Generate random integers between 0 and 9

1067

How can I generate random integers between 0 and 9 (inclusive) in Python?

For example, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

edited Oct 18 '18 at 8:08

K48

5,62594096

asked Oct 22 '10 at 12:48

aneuryzm

21k87238448

add a comment |

1067

How can I generate random integers between 0 and 9 (inclusive) in Python?

For example, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

edited Oct 18 '18 at 8:08

K48

5,62594096

asked Oct 22 '10 at 12:48

aneuryzm

21k87238448

add a comment |

1067

133

How can I generate random integers between 0 and 9 (inclusive) in Python?

For example, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

edited Oct 18 '18 at 8:08

K48

5,62594096

asked Oct 22 '10 at 12:48

aneuryzm

21k87238448

How can I generate random integers between 0 and 9 (inclusive) in Python?

For example, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

python random integer

edited Oct 18 '18 at 8:08

K48

5,62594096

asked Oct 22 '10 at 12:48

aneuryzm

21k87238448

edited Oct 18 '18 at 8:08

K48

5,62594096

asked Oct 22 '10 at 12:48

aneuryzm

21k87238448

edited Oct 18 '18 at 8:08

K48

5,62594096

edited Oct 18 '18 at 8:08

K48

5,62594096

edited Oct 18 '18 at 8:08

K48

5,62594096

asked Oct 22 '10 at 12:48

aneuryzm

21k87238448

asked Oct 22 '10 at 12:48

aneuryzm

21k87238448

asked Oct 22 '10 at 12:48

aneuryzm

21k87238448

add a comment |

21 Answers
21

active

oldest

votes

1713

Try:

from random import randint

print(randint(0, 9))

More info: https://docs.python.org/3/library/random.html#random.randint

edited Jun 11 '17 at 21:38

A-B-B

23.9k66370

answered Oct 22 '10 at 12:51

kovshenin

21.7k43042

21

Just a note, these are pseudorandom numbers and they are not cryptographically secure. Do not use this in any case where you don't want an attacker to guess your numbers. Use the secrets module for better random numbers. Reference: docs.python.org/3/library/random.html

– K48
Oct 18 '18 at 8:08

add a comment |

311

import random

print(random.randint(0,9))

random.randint(a, b)

Return a random integer N such that a <= N <= b.

Docs: https://docs.python.org/3.1/library/random.html#random.randint

edited Jun 30 '15 at 14:51

FlipperPA

7,23622145

answered May 4 '13 at 17:13

JMSamudio

3,307178

add a comment |

101

Try this:

from random import randrange, uniform



# randrange gives you an integral value

irand = randrange(0, 10)



# uniform gives you a floating-point value

frand = uniform(0, 10)

edited Oct 22 '10 at 12:55

answered Oct 22 '10 at 12:49

Andrew Hare

279k54581602

add a comment |

from random import randint



x = [randint(0, 9) for p in range(0, 10)]

This generates 10 pseudorandom integers in range 0 to 9 inclusive.

edited May 17 '18 at 8:05

Community♦

answered Nov 26 '13 at 17:39

user14372

821711

3

10 or 9? I'm getting only 9.

– Sigur
May 11 '17 at 13:52

add a comment |

The secrets module is new in Python 3.6. This is better than the random module for cryptography or security uses.

To randomly print an integer in the inclusive range 0-9:

from secrets import randbelow

print(randbelow(10))

For details, see PEP 506.

edited Dec 6 '16 at 10:40

answered Dec 6 '16 at 10:29

Chris_Rands

17k54176

1

This would improve the answer and should be added. The more security minded answers should always be added if available.

– SudoKid
Feb 7 '18 at 17:15

add a comment |

Try this through random.shuffle

>>> import random

>>> nums = [x for x in range(10)]

>>> random.shuffle(nums)

>>> nums

[6, 3, 5, 4, 0, 1, 2, 9, 8, 7]

edited Dec 10 '15 at 17:57

Stophface

2,58273080

answered Oct 29 '15 at 9:13

zangw

24k795116

3

nums = range(10)

– Kamejoin
Dec 14 '17 at 20:10

add a comment |

Choose the size of the array (in this example, I have chosen the size to be 20). And then, use the following:

import numpy as np   

np.random.randint(10, size=(1, 20))

You can expect to see an output of the following form (different random integers will be returned each time you run it; hence you can expect the integers in the output array to differ from the example given below).

array([[1, 6, 1, 2, 8, 6, 3, 3, 2, 5, 6, 5, 0, 9, 5, 6, 4, 5, 9, 3]])

answered Feb 2 '17 at 6:35

Commoner

549820

2

It's also helpful to know how Numpy can generate a random array of specified size, not just a single random number. (Docs: numpy.random.randint)

– jkdev
Jun 25 '17 at 18:19

add a comment |

In case of continuous numbers randint or randrange are probably the best choices but if you have several distinct values in a sequence (i.e. a list) you could also use choice:

>>> import random

>>> values = list(range(10))

>>> random.choice(values)

5

choice also works for one item from a not-continuous sample:

>>> values = [1, 2, 3, 5, 7, 10]

>>> random.choice(values)

7

If you need it "cryptographically strong" there's also a secrets.choice in python 3.6 and newer:

>>> import secrets

>>> values = list(range(10))

>>> secrets.choice(values)

2

edited Sep 24 '17 at 10:33

answered Jun 3 '17 at 1:45

MSeifert

77.3k18148185

What if we want more numbers from the sequence?

– Gunjan naik
Oct 3 '17 at 13:43

If they should be without replacement: random.sample. With replacement you could use a comprehension with choice: for example for a list containing 3 random values with replacement: [choice(values) for _ in range(3)]

– MSeifert
Oct 3 '17 at 13:53

add a comment |

if you want to use numpy then use the following:

import numpy as np

print(np.random.randint(0,10))

edited Jun 3 '17 at 1:39

MSeifert

77.3k18148185

answered Jan 12 '17 at 3:12

sushmit

1,89711825

1

You could tell something about "numpy".

– Simón
Jan 20 '17 at 4:09

2

numpy.org

– sushmit
Jan 20 '17 at 5:57

9

Yeah. Thanks for the link. But I intended to mean that you could have improved your answer by providing details before just quoting two lines of code; like for what reason would someone prefer to use it instead of something already built in. Not that you're obliged to, anyway.

– Simón
Jan 20 '17 at 16:00

add a comment |

The original question implies generating multiple random integers.

How can I generate integers between 0 and 9 (inclusive) in Python?

Many responses however only show how to get one random number, e.g. random.randint and random.choice.

Multiple Random Integers

For clarity, you can still generate multiple random numbers using those techniques by simply iterating N times:

import random





N = 5



[random.randint(0, 9) for _ in range(N)]

# [9, 7, 0, 7, 3]



[random.choice(range(10)) for _ in range(N)]

# [8, 3, 6, 8, 7]

Sample of Random Integers

Some posts demonstrate how to natively generate multiple random integers.¹ Here are some options that address the implied question:

random.sample returns k unique selections from a population (without replacement):²

random.sample(range(10), k=N)

# [4, 5, 1, 2, 3]

In Python 3.6, random.choices returns k selections from a population (with replacement):

random.choices(range(10), k=N)

# [3, 2, 0, 8, 2]

See also this related post using numpy.random.choice.

_{¹Namely @John Lawrence Aspden, @S T Mohammed, @SiddTheKid, @user14372, @zangw, et al.}

_{²@prashanth mentions this module showing one integer.}

edited Nov 16 '17 at 4:37

answered Sep 22 '17 at 4:29

pylang

14.1k24458

add a comment |

>>> import random

>>> random.randrange(10)

3

>>> random.randrange(10)

1

To get a list of ten samples:

>>> [random.randrange(10) for x in range(10)]

[9, 0, 4, 0, 5, 7, 4, 3, 6, 8]

answered Aug 10 '17 at 15:48

John Lawrence Aspden

11.1k105190

add a comment |

random.sample is another that can be used

import random

n = 1 # specify the no. of numbers

num = random.sample(range(10),  n)

num[0] # is the required number

answered May 14 '17 at 16:46

prashanth

1,7061227

add a comment |

Generating random integers between 0 and 9.

import numpy

X = numpy.random.randint(0, 10, size=10)

print(X)

Output:

[4 8 0 4 9 6 9 9 0 7]

edited Jul 6 '18 at 14:11

answered Jul 6 '18 at 6:25

Ashok Kumar Jayaraman

1,09711119

1

If you're using NumPy, you should use NumPy's random functionalities to generate this list, for example with numpy.random.randint(0, 10, size=10). The method you show is needlessly inefficient.

– Mark Dickinson
Jul 6 '18 at 6:44

add a comment |

Best way is to use import Random function

import random

print(random.sample(range(10), 10))

or without any library import:

n={} 

for i in range(10):

    n[i]=i



for p in range(10):

    print(n.popitem()[1])

here the popitems removes and returns an arbitrary value from the dictionary n.

edited Jun 3 '17 at 1:41

MSeifert

77.3k18148185

answered May 15 '17 at 18:29

S T Mohammed

80126

add a comment |

You can try this:

import numpy as np

print ( np.random.uniform(low=0, high=10, size=(15,)) ).astype(int)



>>> [8 3 6 9 1 0 3 6 3 3 1 2 4 0 4]

Notes:

1.> np.random.uniform generates uniformly distributed numbers over the half-open interval [low, high).

2.> astype(int) casts the numpy array to int data type.

3.> I have chosen size = (15,). This will give you a numpy array of length = 15.

More information on numpy.random.uniform

More information on numpy.ndarray.astype

edited Dec 25 '18 at 23:14

answered Nov 28 '18 at 7:56

Siddharth Satpathy

5841717

add a comment |

I used variable to control the range

from random import randint 

numberStartRange = 1

numberEndRange = 9

randomNumber = randint(numberStartRange, numberEndRange)

print(randomNumber)

I used the print function to see the results. You can comment is out if you do not need this.

edited Oct 24 '17 at 21:12

answered Sep 19 '17 at 11:30

Amir Md Amiruzzaman

1,0931718

add a comment |

This is more of a mathematical approach but it works 100% of the time:

Let's say you want to use random.random() function to generate a number between a and b. To achieve this, just do the following:

num = (b-a)*random.random() + a;

Of course, you can generate more numbers.

answered Nov 30 '18 at 18:27

Orestis Zekai

508

add a comment |

For the example that you have given (a random integer between 0 and 9), the cleanest solution is:

from random import randrange



randrange(10)

edited Jan 2 at 2:08

answered Oct 8 '18 at 14:38

Utku

884929

randrange returns a single number between specified range.

– Shital Shah
Jan 2 at 1:43

@ShitalShah That is exactly what the question wants. Run the accepted answer and realize that it does the same thing.

– Utku
Jan 2 at 2:06

@ShitalShah If you want all numbers between 0 and 9, you use range(10).

– Utku
Jan 2 at 2:07

add a comment |

Try This,

import numpy as np



X = np.random.randint(0, 99, size=1000) # 1k random integer

answered Dec 19 '18 at 10:38

Rakesh Chaudhari

1,06711420

add a comment |

From the documentation page for the random module:

Warning: The pseudo-random generators of this module should not be
used for security purposes. Use os.urandom() or SystemRandom if you
require a cryptographically secure pseudo-random number generator.

random.SystemRandom, which was introduced in Python 2.4, is considered cryptographically secure. It is still available in Python 3.7.1 which is current at time of writing.

>>> import string

>>> string.digits

'0123456789'

>>> import random

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'1'

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'5'

Instead of string.digits, range could be used per some of the other answers along perhaps with a comprehension. Mix and match according to your needs.

edited Feb 7 at 16:49

answered Dec 11 '18 at 22:49

Richard Riehle

1036

add a comment |

-1

I had better luck with this for Python 3.6

str_Key = ""                                                                                                

str_RandomKey = ""                                                                                          

for int_I in range(128):                                                                                    

      str_Key = random.choice('0123456789')

      str_RandomKey = str_RandomKey + str_Key

Just add characters like 'ABCD' and 'abcd' or '^!~=-><' to alter the character pool to pull from, change the range to alter the number of characters generated.

answered Jul 20 '17 at 23:43

M T Head

511411

add a comment |

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21 Answers
21

active

oldest

votes

21 Answers
21

active

oldest

votes

1713

Try:

from random import randint

print(randint(0, 9))

More info: https://docs.python.org/3/library/random.html#random.randint

edited Jun 11 '17 at 21:38

A-B-B

23.9k66370

answered Oct 22 '10 at 12:51

kovshenin

21.7k43042

21

Just a note, these are pseudorandom numbers and they are not cryptographically secure. Do not use this in any case where you don't want an attacker to guess your numbers. Use the secrets module for better random numbers. Reference: docs.python.org/3/library/random.html

– K48
Oct 18 '18 at 8:08

add a comment |

1713

Try:

from random import randint

print(randint(0, 9))

More info: https://docs.python.org/3/library/random.html#random.randint

edited Jun 11 '17 at 21:38

A-B-B

23.9k66370

answered Oct 22 '10 at 12:51

kovshenin

21.7k43042

21

Just a note, these are pseudorandom numbers and they are not cryptographically secure. Do not use this in any case where you don't want an attacker to guess your numbers. Use the secrets module for better random numbers. Reference: docs.python.org/3/library/random.html

– K48
Oct 18 '18 at 8:08

add a comment |

1713

Try:

from random import randint

print(randint(0, 9))

More info: https://docs.python.org/3/library/random.html#random.randint

edited Jun 11 '17 at 21:38

A-B-B

23.9k66370

answered Oct 22 '10 at 12:51

kovshenin

21.7k43042

Try:

from random import randint

print(randint(0, 9))

More info: https://docs.python.org/3/library/random.html#random.randint

edited Jun 11 '17 at 21:38

A-B-B

23.9k66370

answered Oct 22 '10 at 12:51

kovshenin

21.7k43042

edited Jun 11 '17 at 21:38

A-B-B

23.9k66370

edited Jun 11 '17 at 21:38

A-B-B

23.9k66370

edited Jun 11 '17 at 21:38

A-B-B

23.9k66370

answered Oct 22 '10 at 12:51

kovshenin

21.7k43042

answered Oct 22 '10 at 12:51

kovshenin

21.7k43042

answered Oct 22 '10 at 12:51

kovshenin

21.7k43042

21

Just a note, these are pseudorandom numbers and they are not cryptographically secure. Do not use this in any case where you don't want an attacker to guess your numbers. Use the secrets module for better random numbers. Reference: docs.python.org/3/library/random.html

– K48
Oct 18 '18 at 8:08

add a comment |

21

Just a note, these are pseudorandom numbers and they are not cryptographically secure. Do not use this in any case where you don't want an attacker to guess your numbers. Use the secrets module for better random numbers. Reference: docs.python.org/3/library/random.html

– K48
Oct 18 '18 at 8:08

Just a note, these are pseudorandom numbers and they are not cryptographically secure. Do not use this in any case where you don't want an attacker to guess your numbers. Use the secrets module for better random numbers. Reference: docs.python.org/3/library/random.html

– K48
Oct 18 '18 at 8:08

add a comment |

311

import random

print(random.randint(0,9))

random.randint(a, b)

Return a random integer N such that a <= N <= b.

Docs: https://docs.python.org/3.1/library/random.html#random.randint

edited Jun 30 '15 at 14:51

FlipperPA

7,23622145

answered May 4 '13 at 17:13

JMSamudio

3,307178

add a comment |

311

import random

print(random.randint(0,9))

random.randint(a, b)

Return a random integer N such that a <= N <= b.

Docs: https://docs.python.org/3.1/library/random.html#random.randint

edited Jun 30 '15 at 14:51

FlipperPA

7,23622145

answered May 4 '13 at 17:13

JMSamudio

3,307178

add a comment |

311

import random

print(random.randint(0,9))

random.randint(a, b)

Return a random integer N such that a <= N <= b.

Docs: https://docs.python.org/3.1/library/random.html#random.randint

edited Jun 30 '15 at 14:51

FlipperPA

7,23622145

answered May 4 '13 at 17:13

JMSamudio

3,307178

import random

print(random.randint(0,9))

random.randint(a, b)

Return a random integer N such that a <= N <= b.

Docs: https://docs.python.org/3.1/library/random.html#random.randint

edited Jun 30 '15 at 14:51

FlipperPA

7,23622145

answered May 4 '13 at 17:13

JMSamudio

3,307178

edited Jun 30 '15 at 14:51

FlipperPA

7,23622145

edited Jun 30 '15 at 14:51

FlipperPA

7,23622145

edited Jun 30 '15 at 14:51

FlipperPA

7,23622145

answered May 4 '13 at 17:13

JMSamudio

3,307178

answered May 4 '13 at 17:13

JMSamudio

3,307178

answered May 4 '13 at 17:13

JMSamudio

3,307178

add a comment |

101

Try this:

from random import randrange, uniform



# randrange gives you an integral value

irand = randrange(0, 10)



# uniform gives you a floating-point value

frand = uniform(0, 10)

edited Oct 22 '10 at 12:55

answered Oct 22 '10 at 12:49

Andrew Hare

279k54581602

add a comment |

101

Try this:

from random import randrange, uniform



# randrange gives you an integral value

irand = randrange(0, 10)



# uniform gives you a floating-point value

frand = uniform(0, 10)

edited Oct 22 '10 at 12:55

answered Oct 22 '10 at 12:49

Andrew Hare

279k54581602

add a comment |

101

Try this:

from random import randrange, uniform



# randrange gives you an integral value

irand = randrange(0, 10)



# uniform gives you a floating-point value

frand = uniform(0, 10)

edited Oct 22 '10 at 12:55

answered Oct 22 '10 at 12:49

Andrew Hare

279k54581602

Try this:

from random import randrange, uniform



# randrange gives you an integral value

irand = randrange(0, 10)



# uniform gives you a floating-point value

frand = uniform(0, 10)

edited Oct 22 '10 at 12:55

answered Oct 22 '10 at 12:49

Andrew Hare

279k54581602

edited Oct 22 '10 at 12:55

answered Oct 22 '10 at 12:49

Andrew Hare

279k54581602

answered Oct 22 '10 at 12:49

Andrew Hare

279k54581602

answered Oct 22 '10 at 12:49

Andrew Hare

279k54581602

add a comment |

from random import randint



x = [randint(0, 9) for p in range(0, 10)]

This generates 10 pseudorandom integers in range 0 to 9 inclusive.

edited May 17 '18 at 8:05

Community♦

answered Nov 26 '13 at 17:39

user14372

821711

3

10 or 9? I'm getting only 9.

– Sigur
May 11 '17 at 13:52

add a comment |

from random import randint



x = [randint(0, 9) for p in range(0, 10)]

This generates 10 pseudorandom integers in range 0 to 9 inclusive.

edited May 17 '18 at 8:05

Community♦

answered Nov 26 '13 at 17:39

user14372

821711

3

10 or 9? I'm getting only 9.

– Sigur
May 11 '17 at 13:52

add a comment |

from random import randint



x = [randint(0, 9) for p in range(0, 10)]

This generates 10 pseudorandom integers in range 0 to 9 inclusive.

edited May 17 '18 at 8:05

Community♦

answered Nov 26 '13 at 17:39

user14372

821711

from random import randint



x = [randint(0, 9) for p in range(0, 10)]

This generates 10 pseudorandom integers in range 0 to 9 inclusive.

edited May 17 '18 at 8:05

Community♦

answered Nov 26 '13 at 17:39

user14372

821711

edited May 17 '18 at 8:05

Community♦

edited May 17 '18 at 8:05

Community♦

edited May 17 '18 at 8:05

Community♦

answered Nov 26 '13 at 17:39

user14372

821711

answered Nov 26 '13 at 17:39

user14372

821711

answered Nov 26 '13 at 17:39

user14372

821711

3

10 or 9? I'm getting only 9.

– Sigur
May 11 '17 at 13:52

add a comment |

3

10 or 9? I'm getting only 9.

– Sigur
May 11 '17 at 13:52

10 or 9? I'm getting only 9.

– Sigur
May 11 '17 at 13:52

add a comment |

The secrets module is new in Python 3.6. This is better than the random module for cryptography or security uses.

To randomly print an integer in the inclusive range 0-9:

from secrets import randbelow

print(randbelow(10))

For details, see PEP 506.

edited Dec 6 '16 at 10:40

answered Dec 6 '16 at 10:29

Chris_Rands

17k54176

1

This would improve the answer and should be added. The more security minded answers should always be added if available.

– SudoKid
Feb 7 '18 at 17:15

add a comment |

The secrets module is new in Python 3.6. This is better than the random module for cryptography or security uses.

To randomly print an integer in the inclusive range 0-9:

from secrets import randbelow

print(randbelow(10))

For details, see PEP 506.

edited Dec 6 '16 at 10:40

answered Dec 6 '16 at 10:29

Chris_Rands

17k54176

1

This would improve the answer and should be added. The more security minded answers should always be added if available.

– SudoKid
Feb 7 '18 at 17:15

add a comment |

The secrets module is new in Python 3.6. This is better than the random module for cryptography or security uses.

To randomly print an integer in the inclusive range 0-9:

from secrets import randbelow

print(randbelow(10))

For details, see PEP 506.

edited Dec 6 '16 at 10:40

answered Dec 6 '16 at 10:29

Chris_Rands

17k54176

The secrets module is new in Python 3.6. This is better than the random module for cryptography or security uses.

To randomly print an integer in the inclusive range 0-9:

from secrets import randbelow

print(randbelow(10))

For details, see PEP 506.

edited Dec 6 '16 at 10:40

answered Dec 6 '16 at 10:29

Chris_Rands

17k54176

edited Dec 6 '16 at 10:40

answered Dec 6 '16 at 10:29

Chris_Rands

17k54176

answered Dec 6 '16 at 10:29

Chris_Rands

17k54176

answered Dec 6 '16 at 10:29

Chris_Rands

17k54176

1

This would improve the answer and should be added. The more security minded answers should always be added if available.

– SudoKid
Feb 7 '18 at 17:15

add a comment |

1

This would improve the answer and should be added. The more security minded answers should always be added if available.

– SudoKid
Feb 7 '18 at 17:15

This would improve the answer and should be added. The more security minded answers should always be added if available.

– SudoKid
Feb 7 '18 at 17:15

add a comment |

Try this through random.shuffle

>>> import random

>>> nums = [x for x in range(10)]

>>> random.shuffle(nums)

>>> nums

[6, 3, 5, 4, 0, 1, 2, 9, 8, 7]

edited Dec 10 '15 at 17:57

Stophface

2,58273080

answered Oct 29 '15 at 9:13

zangw

24k795116

3

nums = range(10)

– Kamejoin
Dec 14 '17 at 20:10

add a comment |

Try this through random.shuffle

>>> import random

>>> nums = [x for x in range(10)]

>>> random.shuffle(nums)

>>> nums

[6, 3, 5, 4, 0, 1, 2, 9, 8, 7]

edited Dec 10 '15 at 17:57

Stophface

2,58273080

answered Oct 29 '15 at 9:13

zangw

24k795116

3

nums = range(10)

– Kamejoin
Dec 14 '17 at 20:10

add a comment |

Try this through random.shuffle

>>> import random

>>> nums = [x for x in range(10)]

>>> random.shuffle(nums)

>>> nums

[6, 3, 5, 4, 0, 1, 2, 9, 8, 7]

edited Dec 10 '15 at 17:57

Stophface

2,58273080

answered Oct 29 '15 at 9:13

zangw

24k795116

Try this through random.shuffle

>>> import random

>>> nums = [x for x in range(10)]

>>> random.shuffle(nums)

>>> nums

[6, 3, 5, 4, 0, 1, 2, 9, 8, 7]

edited Dec 10 '15 at 17:57

Stophface

2,58273080

answered Oct 29 '15 at 9:13

zangw

24k795116

edited Dec 10 '15 at 17:57

Stophface

2,58273080

edited Dec 10 '15 at 17:57

Stophface

2,58273080

edited Dec 10 '15 at 17:57

Stophface

2,58273080

answered Oct 29 '15 at 9:13

zangw

24k795116

answered Oct 29 '15 at 9:13

zangw

24k795116

answered Oct 29 '15 at 9:13

zangw

24k795116

3

nums = range(10)

– Kamejoin
Dec 14 '17 at 20:10

add a comment |

3

nums = range(10)

– Kamejoin
Dec 14 '17 at 20:10

nums = range(10)

– Kamejoin
Dec 14 '17 at 20:10

add a comment |

Choose the size of the array (in this example, I have chosen the size to be 20). And then, use the following:

import numpy as np   

np.random.randint(10, size=(1, 20))

array([[1, 6, 1, 2, 8, 6, 3, 3, 2, 5, 6, 5, 0, 9, 5, 6, 4, 5, 9, 3]])

answered Feb 2 '17 at 6:35

Commoner

549820

2

It's also helpful to know how Numpy can generate a random array of specified size, not just a single random number. (Docs: numpy.random.randint)

– jkdev
Jun 25 '17 at 18:19

add a comment |

Choose the size of the array (in this example, I have chosen the size to be 20). And then, use the following:

import numpy as np   

np.random.randint(10, size=(1, 20))

array([[1, 6, 1, 2, 8, 6, 3, 3, 2, 5, 6, 5, 0, 9, 5, 6, 4, 5, 9, 3]])

answered Feb 2 '17 at 6:35

Commoner

549820

2

It's also helpful to know how Numpy can generate a random array of specified size, not just a single random number. (Docs: numpy.random.randint)

– jkdev
Jun 25 '17 at 18:19

add a comment |

Choose the size of the array (in this example, I have chosen the size to be 20). And then, use the following:

import numpy as np   

np.random.randint(10, size=(1, 20))

array([[1, 6, 1, 2, 8, 6, 3, 3, 2, 5, 6, 5, 0, 9, 5, 6, 4, 5, 9, 3]])

answered Feb 2 '17 at 6:35

Commoner

549820

Choose the size of the array (in this example, I have chosen the size to be 20). And then, use the following:

import numpy as np   

np.random.randint(10, size=(1, 20))

array([[1, 6, 1, 2, 8, 6, 3, 3, 2, 5, 6, 5, 0, 9, 5, 6, 4, 5, 9, 3]])

answered Feb 2 '17 at 6:35

Commoner

549820

answered Feb 2 '17 at 6:35

Commoner

549820

answered Feb 2 '17 at 6:35

Commoner

549820

answered Feb 2 '17 at 6:35

Commoner

549820

2

It's also helpful to know how Numpy can generate a random array of specified size, not just a single random number. (Docs: numpy.random.randint)

– jkdev
Jun 25 '17 at 18:19

add a comment |

2

It's also helpful to know how Numpy can generate a random array of specified size, not just a single random number. (Docs: numpy.random.randint)

– jkdev
Jun 25 '17 at 18:19

It's also helpful to know how Numpy can generate a random array of specified size, not just a single random number. (Docs: numpy.random.randint)

– jkdev
Jun 25 '17 at 18:19

add a comment |

In case of continuous numbers randint or randrange are probably the best choices but if you have several distinct values in a sequence (i.e. a list) you could also use choice:

>>> import random

>>> values = list(range(10))

>>> random.choice(values)

5

choice also works for one item from a not-continuous sample:

>>> values = [1, 2, 3, 5, 7, 10]

>>> random.choice(values)

7

If you need it "cryptographically strong" there's also a secrets.choice in python 3.6 and newer:

>>> import secrets

>>> values = list(range(10))

>>> secrets.choice(values)

2

edited Sep 24 '17 at 10:33

answered Jun 3 '17 at 1:45

MSeifert

77.3k18148185

What if we want more numbers from the sequence?

– Gunjan naik
Oct 3 '17 at 13:43

If they should be without replacement: random.sample. With replacement you could use a comprehension with choice: for example for a list containing 3 random values with replacement: [choice(values) for _ in range(3)]

– MSeifert
Oct 3 '17 at 13:53

add a comment |

In case of continuous numbers randint or randrange are probably the best choices but if you have several distinct values in a sequence (i.e. a list) you could also use choice:

>>> import random

>>> values = list(range(10))

>>> random.choice(values)

5

choice also works for one item from a not-continuous sample:

>>> values = [1, 2, 3, 5, 7, 10]

>>> random.choice(values)

7

If you need it "cryptographically strong" there's also a secrets.choice in python 3.6 and newer:

>>> import secrets

>>> values = list(range(10))

>>> secrets.choice(values)

2

edited Sep 24 '17 at 10:33

answered Jun 3 '17 at 1:45

MSeifert

77.3k18148185

What if we want more numbers from the sequence?

– Gunjan naik
Oct 3 '17 at 13:43

If they should be without replacement: random.sample. With replacement you could use a comprehension with choice: for example for a list containing 3 random values with replacement: [choice(values) for _ in range(3)]

– MSeifert
Oct 3 '17 at 13:53

add a comment |

In case of continuous numbers randint or randrange are probably the best choices but if you have several distinct values in a sequence (i.e. a list) you could also use choice:

>>> import random

>>> values = list(range(10))

>>> random.choice(values)

5

choice also works for one item from a not-continuous sample:

>>> values = [1, 2, 3, 5, 7, 10]

>>> random.choice(values)

7

If you need it "cryptographically strong" there's also a secrets.choice in python 3.6 and newer:

>>> import secrets

>>> values = list(range(10))

>>> secrets.choice(values)

2

edited Sep 24 '17 at 10:33

answered Jun 3 '17 at 1:45

MSeifert

77.3k18148185

In case of continuous numbers randint or randrange are probably the best choices but if you have several distinct values in a sequence (i.e. a list) you could also use choice:

>>> import random

>>> values = list(range(10))

>>> random.choice(values)

5

choice also works for one item from a not-continuous sample:

>>> values = [1, 2, 3, 5, 7, 10]

>>> random.choice(values)

7

If you need it "cryptographically strong" there's also a secrets.choice in python 3.6 and newer:

>>> import secrets

>>> values = list(range(10))

>>> secrets.choice(values)

2

edited Sep 24 '17 at 10:33

answered Jun 3 '17 at 1:45

MSeifert

77.3k18148185

edited Sep 24 '17 at 10:33

answered Jun 3 '17 at 1:45

MSeifert

77.3k18148185

answered Jun 3 '17 at 1:45

MSeifert

77.3k18148185

answered Jun 3 '17 at 1:45

MSeifert

77.3k18148185

What if we want more numbers from the sequence?

– Gunjan naik
Oct 3 '17 at 13:43

If they should be without replacement: random.sample. With replacement you could use a comprehension with choice: for example for a list containing 3 random values with replacement: [choice(values) for _ in range(3)]

– MSeifert
Oct 3 '17 at 13:53

add a comment |

What if we want more numbers from the sequence?

– Gunjan naik
Oct 3 '17 at 13:43

If they should be without replacement: random.sample. With replacement you could use a comprehension with choice: for example for a list containing 3 random values with replacement: [choice(values) for _ in range(3)]

– MSeifert
Oct 3 '17 at 13:53

What if we want more numbers from the sequence?

– Gunjan naik
Oct 3 '17 at 13:43

If they should be without replacement: random.sample. With replacement you could use a comprehension with choice: for example for a list containing 3 random values with replacement: [choice(values) for _ in range(3)]

– MSeifert
Oct 3 '17 at 13:53

add a comment |

if you want to use numpy then use the following:

import numpy as np

print(np.random.randint(0,10))

edited Jun 3 '17 at 1:39

MSeifert

77.3k18148185

answered Jan 12 '17 at 3:12

sushmit

1,89711825

1

You could tell something about "numpy".

– Simón
Jan 20 '17 at 4:09

2

numpy.org

– sushmit
Jan 20 '17 at 5:57

9

Yeah. Thanks for the link. But I intended to mean that you could have improved your answer by providing details before just quoting two lines of code; like for what reason would someone prefer to use it instead of something already built in. Not that you're obliged to, anyway.

– Simón
Jan 20 '17 at 16:00

add a comment |

if you want to use numpy then use the following:

import numpy as np

print(np.random.randint(0,10))

edited Jun 3 '17 at 1:39

MSeifert

77.3k18148185

answered Jan 12 '17 at 3:12

sushmit

1,89711825

1

You could tell something about "numpy".

– Simón
Jan 20 '17 at 4:09

2

numpy.org

– sushmit
Jan 20 '17 at 5:57

9

Yeah. Thanks for the link. But I intended to mean that you could have improved your answer by providing details before just quoting two lines of code; like for what reason would someone prefer to use it instead of something already built in. Not that you're obliged to, anyway.

– Simón
Jan 20 '17 at 16:00

add a comment |

if you want to use numpy then use the following:

import numpy as np

print(np.random.randint(0,10))

edited Jun 3 '17 at 1:39

MSeifert

77.3k18148185

answered Jan 12 '17 at 3:12

sushmit

1,89711825

if you want to use numpy then use the following:

import numpy as np

print(np.random.randint(0,10))

edited Jun 3 '17 at 1:39

MSeifert

77.3k18148185

answered Jan 12 '17 at 3:12

sushmit

1,89711825

edited Jun 3 '17 at 1:39

MSeifert

77.3k18148185

edited Jun 3 '17 at 1:39

MSeifert

77.3k18148185

edited Jun 3 '17 at 1:39

MSeifert

77.3k18148185

answered Jan 12 '17 at 3:12

sushmit

1,89711825

answered Jan 12 '17 at 3:12

sushmit

1,89711825

answered Jan 12 '17 at 3:12

sushmit

1,89711825

1

You could tell something about "numpy".

– Simón
Jan 20 '17 at 4:09

2

numpy.org

– sushmit
Jan 20 '17 at 5:57

9

Yeah. Thanks for the link. But I intended to mean that you could have improved your answer by providing details before just quoting two lines of code; like for what reason would someone prefer to use it instead of something already built in. Not that you're obliged to, anyway.

– Simón
Jan 20 '17 at 16:00

add a comment |

1

You could tell something about "numpy".

– Simón
Jan 20 '17 at 4:09

2

numpy.org

– sushmit
Jan 20 '17 at 5:57

9

Yeah. Thanks for the link. But I intended to mean that you could have improved your answer by providing details before just quoting two lines of code; like for what reason would someone prefer to use it instead of something already built in. Not that you're obliged to, anyway.

– Simón
Jan 20 '17 at 16:00

You could tell something about "numpy".

– Simón
Jan 20 '17 at 4:09

numpy.org

– sushmit
Jan 20 '17 at 5:57

Yeah. Thanks for the link. But I intended to mean that you could have improved your answer by providing details before just quoting two lines of code; like for what reason would someone prefer to use it instead of something already built in. Not that you're obliged to, anyway.

– Simón
Jan 20 '17 at 16:00

add a comment |

The original question implies generating multiple random integers.

How can I generate integers between 0 and 9 (inclusive) in Python?

Many responses however only show how to get one random number, e.g. random.randint and random.choice.

Multiple Random Integers

For clarity, you can still generate multiple random numbers using those techniques by simply iterating N times:

import random





N = 5



[random.randint(0, 9) for _ in range(N)]

# [9, 7, 0, 7, 3]



[random.choice(range(10)) for _ in range(N)]

# [8, 3, 6, 8, 7]

Sample of Random Integers

Some posts demonstrate how to natively generate multiple random integers.¹ Here are some options that address the implied question:

random.sample returns k unique selections from a population (without replacement):²

random.sample(range(10), k=N)

# [4, 5, 1, 2, 3]

In Python 3.6, random.choices returns k selections from a population (with replacement):

random.choices(range(10), k=N)

# [3, 2, 0, 8, 2]

See also this related post using numpy.random.choice.

_{¹Namely @John Lawrence Aspden, @S T Mohammed, @SiddTheKid, @user14372, @zangw, et al.}

_{²@prashanth mentions this module showing one integer.}

edited Nov 16 '17 at 4:37

answered Sep 22 '17 at 4:29

pylang

14.1k24458

add a comment |

The original question implies generating multiple random integers.

How can I generate integers between 0 and 9 (inclusive) in Python?

Many responses however only show how to get one random number, e.g. random.randint and random.choice.

Multiple Random Integers

For clarity, you can still generate multiple random numbers using those techniques by simply iterating N times:

import random





N = 5



[random.randint(0, 9) for _ in range(N)]

# [9, 7, 0, 7, 3]



[random.choice(range(10)) for _ in range(N)]

# [8, 3, 6, 8, 7]

Sample of Random Integers

Some posts demonstrate how to natively generate multiple random integers.¹ Here are some options that address the implied question:

random.sample returns k unique selections from a population (without replacement):²

random.sample(range(10), k=N)

# [4, 5, 1, 2, 3]

In Python 3.6, random.choices returns k selections from a population (with replacement):

random.choices(range(10), k=N)

# [3, 2, 0, 8, 2]

See also this related post using numpy.random.choice.

_{¹Namely @John Lawrence Aspden, @S T Mohammed, @SiddTheKid, @user14372, @zangw, et al.}

_{²@prashanth mentions this module showing one integer.}

edited Nov 16 '17 at 4:37

answered Sep 22 '17 at 4:29

pylang

14.1k24458

add a comment |

The original question implies generating multiple random integers.

How can I generate integers between 0 and 9 (inclusive) in Python?

Many responses however only show how to get one random number, e.g. random.randint and random.choice.

Multiple Random Integers

For clarity, you can still generate multiple random numbers using those techniques by simply iterating N times:

import random





N = 5



[random.randint(0, 9) for _ in range(N)]

# [9, 7, 0, 7, 3]



[random.choice(range(10)) for _ in range(N)]

# [8, 3, 6, 8, 7]

Sample of Random Integers

Some posts demonstrate how to natively generate multiple random integers.¹ Here are some options that address the implied question:

random.sample returns k unique selections from a population (without replacement):²

random.sample(range(10), k=N)

# [4, 5, 1, 2, 3]

In Python 3.6, random.choices returns k selections from a population (with replacement):

random.choices(range(10), k=N)

# [3, 2, 0, 8, 2]

See also this related post using numpy.random.choice.

_{¹Namely @John Lawrence Aspden, @S T Mohammed, @SiddTheKid, @user14372, @zangw, et al.}

_{²@prashanth mentions this module showing one integer.}

edited Nov 16 '17 at 4:37

answered Sep 22 '17 at 4:29

pylang

14.1k24458

The original question implies generating multiple random integers.

How can I generate integers between 0 and 9 (inclusive) in Python?

Many responses however only show how to get one random number, e.g. random.randint and random.choice.

Multiple Random Integers

For clarity, you can still generate multiple random numbers using those techniques by simply iterating N times:

import random





N = 5



[random.randint(0, 9) for _ in range(N)]

# [9, 7, 0, 7, 3]



[random.choice(range(10)) for _ in range(N)]

# [8, 3, 6, 8, 7]

Sample of Random Integers

Some posts demonstrate how to natively generate multiple random integers.¹ Here are some options that address the implied question:

random.sample returns k unique selections from a population (without replacement):²

random.sample(range(10), k=N)

# [4, 5, 1, 2, 3]

In Python 3.6, random.choices returns k selections from a population (with replacement):

random.choices(range(10), k=N)

# [3, 2, 0, 8, 2]

See also this related post using numpy.random.choice.

_{¹Namely @John Lawrence Aspden, @S T Mohammed, @SiddTheKid, @user14372, @zangw, et al.}

_{²@prashanth mentions this module showing one integer.}

edited Nov 16 '17 at 4:37

answered Sep 22 '17 at 4:29

pylang

14.1k24458

edited Nov 16 '17 at 4:37

answered Sep 22 '17 at 4:29

pylang

14.1k24458

answered Sep 22 '17 at 4:29

pylang

14.1k24458

answered Sep 22 '17 at 4:29

pylang

14.1k24458

add a comment |

>>> import random

>>> random.randrange(10)

3

>>> random.randrange(10)

1

To get a list of ten samples:

>>> [random.randrange(10) for x in range(10)]

[9, 0, 4, 0, 5, 7, 4, 3, 6, 8]

answered Aug 10 '17 at 15:48

John Lawrence Aspden

11.1k105190

add a comment |

>>> import random

>>> random.randrange(10)

3

>>> random.randrange(10)

1

To get a list of ten samples:

>>> [random.randrange(10) for x in range(10)]

[9, 0, 4, 0, 5, 7, 4, 3, 6, 8]

answered Aug 10 '17 at 15:48

John Lawrence Aspden

11.1k105190

add a comment |

>>> import random

>>> random.randrange(10)

3

>>> random.randrange(10)

1

To get a list of ten samples:

>>> [random.randrange(10) for x in range(10)]

[9, 0, 4, 0, 5, 7, 4, 3, 6, 8]

answered Aug 10 '17 at 15:48

John Lawrence Aspden

11.1k105190

>>> import random

>>> random.randrange(10)

3

>>> random.randrange(10)

1

To get a list of ten samples:

>>> [random.randrange(10) for x in range(10)]

[9, 0, 4, 0, 5, 7, 4, 3, 6, 8]

answered Aug 10 '17 at 15:48

John Lawrence Aspden

11.1k105190

answered Aug 10 '17 at 15:48

John Lawrence Aspden

11.1k105190

answered Aug 10 '17 at 15:48

John Lawrence Aspden

11.1k105190

answered Aug 10 '17 at 15:48

John Lawrence Aspden

11.1k105190

add a comment |

random.sample is another that can be used

import random

n = 1 # specify the no. of numbers

num = random.sample(range(10),  n)

num[0] # is the required number

answered May 14 '17 at 16:46

prashanth

1,7061227

add a comment |

random.sample is another that can be used

import random

n = 1 # specify the no. of numbers

num = random.sample(range(10),  n)

num[0] # is the required number

answered May 14 '17 at 16:46

prashanth

1,7061227

add a comment |

random.sample is another that can be used

import random

n = 1 # specify the no. of numbers

num = random.sample(range(10),  n)

num[0] # is the required number

answered May 14 '17 at 16:46

prashanth

1,7061227

random.sample is another that can be used

import random

n = 1 # specify the no. of numbers

num = random.sample(range(10),  n)

num[0] # is the required number

answered May 14 '17 at 16:46

prashanth

1,7061227

answered May 14 '17 at 16:46

prashanth

1,7061227

answered May 14 '17 at 16:46

prashanth

1,7061227

answered May 14 '17 at 16:46

prashanth

1,7061227

add a comment |

Generating random integers between 0 and 9.

import numpy

X = numpy.random.randint(0, 10, size=10)

print(X)

Output:

[4 8 0 4 9 6 9 9 0 7]

edited Jul 6 '18 at 14:11

answered Jul 6 '18 at 6:25

Ashok Kumar Jayaraman

1,09711119

1

If you're using NumPy, you should use NumPy's random functionalities to generate this list, for example with numpy.random.randint(0, 10, size=10). The method you show is needlessly inefficient.

– Mark Dickinson
Jul 6 '18 at 6:44

add a comment |

Generating random integers between 0 and 9.

import numpy

X = numpy.random.randint(0, 10, size=10)

print(X)

Output:

[4 8 0 4 9 6 9 9 0 7]

edited Jul 6 '18 at 14:11

answered Jul 6 '18 at 6:25

Ashok Kumar Jayaraman

1,09711119

1

If you're using NumPy, you should use NumPy's random functionalities to generate this list, for example with numpy.random.randint(0, 10, size=10). The method you show is needlessly inefficient.

– Mark Dickinson
Jul 6 '18 at 6:44

add a comment |

Generating random integers between 0 and 9.

import numpy

X = numpy.random.randint(0, 10, size=10)

print(X)

Output:

[4 8 0 4 9 6 9 9 0 7]

edited Jul 6 '18 at 14:11

answered Jul 6 '18 at 6:25

Ashok Kumar Jayaraman

1,09711119

Generating random integers between 0 and 9.

import numpy

X = numpy.random.randint(0, 10, size=10)

print(X)

Output:

[4 8 0 4 9 6 9 9 0 7]

edited Jul 6 '18 at 14:11

answered Jul 6 '18 at 6:25

Ashok Kumar Jayaraman

1,09711119

edited Jul 6 '18 at 14:11

answered Jul 6 '18 at 6:25

Ashok Kumar Jayaraman

1,09711119

answered Jul 6 '18 at 6:25

Ashok Kumar Jayaraman

1,09711119

answered Jul 6 '18 at 6:25

Ashok Kumar Jayaraman

1,09711119

1

If you're using NumPy, you should use NumPy's random functionalities to generate this list, for example with numpy.random.randint(0, 10, size=10). The method you show is needlessly inefficient.

– Mark Dickinson
Jul 6 '18 at 6:44

add a comment |

1

If you're using NumPy, you should use NumPy's random functionalities to generate this list, for example with numpy.random.randint(0, 10, size=10). The method you show is needlessly inefficient.

– Mark Dickinson
Jul 6 '18 at 6:44

If you're using NumPy, you should use NumPy's random functionalities to generate this list, for example with numpy.random.randint(0, 10, size=10). The method you show is needlessly inefficient.

– Mark Dickinson
Jul 6 '18 at 6:44

add a comment |

Best way is to use import Random function

import random

print(random.sample(range(10), 10))

or without any library import:

n={} 

for i in range(10):

    n[i]=i



for p in range(10):

    print(n.popitem()[1])

here the popitems removes and returns an arbitrary value from the dictionary n.

edited Jun 3 '17 at 1:41

MSeifert

77.3k18148185

answered May 15 '17 at 18:29

S T Mohammed

80126

add a comment |

Best way is to use import Random function

import random

print(random.sample(range(10), 10))

or without any library import:

n={} 

for i in range(10):

    n[i]=i



for p in range(10):

    print(n.popitem()[1])

here the popitems removes and returns an arbitrary value from the dictionary n.

edited Jun 3 '17 at 1:41

MSeifert

77.3k18148185

answered May 15 '17 at 18:29

S T Mohammed

80126

add a comment |

Best way is to use import Random function

import random

print(random.sample(range(10), 10))

or without any library import:

n={} 

for i in range(10):

    n[i]=i



for p in range(10):

    print(n.popitem()[1])

here the popitems removes and returns an arbitrary value from the dictionary n.

edited Jun 3 '17 at 1:41

MSeifert

77.3k18148185

answered May 15 '17 at 18:29

S T Mohammed

80126

Best way is to use import Random function

import random

print(random.sample(range(10), 10))

or without any library import:

n={} 

for i in range(10):

    n[i]=i



for p in range(10):

    print(n.popitem()[1])

here the popitems removes and returns an arbitrary value from the dictionary n.

edited Jun 3 '17 at 1:41

MSeifert

77.3k18148185

answered May 15 '17 at 18:29

S T Mohammed

80126

edited Jun 3 '17 at 1:41

MSeifert

77.3k18148185

edited Jun 3 '17 at 1:41

MSeifert

77.3k18148185

edited Jun 3 '17 at 1:41

MSeifert

77.3k18148185

answered May 15 '17 at 18:29

S T Mohammed

80126

answered May 15 '17 at 18:29

S T Mohammed

80126

answered May 15 '17 at 18:29

S T Mohammed

80126

add a comment |

You can try this:

import numpy as np

print ( np.random.uniform(low=0, high=10, size=(15,)) ).astype(int)



>>> [8 3 6 9 1 0 3 6 3 3 1 2 4 0 4]

Notes:

1.> np.random.uniform generates uniformly distributed numbers over the half-open interval [low, high).

2.> astype(int) casts the numpy array to int data type.

3.> I have chosen size = (15,). This will give you a numpy array of length = 15.

More information on numpy.random.uniform

More information on numpy.ndarray.astype

edited Dec 25 '18 at 23:14

answered Nov 28 '18 at 7:56

Siddharth Satpathy

5841717

add a comment |

You can try this:

import numpy as np

print ( np.random.uniform(low=0, high=10, size=(15,)) ).astype(int)



>>> [8 3 6 9 1 0 3 6 3 3 1 2 4 0 4]

Notes:

1.> np.random.uniform generates uniformly distributed numbers over the half-open interval [low, high).

2.> astype(int) casts the numpy array to int data type.

3.> I have chosen size = (15,). This will give you a numpy array of length = 15.

More information on numpy.random.uniform

More information on numpy.ndarray.astype

edited Dec 25 '18 at 23:14

answered Nov 28 '18 at 7:56

Siddharth Satpathy

5841717

add a comment |

You can try this:

import numpy as np

print ( np.random.uniform(low=0, high=10, size=(15,)) ).astype(int)



>>> [8 3 6 9 1 0 3 6 3 3 1 2 4 0 4]

Notes:

1.> np.random.uniform generates uniformly distributed numbers over the half-open interval [low, high).

2.> astype(int) casts the numpy array to int data type.

3.> I have chosen size = (15,). This will give you a numpy array of length = 15.

More information on numpy.random.uniform

More information on numpy.ndarray.astype

edited Dec 25 '18 at 23:14

answered Nov 28 '18 at 7:56

Siddharth Satpathy

5841717

You can try this:

import numpy as np

print ( np.random.uniform(low=0, high=10, size=(15,)) ).astype(int)



>>> [8 3 6 9 1 0 3 6 3 3 1 2 4 0 4]

Notes:

1.> np.random.uniform generates uniformly distributed numbers over the half-open interval [low, high).

2.> astype(int) casts the numpy array to int data type.

3.> I have chosen size = (15,). This will give you a numpy array of length = 15.

More information on numpy.random.uniform

More information on numpy.ndarray.astype

edited Dec 25 '18 at 23:14

answered Nov 28 '18 at 7:56

Siddharth Satpathy

5841717

edited Dec 25 '18 at 23:14

answered Nov 28 '18 at 7:56

Siddharth Satpathy

5841717

answered Nov 28 '18 at 7:56

Siddharth Satpathy

5841717

answered Nov 28 '18 at 7:56

Siddharth Satpathy

5841717

add a comment |

I used variable to control the range

from random import randint 

numberStartRange = 1

numberEndRange = 9

randomNumber = randint(numberStartRange, numberEndRange)

print(randomNumber)

I used the print function to see the results. You can comment is out if you do not need this.

edited Oct 24 '17 at 21:12

answered Sep 19 '17 at 11:30

Amir Md Amiruzzaman

1,0931718

add a comment |

I used variable to control the range

from random import randint 

numberStartRange = 1

numberEndRange = 9

randomNumber = randint(numberStartRange, numberEndRange)

print(randomNumber)

I used the print function to see the results. You can comment is out if you do not need this.

edited Oct 24 '17 at 21:12

answered Sep 19 '17 at 11:30

Amir Md Amiruzzaman

1,0931718

add a comment |

I used variable to control the range

from random import randint 

numberStartRange = 1

numberEndRange = 9

randomNumber = randint(numberStartRange, numberEndRange)

print(randomNumber)

I used the print function to see the results. You can comment is out if you do not need this.

edited Oct 24 '17 at 21:12

answered Sep 19 '17 at 11:30

Amir Md Amiruzzaman

1,0931718

I used variable to control the range

from random import randint 

numberStartRange = 1

numberEndRange = 9

randomNumber = randint(numberStartRange, numberEndRange)

print(randomNumber)

I used the print function to see the results. You can comment is out if you do not need this.

edited Oct 24 '17 at 21:12

answered Sep 19 '17 at 11:30

Amir Md Amiruzzaman

1,0931718

edited Oct 24 '17 at 21:12

answered Sep 19 '17 at 11:30

Amir Md Amiruzzaman

1,0931718

answered Sep 19 '17 at 11:30

Amir Md Amiruzzaman

1,0931718

answered Sep 19 '17 at 11:30

Amir Md Amiruzzaman

1,0931718

add a comment |

This is more of a mathematical approach but it works 100% of the time:

Let's say you want to use random.random() function to generate a number between a and b. To achieve this, just do the following:

num = (b-a)*random.random() + a;

Of course, you can generate more numbers.

answered Nov 30 '18 at 18:27

Orestis Zekai

508

add a comment |

This is more of a mathematical approach but it works 100% of the time:

Let's say you want to use random.random() function to generate a number between a and b. To achieve this, just do the following:

num = (b-a)*random.random() + a;

Of course, you can generate more numbers.

answered Nov 30 '18 at 18:27

Orestis Zekai

508

add a comment |

This is more of a mathematical approach but it works 100% of the time:

Let's say you want to use random.random() function to generate a number between a and b. To achieve this, just do the following:

num = (b-a)*random.random() + a;

Of course, you can generate more numbers.

answered Nov 30 '18 at 18:27

Orestis Zekai

508

This is more of a mathematical approach but it works 100% of the time:

Let's say you want to use random.random() function to generate a number between a and b. To achieve this, just do the following:

num = (b-a)*random.random() + a;

Of course, you can generate more numbers.

answered Nov 30 '18 at 18:27

Orestis Zekai

508

answered Nov 30 '18 at 18:27

Orestis Zekai

508

answered Nov 30 '18 at 18:27

Orestis Zekai

508

answered Nov 30 '18 at 18:27

Orestis Zekai

508

add a comment |

For the example that you have given (a random integer between 0 and 9), the cleanest solution is:

from random import randrange



randrange(10)

edited Jan 2 at 2:08

answered Oct 8 '18 at 14:38

Utku

884929

randrange returns a single number between specified range.

– Shital Shah
Jan 2 at 1:43

@ShitalShah That is exactly what the question wants. Run the accepted answer and realize that it does the same thing.

– Utku
Jan 2 at 2:06

@ShitalShah If you want all numbers between 0 and 9, you use range(10).

– Utku
Jan 2 at 2:07

add a comment |

For the example that you have given (a random integer between 0 and 9), the cleanest solution is:

from random import randrange



randrange(10)

edited Jan 2 at 2:08

answered Oct 8 '18 at 14:38

Utku

884929

randrange returns a single number between specified range.

– Shital Shah
Jan 2 at 1:43

@ShitalShah That is exactly what the question wants. Run the accepted answer and realize that it does the same thing.

– Utku
Jan 2 at 2:06

@ShitalShah If you want all numbers between 0 and 9, you use range(10).

– Utku
Jan 2 at 2:07

add a comment |

For the example that you have given (a random integer between 0 and 9), the cleanest solution is:

from random import randrange



randrange(10)

edited Jan 2 at 2:08

answered Oct 8 '18 at 14:38

Utku

884929

For the example that you have given (a random integer between 0 and 9), the cleanest solution is:

from random import randrange



randrange(10)

edited Jan 2 at 2:08

answered Oct 8 '18 at 14:38

Utku

884929

edited Jan 2 at 2:08

answered Oct 8 '18 at 14:38

Utku

884929

answered Oct 8 '18 at 14:38

Utku

884929

answered Oct 8 '18 at 14:38

Utku

884929

randrange returns a single number between specified range.

– Shital Shah
Jan 2 at 1:43

@ShitalShah That is exactly what the question wants. Run the accepted answer and realize that it does the same thing.

– Utku
Jan 2 at 2:06

@ShitalShah If you want all numbers between 0 and 9, you use range(10).

– Utku
Jan 2 at 2:07

add a comment |

randrange returns a single number between specified range.

– Shital Shah
Jan 2 at 1:43

@ShitalShah That is exactly what the question wants. Run the accepted answer and realize that it does the same thing.

– Utku
Jan 2 at 2:06

@ShitalShah If you want all numbers between 0 and 9, you use range(10).

– Utku
Jan 2 at 2:07

randrange returns a single number between specified range.

– Shital Shah
Jan 2 at 1:43

@ShitalShah That is exactly what the question wants. Run the accepted answer and realize that it does the same thing.

– Utku
Jan 2 at 2:06

@ShitalShah If you want all numbers between 0 and 9, you use range(10).

– Utku
Jan 2 at 2:07

add a comment |

Try This,

import numpy as np



X = np.random.randint(0, 99, size=1000) # 1k random integer

answered Dec 19 '18 at 10:38

Rakesh Chaudhari

1,06711420

add a comment |

Try This,

import numpy as np



X = np.random.randint(0, 99, size=1000) # 1k random integer

answered Dec 19 '18 at 10:38

Rakesh Chaudhari

1,06711420

add a comment |

Try This,

import numpy as np



X = np.random.randint(0, 99, size=1000) # 1k random integer

answered Dec 19 '18 at 10:38

Rakesh Chaudhari

1,06711420

Try This,

import numpy as np



X = np.random.randint(0, 99, size=1000) # 1k random integer

answered Dec 19 '18 at 10:38

Rakesh Chaudhari

1,06711420

answered Dec 19 '18 at 10:38

Rakesh Chaudhari

1,06711420

answered Dec 19 '18 at 10:38

Rakesh Chaudhari

1,06711420

answered Dec 19 '18 at 10:38

Rakesh Chaudhari

1,06711420

add a comment |

From the documentation page for the random module:

Warning: The pseudo-random generators of this module should not be
used for security purposes. Use os.urandom() or SystemRandom if you
require a cryptographically secure pseudo-random number generator.

random.SystemRandom, which was introduced in Python 2.4, is considered cryptographically secure. It is still available in Python 3.7.1 which is current at time of writing.

>>> import string

>>> string.digits

'0123456789'

>>> import random

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'1'

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'5'

Instead of string.digits, range could be used per some of the other answers along perhaps with a comprehension. Mix and match according to your needs.

edited Feb 7 at 16:49

answered Dec 11 '18 at 22:49

Richard Riehle

1036

add a comment |

From the documentation page for the random module:

Warning: The pseudo-random generators of this module should not be
used for security purposes. Use os.urandom() or SystemRandom if you
require a cryptographically secure pseudo-random number generator.

random.SystemRandom, which was introduced in Python 2.4, is considered cryptographically secure. It is still available in Python 3.7.1 which is current at time of writing.

>>> import string

>>> string.digits

'0123456789'

>>> import random

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'1'

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'5'

Instead of string.digits, range could be used per some of the other answers along perhaps with a comprehension. Mix and match according to your needs.

edited Feb 7 at 16:49

answered Dec 11 '18 at 22:49

Richard Riehle

1036

add a comment |

From the documentation page for the random module:

Warning: The pseudo-random generators of this module should not be
used for security purposes. Use os.urandom() or SystemRandom if you
require a cryptographically secure pseudo-random number generator.

random.SystemRandom, which was introduced in Python 2.4, is considered cryptographically secure. It is still available in Python 3.7.1 which is current at time of writing.

>>> import string

>>> string.digits

'0123456789'

>>> import random

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'1'

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'5'

Instead of string.digits, range could be used per some of the other answers along perhaps with a comprehension. Mix and match according to your needs.

edited Feb 7 at 16:49

answered Dec 11 '18 at 22:49

Richard Riehle

1036

From the documentation page for the random module:

Warning: The pseudo-random generators of this module should not be
used for security purposes. Use os.urandom() or SystemRandom if you
require a cryptographically secure pseudo-random number generator.

random.SystemRandom, which was introduced in Python 2.4, is considered cryptographically secure. It is still available in Python 3.7.1 which is current at time of writing.

>>> import string

>>> string.digits

'0123456789'

>>> import random

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'1'

>>> random.SystemRandom().choice(string.digits)

'8'

>>> random.SystemRandom().choice(string.digits)

'5'

Instead of string.digits, range could be used per some of the other answers along perhaps with a comprehension. Mix and match according to your needs.

edited Feb 7 at 16:49

answered Dec 11 '18 at 22:49

Richard Riehle

1036

edited Feb 7 at 16:49

answered Dec 11 '18 at 22:49

Richard Riehle

1036

answered Dec 11 '18 at 22:49

Richard Riehle

1036

answered Dec 11 '18 at 22:49

Richard Riehle

1036

add a comment |

-1

I had better luck with this for Python 3.6

str_Key = ""                                                                                                

str_RandomKey = ""                                                                                          

for int_I in range(128):                                                                                    

      str_Key = random.choice('0123456789')

      str_RandomKey = str_RandomKey + str_Key

Just add characters like 'ABCD' and 'abcd' or '^!~=-><' to alter the character pool to pull from, change the range to alter the number of characters generated.

answered Jul 20 '17 at 23:43

M T Head

511411

add a comment |

-1

I had better luck with this for Python 3.6

str_Key = ""                                                                                                

str_RandomKey = ""                                                                                          

for int_I in range(128):                                                                                    

      str_Key = random.choice('0123456789')

      str_RandomKey = str_RandomKey + str_Key

Just add characters like 'ABCD' and 'abcd' or '^!~=-><' to alter the character pool to pull from, change the range to alter the number of characters generated.

answered Jul 20 '17 at 23:43

M T Head

511411

add a comment |

-1

I had better luck with this for Python 3.6

str_Key = ""                                                                                                

str_RandomKey = ""                                                                                          

for int_I in range(128):                                                                                    

      str_Key = random.choice('0123456789')

      str_RandomKey = str_RandomKey + str_Key

Just add characters like 'ABCD' and 'abcd' or '^!~=-><' to alter the character pool to pull from, change the range to alter the number of characters generated.

answered Jul 20 '17 at 23:43

M T Head

511411

I had better luck with this for Python 3.6

str_Key = ""                                                                                                

str_RandomKey = ""                                                                                          

for int_I in range(128):                                                                                    

      str_Key = random.choice('0123456789')

      str_RandomKey = str_RandomKey + str_Key

Just add characters like 'ABCD' and 'abcd' or '^!~=-><' to alter the character pool to pull from, change the range to alter the number of characters generated.

answered Jul 20 '17 at 23:43

M T Head

511411

answered Jul 20 '17 at 23:43

M T Head

511411

answered Jul 20 '17 at 23:43

M T Head

511411

answered Jul 20 '17 at 23:43

M T Head

511411

add a comment |

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