:23
ChristianChristian
1,168714
answered Jan 3 at 4:23
ChristianChristian
1,168714
answered Jan 3 at 4:23
ChristianChristian
1,168714
1,168714
add a comment |
add a comment |
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Do you intend to do some process on
agefor example and show it in the template?– jal
Jan 2 at 23:14
In your examples you only use
namein the template. Can you clarify?– jal
Jan 2 at 23:25
.subscribe(value => this.value = value)is never a good thing.– cgTag
Jan 3 at 3:44