Minimum genus of torus necessary to embed complete graph $K_n$












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You can embed complete graphs $K_1$, $K_2$, $K_3$, and $K_4$ on a genus $0$ torus (a sphere).
The minimal genus of a torus on which you can embed $K_5$, $K_6$, and $K_7$ is a $1$.
Then you need a torus of genus $2$ to embed ...



Is there a formula for any $K_n$, stating the minimum genus necessary to embed $K_n$ on a torus with that genus?










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    Welcome to Math.SE! Please use MathJax. For some basic information about writing math at this site see e.g. basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
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    – GNUSupporter 8964民主女神 地下教會
    Mar 14 '18 at 16:43
















0












$begingroup$


You can embed complete graphs $K_1$, $K_2$, $K_3$, and $K_4$ on a genus $0$ torus (a sphere).
The minimal genus of a torus on which you can embed $K_5$, $K_6$, and $K_7$ is a $1$.
Then you need a torus of genus $2$ to embed ...



Is there a formula for any $K_n$, stating the minimum genus necessary to embed $K_n$ on a torus with that genus?










share|cite|improve this question











$endgroup$












  • $begingroup$
    Welcome to Math.SE! Please use MathJax. For some basic information about writing math at this site see e.g. basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
    $endgroup$
    – GNUSupporter 8964民主女神 地下教會
    Mar 14 '18 at 16:43














0












0








0





$begingroup$


You can embed complete graphs $K_1$, $K_2$, $K_3$, and $K_4$ on a genus $0$ torus (a sphere).
The minimal genus of a torus on which you can embed $K_5$, $K_6$, and $K_7$ is a $1$.
Then you need a torus of genus $2$ to embed ...



Is there a formula for any $K_n$, stating the minimum genus necessary to embed $K_n$ on a torus with that genus?










share|cite|improve this question











$endgroup$




You can embed complete graphs $K_1$, $K_2$, $K_3$, and $K_4$ on a genus $0$ torus (a sphere).
The minimal genus of a torus on which you can embed $K_5$, $K_6$, and $K_7$ is a $1$.
Then you need a torus of genus $2$ to embed ...



Is there a formula for any $K_n$, stating the minimum genus necessary to embed $K_n$ on a torus with that genus?







topological-graph-theory






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edited Jan 7 at 9:10









Saad

19.7k92352




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asked Mar 14 '18 at 16:41









J.ShootJ.Shoot

83




83












  • $begingroup$
    Welcome to Math.SE! Please use MathJax. For some basic information about writing math at this site see e.g. basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
    $endgroup$
    – GNUSupporter 8964民主女神 地下教會
    Mar 14 '18 at 16:43


















  • $begingroup$
    Welcome to Math.SE! Please use MathJax. For some basic information about writing math at this site see e.g. basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
    $endgroup$
    – GNUSupporter 8964民主女神 地下教會
    Mar 14 '18 at 16:43
















$begingroup$
Welcome to Math.SE! Please use MathJax. For some basic information about writing math at this site see e.g. basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– GNUSupporter 8964民主女神 地下教會
Mar 14 '18 at 16:43




$begingroup$
Welcome to Math.SE! Please use MathJax. For some basic information about writing math at this site see e.g. basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– GNUSupporter 8964民主女神 地下教會
Mar 14 '18 at 16:43










1 Answer
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Found it. All I needed to search for was "genus of complete graphs" :



http://mathworld.wolfram.com/GraphGenus.html



Ringel and Youngs 1968; Harary 1994, p. 118 :



$$mbox{ceil}left((n-3)(n-4)over 12right)$$



Please do edit the formula with MathJax.






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    1 Answer
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    1 Answer
    1






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    Found it. All I needed to search for was "genus of complete graphs" :



    http://mathworld.wolfram.com/GraphGenus.html



    Ringel and Youngs 1968; Harary 1994, p. 118 :



    $$mbox{ceil}left((n-3)(n-4)over 12right)$$



    Please do edit the formula with MathJax.






    share|cite|improve this answer











    $endgroup$


















      0












      $begingroup$

      Found it. All I needed to search for was "genus of complete graphs" :



      http://mathworld.wolfram.com/GraphGenus.html



      Ringel and Youngs 1968; Harary 1994, p. 118 :



      $$mbox{ceil}left((n-3)(n-4)over 12right)$$



      Please do edit the formula with MathJax.






      share|cite|improve this answer











      $endgroup$
















        0












        0








        0





        $begingroup$

        Found it. All I needed to search for was "genus of complete graphs" :



        http://mathworld.wolfram.com/GraphGenus.html



        Ringel and Youngs 1968; Harary 1994, p. 118 :



        $$mbox{ceil}left((n-3)(n-4)over 12right)$$



        Please do edit the formula with MathJax.






        share|cite|improve this answer











        $endgroup$



        Found it. All I needed to search for was "genus of complete graphs" :



        http://mathworld.wolfram.com/GraphGenus.html



        Ringel and Youngs 1968; Harary 1994, p. 118 :



        $$mbox{ceil}left((n-3)(n-4)over 12right)$$



        Please do edit the formula with MathJax.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Mar 16 '18 at 15:18









        user36196

        41337




        41337










        answered Mar 16 '18 at 14:57









        J.ShootJ.Shoot

        83




        83






























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