Given two positions, and a list of all positions, find quickest path












-2















I have two points (x1, y1) & (x2, y2), and a list of all possible positions that can be traversed across with format (x, y), how would I find/estimate the quickest path between the two values.



I am implementing this in Java, but the language doesn't matter much.





Some limitations & additional info around the question:




  • The values of x1 & x2 will be never the same, unless y1 = y2, this is because these positions are always located on the edge of a box.

  • There may not always be a path between (x1, y1) & (x2, y2) (for when checking for continuity between the paths

  • Not all possible points will be connected to either (x1, y1) or (x2, y2)

  • Shortest path isn't required but would be handy to know

  • Would be happy with simply some hints about what direction to take or algorithms to look into

  • Travel can happen via a diagonal ((x, y) & (x + 1, y + 1) are considered neighbours)










share|improve this question





























    -2















    I have two points (x1, y1) & (x2, y2), and a list of all possible positions that can be traversed across with format (x, y), how would I find/estimate the quickest path between the two values.



    I am implementing this in Java, but the language doesn't matter much.





    Some limitations & additional info around the question:




    • The values of x1 & x2 will be never the same, unless y1 = y2, this is because these positions are always located on the edge of a box.

    • There may not always be a path between (x1, y1) & (x2, y2) (for when checking for continuity between the paths

    • Not all possible points will be connected to either (x1, y1) or (x2, y2)

    • Shortest path isn't required but would be handy to know

    • Would be happy with simply some hints about what direction to take or algorithms to look into

    • Travel can happen via a diagonal ((x, y) & (x + 1, y + 1) are considered neighbours)










    share|improve this question



























      -2












      -2








      -2








      I have two points (x1, y1) & (x2, y2), and a list of all possible positions that can be traversed across with format (x, y), how would I find/estimate the quickest path between the two values.



      I am implementing this in Java, but the language doesn't matter much.





      Some limitations & additional info around the question:




      • The values of x1 & x2 will be never the same, unless y1 = y2, this is because these positions are always located on the edge of a box.

      • There may not always be a path between (x1, y1) & (x2, y2) (for when checking for continuity between the paths

      • Not all possible points will be connected to either (x1, y1) or (x2, y2)

      • Shortest path isn't required but would be handy to know

      • Would be happy with simply some hints about what direction to take or algorithms to look into

      • Travel can happen via a diagonal ((x, y) & (x + 1, y + 1) are considered neighbours)










      share|improve this question
















      I have two points (x1, y1) & (x2, y2), and a list of all possible positions that can be traversed across with format (x, y), how would I find/estimate the quickest path between the two values.



      I am implementing this in Java, but the language doesn't matter much.





      Some limitations & additional info around the question:




      • The values of x1 & x2 will be never the same, unless y1 = y2, this is because these positions are always located on the edge of a box.

      • There may not always be a path between (x1, y1) & (x2, y2) (for when checking for continuity between the paths

      • Not all possible points will be connected to either (x1, y1) or (x2, y2)

      • Shortest path isn't required but would be handy to know

      • Would be happy with simply some hints about what direction to take or algorithms to look into

      • Travel can happen via a diagonal ((x, y) & (x + 1, y + 1) are considered neighbours)







      language-agnostic path-finding






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 1 at 21:23







      FabianCook

















      asked Jan 1 at 21:16









      FabianCookFabianCook

      12.1k145198




      12.1k145198
























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          The answer I was looking for is to use A* as a search algorithm, this finds the shortest path between two points given a map of all the nodes.






          share|improve this answer























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            The answer I was looking for is to use A* as a search algorithm, this finds the shortest path between two points given a map of all the nodes.






            share|improve this answer




























              0














              The answer I was looking for is to use A* as a search algorithm, this finds the shortest path between two points given a map of all the nodes.






              share|improve this answer


























                0












                0








                0







                The answer I was looking for is to use A* as a search algorithm, this finds the shortest path between two points given a map of all the nodes.






                share|improve this answer













                The answer I was looking for is to use A* as a search algorithm, this finds the shortest path between two points given a map of all the nodes.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Jan 2 at 22:14









                FabianCookFabianCook

                12.1k145198




                12.1k145198
































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