Mixing
Solve differential equation involving $y$ through $^{(5)}$
1
$begingroup$
I'm trying to self-study in advance but I'm having a hard time.
Solve the linear differential equation: $$bigl(y^{(5)}–12y^{(4)}+52y^{(3)}–112y''+192y'–256bigr)y = 0$$
ordinary-differential-equations
edited Feb 3 at 0:35
Chase Ryan Taylor
4,46221531
asked Sep 4 '16 at 11:58
Agent CollinsAgent Collins
134
$endgroup$
add a comment |
1
$begingroup$
I'm trying to self-study in advance but I'm having a hard time.
Solve the linear differential equation: $$bigl(y^{(5)}–12y^{(4)}+52y^{(3)}–112y''+192y'–256bigr)y = 0$$
ordinary-differential-equations
edited Feb 3 at 0:35
Chase Ryan Taylor
4,46221531
asked Sep 4 '16 at 11:58
Agent CollinsAgent Collins
134
$endgroup$
1
$begingroup$
is $$D5y=y'''''(x)$$?
$endgroup$
– Dr. Sonnhard Graubner
Sep 4 '16 at 12:00
$begingroup$
I got (D-4)^3(D^2 +4) , what's next then?
$endgroup$
– Agent Collins
Sep 4 '16 at 12:44
$begingroup$
I got now the equation: Y=(C1 + C2x + C3x^2) e^4x) +.. What about my D^2+4? How can I put that in my equation?
$endgroup$
– Agent Collins
Sep 4 '16 at 13:07
$begingroup$
I can't 😩 What is the complex root of D^2+4 ? Is it 2i? But what is the complex conjugate of that?
$endgroup$
– Agent Collins
Sep 4 '16 at 14:32
$begingroup$
This is not a linear dif. eq. because it is not of the form $y’ + f(x),y=g(x)$.
$endgroup$
– Chase Ryan Taylor
Feb 3 at 0:36
add a comment |
1
1
1
$begingroup$
I'm trying to self-study in advance but I'm having a hard time.
Solve the linear differential equation: $$bigl(y^{(5)}–12y^{(4)}+52y^{(3)}–112y''+192y'–256bigr)y = 0$$
ordinary-differential-equations
edited Feb 3 at 0:35
Chase Ryan Taylor
4,46221531
asked Sep 4 '16 at 11:58
Agent CollinsAgent Collins
134
$endgroup$
I'm trying to self-study in advance but I'm having a hard time.
Solve the linear differential equation: $$bigl(y^{(5)}–12y^{(4)}+52y^{(3)}–112y''+192y'–256bigr)y = 0$$
ordinary-differential-equations
ordinary-differential-equations
edited Feb 3 at 0:35
Chase Ryan Taylor
4,46221531
asked Sep 4 '16 at 11:58
Agent CollinsAgent Collins
134
edited Feb 3 at 0:35
Chase Ryan Taylor
4,46221531
asked Sep 4 '16 at 11:58
Agent CollinsAgent Collins
134
edited Feb 3 at 0:35
Chase Ryan Taylor
4,46221531
edited Feb 3 at 0:35
Chase Ryan Taylor
4,46221531
edited Feb 3 at 0:35
Chase Ryan Taylor
4,46221531
4,46221531
asked Sep 4 '16 at 11:58
Agent CollinsAgent Collins
134
asked Sep 4 '16 at 11:58
Agent CollinsAgent Collins
134
asked Sep 4 '16 at 11:58
Agent CollinsAgent Collins
134
134
1
$begingroup$
is $$D5y=y'''''(x)$$?
$endgroup$
– Dr. Sonnhard Graubner
Sep 4 '16 at 12:00
$begingroup$
I got (D-4)^3(D^2 +4) , what's next then?
$endgroup$
– Agent Collins
Sep 4 '16 at 12:44
$begingroup$
I got now the equation: Y=(C1 + C2x + C3x^2) e^4x) +.. What about my D^2+4? How can I put that in my equation?
$endgroup$
– Agent Collins
Sep 4 '16 at 13:07
$begingroup$
I can't 😩 What is the complex root of D^2+4 ? Is it 2i? But what is the complex conjugate of that?
$endgroup$
– Agent Collins
Sep 4 '16 at 14:32
$begingroup$
This is not a linear dif. eq. because it is not of the form $y’ + f(x),y=g(x)$.
$endgroup$
– Chase Ryan Taylor
Feb 3 at 0:36
add a comment |
1
$begingroup$
is $$D5y=y'''''(x)$$?
$endgroup$
– Dr. Sonnhard Graubner
Sep 4 '16 at 12:00
$begingroup$
I got (D-4)^3(D^2 +4) , what's next then?
$endgroup$
– Agent Collins
Sep 4 '16 at 12:44
$begingroup$
I got now the equation: Y=(C1 + C2x + C3x^2) e^4x) +.. What about my D^2+4? How can I put that in my equation?
$endgroup$
– Agent Collins
Sep 4 '16 at 13:07
$begingroup$
I can't 😩 What is the complex root of D^2+4 ? Is it 2i? But what is the complex conjugate of that?
$endgroup$
– Agent Collins
Sep 4 '16 at 14:32
$begingroup$
This is not a linear dif. eq. because it is not of the form $y’ + f(x),y=g(x)$.
$endgroup$
– Chase Ryan Taylor
Feb 3 at 0:36
1
1
$begingroup$
is $$D5y=y'''''(x)$$?
$endgroup$
– Dr. Sonnhard Graubner
Sep 4 '16 at 12:00
$begingroup$
is $$D5y=y'''''(x)$$?
$endgroup$
– Dr. Sonnhard Graubner
Sep 4 '16 at 12:00
$begingroup$
I got (D-4)^3(D^2 +4) , what's next then?
$endgroup$
– Agent Collins
Sep 4 '16 at 12:44
$begingroup$
I got (D-4)^3(D^2 +4) , what's next then?
$endgroup$
– Agent Collins
Sep 4 '16 at 12:44
$begingroup$
I got now the equation: Y=(C1 + C2x + C3x^2) e^4x) +.. What about my D^2+4? How can I put that in my equation?
$endgroup$
– Agent Collins
Sep 4 '16 at 13:07
$begingroup$
I got now the equation: Y=(C1 + C2x + C3x^2) e^4x) +.. What about my D^2+4? How can I put that in my equation?
$endgroup$
– Agent Collins
Sep 4 '16 at 13:07
$begingroup$
I can't 😩 What is the complex root of D^2+4 ? Is it 2i? But what is the complex conjugate of that?
$endgroup$
– Agent Collins
Sep 4 '16 at 14:32
$begingroup$
I can't 😩 What is the complex root of D^2+4 ? Is it 2i? But what is the complex conjugate of that?
$endgroup$
– Agent Collins
Sep 4 '16 at 14:32
$begingroup$
This is not a linear dif. eq. because it is not of the form $y’ + f(x),y=g(x)$.
$endgroup$
– Chase Ryan Taylor
Feb 3 at 0:36
$begingroup$
This is not a linear dif. eq. because it is not of the form $y’ + f(x),y=g(x)$.
$endgroup$
– Chase Ryan Taylor
Feb 3 at 0:36
add a comment |
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1
$begingroup$
is $$D5y=y'''''(x)$$?
$endgroup$
– Dr. Sonnhard Graubner
Sep 4 '16 at 12:00
$begingroup$
I got (D-4)^3(D^2 +4) , what's next then?
$endgroup$
– Agent Collins
Sep 4 '16 at 12:44
$begingroup$
I got now the equation: Y=(C1 + C2x + C3x^2) e^4x) +.. What about my D^2+4? How can I put that in my equation?
$endgroup$
– Agent Collins
Sep 4 '16 at 13:07
$begingroup$
I can't 😩 What is the complex root of D^2+4 ? Is it 2i? But what is the complex conjugate of that?
$endgroup$
– Agent Collins
Sep 4 '16 at 14:32
$begingroup$
This is not a linear dif. eq. because it is not of the form $y’ + f(x),y=g(x)$.
$endgroup$
– Chase Ryan Taylor
Feb 3 at 0:36