$(AB) ^3=O_n$ and$(BA) ^3 neq O_n$












2












$begingroup$


Let $A, B in M_n(mathbb C) $ so that $(AB) ^3=O_n$. Does this imply $(BA)^3=O_n$?.

I saw that the implication is true if $nle 3$ and not true for $nge 4$. What I want is either a counterexample for $nge 4$ or some proof.( I can't find neither of them, I have tried using both HC and taking random matrices)










share|cite|improve this question









$endgroup$












  • $begingroup$
    By $O_n$, do you mean the $ntimes n$ zero matrix?
    $endgroup$
    – Arthur
    Jan 28 at 15:43










  • $begingroup$
    Yes, that is what I mean by it.
    $endgroup$
    – JustAnAmateur
    Jan 28 at 15:47
















2












$begingroup$


Let $A, B in M_n(mathbb C) $ so that $(AB) ^3=O_n$. Does this imply $(BA)^3=O_n$?.

I saw that the implication is true if $nle 3$ and not true for $nge 4$. What I want is either a counterexample for $nge 4$ or some proof.( I can't find neither of them, I have tried using both HC and taking random matrices)










share|cite|improve this question









$endgroup$












  • $begingroup$
    By $O_n$, do you mean the $ntimes n$ zero matrix?
    $endgroup$
    – Arthur
    Jan 28 at 15:43










  • $begingroup$
    Yes, that is what I mean by it.
    $endgroup$
    – JustAnAmateur
    Jan 28 at 15:47














2












2








2


1



$begingroup$


Let $A, B in M_n(mathbb C) $ so that $(AB) ^3=O_n$. Does this imply $(BA)^3=O_n$?.

I saw that the implication is true if $nle 3$ and not true for $nge 4$. What I want is either a counterexample for $nge 4$ or some proof.( I can't find neither of them, I have tried using both HC and taking random matrices)










share|cite|improve this question









$endgroup$




Let $A, B in M_n(mathbb C) $ so that $(AB) ^3=O_n$. Does this imply $(BA)^3=O_n$?.

I saw that the implication is true if $nle 3$ and not true for $nge 4$. What I want is either a counterexample for $nge 4$ or some proof.( I can't find neither of them, I have tried using both HC and taking random matrices)







linear-algebra matrices






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 28 at 15:41









JustAnAmateurJustAnAmateur

1096




1096












  • $begingroup$
    By $O_n$, do you mean the $ntimes n$ zero matrix?
    $endgroup$
    – Arthur
    Jan 28 at 15:43










  • $begingroup$
    Yes, that is what I mean by it.
    $endgroup$
    – JustAnAmateur
    Jan 28 at 15:47


















  • $begingroup$
    By $O_n$, do you mean the $ntimes n$ zero matrix?
    $endgroup$
    – Arthur
    Jan 28 at 15:43










  • $begingroup$
    Yes, that is what I mean by it.
    $endgroup$
    – JustAnAmateur
    Jan 28 at 15:47
















$begingroup$
By $O_n$, do you mean the $ntimes n$ zero matrix?
$endgroup$
– Arthur
Jan 28 at 15:43




$begingroup$
By $O_n$, do you mean the $ntimes n$ zero matrix?
$endgroup$
– Arthur
Jan 28 at 15:43












$begingroup$
Yes, that is what I mean by it.
$endgroup$
– JustAnAmateur
Jan 28 at 15:47




$begingroup$
Yes, that is what I mean by it.
$endgroup$
– JustAnAmateur
Jan 28 at 15:47










1 Answer
1






active

oldest

votes


















4












$begingroup$

One classical counterexample is given by
$$
A=pmatrix{0&1\ &0&1\ &&0&1\ &&&0},
B=pmatrix{1\ &1\ &&1\ &&&0},
$$

so that $AB=J_3(0)oplus0$ and $BA=A=J_4(0)$, where $J_k(0)$ denotes the $ktimes k$ nilpotent Jordan block.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    How did you come up with them?
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:00






  • 2




    $begingroup$
    @JustAnAmateur It's just a generalisation of the classical example of a pair of $(A,B)$ such that $AB=0$ but $BAne0$.
    $endgroup$
    – user1551
    Jan 28 at 16:02










  • $begingroup$
    Thank you for your insight!
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:03












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1 Answer
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active

oldest

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1 Answer
1






active

oldest

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active

oldest

votes






active

oldest

votes









4












$begingroup$

One classical counterexample is given by
$$
A=pmatrix{0&1\ &0&1\ &&0&1\ &&&0},
B=pmatrix{1\ &1\ &&1\ &&&0},
$$

so that $AB=J_3(0)oplus0$ and $BA=A=J_4(0)$, where $J_k(0)$ denotes the $ktimes k$ nilpotent Jordan block.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    How did you come up with them?
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:00






  • 2




    $begingroup$
    @JustAnAmateur It's just a generalisation of the classical example of a pair of $(A,B)$ such that $AB=0$ but $BAne0$.
    $endgroup$
    – user1551
    Jan 28 at 16:02










  • $begingroup$
    Thank you for your insight!
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:03
















4












$begingroup$

One classical counterexample is given by
$$
A=pmatrix{0&1\ &0&1\ &&0&1\ &&&0},
B=pmatrix{1\ &1\ &&1\ &&&0},
$$

so that $AB=J_3(0)oplus0$ and $BA=A=J_4(0)$, where $J_k(0)$ denotes the $ktimes k$ nilpotent Jordan block.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    How did you come up with them?
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:00






  • 2




    $begingroup$
    @JustAnAmateur It's just a generalisation of the classical example of a pair of $(A,B)$ such that $AB=0$ but $BAne0$.
    $endgroup$
    – user1551
    Jan 28 at 16:02










  • $begingroup$
    Thank you for your insight!
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:03














4












4








4





$begingroup$

One classical counterexample is given by
$$
A=pmatrix{0&1\ &0&1\ &&0&1\ &&&0},
B=pmatrix{1\ &1\ &&1\ &&&0},
$$

so that $AB=J_3(0)oplus0$ and $BA=A=J_4(0)$, where $J_k(0)$ denotes the $ktimes k$ nilpotent Jordan block.






share|cite|improve this answer









$endgroup$



One classical counterexample is given by
$$
A=pmatrix{0&1\ &0&1\ &&0&1\ &&&0},
B=pmatrix{1\ &1\ &&1\ &&&0},
$$

so that $AB=J_3(0)oplus0$ and $BA=A=J_4(0)$, where $J_k(0)$ denotes the $ktimes k$ nilpotent Jordan block.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Jan 28 at 15:54









user1551user1551

73.9k566129




73.9k566129












  • $begingroup$
    How did you come up with them?
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:00






  • 2




    $begingroup$
    @JustAnAmateur It's just a generalisation of the classical example of a pair of $(A,B)$ such that $AB=0$ but $BAne0$.
    $endgroup$
    – user1551
    Jan 28 at 16:02










  • $begingroup$
    Thank you for your insight!
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:03


















  • $begingroup$
    How did you come up with them?
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:00






  • 2




    $begingroup$
    @JustAnAmateur It's just a generalisation of the classical example of a pair of $(A,B)$ such that $AB=0$ but $BAne0$.
    $endgroup$
    – user1551
    Jan 28 at 16:02










  • $begingroup$
    Thank you for your insight!
    $endgroup$
    – JustAnAmateur
    Jan 28 at 16:03
















$begingroup$
How did you come up with them?
$endgroup$
– JustAnAmateur
Jan 28 at 16:00




$begingroup$
How did you come up with them?
$endgroup$
– JustAnAmateur
Jan 28 at 16:00




2




2




$begingroup$
@JustAnAmateur It's just a generalisation of the classical example of a pair of $(A,B)$ such that $AB=0$ but $BAne0$.
$endgroup$
– user1551
Jan 28 at 16:02




$begingroup$
@JustAnAmateur It's just a generalisation of the classical example of a pair of $(A,B)$ such that $AB=0$ but $BAne0$.
$endgroup$
– user1551
Jan 28 at 16:02












$begingroup$
Thank you for your insight!
$endgroup$
– JustAnAmateur
Jan 28 at 16:03




$begingroup$
Thank you for your insight!
$endgroup$
– JustAnAmateur
Jan 28 at 16:03


















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