Mixing
Validate two forms inside one form element with ParsleyJS
I'm building two forms which will live on a single page on a Kentico website. kentico websites are wrapped in one single form field so I can't create individual form elements for each form on the page. The problem is parsleyJS will only allow you to pass a form to initialise it e.g. $("#form").parsley(); and I need to validate the forms independent of each other. Has anyone had this issue before? Can anyone recommend a workaround.
$("#form").parsley();input{
display:block;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/parsley.js/2.8.1/parsley.min.js"></script>
<form action="" id="form">
<div class="form1">
<label for="fname">First Name</label>
<input type="text" name="fname" required>
<label for="lname">Last Name</label>
<input type="text" name="lname" required>
<input type="submit" value="submit">
</div>
<div class="form2">
<input type="text" name="anotherInput" required>
<input type="submit" value="submit">
</div>
</form>javascript forms kentico parsley.js
asked Nov 19 '18 at 11:59
user3486427
1239
add a comment |
I'm building two forms which will live on a single page on a Kentico website. kentico websites are wrapped in one single form field so I can't create individual form elements for each form on the page. The problem is parsleyJS will only allow you to pass a form to initialise it e.g. $("#form").parsley(); and I need to validate the forms independent of each other. Has anyone had this issue before? Can anyone recommend a workaround.
$("#form").parsley();input{
display:block;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/parsley.js/2.8.1/parsley.min.js"></script>
<form action="" id="form">
<div class="form1">
<label for="fname">First Name</label>
<input type="text" name="fname" required>
<label for="lname">Last Name</label>
<input type="text" name="lname" required>
<input type="submit" value="submit">
</div>
<div class="form2">
<input type="text" name="anotherInput" required>
<input type="submit" value="submit">
</div>
</form>javascript forms kentico parsley.js
asked Nov 19 '18 at 11:59
user3486427
1239
add a comment |
I'm building two forms which will live on a single page on a Kentico website. kentico websites are wrapped in one single form field so I can't create individual form elements for each form on the page. The problem is parsleyJS will only allow you to pass a form to initialise it e.g. $("#form").parsley(); and I need to validate the forms independent of each other. Has anyone had this issue before? Can anyone recommend a workaround.
$("#form").parsley();input{
display:block;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/parsley.js/2.8.1/parsley.min.js"></script>
<form action="" id="form">
<div class="form1">
<label for="fname">First Name</label>
<input type="text" name="fname" required>
<label for="lname">Last Name</label>
<input type="text" name="lname" required>
<input type="submit" value="submit">
</div>
<div class="form2">
<input type="text" name="anotherInput" required>
<input type="submit" value="submit">
</div>
</form>javascript forms kentico parsley.js
asked Nov 19 '18 at 11:59
user3486427
1239
I'm building two forms which will live on a single page on a Kentico website. kentico websites are wrapped in one single form field so I can't create individual form elements for each form on the page. The problem is parsleyJS will only allow you to pass a form to initialise it e.g. $("#form").parsley(); and I need to validate the forms independent of each other. Has anyone had this issue before? Can anyone recommend a workaround.
$("#form").parsley();input{
display:block;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/parsley.js/2.8.1/parsley.min.js"></script>
<form action="" id="form">
<div class="form1">
<label for="fname">First Name</label>
<input type="text" name="fname" required>
<label for="lname">Last Name</label>
<input type="text" name="lname" required>
<input type="submit" value="submit">
</div>
<div class="form2">
<input type="text" name="anotherInput" required>
<input type="submit" value="submit">
</div>
</form>$("#form").parsley();input{
display:block;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/parsley.js/2.8.1/parsley.min.js"></script>
<form action="" id="form">
<div class="form1">
<label for="fname">First Name</label>
<input type="text" name="fname" required>
<label for="lname">Last Name</label>
<input type="text" name="lname" required>
<input type="submit" value="submit">
</div>
<div class="form2">
<input type="text" name="anotherInput" required>
<input type="submit" value="submit">
</div>
</form>$("#form").parsley();input{
display:block;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/parsley.js/2.8.1/parsley.min.js"></script>
<form action="" id="form">
<div class="form1">
<label for="fname">First Name</label>
<input type="text" name="fname" required>
<label for="lname">Last Name</label>
<input type="text" name="lname" required>
<input type="submit" value="submit">
</div>
<div class="form2">
<input type="text" name="anotherInput" required>
<input type="submit" value="submit">
</div>
</form>javascript forms kentico parsley.js
javascript forms kentico parsley.js
asked Nov 19 '18 at 11:59
user3486427
1239
asked Nov 19 '18 at 11:59
user3486427
1239
asked Nov 19 '18 at 11:59
user3486427
1239
asked Nov 19 '18 at 11:59
user3486427
1239
asked Nov 19 '18 at 11:59
user3486427
1239
1239
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You may be able to get the results you want using the group option to validate only part of the fields in your form. This is used in this example of a multi step form.
answered Nov 19 '18 at 20:43
Marc-André Lafortune
62.4k12139158
add a comment |
Initialize the forms independent of one another by using the class selector.
$(".form1").parsley();
$(".form2").parsley();
answered Nov 19 '18 at 14:06
Brenden Kehren
4,277922
You can only pass a form to parsley it will not accept a class unless it is on a form.
– user3486427
Nov 19 '18 at 14:45
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You may be able to get the results you want using the group option to validate only part of the fields in your form. This is used in this example of a multi step form.
answered Nov 19 '18 at 20:43
Marc-André Lafortune
62.4k12139158
add a comment |
You may be able to get the results you want using the group option to validate only part of the fields in your form. This is used in this example of a multi step form.
answered Nov 19 '18 at 20:43
Marc-André Lafortune
62.4k12139158
add a comment |
You may be able to get the results you want using the group option to validate only part of the fields in your form. This is used in this example of a multi step form.
answered Nov 19 '18 at 20:43
Marc-André Lafortune
62.4k12139158
You may be able to get the results you want using the group option to validate only part of the fields in your form. This is used in this example of a multi step form.
answered Nov 19 '18 at 20:43
Marc-André Lafortune
62.4k12139158
answered Nov 19 '18 at 20:43
Marc-André Lafortune
62.4k12139158
answered Nov 19 '18 at 20:43
Marc-André Lafortune
62.4k12139158
answered Nov 19 '18 at 20:43
Marc-André Lafortune
62.4k12139158
62.4k12139158
add a comment |
add a comment |
Initialize the forms independent of one another by using the class selector.
$(".form1").parsley();
$(".form2").parsley();
answered Nov 19 '18 at 14:06
Brenden Kehren
4,277922
You can only pass a form to parsley it will not accept a class unless it is on a form.
– user3486427
Nov 19 '18 at 14:45
add a comment |
Initialize the forms independent of one another by using the class selector.
$(".form1").parsley();
$(".form2").parsley();
answered Nov 19 '18 at 14:06
Brenden Kehren
4,277922
You can only pass a form to parsley it will not accept a class unless it is on a form.
– user3486427
Nov 19 '18 at 14:45
add a comment |
Initialize the forms independent of one another by using the class selector.
$(".form1").parsley();
$(".form2").parsley();
answered Nov 19 '18 at 14:06
Brenden Kehren
4,277922
Initialize the forms independent of one another by using the class selector.
$(".form1").parsley();
$(".form2").parsley();
answered Nov 19 '18 at 14:06
Brenden Kehren
4,277922
answered Nov 19 '18 at 14:06
Brenden Kehren
4,277922
answered Nov 19 '18 at 14:06
Brenden Kehren
4,277922
answered Nov 19 '18 at 14:06
Brenden Kehren
4,277922
4,277922
You can only pass a form to parsley it will not accept a class unless it is on a form.
– user3486427
Nov 19 '18 at 14:45
add a comment |
You can only pass a form to parsley it will not accept a class unless it is on a form.
– user3486427
Nov 19 '18 at 14:45
You can only pass a form to parsley it will not accept a class unless it is on a form.
– user3486427
Nov 19 '18 at 14:45
You can only pass a form to parsley it will not accept a class unless it is on a form.
– user3486427
Nov 19 '18 at 14:45
add a comment |
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