How do I find the $z-score of something when not given an x?












-1












$begingroup$


I'm given a mean and a standard deviation.
The question asks: How much chicken do you have to eat in order to be in the top $5%$ of everyone else.



Mean = $55$



Standard Deviation $=9.2$



The answer is $X=70.13$ but I can't figure out how to get that without a $z$ score.










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  • $begingroup$
    Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
    $endgroup$
    – Michael Hoppe
    Jan 23 at 14:49


















-1












$begingroup$


I'm given a mean and a standard deviation.
The question asks: How much chicken do you have to eat in order to be in the top $5%$ of everyone else.



Mean = $55$



Standard Deviation $=9.2$



The answer is $X=70.13$ but I can't figure out how to get that without a $z$ score.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
    $endgroup$
    – Michael Hoppe
    Jan 23 at 14:49
















-1












-1








-1





$begingroup$


I'm given a mean and a standard deviation.
The question asks: How much chicken do you have to eat in order to be in the top $5%$ of everyone else.



Mean = $55$



Standard Deviation $=9.2$



The answer is $X=70.13$ but I can't figure out how to get that without a $z$ score.










share|cite|improve this question











$endgroup$




I'm given a mean and a standard deviation.
The question asks: How much chicken do you have to eat in order to be in the top $5%$ of everyone else.



Mean = $55$



Standard Deviation $=9.2$



The answer is $X=70.13$ but I can't figure out how to get that without a $z$ score.







statistics standard-deviation






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share|cite|improve this question













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edited Jan 23 at 15:13









Jneven

904322




904322










asked Jan 23 at 14:46









CriramCriram

1




1












  • $begingroup$
    Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
    $endgroup$
    – Michael Hoppe
    Jan 23 at 14:49




















  • $begingroup$
    Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
    $endgroup$
    – Michael Hoppe
    Jan 23 at 14:49


















$begingroup$
Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
$endgroup$
– Michael Hoppe
Jan 23 at 14:49






$begingroup$
Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
$endgroup$
– Michael Hoppe
Jan 23 at 14:49












1 Answer
1






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$begingroup$

The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.



Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.






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    $begingroup$

    The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.



    Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.



      Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.



        Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.






        share|cite|improve this answer









        $endgroup$



        The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.



        Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 23 at 14:50









        kccukccu

        10.6k11229




        10.6k11229






























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