How do I find the $z-score of something when not given an x?
$begingroup$
I'm given a mean and a standard deviation.
The question asks: How much chicken do you have to eat in order to be in the top $5%$ of everyone else.
Mean = $55$
Standard Deviation $=9.2$
The answer is $X=70.13$ but I can't figure out how to get that without a $z$ score.
statistics standard-deviation
$endgroup$
add a comment |
$begingroup$
I'm given a mean and a standard deviation.
The question asks: How much chicken do you have to eat in order to be in the top $5%$ of everyone else.
Mean = $55$
Standard Deviation $=9.2$
The answer is $X=70.13$ but I can't figure out how to get that without a $z$ score.
statistics standard-deviation
$endgroup$
$begingroup$
Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
$endgroup$
– Michael Hoppe
Jan 23 at 14:49
add a comment |
$begingroup$
I'm given a mean and a standard deviation.
The question asks: How much chicken do you have to eat in order to be in the top $5%$ of everyone else.
Mean = $55$
Standard Deviation $=9.2$
The answer is $X=70.13$ but I can't figure out how to get that without a $z$ score.
statistics standard-deviation
$endgroup$
I'm given a mean and a standard deviation.
The question asks: How much chicken do you have to eat in order to be in the top $5%$ of everyone else.
Mean = $55$
Standard Deviation $=9.2$
The answer is $X=70.13$ but I can't figure out how to get that without a $z$ score.
statistics standard-deviation
statistics standard-deviation
edited Jan 23 at 15:13


Jneven
904322
904322
asked Jan 23 at 14:46


CriramCriram
1
1
$begingroup$
Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
$endgroup$
– Michael Hoppe
Jan 23 at 14:49
add a comment |
$begingroup$
Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
$endgroup$
– Michael Hoppe
Jan 23 at 14:49
$begingroup$
Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
$endgroup$
– Michael Hoppe
Jan 23 at 14:49
$begingroup$
Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
$endgroup$
– Michael Hoppe
Jan 23 at 14:49
add a comment |
1 Answer
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$begingroup$
The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.
Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.
$endgroup$
add a comment |
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1 Answer
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1 Answer
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oldest
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active
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$begingroup$
The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.
Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.
$endgroup$
add a comment |
$begingroup$
The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.
Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.
$endgroup$
add a comment |
$begingroup$
The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.
Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.
$endgroup$
The question here requires you to find the $z$-score. The question is "what would the $z$-score have to be in order to be in the top $5%$?" Instead of calculating a $z$-score and looking up the probability in a table, you need to look up the probability in the table and find the corresponding $z$-score.
Once you know the $z$-score, you can use $z=frac{x-mu}{sigma}$ to calculate the corresponding $x$.
answered Jan 23 at 14:50
kccukccu
10.6k11229
10.6k11229
add a comment |
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$begingroup$
Just solve $Phi((X-55)/9.2)=0.95$. But who in the world is supposed to eat 70 chicken ...
$endgroup$
– Michael Hoppe
Jan 23 at 14:49