Mixing
Azure Service Bus in Azure Function
I'm using Service Bus trigger in Azure Functions v2.0. In the previous version i have used Brokered Message and there are no problems with this. But as i moved to v2.0 i need to use Message instead of Brokered Message. And once i called
await queueClient.CompleteAsync(message.SystemProperties.LockToken);
i get an exception which says:
The lock supplied is invalid. Either the lock expired, or the message has already been removed from the queue, or was received by a different receiver instance.
I have configured my Queue Client as follows:
var queueClient = new QueueClient(serviceBusString, MessageQueueName);
Does anyone face this issue? Are there any workarounds ?
c#
azure .net-core azure-functions azureservicebus asked Nov 20 '18 at 15:20
usrereusrere
234
add a comment |
I'm using Service Bus trigger in Azure Functions v2.0. In the previous version i have used Brokered Message and there are no problems with this. But as i moved to v2.0 i need to use Message instead of Brokered Message. And once i called
await queueClient.CompleteAsync(message.SystemProperties.LockToken);
i get an exception which says:
The lock supplied is invalid. Either the lock expired, or the message has already been removed from the queue, or was received by a different receiver instance.
I have configured my Queue Client as follows:
var queueClient = new QueueClient(serviceBusString, MessageQueueName);
Does anyone face this issue? Are there any workarounds ?
c#
azure .net-core azure-functions azureservicebus asked Nov 20 '18 at 15:20
usrereusrere
234
add a comment |
I'm using Service Bus trigger in Azure Functions v2.0. In the previous version i have used Brokered Message and there are no problems with this. But as i moved to v2.0 i need to use Message instead of Brokered Message. And once i called
await queueClient.CompleteAsync(message.SystemProperties.LockToken);
i get an exception which says:
The lock supplied is invalid. Either the lock expired, or the message has already been removed from the queue, or was received by a different receiver instance.
I have configured my Queue Client as follows:
var queueClient = new QueueClient(serviceBusString, MessageQueueName);
Does anyone face this issue? Are there any workarounds ?
c#
azure .net-core azure-functions azureservicebus asked Nov 20 '18 at 15:20
usrereusrere
234
I'm using Service Bus trigger in Azure Functions v2.0. In the previous version i have used Brokered Message and there are no problems with this. But as i moved to v2.0 i need to use Message instead of Brokered Message. And once i called
await queueClient.CompleteAsync(message.SystemProperties.LockToken);
i get an exception which says:
The lock supplied is invalid. Either the lock expired, or the message has already been removed from the queue, or was received by a different receiver instance.
I have configured my Queue Client as follows:
var queueClient = new QueueClient(serviceBusString, MessageQueueName);
Does anyone face this issue? Are there any workarounds ?
c#
azure .net-core azure-functions azureservicebus c#
azure .net-core azure-functions azureservicebus asked Nov 20 '18 at 15:20
usrereusrere
234
asked Nov 20 '18 at 15:20
usrereusrere
234
asked Nov 20 '18 at 15:20
usrereusrere
234
asked Nov 20 '18 at 15:20
usrereusrere
234
asked Nov 20 '18 at 15:20
usrereusrere
234
234
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Incoming messages that trigger Function execution are automatically completed when function is done. You do not need to complete those messages yourself. The exception you see is indicating that.
answered Nov 20 '18 at 18:11
Sean FeldmanSean Feldman
9,12922848
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53396173%2fazure-service-bus-in-azure-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Incoming messages that trigger Function execution are automatically completed when function is done. You do not need to complete those messages yourself. The exception you see is indicating that.
answered Nov 20 '18 at 18:11
Sean FeldmanSean Feldman
9,12922848
add a comment |
Incoming messages that trigger Function execution are automatically completed when function is done. You do not need to complete those messages yourself. The exception you see is indicating that.
answered Nov 20 '18 at 18:11
Sean FeldmanSean Feldman
9,12922848
add a comment |
Incoming messages that trigger Function execution are automatically completed when function is done. You do not need to complete those messages yourself. The exception you see is indicating that.
answered Nov 20 '18 at 18:11
Sean FeldmanSean Feldman
9,12922848
Incoming messages that trigger Function execution are automatically completed when function is done. You do not need to complete those messages yourself. The exception you see is indicating that.
answered Nov 20 '18 at 18:11
Sean FeldmanSean Feldman
9,12922848
answered Nov 20 '18 at 18:11
Sean FeldmanSean Feldman
9,12922848
answered Nov 20 '18 at 18:11
Sean FeldmanSean Feldman
9,12922848
answered Nov 20 '18 at 18:11
Sean FeldmanSean Feldman
9,12922848
9,12922848
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53396173%2fazure-service-bus-in-azure-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
