If statement ignoring condition

-1

#include <stdio.h>

#include<math.h>



int binary_to_decimal(int n){

    int ostatok, i=0, pom, decimal=0;

    pom=n;

    while(pom)

    {

        ostatok=pom%10;

        decimal+=ostatok*pow(2,i);

        pom/=10;

        i++;

    }

    return decimal;

}



int main()

{

    int m, n, i, max=0, number;

    scanf(" %d %d", &n, &m);

    int array[n];



    for(i=0; i<n ;i++){

        scanf(" %d", &number);

        binary_to_decimal(number);

        if(number>m) // this if statement doesn't seem to be doing it's job

            array[i]=number;

        if(array[i]>max)

            max=array[i];

    }



    for(i=0; i<n ;i++)

    {

        printf(" %d %dn", array[i], binary_to_decimal(array[i]));

    }

    printf("Max %d %d", max,  binary_to_decimal(max));

    return 0;

}

The program is: you enter two int values, m and n. m is used as a value for comparison, while n is the number of binary number the user is inputting in the loop. If the inputted number is greater than the number m print out the values of the inputted number in binary then in decimal. At the end, print out the number with the biggest value in binary and decimal.
My problem is the if where i am comparing m and the inputted number and i can't seem to find the problem.

edited Nov 20 '18 at 17:01

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2

binary_to_decimal(number); this has no effect at all.

– Osiris
Nov 20 '18 at 16:37

Add printf("%d > %d?n", number, m); above if(number>m)?

– Fiddling Bits
Nov 20 '18 at 16:37

1

My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

– Osiris
Nov 20 '18 at 16:39

1

array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

– donjuedo
Nov 20 '18 at 16:45

3

@Spyware If you get some random number then maybe your binary_to_decimal function is broken.

– Osiris
Nov 20 '18 at 16:51

|
show 4 more comments

-1

#include <stdio.h>

#include<math.h>



int binary_to_decimal(int n){

    int ostatok, i=0, pom, decimal=0;

    pom=n;

    while(pom)

    {

        ostatok=pom%10;

        decimal+=ostatok*pow(2,i);

        pom/=10;

        i++;

    }

    return decimal;

}



int main()

{

    int m, n, i, max=0, number;

    scanf(" %d %d", &n, &m);

    int array[n];



    for(i=0; i<n ;i++){

        scanf(" %d", &number);

        binary_to_decimal(number);

        if(number>m) // this if statement doesn't seem to be doing it's job

            array[i]=number;

        if(array[i]>max)

            max=array[i];

    }



    for(i=0; i<n ;i++)

    {

        printf(" %d %dn", array[i], binary_to_decimal(array[i]));

    }

    printf("Max %d %d", max,  binary_to_decimal(max));

    return 0;

}

edited Nov 20 '18 at 17:01

dbush

94.7k12101136

asked Nov 20 '18 at 16:35

PauseUnpause

6418

2

binary_to_decimal(number); this has no effect at all.

– Osiris
Nov 20 '18 at 16:37

Add printf("%d > %d?n", number, m); above if(number>m)?

– Fiddling Bits
Nov 20 '18 at 16:37

1

My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

– Osiris
Nov 20 '18 at 16:39

1

array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

– donjuedo
Nov 20 '18 at 16:45

3

@Spyware If you get some random number then maybe your binary_to_decimal function is broken.

– Osiris
Nov 20 '18 at 16:51

|
show 4 more comments

-1

#include <stdio.h>

#include<math.h>



int binary_to_decimal(int n){

    int ostatok, i=0, pom, decimal=0;

    pom=n;

    while(pom)

    {

        ostatok=pom%10;

        decimal+=ostatok*pow(2,i);

        pom/=10;

        i++;

    }

    return decimal;

}



int main()

{

    int m, n, i, max=0, number;

    scanf(" %d %d", &n, &m);

    int array[n];



    for(i=0; i<n ;i++){

        scanf(" %d", &number);

        binary_to_decimal(number);

        if(number>m) // this if statement doesn't seem to be doing it's job

            array[i]=number;

        if(array[i]>max)

            max=array[i];

    }



    for(i=0; i<n ;i++)

    {

        printf(" %d %dn", array[i], binary_to_decimal(array[i]));

    }

    printf("Max %d %d", max,  binary_to_decimal(max));

    return 0;

}

edited Nov 20 '18 at 17:01

dbush

94.7k12101136

asked Nov 20 '18 at 16:35

PauseUnpause

6418

#include <stdio.h>

#include<math.h>



int binary_to_decimal(int n){

    int ostatok, i=0, pom, decimal=0;

    pom=n;

    while(pom)

    {

        ostatok=pom%10;

        decimal+=ostatok*pow(2,i);

        pom/=10;

        i++;

    }

    return decimal;

}



int main()

{

    int m, n, i, max=0, number;

    scanf(" %d %d", &n, &m);

    int array[n];



    for(i=0; i<n ;i++){

        scanf(" %d", &number);

        binary_to_decimal(number);

        if(number>m) // this if statement doesn't seem to be doing it's job

            array[i]=number;

        if(array[i]>max)

            max=array[i];

    }



    for(i=0; i<n ;i++)

    {

        printf(" %d %dn", array[i], binary_to_decimal(array[i]));

    }

    printf("Max %d %d", max,  binary_to_decimal(max));

    return 0;

}

c if-statement

edited Nov 20 '18 at 17:01

dbush

94.7k12101136

asked Nov 20 '18 at 16:35

PauseUnpause

6418

edited Nov 20 '18 at 17:01

dbush

94.7k12101136

asked Nov 20 '18 at 16:35

PauseUnpause

6418

edited Nov 20 '18 at 17:01

dbush

94.7k12101136

edited Nov 20 '18 at 17:01

dbush

94.7k12101136

edited Nov 20 '18 at 17:01

dbush

94.7k12101136

asked Nov 20 '18 at 16:35

PauseUnpause

6418

asked Nov 20 '18 at 16:35

PauseUnpause

6418

asked Nov 20 '18 at 16:35

PauseUnpause

6418

2

binary_to_decimal(number); this has no effect at all.

– Osiris
Nov 20 '18 at 16:37

Add printf("%d > %d?n", number, m); above if(number>m)?

– Fiddling Bits
Nov 20 '18 at 16:37

1

My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

– Osiris
Nov 20 '18 at 16:39

1

array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

– donjuedo
Nov 20 '18 at 16:45

3

@Spyware If you get some random number then maybe your binary_to_decimal function is broken.

– Osiris
Nov 20 '18 at 16:51

|
show 4 more comments

2

binary_to_decimal(number); this has no effect at all.

– Osiris
Nov 20 '18 at 16:37

Add printf("%d > %d?n", number, m); above if(number>m)?

– Fiddling Bits
Nov 20 '18 at 16:37

1

My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

– Osiris
Nov 20 '18 at 16:39

1

array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

– donjuedo
Nov 20 '18 at 16:45

3

@Spyware If you get some random number then maybe your binary_to_decimal function is broken.

– Osiris
Nov 20 '18 at 16:51

binary_to_decimal(number); this has no effect at all.

– Osiris
Nov 20 '18 at 16:37

Add printf("%d > %d?n", number, m); above if(number>m)?

– Fiddling Bits
Nov 20 '18 at 16:37

My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

– Osiris
Nov 20 '18 at 16:39

array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

– donjuedo
Nov 20 '18 at 16:45

@Spyware If you get some random number then maybe your binary_to_decimal function is broken.

– Osiris
Nov 20 '18 at 16:51

|
show 4 more comments

1 Answer
1

active

oldest

votes

The call binary_to_decimal(number) does not change your number.
Try something like:

number = binary_to_decimal(number);

edited Nov 20 '18 at 16:54

answered Nov 20 '18 at 16:45

D. Diana

314

3

C does not have references

– Gerhardh
Nov 20 '18 at 16:52

1

int &n is C++, not C.

– Barmar
Nov 20 '18 at 16:53

And your function never changes n.

– Barmar
Nov 20 '18 at 16:54

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

The call binary_to_decimal(number) does not change your number.
Try something like:

number = binary_to_decimal(number);

edited Nov 20 '18 at 16:54

answered Nov 20 '18 at 16:45

D. Diana

314

3

C does not have references

– Gerhardh
Nov 20 '18 at 16:52

1

int &n is C++, not C.

– Barmar
Nov 20 '18 at 16:53

And your function never changes n.

– Barmar
Nov 20 '18 at 16:54

add a comment |

The call binary_to_decimal(number) does not change your number.
Try something like:

number = binary_to_decimal(number);

edited Nov 20 '18 at 16:54

answered Nov 20 '18 at 16:45

D. Diana

314

3

C does not have references

– Gerhardh
Nov 20 '18 at 16:52

1

int &n is C++, not C.

– Barmar
Nov 20 '18 at 16:53

And your function never changes n.

– Barmar
Nov 20 '18 at 16:54

add a comment |

The call binary_to_decimal(number) does not change your number.
Try something like:

number = binary_to_decimal(number);

edited Nov 20 '18 at 16:54

answered Nov 20 '18 at 16:45

D. Diana

314

The call binary_to_decimal(number) does not change your number.
Try something like:

number = binary_to_decimal(number);

edited Nov 20 '18 at 16:54

answered Nov 20 '18 at 16:45

D. Diana

314

edited Nov 20 '18 at 16:54

answered Nov 20 '18 at 16:45

D. Diana

314

answered Nov 20 '18 at 16:45

D. Diana

314

answered Nov 20 '18 at 16:45

D. Diana

314

3

C does not have references

– Gerhardh
Nov 20 '18 at 16:52

1

int &n is C++, not C.

– Barmar
Nov 20 '18 at 16:53

And your function never changes n.

– Barmar
Nov 20 '18 at 16:54

add a comment |

3

C does not have references

– Gerhardh
Nov 20 '18 at 16:52

1

int &n is C++, not C.

– Barmar
Nov 20 '18 at 16:53

And your function never changes n.

– Barmar
Nov 20 '18 at 16:54

C does not have references

– Gerhardh
Nov 20 '18 at 16:52

int &n is C++, not C.

– Barmar
Nov 20 '18 at 16:53

And your function never changes n.

– Barmar
Nov 20 '18 at 16:54

add a comment |

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