Mixing
Delete table record in php
0
Within the while I created the delete button:
while($rows_cursos = mysqli_fetch_array($resultado_cursos)) {
$tabela2 .= '<tr>';
$tabela2 .= '<td>'.$rows_cursos['IdEstado'].'</td>';
$tabela2 .= '<td>'.$rows_cursos['DataRequis'].'</td>';
$tabela2 .= '<td>'.$rows_cursos['Funcionario'].'</td>';
$tabela2 .= '<td><form action="./delete" method="post">';
$tabela2 .= '<input type="hidden" name="IdEstado" value="'.$rows_cursos['IdEstado'].'">';
$tabela2 .= '<button type="button" class="btn btn-danger">Excluir</button>'; //aqui está o seu botão
$tabela2 .= '</form></td>'; //só fechando o form
$tabela2 .= '</tr>';
}
$tabela2 .= '</tr>';
$tabela2 .='</tbody>';
$tabela2 .= '</table>';
$tabela2 .= '</div>';
echo $tabela2;
The action = "./delete" I put it this way because I'm working on wordpress and the action of this form is equal to action = "delete.php".
After deleting.php I have this code:
$id = $_POST['IdEstado'];
$sql = "DELETE FROM `centrodb`.`RequisicaoLuvas` WHERE `RequisicaoLuvas`.`id` = " . $id;
mysqli_query($conn,$sql) or die("Erro ao tentar cadastrar registro");
mysqli_close($conn);
$sql1 = "DELETE FROM `centrodb`.`EstadoLuvas` WHERE `EstadoLuvas`.`IdEstado` = " . $id;
mysqli_query($conn,$sql1) or die("Erro ao tentar cadastrar registro");
mysqli_close($conn);
When I click the delete button it does not delete anything in the database table.
php html mysql
asked Nov 19 '18 at 14:06
Bruno
166
|
show 9 more comments
0
Within the while I created the delete button:
while($rows_cursos = mysqli_fetch_array($resultado_cursos)) {
$tabela2 .= '<tr>';
$tabela2 .= '<td>'.$rows_cursos['IdEstado'].'</td>';
$tabela2 .= '<td>'.$rows_cursos['DataRequis'].'</td>';
$tabela2 .= '<td>'.$rows_cursos['Funcionario'].'</td>';
$tabela2 .= '<td><form action="./delete" method="post">';
$tabela2 .= '<input type="hidden" name="IdEstado" value="'.$rows_cursos['IdEstado'].'">';
$tabela2 .= '<button type="button" class="btn btn-danger">Excluir</button>'; //aqui está o seu botão
$tabela2 .= '</form></td>'; //só fechando o form
$tabela2 .= '</tr>';
}
$tabela2 .= '</tr>';
$tabela2 .='</tbody>';
$tabela2 .= '</table>';
$tabela2 .= '</div>';
echo $tabela2;
The action = "./delete" I put it this way because I'm working on wordpress and the action of this form is equal to action = "delete.php".
After deleting.php I have this code:
$id = $_POST['IdEstado'];
$sql = "DELETE FROM `centrodb`.`RequisicaoLuvas` WHERE `RequisicaoLuvas`.`id` = " . $id;
mysqli_query($conn,$sql) or die("Erro ao tentar cadastrar registro");
mysqli_close($conn);
$sql1 = "DELETE FROM `centrodb`.`EstadoLuvas` WHERE `EstadoLuvas`.`IdEstado` = " . $id;
mysqli_query($conn,$sql1) or die("Erro ao tentar cadastrar registro");
mysqli_close($conn);
When I click the delete button it does not delete anything in the database table.
php html mysql
asked Nov 19 '18 at 14:06
Bruno
166
what error do you get?
– Prashanth Benny
Nov 19 '18 at 14:08
3
Your button is a button and not a type="submit".
– Demodave
Nov 19 '18 at 14:09
@Prashanth Benny I am not receiving any errors, neither on the page nor in the chrome console
– Bruno
Nov 19 '18 at 14:09
@Demodave is going to delete.php page
– Bruno
Nov 19 '18 at 14:11
you could use die(mysqli_error($conn)); to display the exact error
– Prashanth Benny
Nov 19 '18 at 14:12
|
show 9 more comments
0
0
0
Within the while I created the delete button:
while($rows_cursos = mysqli_fetch_array($resultado_cursos)) {
$tabela2 .= '<tr>';
$tabela2 .= '<td>'.$rows_cursos['IdEstado'].'</td>';
$tabela2 .= '<td>'.$rows_cursos['DataRequis'].'</td>';
$tabela2 .= '<td>'.$rows_cursos['Funcionario'].'</td>';
$tabela2 .= '<td><form action="./delete" method="post">';
$tabela2 .= '<input type="hidden" name="IdEstado" value="'.$rows_cursos['IdEstado'].'">';
$tabela2 .= '<button type="button" class="btn btn-danger">Excluir</button>'; //aqui está o seu botão
$tabela2 .= '</form></td>'; //só fechando o form
$tabela2 .= '</tr>';
}
$tabela2 .= '</tr>';
$tabela2 .='</tbody>';
$tabela2 .= '</table>';
$tabela2 .= '</div>';
echo $tabela2;
The action = "./delete" I put it this way because I'm working on wordpress and the action of this form is equal to action = "delete.php".
After deleting.php I have this code:
$id = $_POST['IdEstado'];
$sql = "DELETE FROM `centrodb`.`RequisicaoLuvas` WHERE `RequisicaoLuvas`.`id` = " . $id;
mysqli_query($conn,$sql) or die("Erro ao tentar cadastrar registro");
mysqli_close($conn);
$sql1 = "DELETE FROM `centrodb`.`EstadoLuvas` WHERE `EstadoLuvas`.`IdEstado` = " . $id;
mysqli_query($conn,$sql1) or die("Erro ao tentar cadastrar registro");
mysqli_close($conn);
When I click the delete button it does not delete anything in the database table.
php html mysql
asked Nov 19 '18 at 14:06
Bruno
166
Within the while I created the delete button:
while($rows_cursos = mysqli_fetch_array($resultado_cursos)) {
$tabela2 .= '<tr>';
$tabela2 .= '<td>'.$rows_cursos['IdEstado'].'</td>';
$tabela2 .= '<td>'.$rows_cursos['DataRequis'].'</td>';
$tabela2 .= '<td>'.$rows_cursos['Funcionario'].'</td>';
$tabela2 .= '<td><form action="./delete" method="post">';
$tabela2 .= '<input type="hidden" name="IdEstado" value="'.$rows_cursos['IdEstado'].'">';
$tabela2 .= '<button type="button" class="btn btn-danger">Excluir</button>'; //aqui está o seu botão
$tabela2 .= '</form></td>'; //só fechando o form
$tabela2 .= '</tr>';
}
$tabela2 .= '</tr>';
$tabela2 .='</tbody>';
$tabela2 .= '</table>';
$tabela2 .= '</div>';
echo $tabela2;
The action = "./delete" I put it this way because I'm working on wordpress and the action of this form is equal to action = "delete.php".
After deleting.php I have this code:
$id = $_POST['IdEstado'];
$sql = "DELETE FROM `centrodb`.`RequisicaoLuvas` WHERE `RequisicaoLuvas`.`id` = " . $id;
mysqli_query($conn,$sql) or die("Erro ao tentar cadastrar registro");
mysqli_close($conn);
$sql1 = "DELETE FROM `centrodb`.`EstadoLuvas` WHERE `EstadoLuvas`.`IdEstado` = " . $id;
mysqli_query($conn,$sql1) or die("Erro ao tentar cadastrar registro");
mysqli_close($conn);
When I click the delete button it does not delete anything in the database table.
php html mysql
php html mysql
asked Nov 19 '18 at 14:06
Bruno
166
asked Nov 19 '18 at 14:06
Bruno
166
edited Nov 19 '18 at 14:12
asked Nov 19 '18 at 14:06
Bruno
166
asked Nov 19 '18 at 14:06
Bruno
166
asked Nov 19 '18 at 14:06
Bruno
166
166
what error do you get?
– Prashanth Benny
Nov 19 '18 at 14:08
3
Your button is a button and not a type="submit".
– Demodave
Nov 19 '18 at 14:09
@Prashanth Benny I am not receiving any errors, neither on the page nor in the chrome console
– Bruno
Nov 19 '18 at 14:09
@Demodave is going to delete.php page
– Bruno
Nov 19 '18 at 14:11
you could use die(mysqli_error($conn)); to display the exact error
– Prashanth Benny
Nov 19 '18 at 14:12
|
show 9 more comments
what error do you get?
– Prashanth Benny
Nov 19 '18 at 14:08
3
Your button is a button and not a type="submit".
– Demodave
Nov 19 '18 at 14:09
@Prashanth Benny I am not receiving any errors, neither on the page nor in the chrome console
– Bruno
Nov 19 '18 at 14:09
@Demodave is going to delete.php page
– Bruno
Nov 19 '18 at 14:11
you could use die(mysqli_error($conn)); to display the exact error
– Prashanth Benny
Nov 19 '18 at 14:12
what error do you get?
– Prashanth Benny
Nov 19 '18 at 14:08
what error do you get?
– Prashanth Benny
Nov 19 '18 at 14:08
3
3
Your button is a button and not a type="submit".
– Demodave
Nov 19 '18 at 14:09
Your button is a button and not a type="submit".
– Demodave
Nov 19 '18 at 14:09
@Prashanth Benny I am not receiving any errors, neither on the page nor in the chrome console
– Bruno
Nov 19 '18 at 14:09
@Prashanth Benny I am not receiving any errors, neither on the page nor in the chrome console
– Bruno
Nov 19 '18 at 14:09
@Demodave is going to delete.php page
– Bruno
Nov 19 '18 at 14:11
@Demodave is going to delete.php page
– Bruno
Nov 19 '18 at 14:11
you could use die(mysqli_error($conn)); to display the exact error
– Prashanth Benny
Nov 19 '18 at 14:12
you could use die(mysqli_error($conn)); to display the exact error
– Prashanth Benny
Nov 19 '18 at 14:12
|
show 9 more comments
1 Answer
1
active
oldest
votes
0
You can do it easy with PDO and avoid SQL Inyection if you want to use mysqli you can do something similar. Follow this link: http://php.net/manual/es/mysqli-stmt.bind-param.php
<?php
$id = $_POST['IdEstado'];
$pdo = new PDO("mysql:host=" . $dataBaseHost . "; dbname=" . $dataBaseName . "", $dataBaseUserName, $dataBasePassword);
$prepared_statement = $pdo->prepare("DELETE FROM RequisicaoLuvas WHERE id=:id");
$prepared_statement->bindParam(':id', $id);
$prepared_statement->execute();
$pdo = null;
?>
answered Nov 19 '18 at 14:50
manelseo
1124
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You can do it easy with PDO and avoid SQL Inyection if you want to use mysqli you can do something similar. Follow this link: http://php.net/manual/es/mysqli-stmt.bind-param.php
<?php
$id = $_POST['IdEstado'];
$pdo = new PDO("mysql:host=" . $dataBaseHost . "; dbname=" . $dataBaseName . "", $dataBaseUserName, $dataBasePassword);
$prepared_statement = $pdo->prepare("DELETE FROM RequisicaoLuvas WHERE id=:id");
$prepared_statement->bindParam(':id', $id);
$prepared_statement->execute();
$pdo = null;
?>
answered Nov 19 '18 at 14:50
manelseo
1124
add a comment |
0
You can do it easy with PDO and avoid SQL Inyection if you want to use mysqli you can do something similar. Follow this link: http://php.net/manual/es/mysqli-stmt.bind-param.php
<?php
$id = $_POST['IdEstado'];
$pdo = new PDO("mysql:host=" . $dataBaseHost . "; dbname=" . $dataBaseName . "", $dataBaseUserName, $dataBasePassword);
$prepared_statement = $pdo->prepare("DELETE FROM RequisicaoLuvas WHERE id=:id");
$prepared_statement->bindParam(':id', $id);
$prepared_statement->execute();
$pdo = null;
?>
answered Nov 19 '18 at 14:50
manelseo
1124
add a comment |
0
0
0
You can do it easy with PDO and avoid SQL Inyection if you want to use mysqli you can do something similar. Follow this link: http://php.net/manual/es/mysqli-stmt.bind-param.php
<?php
$id = $_POST['IdEstado'];
$pdo = new PDO("mysql:host=" . $dataBaseHost . "; dbname=" . $dataBaseName . "", $dataBaseUserName, $dataBasePassword);
$prepared_statement = $pdo->prepare("DELETE FROM RequisicaoLuvas WHERE id=:id");
$prepared_statement->bindParam(':id', $id);
$prepared_statement->execute();
$pdo = null;
?>
answered Nov 19 '18 at 14:50
manelseo
1124
You can do it easy with PDO and avoid SQL Inyection if you want to use mysqli you can do something similar. Follow this link: http://php.net/manual/es/mysqli-stmt.bind-param.php
<?php
$id = $_POST['IdEstado'];
$pdo = new PDO("mysql:host=" . $dataBaseHost . "; dbname=" . $dataBaseName . "", $dataBaseUserName, $dataBasePassword);
$prepared_statement = $pdo->prepare("DELETE FROM RequisicaoLuvas WHERE id=:id");
$prepared_statement->bindParam(':id', $id);
$prepared_statement->execute();
$pdo = null;
?>
answered Nov 19 '18 at 14:50
manelseo
1124
answered Nov 19 '18 at 14:50
manelseo
1124
answered Nov 19 '18 at 14:50
manelseo
1124
answered Nov 19 '18 at 14:50
manelseo
1124
1124
add a comment |
add a comment |
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what error do you get?
– Prashanth Benny
Nov 19 '18 at 14:08
3
Your button is a button and not a type="submit".
– Demodave
Nov 19 '18 at 14:09
@Prashanth Benny I am not receiving any errors, neither on the page nor in the chrome console
– Bruno
Nov 19 '18 at 14:09
@Demodave is going to delete.php page
– Bruno
Nov 19 '18 at 14:11
you could use die(mysqli_error($conn)); to display the exact error
– Prashanth Benny
Nov 19 '18 at 14:12