Mixing
Could someone explain midpoint method to me?
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I have an exercise here, but I would like to familiarise myself with the midpoint differential equation method and solve this exercise, could anyone help me out? How do I go about solving it?
Consider the ordinary differential equation initial value problem given by
$$
y'(t) = y^2 + t quad text{with} quad y(0) = 1,
$$
where $y'(t)$ denotes the time derivative of $y$.
Approximate the solution of this problem using two steps of the midpoint method
using a value of $dt = 0.2$.
ordinary-differential-equations numerical-methods
edited Jan 23 at 19:24
LutzL
59.6k42057
asked Jan 23 at 19:06
ValVal
83
$endgroup$
add a comment |
$begingroup$
I have an exercise here, but I would like to familiarise myself with the midpoint differential equation method and solve this exercise, could anyone help me out? How do I go about solving it?
Consider the ordinary differential equation initial value problem given by
$$
y'(t) = y^2 + t quad text{with} quad y(0) = 1,
$$
where $y'(t)$ denotes the time derivative of $y$.
Approximate the solution of this problem using two steps of the midpoint method
using a value of $dt = 0.2$.
ordinary-differential-equations numerical-methods
edited Jan 23 at 19:24
LutzL
59.6k42057
asked Jan 23 at 19:06
ValVal
83
$endgroup$
5
$begingroup$
Does the task demand the explicit midpoint method or the implicit variant? Did you find the wikipedia page for it, and what is not clear from it?
$endgroup$
– LutzL
Jan 23 at 19:24
add a comment |
$begingroup$
I have an exercise here, but I would like to familiarise myself with the midpoint differential equation method and solve this exercise, could anyone help me out? How do I go about solving it?
Consider the ordinary differential equation initial value problem given by
$$
y'(t) = y^2 + t quad text{with} quad y(0) = 1,
$$
where $y'(t)$ denotes the time derivative of $y$.
Approximate the solution of this problem using two steps of the midpoint method
using a value of $dt = 0.2$.
ordinary-differential-equations numerical-methods
edited Jan 23 at 19:24
LutzL
59.6k42057
asked Jan 23 at 19:06
ValVal
83
$endgroup$
I have an exercise here, but I would like to familiarise myself with the midpoint differential equation method and solve this exercise, could anyone help me out? How do I go about solving it?
Consider the ordinary differential equation initial value problem given by
$$
y'(t) = y^2 + t quad text{with} quad y(0) = 1,
$$
where $y'(t)$ denotes the time derivative of $y$.
Approximate the solution of this problem using two steps of the midpoint method
using a value of $dt = 0.2$.
ordinary-differential-equations numerical-methods
ordinary-differential-equations numerical-methods
edited Jan 23 at 19:24
LutzL
59.6k42057
asked Jan 23 at 19:06
ValVal
83
edited Jan 23 at 19:24
LutzL
59.6k42057
asked Jan 23 at 19:06
ValVal
83
edited Jan 23 at 19:24
LutzL
59.6k42057
edited Jan 23 at 19:24
LutzL
59.6k42057
edited Jan 23 at 19:24
LutzL
59.6k42057
59.6k42057
asked Jan 23 at 19:06
ValVal
83
asked Jan 23 at 19:06
ValVal
83
asked Jan 23 at 19:06
ValVal
83
83
5
$begingroup$
Does the task demand the explicit midpoint method or the implicit variant? Did you find the wikipedia page for it, and what is not clear from it?
$endgroup$
– LutzL
Jan 23 at 19:24
add a comment |
5
$begingroup$
Does the task demand the explicit midpoint method or the implicit variant? Did you find the wikipedia page for it, and what is not clear from it?
$endgroup$
– LutzL
Jan 23 at 19:24
5
5
$begingroup$
Does the task demand the explicit midpoint method or the implicit variant? Did you find the wikipedia page for it, and what is not clear from it?
$endgroup$
– LutzL
Jan 23 at 19:24
$begingroup$
Does the task demand the explicit midpoint method or the implicit variant? Did you find the wikipedia page for it, and what is not clear from it?
$endgroup$
– LutzL
Jan 23 at 19:24
add a comment |
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$begingroup$
Does the task demand the explicit midpoint method or the implicit variant? Did you find the wikipedia page for it, and what is not clear from it?
$endgroup$
– LutzL
Jan 23 at 19:24