Mixing
using z transform pairs to solve the question.
$begingroup$
Following is a question of z transform:
$$ (-frac{1}{3})^n u[-n-2] $$
Now I know that a transform pair similar to this is:
$$ -alpha^n u[-n-1]=frac{1}{1-alpha z^{-1}} $$
Now using that property what I get is:
$$ frac{1}{1-(1/3)z^{-1}} $$
now since the shift is of $-1$ so using that property my final answer is:
$$ (z^{-1})(frac{1}{1-(1/3)z^{-1}}) $$
Is it correct?
z-transform
asked Jan 6 at 14:25
Ahmad QayyumAhmad Qayyum
677
$endgroup$
add a comment |
$begingroup$
Following is a question of z transform:
$$ (-frac{1}{3})^n u[-n-2] $$
Now I know that a transform pair similar to this is:
$$ -alpha^n u[-n-1]=frac{1}{1-alpha z^{-1}} $$
Now using that property what I get is:
$$ frac{1}{1-(1/3)z^{-1}} $$
now since the shift is of $-1$ so using that property my final answer is:
$$ (z^{-1})(frac{1}{1-(1/3)z^{-1}}) $$
Is it correct?
z-transform
asked Jan 6 at 14:25
Ahmad QayyumAhmad Qayyum
677
$endgroup$
$begingroup$
@LordSharktheUnknown can you help me on this one?
$endgroup$
– Ahmad Qayyum
Jan 6 at 16:15
add a comment |
$begingroup$
Following is a question of z transform:
$$ (-frac{1}{3})^n u[-n-2] $$
Now I know that a transform pair similar to this is:
$$ -alpha^n u[-n-1]=frac{1}{1-alpha z^{-1}} $$
Now using that property what I get is:
$$ frac{1}{1-(1/3)z^{-1}} $$
now since the shift is of $-1$ so using that property my final answer is:
$$ (z^{-1})(frac{1}{1-(1/3)z^{-1}}) $$
Is it correct?
z-transform
asked Jan 6 at 14:25
Ahmad QayyumAhmad Qayyum
677
$endgroup$
Following is a question of z transform:
$$ (-frac{1}{3})^n u[-n-2] $$
Now I know that a transform pair similar to this is:
$$ -alpha^n u[-n-1]=frac{1}{1-alpha z^{-1}} $$
Now using that property what I get is:
$$ frac{1}{1-(1/3)z^{-1}} $$
now since the shift is of $-1$ so using that property my final answer is:
$$ (z^{-1})(frac{1}{1-(1/3)z^{-1}}) $$
Is it correct?
z-transform
z-transform
asked Jan 6 at 14:25
Ahmad QayyumAhmad Qayyum
677
asked Jan 6 at 14:25
Ahmad QayyumAhmad Qayyum
677
edited Jan 6 at 14:39
Ahmad Qayyum
asked Jan 6 at 14:25
Ahmad QayyumAhmad Qayyum
677
asked Jan 6 at 14:25
Ahmad QayyumAhmad Qayyum
677
asked Jan 6 at 14:25
Ahmad QayyumAhmad Qayyum
677
677
$begingroup$
@LordSharktheUnknown can you help me on this one?
$endgroup$
– Ahmad Qayyum
Jan 6 at 16:15
add a comment |
$begingroup$
@LordSharktheUnknown can you help me on this one?
$endgroup$
– Ahmad Qayyum
Jan 6 at 16:15
$begingroup$
@LordSharktheUnknown can you help me on this one?
$endgroup$
– Ahmad Qayyum
Jan 6 at 16:15
$begingroup$
@LordSharktheUnknown can you help me on this one?
$endgroup$
– Ahmad Qayyum
Jan 6 at 16:15
add a comment |
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$begingroup$
@LordSharktheUnknown can you help me on this one?
$endgroup$
– Ahmad Qayyum
Jan 6 at 16:15