Mixing
Find the Area of Rectangle that has Two similar triangle
0
$begingroup$
A rectangle DEBC has triangle ABC.AB and AC intersect side DE at points F and G respectively. FG = 4, The perimeter of triangle ABC is double of the perimeter of Triangle AFG. The area of Triangle ABC = 16 sq units. What is the area of DEBC?
geometry euclidean-geometry rectangles
asked Jan 28 at 19:12
GhostGhost
163
$endgroup$
|
show 2 more comments
0
$begingroup$
A rectangle DEBC has triangle ABC.AB and AC intersect side DE at points F and G respectively. FG = 4, The perimeter of triangle ABC is double of the perimeter of Triangle AFG. The area of Triangle ABC = 16 sq units. What is the area of DEBC?
geometry euclidean-geometry rectangles
asked Jan 28 at 19:12
GhostGhost
163
$endgroup$
1
$begingroup$
Is A in the interior or exterior of the rectangle. What does a rectangle "having" a triangle mean?
$endgroup$
– fleablood
Jan 28 at 19:34
$begingroup$
If you can prove the triangles are symmetric then twice the perimeter means four times the area.
$endgroup$
– fleablood
Jan 28 at 19:42
$begingroup$
Sir/Madam, fleablood, The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G.
$endgroup$
– Ghost
Jan 28 at 19:45
$begingroup$
The two triangles has three similar angles which makes it similar triangle
$endgroup$
– Ghost
Jan 28 at 19:50
$begingroup$
"The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G" Not if you extend $AB$ past $A$ and $AC$ past $A$ and they intersect $DE$ on the other side.
$endgroup$
– fleablood
Jan 28 at 19:54
|
show 2 more comments
0
0
0
$begingroup$
A rectangle DEBC has triangle ABC.AB and AC intersect side DE at points F and G respectively. FG = 4, The perimeter of triangle ABC is double of the perimeter of Triangle AFG. The area of Triangle ABC = 16 sq units. What is the area of DEBC?
geometry euclidean-geometry rectangles
asked Jan 28 at 19:12
GhostGhost
163
$endgroup$
A rectangle DEBC has triangle ABC.AB and AC intersect side DE at points F and G respectively. FG = 4, The perimeter of triangle ABC is double of the perimeter of Triangle AFG. The area of Triangle ABC = 16 sq units. What is the area of DEBC?
geometry euclidean-geometry rectangles
geometry euclidean-geometry rectangles
asked Jan 28 at 19:12
GhostGhost
163
asked Jan 28 at 19:12
GhostGhost
163
edited Jan 30 at 9:36
Ghost
asked Jan 28 at 19:12
GhostGhost
163
asked Jan 28 at 19:12
GhostGhost
163
asked Jan 28 at 19:12
GhostGhost
163
163
1
$begingroup$
Is A in the interior or exterior of the rectangle. What does a rectangle "having" a triangle mean?
$endgroup$
– fleablood
Jan 28 at 19:34
$begingroup$
If you can prove the triangles are symmetric then twice the perimeter means four times the area.
$endgroup$
– fleablood
Jan 28 at 19:42
$begingroup$
Sir/Madam, fleablood, The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G.
$endgroup$
– Ghost
Jan 28 at 19:45
$begingroup$
The two triangles has three similar angles which makes it similar triangle
$endgroup$
– Ghost
Jan 28 at 19:50
$begingroup$
"The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G" Not if you extend $AB$ past $A$ and $AC$ past $A$ and they intersect $DE$ on the other side.
$endgroup$
– fleablood
Jan 28 at 19:54
|
show 2 more comments
1
$begingroup$
Is A in the interior or exterior of the rectangle. What does a rectangle "having" a triangle mean?
$endgroup$
– fleablood
Jan 28 at 19:34
$begingroup$
If you can prove the triangles are symmetric then twice the perimeter means four times the area.
$endgroup$
– fleablood
Jan 28 at 19:42
$begingroup$
Sir/Madam, fleablood, The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G.
$endgroup$
– Ghost
Jan 28 at 19:45
$begingroup$
The two triangles has three similar angles which makes it similar triangle
$endgroup$
– Ghost
Jan 28 at 19:50
$begingroup$
"The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G" Not if you extend $AB$ past $A$ and $AC$ past $A$ and they intersect $DE$ on the other side.
$endgroup$
– fleablood
Jan 28 at 19:54
1
1
$begingroup$
Is A in the interior or exterior of the rectangle. What does a rectangle "having" a triangle mean?
$endgroup$
– fleablood
Jan 28 at 19:34
$begingroup$
Is A in the interior or exterior of the rectangle. What does a rectangle "having" a triangle mean?
$endgroup$
– fleablood
Jan 28 at 19:34
$begingroup$
If you can prove the triangles are symmetric then twice the perimeter means four times the area.
$endgroup$
– fleablood
Jan 28 at 19:42
$begingroup$
If you can prove the triangles are symmetric then twice the perimeter means four times the area.
$endgroup$
– fleablood
Jan 28 at 19:42
$begingroup$
Sir/Madam, fleablood, The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G.
$endgroup$
– Ghost
Jan 28 at 19:45
$begingroup$
Sir/Madam, fleablood, The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G.
$endgroup$
– Ghost
Jan 28 at 19:45
$begingroup$
The two triangles has three similar angles which makes it similar triangle
$endgroup$
– Ghost
Jan 28 at 19:50
$begingroup$
The two triangles has three similar angles which makes it similar triangle
$endgroup$
– Ghost
Jan 28 at 19:50
$begingroup$
"The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G" Not if you extend $AB$ past $A$ and $AC$ past $A$ and they intersect $DE$ on the other side.
$endgroup$
– fleablood
Jan 28 at 19:54
$begingroup$
"The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G" Not if you extend $AB$ past $A$ and $AC$ past $A$ and they intersect $DE$ on the other side.
$endgroup$
– fleablood
Jan 28 at 19:54
|
show 2 more comments
1 Answer
1
active
oldest
votes
0
$begingroup$
Since $Delta ABCsimDelta AFG$, we obtain:
$$frac{S_{Delta AFG}}{S_{Delta ABC}}=left(frac{1}{2}right)^2,$$
which gives $$S_{Delta AFG}=4$$ and since
$$frac{S_{Delta AFC}}{S_{Delta AFG}}=frac{AC}{AG}=2,$$ we obtain $$S_{Delta AFC}=8.$$
Thus, $$4+8=S_{Delta CFG}=frac{4cdot DC}{2},$$
which gives $$DC=6$$ and $$S_{DEBC}=6cdot8=48.$$
answered Jan 28 at 20:16
Michael RozenbergMichael Rozenberg
109k1896201
$endgroup$
$begingroup$
I am sorry Sir but I can't understand what exactly did you mean by triangle "AFC" and Triangle "CFG" also DC. It isn't actually matching with my depiction. Also can you please describe?The first line with clarification of above problems?
$endgroup$
– Ghost
Jan 28 at 20:28
$begingroup$
Sir An image of your depiction will be very helpful to understand.
$endgroup$
– Ghost
Jan 28 at 20:32
$begingroup$
@Ghost $CD$ is an altitude to side $GF$ from $C$ of the $Delta CFG$. I don't know to draw in the net. I drew it by the given.
$endgroup$
– Michael Rozenberg
Jan 28 at 20:42
$begingroup$
$S_{Delta CFG}=S_{Delta AFG}+S_{Delta AFC}.$
$endgroup$
– Michael Rozenberg
Jan 28 at 20:48
$begingroup$
Sir please can you send me a photo of the papers that you've used to draw.It will really helpful.
$endgroup$
– Ghost
Jan 29 at 6:23
add a comment |
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0
$begingroup$
Since $Delta ABCsimDelta AFG$, we obtain:
$$frac{S_{Delta AFG}}{S_{Delta ABC}}=left(frac{1}{2}right)^2,$$
which gives $$S_{Delta AFG}=4$$ and since
$$frac{S_{Delta AFC}}{S_{Delta AFG}}=frac{AC}{AG}=2,$$ we obtain $$S_{Delta AFC}=8.$$
Thus, $$4+8=S_{Delta CFG}=frac{4cdot DC}{2},$$
which gives $$DC=6$$ and $$S_{DEBC}=6cdot8=48.$$
answered Jan 28 at 20:16
Michael RozenbergMichael Rozenberg
109k1896201
$endgroup$
$begingroup$
I am sorry Sir but I can't understand what exactly did you mean by triangle "AFC" and Triangle "CFG" also DC. It isn't actually matching with my depiction. Also can you please describe?The first line with clarification of above problems?
$endgroup$
– Ghost
Jan 28 at 20:28
$begingroup$
Sir An image of your depiction will be very helpful to understand.
$endgroup$
– Ghost
Jan 28 at 20:32
$begingroup$
@Ghost $CD$ is an altitude to side $GF$ from $C$ of the $Delta CFG$. I don't know to draw in the net. I drew it by the given.
$endgroup$
– Michael Rozenberg
Jan 28 at 20:42
$begingroup$
$S_{Delta CFG}=S_{Delta AFG}+S_{Delta AFC}.$
$endgroup$
– Michael Rozenberg
Jan 28 at 20:48
$begingroup$
Sir please can you send me a photo of the papers that you've used to draw.It will really helpful.
$endgroup$
– Ghost
Jan 29 at 6:23
add a comment |
0
$begingroup$
Since $Delta ABCsimDelta AFG$, we obtain:
$$frac{S_{Delta AFG}}{S_{Delta ABC}}=left(frac{1}{2}right)^2,$$
which gives $$S_{Delta AFG}=4$$ and since
$$frac{S_{Delta AFC}}{S_{Delta AFG}}=frac{AC}{AG}=2,$$ we obtain $$S_{Delta AFC}=8.$$
Thus, $$4+8=S_{Delta CFG}=frac{4cdot DC}{2},$$
which gives $$DC=6$$ and $$S_{DEBC}=6cdot8=48.$$
answered Jan 28 at 20:16
Michael RozenbergMichael Rozenberg
109k1896201
$endgroup$
$begingroup$
I am sorry Sir but I can't understand what exactly did you mean by triangle "AFC" and Triangle "CFG" also DC. It isn't actually matching with my depiction. Also can you please describe?The first line with clarification of above problems?
$endgroup$
– Ghost
Jan 28 at 20:28
$begingroup$
Sir An image of your depiction will be very helpful to understand.
$endgroup$
– Ghost
Jan 28 at 20:32
$begingroup$
@Ghost $CD$ is an altitude to side $GF$ from $C$ of the $Delta CFG$. I don't know to draw in the net. I drew it by the given.
$endgroup$
– Michael Rozenberg
Jan 28 at 20:42
$begingroup$
$S_{Delta CFG}=S_{Delta AFG}+S_{Delta AFC}.$
$endgroup$
– Michael Rozenberg
Jan 28 at 20:48
$begingroup$
Sir please can you send me a photo of the papers that you've used to draw.It will really helpful.
$endgroup$
– Ghost
Jan 29 at 6:23
add a comment |
0
0
0
$begingroup$
Since $Delta ABCsimDelta AFG$, we obtain:
$$frac{S_{Delta AFG}}{S_{Delta ABC}}=left(frac{1}{2}right)^2,$$
which gives $$S_{Delta AFG}=4$$ and since
$$frac{S_{Delta AFC}}{S_{Delta AFG}}=frac{AC}{AG}=2,$$ we obtain $$S_{Delta AFC}=8.$$
Thus, $$4+8=S_{Delta CFG}=frac{4cdot DC}{2},$$
which gives $$DC=6$$ and $$S_{DEBC}=6cdot8=48.$$
answered Jan 28 at 20:16
Michael RozenbergMichael Rozenberg
109k1896201
$endgroup$
Since $Delta ABCsimDelta AFG$, we obtain:
$$frac{S_{Delta AFG}}{S_{Delta ABC}}=left(frac{1}{2}right)^2,$$
which gives $$S_{Delta AFG}=4$$ and since
$$frac{S_{Delta AFC}}{S_{Delta AFG}}=frac{AC}{AG}=2,$$ we obtain $$S_{Delta AFC}=8.$$
Thus, $$4+8=S_{Delta CFG}=frac{4cdot DC}{2},$$
which gives $$DC=6$$ and $$S_{DEBC}=6cdot8=48.$$
answered Jan 28 at 20:16
Michael RozenbergMichael Rozenberg
109k1896201
answered Jan 28 at 20:16
Michael RozenbergMichael Rozenberg
109k1896201
answered Jan 28 at 20:16
Michael RozenbergMichael Rozenberg
109k1896201
answered Jan 28 at 20:16
Michael RozenbergMichael Rozenberg
109k1896201
109k1896201
$begingroup$
I am sorry Sir but I can't understand what exactly did you mean by triangle "AFC" and Triangle "CFG" also DC. It isn't actually matching with my depiction. Also can you please describe?The first line with clarification of above problems?
$endgroup$
– Ghost
Jan 28 at 20:28
$begingroup$
Sir An image of your depiction will be very helpful to understand.
$endgroup$
– Ghost
Jan 28 at 20:32
$begingroup$
@Ghost $CD$ is an altitude to side $GF$ from $C$ of the $Delta CFG$. I don't know to draw in the net. I drew it by the given.
$endgroup$
– Michael Rozenberg
Jan 28 at 20:42
$begingroup$
$S_{Delta CFG}=S_{Delta AFG}+S_{Delta AFC}.$
$endgroup$
– Michael Rozenberg
Jan 28 at 20:48
$begingroup$
Sir please can you send me a photo of the papers that you've used to draw.It will really helpful.
$endgroup$
– Ghost
Jan 29 at 6:23
add a comment |
$begingroup$
I am sorry Sir but I can't understand what exactly did you mean by triangle "AFC" and Triangle "CFG" also DC. It isn't actually matching with my depiction. Also can you please describe?The first line with clarification of above problems?
$endgroup$
– Ghost
Jan 28 at 20:28
$begingroup$
Sir An image of your depiction will be very helpful to understand.
$endgroup$
– Ghost
Jan 28 at 20:32
$begingroup$
@Ghost $CD$ is an altitude to side $GF$ from $C$ of the $Delta CFG$. I don't know to draw in the net. I drew it by the given.
$endgroup$
– Michael Rozenberg
Jan 28 at 20:42
$begingroup$
$S_{Delta CFG}=S_{Delta AFG}+S_{Delta AFC}.$
$endgroup$
– Michael Rozenberg
Jan 28 at 20:48
$begingroup$
Sir please can you send me a photo of the papers that you've used to draw.It will really helpful.
$endgroup$
– Ghost
Jan 29 at 6:23
$begingroup$
I am sorry Sir but I can't understand what exactly did you mean by triangle "AFC" and Triangle "CFG" also DC. It isn't actually matching with my depiction. Also can you please describe?The first line with clarification of above problems?
$endgroup$
– Ghost
Jan 28 at 20:28
$begingroup$
I am sorry Sir but I can't understand what exactly did you mean by triangle "AFC" and Triangle "CFG" also DC. It isn't actually matching with my depiction. Also can you please describe?The first line with clarification of above problems?
$endgroup$
– Ghost
Jan 28 at 20:28
$begingroup$
Sir An image of your depiction will be very helpful to understand.
$endgroup$
– Ghost
Jan 28 at 20:32
$begingroup$
Sir An image of your depiction will be very helpful to understand.
$endgroup$
– Ghost
Jan 28 at 20:32
$begingroup$
@Ghost $CD$ is an altitude to side $GF$ from $C$ of the $Delta CFG$. I don't know to draw in the net. I drew it by the given.
$endgroup$
– Michael Rozenberg
Jan 28 at 20:42
$begingroup$
@Ghost $CD$ is an altitude to side $GF$ from $C$ of the $Delta CFG$. I don't know to draw in the net. I drew it by the given.
$endgroup$
– Michael Rozenberg
Jan 28 at 20:42
$begingroup$
$S_{Delta CFG}=S_{Delta AFG}+S_{Delta AFC}.$
$endgroup$
– Michael Rozenberg
Jan 28 at 20:48
$begingroup$
$S_{Delta CFG}=S_{Delta AFG}+S_{Delta AFC}.$
$endgroup$
– Michael Rozenberg
Jan 28 at 20:48
$begingroup$
Sir please can you send me a photo of the papers that you've used to draw.It will really helpful.
$endgroup$
– Ghost
Jan 29 at 6:23
$begingroup$
Sir please can you send me a photo of the papers that you've used to draw.It will really helpful.
$endgroup$
– Ghost
Jan 29 at 6:23
add a comment |
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1
$begingroup$
Is A in the interior or exterior of the rectangle. What does a rectangle "having" a triangle mean?
$endgroup$
– fleablood
Jan 28 at 19:34
$begingroup$
If you can prove the triangles are symmetric then twice the perimeter means four times the area.
$endgroup$
– fleablood
Jan 28 at 19:42
$begingroup$
Sir/Madam, fleablood, The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G.
$endgroup$
– Ghost
Jan 28 at 19:45
$begingroup$
The two triangles has three similar angles which makes it similar triangle
$endgroup$
– Ghost
Jan 28 at 19:50
$begingroup$
"The A is actually gets outside of the rectangle if you draw AB and AC lines from points B and C which has to intersects side DE at point F and G" Not if you extend $AB$ past $A$ and $AC$ past $A$ and they intersect $DE$ on the other side.
$endgroup$
– fleablood
Jan 28 at 19:54