How to extract text which are outside and inside a bracket from a sentence through javascript or jquery

I have a sentence stored in a variable.That sentence I need to extract into 3 parts which I have mentioned in other 3 variable in my code,for now I have hard coded in the variable. Then I need to console those variable separately.I have already tried with slice for first one,is there any better way to do it.Here is the code below.Can anyone please help me.

HTML

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

SCRIPT

$(document).ready(function(){

 var maintext = "Welcome to project,are you (1. Existing user or 2. new user)"  ;

 var text_split1 = maintext.split(' ').slice(0,4).join(' ');

//var text_split1 =  "Welcome to project,are you" ; /*this text should come from maintext after extraction*/

var text_split2 = "1. Existing user" ; /*this text should come from maintext after extraction*/

var text_split3 = "2. new user" ; /*this text should come from maintext after extraction*/

console.log(text_split1);

console.log(text_split2);

console.log(text_split3);

});

edited Nov 20 '18 at 16:29

asked Nov 20 '18 at 16:18

carreankush

1607

1

What have you tried so far? What specifically are you having difficulty with?

– freedomn-m
Nov 20 '18 at 16:20

2

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– freedomn-m
Nov 20 '18 at 16:21

I have tried slice,but if there any other better way to fix this, var text_split1 = maintext.split(' ').slice(0,4).join(' ');

– carreankush
Nov 20 '18 at 16:25

You need to explicitly state your rules. eg text1 is text before first (, text2 is inside the bracket, before and no including "or", etc. Otherwise it's just guesswork and only fit for this exact scenario - which your existing code is also; only fit for this exact scenario.

– freedomn-m
Nov 20 '18 at 16:32

add a comment |

HTML

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

SCRIPT

$(document).ready(function(){

 var maintext = "Welcome to project,are you (1. Existing user or 2. new user)"  ;

 var text_split1 = maintext.split(' ').slice(0,4).join(' ');

//var text_split1 =  "Welcome to project,are you" ; /*this text should come from maintext after extraction*/

var text_split2 = "1. Existing user" ; /*this text should come from maintext after extraction*/

var text_split3 = "2. new user" ; /*this text should come from maintext after extraction*/

console.log(text_split1);

console.log(text_split2);

console.log(text_split3);

});

edited Nov 20 '18 at 16:29

asked Nov 20 '18 at 16:18

carreankush

1607

1

What have you tried so far? What specifically are you having difficulty with?

– freedomn-m
Nov 20 '18 at 16:20

2

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– freedomn-m
Nov 20 '18 at 16:21

I have tried slice,but if there any other better way to fix this, var text_split1 = maintext.split(' ').slice(0,4).join(' ');

– carreankush
Nov 20 '18 at 16:25

You need to explicitly state your rules. eg text1 is text before first (, text2 is inside the bracket, before and no including "or", etc. Otherwise it's just guesswork and only fit for this exact scenario - which your existing code is also; only fit for this exact scenario.

– freedomn-m
Nov 20 '18 at 16:32

add a comment |

HTML

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

SCRIPT

$(document).ready(function(){

 var maintext = "Welcome to project,are you (1. Existing user or 2. new user)"  ;

 var text_split1 = maintext.split(' ').slice(0,4).join(' ');

//var text_split1 =  "Welcome to project,are you" ; /*this text should come from maintext after extraction*/

var text_split2 = "1. Existing user" ; /*this text should come from maintext after extraction*/

var text_split3 = "2. new user" ; /*this text should come from maintext after extraction*/

console.log(text_split1);

console.log(text_split2);

console.log(text_split3);

});

edited Nov 20 '18 at 16:29

asked Nov 20 '18 at 16:18

carreankush

1607

HTML

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

SCRIPT

$(document).ready(function(){

 var maintext = "Welcome to project,are you (1. Existing user or 2. new user)"  ;

 var text_split1 = maintext.split(' ').slice(0,4).join(' ');

//var text_split1 =  "Welcome to project,are you" ; /*this text should come from maintext after extraction*/

var text_split2 = "1. Existing user" ; /*this text should come from maintext after extraction*/

var text_split3 = "2. new user" ; /*this text should come from maintext after extraction*/

console.log(text_split1);

console.log(text_split2);

console.log(text_split3);

});

javascript jquery html

edited Nov 20 '18 at 16:29

asked Nov 20 '18 at 16:18

carreankush

1607

edited Nov 20 '18 at 16:29

asked Nov 20 '18 at 16:18

carreankush

1607

edited Nov 20 '18 at 16:29

asked Nov 20 '18 at 16:18

carreankush

1607

asked Nov 20 '18 at 16:18

carreankush

1607

asked Nov 20 '18 at 16:18

carreankush

1607

1

What have you tried so far? What specifically are you having difficulty with?

– freedomn-m
Nov 20 '18 at 16:20

2

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– freedomn-m
Nov 20 '18 at 16:21

I have tried slice,but if there any other better way to fix this, var text_split1 = maintext.split(' ').slice(0,4).join(' ');

– carreankush
Nov 20 '18 at 16:25

You need to explicitly state your rules. eg text1 is text before first (, text2 is inside the bracket, before and no including "or", etc. Otherwise it's just guesswork and only fit for this exact scenario - which your existing code is also; only fit for this exact scenario.

– freedomn-m
Nov 20 '18 at 16:32

add a comment |

1

What have you tried so far? What specifically are you having difficulty with?

– freedomn-m
Nov 20 '18 at 16:20

2

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– freedomn-m
Nov 20 '18 at 16:21

I have tried slice,but if there any other better way to fix this, var text_split1 = maintext.split(' ').slice(0,4).join(' ');

– carreankush
Nov 20 '18 at 16:25

You need to explicitly state your rules. eg text1 is text before first (, text2 is inside the bracket, before and no including "or", etc. Otherwise it's just guesswork and only fit for this exact scenario - which your existing code is also; only fit for this exact scenario.

– freedomn-m
Nov 20 '18 at 16:32

What have you tried so far? What specifically are you having difficulty with?

– freedomn-m
Nov 20 '18 at 16:20

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– freedomn-m
Nov 20 '18 at 16:21

I have tried slice,but if there any other better way to fix this, var text_split1 = maintext.split(' ').slice(0,4).join(' ');

– carreankush
Nov 20 '18 at 16:25

You need to explicitly state your rules. eg text1 is text before first (, text2 is inside the bracket, before and no including "or", etc. Otherwise it's just guesswork and only fit for this exact scenario - which your existing code is also; only fit for this exact scenario.

– freedomn-m
Nov 20 '18 at 16:32

add a comment |

2 Answers
2

active

oldest

votes

The best option in this case is to create a regular expression.

In your case (if I got it right) you have a sentence consisting of:

Some text

Open parenthesis '('

More text

The word 'or'

More text

Close parenthesis ')'

So you want a regex to match the format above and you want to capture the items 1, 3 and 5.

Here, I made the regex for you: /^(.*) ?((.*) or (.*))$/

Now, using the function exec(string) you can match the desired string and capture the desired sections from it.

regex = /^(.*) ?((.*) or (.*))$/;

maintext = "Welcome to project,are you (1. Existing user or 2. new user)";

matches = regex.exec(maintext);

text_split1 = matches[1];

text_split2 = matches[2];

text_split3 = matches[3];

Notice that I didn't use matches[0]. That's because this is the full match from the regex, which, in this case, would be the full string you had at first.

Also, notice that the regex may fail with any of the texts inside the parenthesis contain the full word 'or', which is being used to separate the two portions of the string. You must secure this won't happen, or maybe use some special character to separate the two texts instead of the word.

answered Nov 20 '18 at 16:51

Pedro Lima

361210

1

Thanks for you help

– carreankush
Nov 20 '18 at 16:59

You could use word-boundary borb or whitespace sors so that it's not picked up inside a word. Still won't fix the issue when there's more than one " or ".

– freedomn-m
Nov 20 '18 at 19:34

@freedomn-m, I used whitespaces.

– Pedro Lima
Nov 21 '18 at 1:52

s is for whitespace - you've used a space, subtle difference (that likely has no impact on OPs scenario, but just for completeness)

– freedomn-m
Nov 21 '18 at 8:43

I need one more help,some times sentence may like this 'Welcome to project,are you (1. Existing user,2. Test user or 2. new user)' ,I need to get all options in separate console. so how to handle in this case

– carreankush
Nov 21 '18 at 16:12

|
show 1 more comment

I suggest you take a look at the Split, Substring and IndexOf methods.

For example if you wanted to grab what's inside the parenthesis you could do

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) )

and then whats outside of it

var outside_split = maintext.substring(0, maintext.indexOf("(") - 1)

or with Split

var split_Text = maintext.split("(")

Careful with Split here because it'll result in the last parenthesis being included in.

Array [ "Welcome to project,are you ", "1. Existing user or 2. new user)" ]

and from that you can Split the two options with

split_Text[1].split("or")

which results in

Array [ "1. Existing user ", " 2. new user)" ]

and then manipulate the remaining closing parenthesis

edited Nov 20 '18 at 16:33

answered Nov 20 '18 at 16:28

Matheus Souza

648

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) ) , I am fine with this but how to separate both the sentence from 'or' again

– carreankush
Nov 20 '18 at 16:41

Did you read the rest of the post? You can pass "or" to Split

– Matheus Souza
Nov 20 '18 at 16:44

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

The best option in this case is to create a regular expression.

In your case (if I got it right) you have a sentence consisting of:

Some text

Open parenthesis '('

More text

The word 'or'

More text

Close parenthesis ')'

So you want a regex to match the format above and you want to capture the items 1, 3 and 5.

Here, I made the regex for you: /^(.*) ?((.*) or (.*))$/

Now, using the function exec(string) you can match the desired string and capture the desired sections from it.

regex = /^(.*) ?((.*) or (.*))$/;

maintext = "Welcome to project,are you (1. Existing user or 2. new user)";

matches = regex.exec(maintext);

text_split1 = matches[1];

text_split2 = matches[2];

text_split3 = matches[3];

Notice that I didn't use matches[0]. That's because this is the full match from the regex, which, in this case, would be the full string you had at first.

answered Nov 20 '18 at 16:51

Pedro Lima

361210

1

Thanks for you help

– carreankush
Nov 20 '18 at 16:59

You could use word-boundary borb or whitespace sors so that it's not picked up inside a word. Still won't fix the issue when there's more than one " or ".

– freedomn-m
Nov 20 '18 at 19:34

@freedomn-m, I used whitespaces.

– Pedro Lima
Nov 21 '18 at 1:52

s is for whitespace - you've used a space, subtle difference (that likely has no impact on OPs scenario, but just for completeness)

– freedomn-m
Nov 21 '18 at 8:43

I need one more help,some times sentence may like this 'Welcome to project,are you (1. Existing user,2. Test user or 2. new user)' ,I need to get all options in separate console. so how to handle in this case

– carreankush
Nov 21 '18 at 16:12

|
show 1 more comment

The best option in this case is to create a regular expression.

In your case (if I got it right) you have a sentence consisting of:

Some text

Open parenthesis '('

More text

The word 'or'

More text

Close parenthesis ')'

So you want a regex to match the format above and you want to capture the items 1, 3 and 5.

Here, I made the regex for you: /^(.*) ?((.*) or (.*))$/

Now, using the function exec(string) you can match the desired string and capture the desired sections from it.

regex = /^(.*) ?((.*) or (.*))$/;

maintext = "Welcome to project,are you (1. Existing user or 2. new user)";

matches = regex.exec(maintext);

text_split1 = matches[1];

text_split2 = matches[2];

text_split3 = matches[3];

Notice that I didn't use matches[0]. That's because this is the full match from the regex, which, in this case, would be the full string you had at first.

answered Nov 20 '18 at 16:51

Pedro Lima

361210

1

Thanks for you help

– carreankush
Nov 20 '18 at 16:59

You could use word-boundary borb or whitespace sors so that it's not picked up inside a word. Still won't fix the issue when there's more than one " or ".

– freedomn-m
Nov 20 '18 at 19:34

@freedomn-m, I used whitespaces.

– Pedro Lima
Nov 21 '18 at 1:52

s is for whitespace - you've used a space, subtle difference (that likely has no impact on OPs scenario, but just for completeness)

– freedomn-m
Nov 21 '18 at 8:43

I need one more help,some times sentence may like this 'Welcome to project,are you (1. Existing user,2. Test user or 2. new user)' ,I need to get all options in separate console. so how to handle in this case

– carreankush
Nov 21 '18 at 16:12

|
show 1 more comment

The best option in this case is to create a regular expression.

In your case (if I got it right) you have a sentence consisting of:

Some text

Open parenthesis '('

More text

The word 'or'

More text

Close parenthesis ')'

So you want a regex to match the format above and you want to capture the items 1, 3 and 5.

Here, I made the regex for you: /^(.*) ?((.*) or (.*))$/

Now, using the function exec(string) you can match the desired string and capture the desired sections from it.

regex = /^(.*) ?((.*) or (.*))$/;

maintext = "Welcome to project,are you (1. Existing user or 2. new user)";

matches = regex.exec(maintext);

text_split1 = matches[1];

text_split2 = matches[2];

text_split3 = matches[3];

Notice that I didn't use matches[0]. That's because this is the full match from the regex, which, in this case, would be the full string you had at first.

answered Nov 20 '18 at 16:51

Pedro Lima

361210

The best option in this case is to create a regular expression.

In your case (if I got it right) you have a sentence consisting of:

Some text

Open parenthesis '('

More text

The word 'or'

More text

Close parenthesis ')'

So you want a regex to match the format above and you want to capture the items 1, 3 and 5.

Here, I made the regex for you: /^(.*) ?((.*) or (.*))$/

Now, using the function exec(string) you can match the desired string and capture the desired sections from it.

regex = /^(.*) ?((.*) or (.*))$/;

maintext = "Welcome to project,are you (1. Existing user or 2. new user)";

matches = regex.exec(maintext);

text_split1 = matches[1];

text_split2 = matches[2];

text_split3 = matches[3];

Notice that I didn't use matches[0]. That's because this is the full match from the regex, which, in this case, would be the full string you had at first.

answered Nov 20 '18 at 16:51

Pedro Lima

361210

answered Nov 20 '18 at 16:51

Pedro Lima

361210

answered Nov 20 '18 at 16:51

Pedro Lima

361210

answered Nov 20 '18 at 16:51

Pedro Lima

361210

1

Thanks for you help

– carreankush
Nov 20 '18 at 16:59

You could use word-boundary borb or whitespace sors so that it's not picked up inside a word. Still won't fix the issue when there's more than one " or ".

– freedomn-m
Nov 20 '18 at 19:34

@freedomn-m, I used whitespaces.

– Pedro Lima
Nov 21 '18 at 1:52

s is for whitespace - you've used a space, subtle difference (that likely has no impact on OPs scenario, but just for completeness)

– freedomn-m
Nov 21 '18 at 8:43

I need one more help,some times sentence may like this 'Welcome to project,are you (1. Existing user,2. Test user or 2. new user)' ,I need to get all options in separate console. so how to handle in this case

– carreankush
Nov 21 '18 at 16:12

|
show 1 more comment

1

Thanks for you help

– carreankush
Nov 20 '18 at 16:59

You could use word-boundary borb or whitespace sors so that it's not picked up inside a word. Still won't fix the issue when there's more than one " or ".

– freedomn-m
Nov 20 '18 at 19:34

@freedomn-m, I used whitespaces.

– Pedro Lima
Nov 21 '18 at 1:52

s is for whitespace - you've used a space, subtle difference (that likely has no impact on OPs scenario, but just for completeness)

– freedomn-m
Nov 21 '18 at 8:43

I need one more help,some times sentence may like this 'Welcome to project,are you (1. Existing user,2. Test user or 2. new user)' ,I need to get all options in separate console. so how to handle in this case

– carreankush
Nov 21 '18 at 16:12

Thanks for you help

– carreankush
Nov 20 '18 at 16:59

You could use word-boundary borb or whitespace sors so that it's not picked up inside a word. Still won't fix the issue when there's more than one " or ".

– freedomn-m
Nov 20 '18 at 19:34

@freedomn-m, I used whitespaces.

– Pedro Lima
Nov 21 '18 at 1:52

s is for whitespace - you've used a space, subtle difference (that likely has no impact on OPs scenario, but just for completeness)

– freedomn-m
Nov 21 '18 at 8:43

I need one more help,some times sentence may like this 'Welcome to project,are you (1. Existing user,2. Test user or 2. new user)' ,I need to get all options in separate console. so how to handle in this case

– carreankush
Nov 21 '18 at 16:12

|
show 1 more comment

I suggest you take a look at the Split, Substring and IndexOf methods.

For example if you wanted to grab what's inside the parenthesis you could do

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) )

and then whats outside of it

var outside_split = maintext.substring(0, maintext.indexOf("(") - 1)

or with Split

var split_Text = maintext.split("(")

Careful with Split here because it'll result in the last parenthesis being included in.

Array [ "Welcome to project,are you ", "1. Existing user or 2. new user)" ]

and from that you can Split the two options with

split_Text[1].split("or")

which results in

Array [ "1. Existing user ", " 2. new user)" ]

and then manipulate the remaining closing parenthesis

edited Nov 20 '18 at 16:33

answered Nov 20 '18 at 16:28

Matheus Souza

648

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) ) , I am fine with this but how to separate both the sentence from 'or' again

– carreankush
Nov 20 '18 at 16:41

Did you read the rest of the post? You can pass "or" to Split

– Matheus Souza
Nov 20 '18 at 16:44

add a comment |

I suggest you take a look at the Split, Substring and IndexOf methods.

For example if you wanted to grab what's inside the parenthesis you could do

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) )

and then whats outside of it

var outside_split = maintext.substring(0, maintext.indexOf("(") - 1)

or with Split

var split_Text = maintext.split("(")

Careful with Split here because it'll result in the last parenthesis being included in.

Array [ "Welcome to project,are you ", "1. Existing user or 2. new user)" ]

and from that you can Split the two options with

split_Text[1].split("or")

which results in

Array [ "1. Existing user ", " 2. new user)" ]

and then manipulate the remaining closing parenthesis

edited Nov 20 '18 at 16:33

answered Nov 20 '18 at 16:28

Matheus Souza

648

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) ) , I am fine with this but how to separate both the sentence from 'or' again

– carreankush
Nov 20 '18 at 16:41

Did you read the rest of the post? You can pass "or" to Split

– Matheus Souza
Nov 20 '18 at 16:44

add a comment |

I suggest you take a look at the Split, Substring and IndexOf methods.

For example if you wanted to grab what's inside the parenthesis you could do

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) )

and then whats outside of it

var outside_split = maintext.substring(0, maintext.indexOf("(") - 1)

or with Split

var split_Text = maintext.split("(")

Careful with Split here because it'll result in the last parenthesis being included in.

Array [ "Welcome to project,are you ", "1. Existing user or 2. new user)" ]

and from that you can Split the two options with

split_Text[1].split("or")

which results in

Array [ "1. Existing user ", " 2. new user)" ]

and then manipulate the remaining closing parenthesis

edited Nov 20 '18 at 16:33

answered Nov 20 '18 at 16:28

Matheus Souza

648

I suggest you take a look at the Split, Substring and IndexOf methods.

For example if you wanted to grab what's inside the parenthesis you could do

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) )

and then whats outside of it

var outside_split = maintext.substring(0, maintext.indexOf("(") - 1)

or with Split

var split_Text = maintext.split("(")

Careful with Split here because it'll result in the last parenthesis being included in.

Array [ "Welcome to project,are you ", "1. Existing user or 2. new user)" ]

and from that you can Split the two options with

split_Text[1].split("or")

which results in

Array [ "1. Existing user ", " 2. new user)" ]

and then manipulate the remaining closing parenthesis

edited Nov 20 '18 at 16:33

answered Nov 20 '18 at 16:28

Matheus Souza

648

edited Nov 20 '18 at 16:33

answered Nov 20 '18 at 16:28

Matheus Souza

648

answered Nov 20 '18 at 16:28

Matheus Souza

648

answered Nov 20 '18 at 16:28

Matheus Souza

648

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) ) , I am fine with this but how to separate both the sentence from 'or' again

– carreankush
Nov 20 '18 at 16:41

Did you read the rest of the post? You can pass "or" to Split

– Matheus Souza
Nov 20 '18 at 16:44

add a comment |

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) ) , I am fine with this but how to separate both the sentence from 'or' again

– carreankush
Nov 20 '18 at 16:41

Did you read the rest of the post? You can pass "or" to Split

– Matheus Souza
Nov 20 '18 at 16:44

var inside_split = maintext.substring(maintext.indexOf( "(" ) + 1, maintext.indexOf( ")" ) ) , I am fine with this but how to separate both the sentence from 'or' again

– carreankush
Nov 20 '18 at 16:41

Did you read the rest of the post? You can pass "or" to Split

– Matheus Souza
Nov 20 '18 at 16:44

add a comment |

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