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How to run multiple sidekiq workers using init.d
I'm using Amazon Linux 1. I have 2 apps in the same EC2 server. 1 is rails 3 and the other is a rails 5. I'm trying run sidekiq from both apps using init.d but only one of them runs.
Below is a sample of my script in /etc/init.d/sidekiq_myapp. I just changed the APP_DIR of the other script and used different names for sidekiq (-q parameter):
#!/bin/sh
### BEGIN INIT INFO
# Provides: sidekiq
# Required-Start: $all
# Required-Stop: $all
# Default-Start: 2 3 4 5
# Default-Stop: 0 1 6
# Short-Description: starts and stops sidekiq
# Description: starts and stops sidekiq
### END INIT INFO
# You will need to modify these
APP="myapp"
AS_USER="root"
APP_DIR="/var/www/myapp"
APP_CONFIG="${APP_DIR}/config"
LOG_FILE="/opt/nginx/logs/error.log"
LOCK_FILE="$APP_DIR/tmp/${APP}-sidekiq-lock"
PID_FILE="$APP_DIR/tmp/pids/sidekiq.pid"
GEMFILE="$APP_DIR/Gemfile"
SIDEKIQ="sidekiq"
APP_ENV="production"
BUNDLE="bundle"
START_CMD="$BUNDLE exec $SIDEKIQ -q critical,5 -q default,2 -q low -d -L $LOG_FILE -e $APP_ENV -P $PID_FILE"
CMD="cd ${APP_DIR}; ${START_CMD} >> ${LOG_FILE} 2>&1 &"
RETVAL=0
start() {
status
if [ $? -eq 1 ]; then
[ `id -u` == '0' ] || (echo "$SIDEKIQ runs as root only .."; exit 5)
[ -d $APP_DIR ] || (echo "$APP_DIR not found!.. Exiting"; exit 6)
cd $APP_DIR
echo "Starting $SIDEKIQ message processor .. "
su -c "$CMD" - $AS_USER
RETVAL=$?
#Sleeping for 8 seconds for process to be precisely visible in process table - See status ()
sleep 8
[ $RETVAL -eq 0 ] && touch $LOCK_FILE
return $RETVAL
else
echo "$SIDEKIQ message processor is already running .. "
fi
}
stop() {
status
if [ $? -eq 0 ]; then
echo "Stopping sidekiq message processor .."
SIG="INT"
kill -$SIG `cat $PID_FILE`
RETVAL=$?
[ $RETVAL -eq 0 ] && rm -f $LOCK_FILE
return $RETVAL
else
echo "Sidekiq message processor is stopped already .."
fi
}
status() {
ps -ef | grep 'sidekiq [0-9]*.[0-9]*.[0-9]*' | grep -v grep
return $?
}
case "$1" in
start)
start
;;
stop)
stop
;;
status)
status
if [ $? -eq 0 ]; then
echo "$SIDEKIQ message processor is running .."
RETVAL=0
else
echo "$SIDEKIQ message processor is stopped .."
RETVAL=1
fi
;;
*)
echo "Usage: $0 {start|stop|status}"
exit 0
;;
esac
exit $RETVAL
I can verify that the one from rails 3 is running. The one from rails 5 does not. I still have to manually run bundle exec sidekiq on the rails 5 for it to work.
# ps -ef | grep sidekiq
2672 1 1 13:37 ? 00:00:09 sidekiq 3.3.0 squadzip [0 of 25 busy]
7048 6954 0 13:51 pts/1 00:00:00 grep --color=auto sidekiq
I'd like to stick with systemV. Any thoughts? Both will run if I'll manually run the bundle exec sidekiq, that means that my rails/sidekiq setup is fine. My problem is how to start them both.
ruby-on-rails bash sidekiq init.d
asked Nov 20 '18 at 14:00
tungsten_carbidetungsten_carbide
315312
add a comment |
I'm using Amazon Linux 1. I have 2 apps in the same EC2 server. 1 is rails 3 and the other is a rails 5. I'm trying run sidekiq from both apps using init.d but only one of them runs.
Below is a sample of my script in /etc/init.d/sidekiq_myapp. I just changed the APP_DIR of the other script and used different names for sidekiq (-q parameter):
#!/bin/sh
### BEGIN INIT INFO
# Provides: sidekiq
# Required-Start: $all
# Required-Stop: $all
# Default-Start: 2 3 4 5
# Default-Stop: 0 1 6
# Short-Description: starts and stops sidekiq
# Description: starts and stops sidekiq
### END INIT INFO
# You will need to modify these
APP="myapp"
AS_USER="root"
APP_DIR="/var/www/myapp"
APP_CONFIG="${APP_DIR}/config"
LOG_FILE="/opt/nginx/logs/error.log"
LOCK_FILE="$APP_DIR/tmp/${APP}-sidekiq-lock"
PID_FILE="$APP_DIR/tmp/pids/sidekiq.pid"
GEMFILE="$APP_DIR/Gemfile"
SIDEKIQ="sidekiq"
APP_ENV="production"
BUNDLE="bundle"
START_CMD="$BUNDLE exec $SIDEKIQ -q critical,5 -q default,2 -q low -d -L $LOG_FILE -e $APP_ENV -P $PID_FILE"
CMD="cd ${APP_DIR}; ${START_CMD} >> ${LOG_FILE} 2>&1 &"
RETVAL=0
start() {
status
if [ $? -eq 1 ]; then
[ `id -u` == '0' ] || (echo "$SIDEKIQ runs as root only .."; exit 5)
[ -d $APP_DIR ] || (echo "$APP_DIR not found!.. Exiting"; exit 6)
cd $APP_DIR
echo "Starting $SIDEKIQ message processor .. "
su -c "$CMD" - $AS_USER
RETVAL=$?
#Sleeping for 8 seconds for process to be precisely visible in process table - See status ()
sleep 8
[ $RETVAL -eq 0 ] && touch $LOCK_FILE
return $RETVAL
else
echo "$SIDEKIQ message processor is already running .. "
fi
}
stop() {
status
if [ $? -eq 0 ]; then
echo "Stopping sidekiq message processor .."
SIG="INT"
kill -$SIG `cat $PID_FILE`
RETVAL=$?
[ $RETVAL -eq 0 ] && rm -f $LOCK_FILE
return $RETVAL
else
echo "Sidekiq message processor is stopped already .."
fi
}
status() {
ps -ef | grep 'sidekiq [0-9]*.[0-9]*.[0-9]*' | grep -v grep
return $?
}
case "$1" in
start)
start
;;
stop)
stop
;;
status)
status
if [ $? -eq 0 ]; then
echo "$SIDEKIQ message processor is running .."
RETVAL=0
else
echo "$SIDEKIQ message processor is stopped .."
RETVAL=1
fi
;;
*)
echo "Usage: $0 {start|stop|status}"
exit 0
;;
esac
exit $RETVAL
I can verify that the one from rails 3 is running. The one from rails 5 does not. I still have to manually run bundle exec sidekiq on the rails 5 for it to work.
# ps -ef | grep sidekiq
2672 1 1 13:37 ? 00:00:09 sidekiq 3.3.0 squadzip [0 of 25 busy]
7048 6954 0 13:51 pts/1 00:00:00 grep --color=auto sidekiq
I'd like to stick with systemV. Any thoughts? Both will run if I'll manually run the bundle exec sidekiq, that means that my rails/sidekiq setup is fine. My problem is how to start them both.
ruby-on-rails bash sidekiq init.d
asked Nov 20 '18 at 14:00
tungsten_carbidetungsten_carbide
315312
add a comment |
I'm using Amazon Linux 1. I have 2 apps in the same EC2 server. 1 is rails 3 and the other is a rails 5. I'm trying run sidekiq from both apps using init.d but only one of them runs.
Below is a sample of my script in /etc/init.d/sidekiq_myapp. I just changed the APP_DIR of the other script and used different names for sidekiq (-q parameter):
#!/bin/sh
### BEGIN INIT INFO
# Provides: sidekiq
# Required-Start: $all
# Required-Stop: $all
# Default-Start: 2 3 4 5
# Default-Stop: 0 1 6
# Short-Description: starts and stops sidekiq
# Description: starts and stops sidekiq
### END INIT INFO
# You will need to modify these
APP="myapp"
AS_USER="root"
APP_DIR="/var/www/myapp"
APP_CONFIG="${APP_DIR}/config"
LOG_FILE="/opt/nginx/logs/error.log"
LOCK_FILE="$APP_DIR/tmp/${APP}-sidekiq-lock"
PID_FILE="$APP_DIR/tmp/pids/sidekiq.pid"
GEMFILE="$APP_DIR/Gemfile"
SIDEKIQ="sidekiq"
APP_ENV="production"
BUNDLE="bundle"
START_CMD="$BUNDLE exec $SIDEKIQ -q critical,5 -q default,2 -q low -d -L $LOG_FILE -e $APP_ENV -P $PID_FILE"
CMD="cd ${APP_DIR}; ${START_CMD} >> ${LOG_FILE} 2>&1 &"
RETVAL=0
start() {
status
if [ $? -eq 1 ]; then
[ `id -u` == '0' ] || (echo "$SIDEKIQ runs as root only .."; exit 5)
[ -d $APP_DIR ] || (echo "$APP_DIR not found!.. Exiting"; exit 6)
cd $APP_DIR
echo "Starting $SIDEKIQ message processor .. "
su -c "$CMD" - $AS_USER
RETVAL=$?
#Sleeping for 8 seconds for process to be precisely visible in process table - See status ()
sleep 8
[ $RETVAL -eq 0 ] && touch $LOCK_FILE
return $RETVAL
else
echo "$SIDEKIQ message processor is already running .. "
fi
}
stop() {
status
if [ $? -eq 0 ]; then
echo "Stopping sidekiq message processor .."
SIG="INT"
kill -$SIG `cat $PID_FILE`
RETVAL=$?
[ $RETVAL -eq 0 ] && rm -f $LOCK_FILE
return $RETVAL
else
echo "Sidekiq message processor is stopped already .."
fi
}
status() {
ps -ef | grep 'sidekiq [0-9]*.[0-9]*.[0-9]*' | grep -v grep
return $?
}
case "$1" in
start)
start
;;
stop)
stop
;;
status)
status
if [ $? -eq 0 ]; then
echo "$SIDEKIQ message processor is running .."
RETVAL=0
else
echo "$SIDEKIQ message processor is stopped .."
RETVAL=1
fi
;;
*)
echo "Usage: $0 {start|stop|status}"
exit 0
;;
esac
exit $RETVAL
I can verify that the one from rails 3 is running. The one from rails 5 does not. I still have to manually run bundle exec sidekiq on the rails 5 for it to work.
# ps -ef | grep sidekiq
2672 1 1 13:37 ? 00:00:09 sidekiq 3.3.0 squadzip [0 of 25 busy]
7048 6954 0 13:51 pts/1 00:00:00 grep --color=auto sidekiq
I'd like to stick with systemV. Any thoughts? Both will run if I'll manually run the bundle exec sidekiq, that means that my rails/sidekiq setup is fine. My problem is how to start them both.
ruby-on-rails bash sidekiq init.d
asked Nov 20 '18 at 14:00
tungsten_carbidetungsten_carbide
315312
I'm using Amazon Linux 1. I have 2 apps in the same EC2 server. 1 is rails 3 and the other is a rails 5. I'm trying run sidekiq from both apps using init.d but only one of them runs.
Below is a sample of my script in /etc/init.d/sidekiq_myapp. I just changed the APP_DIR of the other script and used different names for sidekiq (-q parameter):
#!/bin/sh
### BEGIN INIT INFO
# Provides: sidekiq
# Required-Start: $all
# Required-Stop: $all
# Default-Start: 2 3 4 5
# Default-Stop: 0 1 6
# Short-Description: starts and stops sidekiq
# Description: starts and stops sidekiq
### END INIT INFO
# You will need to modify these
APP="myapp"
AS_USER="root"
APP_DIR="/var/www/myapp"
APP_CONFIG="${APP_DIR}/config"
LOG_FILE="/opt/nginx/logs/error.log"
LOCK_FILE="$APP_DIR/tmp/${APP}-sidekiq-lock"
PID_FILE="$APP_DIR/tmp/pids/sidekiq.pid"
GEMFILE="$APP_DIR/Gemfile"
SIDEKIQ="sidekiq"
APP_ENV="production"
BUNDLE="bundle"
START_CMD="$BUNDLE exec $SIDEKIQ -q critical,5 -q default,2 -q low -d -L $LOG_FILE -e $APP_ENV -P $PID_FILE"
CMD="cd ${APP_DIR}; ${START_CMD} >> ${LOG_FILE} 2>&1 &"
RETVAL=0
start() {
status
if [ $? -eq 1 ]; then
[ `id -u` == '0' ] || (echo "$SIDEKIQ runs as root only .."; exit 5)
[ -d $APP_DIR ] || (echo "$APP_DIR not found!.. Exiting"; exit 6)
cd $APP_DIR
echo "Starting $SIDEKIQ message processor .. "
su -c "$CMD" - $AS_USER
RETVAL=$?
#Sleeping for 8 seconds for process to be precisely visible in process table - See status ()
sleep 8
[ $RETVAL -eq 0 ] && touch $LOCK_FILE
return $RETVAL
else
echo "$SIDEKIQ message processor is already running .. "
fi
}
stop() {
status
if [ $? -eq 0 ]; then
echo "Stopping sidekiq message processor .."
SIG="INT"
kill -$SIG `cat $PID_FILE`
RETVAL=$?
[ $RETVAL -eq 0 ] && rm -f $LOCK_FILE
return $RETVAL
else
echo "Sidekiq message processor is stopped already .."
fi
}
status() {
ps -ef | grep 'sidekiq [0-9]*.[0-9]*.[0-9]*' | grep -v grep
return $?
}
case "$1" in
start)
start
;;
stop)
stop
;;
status)
status
if [ $? -eq 0 ]; then
echo "$SIDEKIQ message processor is running .."
RETVAL=0
else
echo "$SIDEKIQ message processor is stopped .."
RETVAL=1
fi
;;
*)
echo "Usage: $0 {start|stop|status}"
exit 0
;;
esac
exit $RETVAL
I can verify that the one from rails 3 is running. The one from rails 5 does not. I still have to manually run bundle exec sidekiq on the rails 5 for it to work.
# ps -ef | grep sidekiq
2672 1 1 13:37 ? 00:00:09 sidekiq 3.3.0 squadzip [0 of 25 busy]
7048 6954 0 13:51 pts/1 00:00:00 grep --color=auto sidekiq
I'd like to stick with systemV. Any thoughts? Both will run if I'll manually run the bundle exec sidekiq, that means that my rails/sidekiq setup is fine. My problem is how to start them both.
ruby-on-rails bash sidekiq init.d
ruby-on-rails bash sidekiq init.d
asked Nov 20 '18 at 14:00
tungsten_carbidetungsten_carbide
315312
asked Nov 20 '18 at 14:00
tungsten_carbidetungsten_carbide
315312
edited Nov 20 '18 at 14:07
tungsten_carbide
asked Nov 20 '18 at 14:00
tungsten_carbidetungsten_carbide
315312
asked Nov 20 '18 at 14:00
tungsten_carbidetungsten_carbide
315312
asked Nov 20 '18 at 14:00
tungsten_carbidetungsten_carbide
315312
315312
add a comment |
add a comment |
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