Concated Oracle statement in SQL Server












0














I have this statement in Oracle:



TO_TIMESTAMP(TO_CHAR(TO_DATE('2018.11.19 13:14:00', 'YYYY.MM.DD HH24:MI:SS')


Is there an equivalent statement in SQL Server for this?










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  • 1




    'yyyy.MM.dd HH:mm:ss' isn't a valid date. '2018.11.11 would be. Also, the TO_CHAR and TO_TIMESTAMP functions aren't closed, so that would also generate an error.
    – Larnu
    Nov 19 '18 at 12:13










  • Oh I understood something wrong, edited it now
    – SilverFullbuster
    Nov 19 '18 at 12:15












  • Could you please mention your expected output ?
    – Santhana
    Nov 19 '18 at 14:03
















0














I have this statement in Oracle:



TO_TIMESTAMP(TO_CHAR(TO_DATE('2018.11.19 13:14:00', 'YYYY.MM.DD HH24:MI:SS')


Is there an equivalent statement in SQL Server for this?










share|improve this question




















  • 1




    'yyyy.MM.dd HH:mm:ss' isn't a valid date. '2018.11.11 would be. Also, the TO_CHAR and TO_TIMESTAMP functions aren't closed, so that would also generate an error.
    – Larnu
    Nov 19 '18 at 12:13










  • Oh I understood something wrong, edited it now
    – SilverFullbuster
    Nov 19 '18 at 12:15












  • Could you please mention your expected output ?
    – Santhana
    Nov 19 '18 at 14:03














0












0








0







I have this statement in Oracle:



TO_TIMESTAMP(TO_CHAR(TO_DATE('2018.11.19 13:14:00', 'YYYY.MM.DD HH24:MI:SS')


Is there an equivalent statement in SQL Server for this?










share|improve this question















I have this statement in Oracle:



TO_TIMESTAMP(TO_CHAR(TO_DATE('2018.11.19 13:14:00', 'YYYY.MM.DD HH24:MI:SS')


Is there an equivalent statement in SQL Server for this?







sql sql-server oracle type-conversion migration






share|improve this question















share|improve this question













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share|improve this question








edited Nov 19 '18 at 12:15

























asked Nov 19 '18 at 12:09









SilverFullbuster

171113




171113








  • 1




    'yyyy.MM.dd HH:mm:ss' isn't a valid date. '2018.11.11 would be. Also, the TO_CHAR and TO_TIMESTAMP functions aren't closed, so that would also generate an error.
    – Larnu
    Nov 19 '18 at 12:13










  • Oh I understood something wrong, edited it now
    – SilverFullbuster
    Nov 19 '18 at 12:15












  • Could you please mention your expected output ?
    – Santhana
    Nov 19 '18 at 14:03














  • 1




    'yyyy.MM.dd HH:mm:ss' isn't a valid date. '2018.11.11 would be. Also, the TO_CHAR and TO_TIMESTAMP functions aren't closed, so that would also generate an error.
    – Larnu
    Nov 19 '18 at 12:13










  • Oh I understood something wrong, edited it now
    – SilverFullbuster
    Nov 19 '18 at 12:15












  • Could you please mention your expected output ?
    – Santhana
    Nov 19 '18 at 14:03








1




1




'yyyy.MM.dd HH:mm:ss' isn't a valid date. '2018.11.11 would be. Also, the TO_CHAR and TO_TIMESTAMP functions aren't closed, so that would also generate an error.
– Larnu
Nov 19 '18 at 12:13




'yyyy.MM.dd HH:mm:ss' isn't a valid date. '2018.11.11 would be. Also, the TO_CHAR and TO_TIMESTAMP functions aren't closed, so that would also generate an error.
– Larnu
Nov 19 '18 at 12:13












Oh I understood something wrong, edited it now
– SilverFullbuster
Nov 19 '18 at 12:15






Oh I understood something wrong, edited it now
– SilverFullbuster
Nov 19 '18 at 12:15














Could you please mention your expected output ?
– Santhana
Nov 19 '18 at 14:03




Could you please mention your expected output ?
– Santhana
Nov 19 '18 at 14:03












2 Answers
2






active

oldest

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0














You can try below



select format(getdate(),'yyyy.MM.dd HH:mm:ss')





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    0














    use format



    declare @d datetime='2018.11.19 13:14:00';

    select format(@d,'yyyy-MM-dd hh:mm:ss.fff') as date





    share|improve this answer





















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      You can try below



      select format(getdate(),'yyyy.MM.dd HH:mm:ss')





      share|improve this answer


























        0














        You can try below



        select format(getdate(),'yyyy.MM.dd HH:mm:ss')





        share|improve this answer
























          0












          0








          0






          You can try below



          select format(getdate(),'yyyy.MM.dd HH:mm:ss')





          share|improve this answer












          You can try below



          select format(getdate(),'yyyy.MM.dd HH:mm:ss')






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 19 '18 at 12:13









          fa06

          11k2917




          11k2917

























              0














              use format



              declare @d datetime='2018.11.19 13:14:00';

              select format(@d,'yyyy-MM-dd hh:mm:ss.fff') as date





              share|improve this answer


























                0














                use format



                declare @d datetime='2018.11.19 13:14:00';

                select format(@d,'yyyy-MM-dd hh:mm:ss.fff') as date





                share|improve this answer
























                  0












                  0








                  0






                  use format



                  declare @d datetime='2018.11.19 13:14:00';

                  select format(@d,'yyyy-MM-dd hh:mm:ss.fff') as date





                  share|improve this answer












                  use format



                  declare @d datetime='2018.11.19 13:14:00';

                  select format(@d,'yyyy-MM-dd hh:mm:ss.fff') as date






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 19 '18 at 12:23









                  Zaynul Abadin Tuhin

                  11.3k2831




                  11.3k2831






























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