Conditionnal 'changed_when' based on output in a 'with_items' task












0














I have a simple shell task which is feed with_items. I want to have the 'changed' status only when the run actually did something. So for that I have to parse the output and look for a «Done».



The issue is using a register at the same time that the with_items generates a list of results. And I don't find a way to access the stdout of the current loop iteration.



---
- name: Test to set changed status only on when output match with 'Done'
hosts: my-host-01
gather_facts: no

tasks:
- name: Task doing stuff
shell: |
echo {{ item }}
register: do_stuff
with_items:
- "Doing... Done!"
- "Nothing to do"
#changed_when: do_stuff.results[{{ item.id }}].stdout.find('Done')

- name: Print 'do_stuff' var to debug
debug:
var: do_stuff
- name: Try to access to the desired stdout
debug:
var: do_stuff.results[0].stdout


The expected result that I want would be:



TASK [Task doing stuff]
*************************************************************************
changed: [cnode02] => (item=Doing... Done!)
Ok: [cnode02] => (item=Nothing to do)









share|improve this question
























  • The following answer didn't help me as it process it in the next task which is too late to update the task status I assume.
    – xenlo
    Nov 19 '18 at 12:03










  • Check this: stackoverflow.com/a/43487756/2795592
    – Konstantin Suvorov
    Nov 19 '18 at 12:06










  • That's also done in 2 tasks. It will not help me to have the correct status of my initial task.
    – xenlo
    Nov 19 '18 at 12:47
















0














I have a simple shell task which is feed with_items. I want to have the 'changed' status only when the run actually did something. So for that I have to parse the output and look for a «Done».



The issue is using a register at the same time that the with_items generates a list of results. And I don't find a way to access the stdout of the current loop iteration.



---
- name: Test to set changed status only on when output match with 'Done'
hosts: my-host-01
gather_facts: no

tasks:
- name: Task doing stuff
shell: |
echo {{ item }}
register: do_stuff
with_items:
- "Doing... Done!"
- "Nothing to do"
#changed_when: do_stuff.results[{{ item.id }}].stdout.find('Done')

- name: Print 'do_stuff' var to debug
debug:
var: do_stuff
- name: Try to access to the desired stdout
debug:
var: do_stuff.results[0].stdout


The expected result that I want would be:



TASK [Task doing stuff]
*************************************************************************
changed: [cnode02] => (item=Doing... Done!)
Ok: [cnode02] => (item=Nothing to do)









share|improve this question
























  • The following answer didn't help me as it process it in the next task which is too late to update the task status I assume.
    – xenlo
    Nov 19 '18 at 12:03










  • Check this: stackoverflow.com/a/43487756/2795592
    – Konstantin Suvorov
    Nov 19 '18 at 12:06










  • That's also done in 2 tasks. It will not help me to have the correct status of my initial task.
    – xenlo
    Nov 19 '18 at 12:47














0












0








0







I have a simple shell task which is feed with_items. I want to have the 'changed' status only when the run actually did something. So for that I have to parse the output and look for a «Done».



The issue is using a register at the same time that the with_items generates a list of results. And I don't find a way to access the stdout of the current loop iteration.



---
- name: Test to set changed status only on when output match with 'Done'
hosts: my-host-01
gather_facts: no

tasks:
- name: Task doing stuff
shell: |
echo {{ item }}
register: do_stuff
with_items:
- "Doing... Done!"
- "Nothing to do"
#changed_when: do_stuff.results[{{ item.id }}].stdout.find('Done')

- name: Print 'do_stuff' var to debug
debug:
var: do_stuff
- name: Try to access to the desired stdout
debug:
var: do_stuff.results[0].stdout


The expected result that I want would be:



TASK [Task doing stuff]
*************************************************************************
changed: [cnode02] => (item=Doing... Done!)
Ok: [cnode02] => (item=Nothing to do)









share|improve this question















I have a simple shell task which is feed with_items. I want to have the 'changed' status only when the run actually did something. So for that I have to parse the output and look for a «Done».



The issue is using a register at the same time that the with_items generates a list of results. And I don't find a way to access the stdout of the current loop iteration.



---
- name: Test to set changed status only on when output match with 'Done'
hosts: my-host-01
gather_facts: no

tasks:
- name: Task doing stuff
shell: |
echo {{ item }}
register: do_stuff
with_items:
- "Doing... Done!"
- "Nothing to do"
#changed_when: do_stuff.results[{{ item.id }}].stdout.find('Done')

- name: Print 'do_stuff' var to debug
debug:
var: do_stuff
- name: Try to access to the desired stdout
debug:
var: do_stuff.results[0].stdout


The expected result that I want would be:



TASK [Task doing stuff]
*************************************************************************
changed: [cnode02] => (item=Doing... Done!)
Ok: [cnode02] => (item=Nothing to do)






loops ansible






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 12:50

























asked Nov 19 '18 at 11:59









xenlo

106




106












  • The following answer didn't help me as it process it in the next task which is too late to update the task status I assume.
    – xenlo
    Nov 19 '18 at 12:03










  • Check this: stackoverflow.com/a/43487756/2795592
    – Konstantin Suvorov
    Nov 19 '18 at 12:06










  • That's also done in 2 tasks. It will not help me to have the correct status of my initial task.
    – xenlo
    Nov 19 '18 at 12:47


















  • The following answer didn't help me as it process it in the next task which is too late to update the task status I assume.
    – xenlo
    Nov 19 '18 at 12:03










  • Check this: stackoverflow.com/a/43487756/2795592
    – Konstantin Suvorov
    Nov 19 '18 at 12:06










  • That's also done in 2 tasks. It will not help me to have the correct status of my initial task.
    – xenlo
    Nov 19 '18 at 12:47
















The following answer didn't help me as it process it in the next task which is too late to update the task status I assume.
– xenlo
Nov 19 '18 at 12:03




The following answer didn't help me as it process it in the next task which is too late to update the task status I assume.
– xenlo
Nov 19 '18 at 12:03












Check this: stackoverflow.com/a/43487756/2795592
– Konstantin Suvorov
Nov 19 '18 at 12:06




Check this: stackoverflow.com/a/43487756/2795592
– Konstantin Suvorov
Nov 19 '18 at 12:06












That's also done in 2 tasks. It will not help me to have the correct status of my initial task.
– xenlo
Nov 19 '18 at 12:47




That's also done in 2 tasks. It will not help me to have the correct status of my initial task.
– xenlo
Nov 19 '18 at 12:47

















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