Counting total number of local maxima and minima of a function












0












$begingroup$


Find the total number of local maxima and local minima for the function
$$
f(x) = begin{cases}
(2+x)^{3} &text{if}, -3 lt x le -1 \
(x)^frac{2}{3} &text{if}, -1 lt x lt 2
end{cases}
$$



My attempt : I differentiated the function for the two different intervals and obtained the following:
$$
f'(x) = begin{cases}
3cdot(2+x)^{2} &text{if}, -3 lt x le -1 \
frac{2}{3}cdot (x)^frac{-1}{3} &text{if}, -1 lt x lt 2
end{cases}
$$
How do I obtain the maxima and minima points from here.



Any help will be appreciated.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    extrema occur where $f'(x) = 0$, $f'(x)$ is undefined, and/or endpoints.
    $endgroup$
    – Dando18
    Jun 6 '17 at 14:12












  • $begingroup$
    @Dando18, "extrema may occur where..." In the problem given, $f'(-2)=0$ but $(-2,0)$ is not an extrema.
    $endgroup$
    – Bernard Massé
    Jun 6 '17 at 14:28










  • $begingroup$
    @BernardMassé Yeah I meant $ text{extrema} implies f'(x)=0,, dots$ not the other way around.
    $endgroup$
    – Dando18
    Jun 6 '17 at 14:30










  • $begingroup$
    Just draw the graph?!
    $endgroup$
    – Pieter21
    Jun 6 '17 at 15:30
















0












$begingroup$


Find the total number of local maxima and local minima for the function
$$
f(x) = begin{cases}
(2+x)^{3} &text{if}, -3 lt x le -1 \
(x)^frac{2}{3} &text{if}, -1 lt x lt 2
end{cases}
$$



My attempt : I differentiated the function for the two different intervals and obtained the following:
$$
f'(x) = begin{cases}
3cdot(2+x)^{2} &text{if}, -3 lt x le -1 \
frac{2}{3}cdot (x)^frac{-1}{3} &text{if}, -1 lt x lt 2
end{cases}
$$
How do I obtain the maxima and minima points from here.



Any help will be appreciated.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    extrema occur where $f'(x) = 0$, $f'(x)$ is undefined, and/or endpoints.
    $endgroup$
    – Dando18
    Jun 6 '17 at 14:12












  • $begingroup$
    @Dando18, "extrema may occur where..." In the problem given, $f'(-2)=0$ but $(-2,0)$ is not an extrema.
    $endgroup$
    – Bernard Massé
    Jun 6 '17 at 14:28










  • $begingroup$
    @BernardMassé Yeah I meant $ text{extrema} implies f'(x)=0,, dots$ not the other way around.
    $endgroup$
    – Dando18
    Jun 6 '17 at 14:30










  • $begingroup$
    Just draw the graph?!
    $endgroup$
    – Pieter21
    Jun 6 '17 at 15:30














0












0








0





$begingroup$


Find the total number of local maxima and local minima for the function
$$
f(x) = begin{cases}
(2+x)^{3} &text{if}, -3 lt x le -1 \
(x)^frac{2}{3} &text{if}, -1 lt x lt 2
end{cases}
$$



My attempt : I differentiated the function for the two different intervals and obtained the following:
$$
f'(x) = begin{cases}
3cdot(2+x)^{2} &text{if}, -3 lt x le -1 \
frac{2}{3}cdot (x)^frac{-1}{3} &text{if}, -1 lt x lt 2
end{cases}
$$
How do I obtain the maxima and minima points from here.



Any help will be appreciated.










share|cite|improve this question











$endgroup$




Find the total number of local maxima and local minima for the function
$$
f(x) = begin{cases}
(2+x)^{3} &text{if}, -3 lt x le -1 \
(x)^frac{2}{3} &text{if}, -1 lt x lt 2
end{cases}
$$



My attempt : I differentiated the function for the two different intervals and obtained the following:
$$
f'(x) = begin{cases}
3cdot(2+x)^{2} &text{if}, -3 lt x le -1 \
frac{2}{3}cdot (x)^frac{-1}{3} &text{if}, -1 lt x lt 2
end{cases}
$$
How do I obtain the maxima and minima points from here.



Any help will be appreciated.







functions maxima-minima






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jun 6 '17 at 14:15









Dando18

4,73241235




4,73241235










asked Jun 6 '17 at 14:11









MathsLearnerMathsLearner

694214




694214








  • 1




    $begingroup$
    extrema occur where $f'(x) = 0$, $f'(x)$ is undefined, and/or endpoints.
    $endgroup$
    – Dando18
    Jun 6 '17 at 14:12












  • $begingroup$
    @Dando18, "extrema may occur where..." In the problem given, $f'(-2)=0$ but $(-2,0)$ is not an extrema.
    $endgroup$
    – Bernard Massé
    Jun 6 '17 at 14:28










  • $begingroup$
    @BernardMassé Yeah I meant $ text{extrema} implies f'(x)=0,, dots$ not the other way around.
    $endgroup$
    – Dando18
    Jun 6 '17 at 14:30










  • $begingroup$
    Just draw the graph?!
    $endgroup$
    – Pieter21
    Jun 6 '17 at 15:30














  • 1




    $begingroup$
    extrema occur where $f'(x) = 0$, $f'(x)$ is undefined, and/or endpoints.
    $endgroup$
    – Dando18
    Jun 6 '17 at 14:12












  • $begingroup$
    @Dando18, "extrema may occur where..." In the problem given, $f'(-2)=0$ but $(-2,0)$ is not an extrema.
    $endgroup$
    – Bernard Massé
    Jun 6 '17 at 14:28










  • $begingroup$
    @BernardMassé Yeah I meant $ text{extrema} implies f'(x)=0,, dots$ not the other way around.
    $endgroup$
    – Dando18
    Jun 6 '17 at 14:30










  • $begingroup$
    Just draw the graph?!
    $endgroup$
    – Pieter21
    Jun 6 '17 at 15:30








1




1




$begingroup$
extrema occur where $f'(x) = 0$, $f'(x)$ is undefined, and/or endpoints.
$endgroup$
– Dando18
Jun 6 '17 at 14:12






$begingroup$
extrema occur where $f'(x) = 0$, $f'(x)$ is undefined, and/or endpoints.
$endgroup$
– Dando18
Jun 6 '17 at 14:12














$begingroup$
@Dando18, "extrema may occur where..." In the problem given, $f'(-2)=0$ but $(-2,0)$ is not an extrema.
$endgroup$
– Bernard Massé
Jun 6 '17 at 14:28




$begingroup$
@Dando18, "extrema may occur where..." In the problem given, $f'(-2)=0$ but $(-2,0)$ is not an extrema.
$endgroup$
– Bernard Massé
Jun 6 '17 at 14:28












$begingroup$
@BernardMassé Yeah I meant $ text{extrema} implies f'(x)=0,, dots$ not the other way around.
$endgroup$
– Dando18
Jun 6 '17 at 14:30




$begingroup$
@BernardMassé Yeah I meant $ text{extrema} implies f'(x)=0,, dots$ not the other way around.
$endgroup$
– Dando18
Jun 6 '17 at 14:30












$begingroup$
Just draw the graph?!
$endgroup$
– Pieter21
Jun 6 '17 at 15:30




$begingroup$
Just draw the graph?!
$endgroup$
– Pieter21
Jun 6 '17 at 15:30










1 Answer
1






active

oldest

votes


















0












$begingroup$

You need to study $f'$ :



What is the sign of $f'(x), xin ]-3 , 2 [$ ?



A local maxima/minima $x_m$ appears when :




  • $f'(x_m) = 0$ or $x_m$ is a remarquable point (here $x_m in {-3,-1,2}$)

  • $f'$ changes sign before and after $x_m$


If the second condition is not verified, $x_m$ is an inflection point.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I think x=0 is another remarkable point here, since f'(x) becomes undefined at x=0 .
    $endgroup$
    – MathsLearner
    Jun 6 '17 at 15:30










  • $begingroup$
    You're absolutely right, I didn't do the $f'$ study before posting my answer but indeed as pointed out by Dando18 if $f'$ is undefined then you should check the nature of the point.
    $endgroup$
    – Furrane
    Jun 8 '17 at 2:38











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1 Answer
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active

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0












$begingroup$

You need to study $f'$ :



What is the sign of $f'(x), xin ]-3 , 2 [$ ?



A local maxima/minima $x_m$ appears when :




  • $f'(x_m) = 0$ or $x_m$ is a remarquable point (here $x_m in {-3,-1,2}$)

  • $f'$ changes sign before and after $x_m$


If the second condition is not verified, $x_m$ is an inflection point.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I think x=0 is another remarkable point here, since f'(x) becomes undefined at x=0 .
    $endgroup$
    – MathsLearner
    Jun 6 '17 at 15:30










  • $begingroup$
    You're absolutely right, I didn't do the $f'$ study before posting my answer but indeed as pointed out by Dando18 if $f'$ is undefined then you should check the nature of the point.
    $endgroup$
    – Furrane
    Jun 8 '17 at 2:38
















0












$begingroup$

You need to study $f'$ :



What is the sign of $f'(x), xin ]-3 , 2 [$ ?



A local maxima/minima $x_m$ appears when :




  • $f'(x_m) = 0$ or $x_m$ is a remarquable point (here $x_m in {-3,-1,2}$)

  • $f'$ changes sign before and after $x_m$


If the second condition is not verified, $x_m$ is an inflection point.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I think x=0 is another remarkable point here, since f'(x) becomes undefined at x=0 .
    $endgroup$
    – MathsLearner
    Jun 6 '17 at 15:30










  • $begingroup$
    You're absolutely right, I didn't do the $f'$ study before posting my answer but indeed as pointed out by Dando18 if $f'$ is undefined then you should check the nature of the point.
    $endgroup$
    – Furrane
    Jun 8 '17 at 2:38














0












0








0





$begingroup$

You need to study $f'$ :



What is the sign of $f'(x), xin ]-3 , 2 [$ ?



A local maxima/minima $x_m$ appears when :




  • $f'(x_m) = 0$ or $x_m$ is a remarquable point (here $x_m in {-3,-1,2}$)

  • $f'$ changes sign before and after $x_m$


If the second condition is not verified, $x_m$ is an inflection point.






share|cite|improve this answer









$endgroup$



You need to study $f'$ :



What is the sign of $f'(x), xin ]-3 , 2 [$ ?



A local maxima/minima $x_m$ appears when :




  • $f'(x_m) = 0$ or $x_m$ is a remarquable point (here $x_m in {-3,-1,2}$)

  • $f'$ changes sign before and after $x_m$


If the second condition is not verified, $x_m$ is an inflection point.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Jun 6 '17 at 14:45









FurraneFurrane

1,3781516




1,3781516












  • $begingroup$
    I think x=0 is another remarkable point here, since f'(x) becomes undefined at x=0 .
    $endgroup$
    – MathsLearner
    Jun 6 '17 at 15:30










  • $begingroup$
    You're absolutely right, I didn't do the $f'$ study before posting my answer but indeed as pointed out by Dando18 if $f'$ is undefined then you should check the nature of the point.
    $endgroup$
    – Furrane
    Jun 8 '17 at 2:38


















  • $begingroup$
    I think x=0 is another remarkable point here, since f'(x) becomes undefined at x=0 .
    $endgroup$
    – MathsLearner
    Jun 6 '17 at 15:30










  • $begingroup$
    You're absolutely right, I didn't do the $f'$ study before posting my answer but indeed as pointed out by Dando18 if $f'$ is undefined then you should check the nature of the point.
    $endgroup$
    – Furrane
    Jun 8 '17 at 2:38
















$begingroup$
I think x=0 is another remarkable point here, since f'(x) becomes undefined at x=0 .
$endgroup$
– MathsLearner
Jun 6 '17 at 15:30




$begingroup$
I think x=0 is another remarkable point here, since f'(x) becomes undefined at x=0 .
$endgroup$
– MathsLearner
Jun 6 '17 at 15:30












$begingroup$
You're absolutely right, I didn't do the $f'$ study before posting my answer but indeed as pointed out by Dando18 if $f'$ is undefined then you should check the nature of the point.
$endgroup$
– Furrane
Jun 8 '17 at 2:38




$begingroup$
You're absolutely right, I didn't do the $f'$ study before posting my answer but indeed as pointed out by Dando18 if $f'$ is undefined then you should check the nature of the point.
$endgroup$
– Furrane
Jun 8 '17 at 2:38


















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