how to interwoven the given string using function

I am very new to javascript programming and I have one puzzle as mention below.

How function to take in a string and return a string that is itself with the reverse of it interwoven together. For example, "ab12" would be"ab12" and "21ba" interwoven to make: "a2b11b2a"

I trying this way which give error.any help will appreciate.
Thanks

function interwoven(str) {

var newString = "";

for (var i = str.length - 1; i >= 0; i--) {

    for (var j = str.length; i <= 0; i++)

    newString += str[j+i];

 }

return newString;

}

interwoven('ab12');

asked Jan 2 at 17:26

Abhirock

121

"ab12".replace(/(?=)/g, (_,index,str) => str.charAt(str.length-index))

– Thomas
Jan 2 at 17:42

add a comment |

I am very new to javascript programming and I have one puzzle as mention below.

How function to take in a string and return a string that is itself with the reverse of it interwoven together. For example, "ab12" would be"ab12" and "21ba" interwoven to make: "a2b11b2a"

I trying this way which give error.any help will appreciate.
Thanks

function interwoven(str) {

var newString = "";

for (var i = str.length - 1; i >= 0; i--) {

    for (var j = str.length; i <= 0; i++)

    newString += str[j+i];

 }

return newString;

}

interwoven('ab12');

asked Jan 2 at 17:26

Abhirock

121

"ab12".replace(/(?=)/g, (_,index,str) => str.charAt(str.length-index))

– Thomas
Jan 2 at 17:42

add a comment |

I am very new to javascript programming and I have one puzzle as mention below.

How function to take in a string and return a string that is itself with the reverse of it interwoven together. For example, "ab12" would be"ab12" and "21ba" interwoven to make: "a2b11b2a"

I trying this way which give error.any help will appreciate.
Thanks

function interwoven(str) {

var newString = "";

for (var i = str.length - 1; i >= 0; i--) {

    for (var j = str.length; i <= 0; i++)

    newString += str[j+i];

 }

return newString;

}

interwoven('ab12');

asked Jan 2 at 17:26

Abhirock

121

I am very new to javascript programming and I have one puzzle as mention below.

How function to take in a string and return a string that is itself with the reverse of it interwoven together. For example, "ab12" would be"ab12" and "21ba" interwoven to make: "a2b11b2a"

I trying this way which give error.any help will appreciate.
Thanks

function interwoven(str) {

var newString = "";

for (var i = str.length - 1; i >= 0; i--) {

    for (var j = str.length; i <= 0; i++)

    newString += str[j+i];

 }

return newString;

}

interwoven('ab12');

javascript

asked Jan 2 at 17:26

Abhirock

121

asked Jan 2 at 17:26

Abhirock

121

asked Jan 2 at 17:26

Abhirock

121

asked Jan 2 at 17:26

Abhirock

121

asked Jan 2 at 17:26

Abhirock

121

"ab12".replace(/(?=)/g, (_,index,str) => str.charAt(str.length-index))

– Thomas
Jan 2 at 17:42

add a comment |

"ab12".replace(/(?=)/g, (_,index,str) => str.charAt(str.length-index))

– Thomas
Jan 2 at 17:42

"ab12".replace(/(?=)/g, (_,index,str) => str.charAt(str.length-index))

– Thomas
Jan 2 at 17:42

add a comment |

3 Answers
3

active

oldest

votes

You could use two indices i that increments and j that decrements.

function interwoven(str) {

  var i = 0, len = str.length, j = len - 1, newString = "";

  for (; i < len; i++, j--) {

    newString += str[i] + str[j]

  }

  return newString;

}

console.log(interwoven('ab12'));

answered Jan 2 at 17:30

Yury Tarabanko

31.1k64668

1

Thanks@Yury its awesome. you make my life easy

– Abhirock
Jan 2 at 17:45

@Abhirock Glad I could help.

– Yury Tarabanko
Jan 2 at 17:49

sorry to ask one query Is it my question is wrong or inappropriate as its given -1?

– Abhirock
Jan 2 at 17:51

@Abhirock Who knows :) Mb the downvoter assumes you haven't done your research or whatever.

– Yury Tarabanko
Jan 2 at 18:04

Ok Thanks I will take care about it:-)

– Abhirock
Jan 2 at 18:11

add a comment |

I would just do this:

    function interwoven(str) {

        return str.split('').reduce((acc, cur, idx, src) => 

            acc + cur + src[src.length - (idx + 1)], '');

    }



    console.log(interwoven('ab12'))

answered Jan 2 at 17:35

dave

36.5k13965

Thanks@Dave it really helpful

– Abhirock
Jan 2 at 17:46

add a comment |

    function interwoven(string) {

    // store string in array string-array

    let string-array = string.split('');

    // copy string-array, reverse, and store in string-array-reverse

    let string-array-reverse = string-array.reverse();

    let interwoven-array = ;

    let index;

    for (index = 0; index < string-array.length; index++) {

        interwoven-array.push(string-array[index]);

        interwoven-array.push(string-array-reverse[index]);

    }



    return interwoven-array;

}



interwoven('ab12');

edited Jan 2 at 17:45

answered Jan 2 at 17:39

rpivovar

81311031

Thanks@rpivovar it really helpful

– Abhirock
Jan 2 at 17:45

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

You could use two indices i that increments and j that decrements.

function interwoven(str) {

  var i = 0, len = str.length, j = len - 1, newString = "";

  for (; i < len; i++, j--) {

    newString += str[i] + str[j]

  }

  return newString;

}

console.log(interwoven('ab12'));

answered Jan 2 at 17:30

Yury Tarabanko

31.1k64668

1

Thanks@Yury its awesome. you make my life easy

– Abhirock
Jan 2 at 17:45

@Abhirock Glad I could help.

– Yury Tarabanko
Jan 2 at 17:49

sorry to ask one query Is it my question is wrong or inappropriate as its given -1?

– Abhirock
Jan 2 at 17:51

@Abhirock Who knows :) Mb the downvoter assumes you haven't done your research or whatever.

– Yury Tarabanko
Jan 2 at 18:04

Ok Thanks I will take care about it:-)

– Abhirock
Jan 2 at 18:11

add a comment |

You could use two indices i that increments and j that decrements.

function interwoven(str) {

  var i = 0, len = str.length, j = len - 1, newString = "";

  for (; i < len; i++, j--) {

    newString += str[i] + str[j]

  }

  return newString;

}

console.log(interwoven('ab12'));

answered Jan 2 at 17:30

Yury Tarabanko

31.1k64668

1

Thanks@Yury its awesome. you make my life easy

– Abhirock
Jan 2 at 17:45

@Abhirock Glad I could help.

– Yury Tarabanko
Jan 2 at 17:49

sorry to ask one query Is it my question is wrong or inappropriate as its given -1?

– Abhirock
Jan 2 at 17:51

@Abhirock Who knows :) Mb the downvoter assumes you haven't done your research or whatever.

– Yury Tarabanko
Jan 2 at 18:04

Ok Thanks I will take care about it:-)

– Abhirock
Jan 2 at 18:11

add a comment |

You could use two indices i that increments and j that decrements.

function interwoven(str) {

  var i = 0, len = str.length, j = len - 1, newString = "";

  for (; i < len; i++, j--) {

    newString += str[i] + str[j]

  }

  return newString;

}

console.log(interwoven('ab12'));

answered Jan 2 at 17:30

Yury Tarabanko

31.1k64668

You could use two indices i that increments and j that decrements.

function interwoven(str) {

  var i = 0, len = str.length, j = len - 1, newString = "";

  for (; i < len; i++, j--) {

    newString += str[i] + str[j]

  }

  return newString;

}

console.log(interwoven('ab12'));

function interwoven(str) {

  var i = 0, len = str.length, j = len - 1, newString = "";

  for (; i < len; i++, j--) {

    newString += str[i] + str[j]

  }

  return newString;

}

console.log(interwoven('ab12'));

function interwoven(str) {

  var i = 0, len = str.length, j = len - 1, newString = "";

  for (; i < len; i++, j--) {

    newString += str[i] + str[j]

  }

  return newString;

}

console.log(interwoven('ab12'));

answered Jan 2 at 17:30

Yury Tarabanko

31.1k64668

answered Jan 2 at 17:30

Yury Tarabanko

31.1k64668

answered Jan 2 at 17:30

Yury Tarabanko

31.1k64668

answered Jan 2 at 17:30

Yury Tarabanko

31.1k64668

1

Thanks@Yury its awesome. you make my life easy

– Abhirock
Jan 2 at 17:45

@Abhirock Glad I could help.

– Yury Tarabanko
Jan 2 at 17:49

sorry to ask one query Is it my question is wrong or inappropriate as its given -1?

– Abhirock
Jan 2 at 17:51

@Abhirock Who knows :) Mb the downvoter assumes you haven't done your research or whatever.

– Yury Tarabanko
Jan 2 at 18:04

Ok Thanks I will take care about it:-)

– Abhirock
Jan 2 at 18:11

add a comment |

1

Thanks@Yury its awesome. you make my life easy

– Abhirock
Jan 2 at 17:45

@Abhirock Glad I could help.

– Yury Tarabanko
Jan 2 at 17:49

sorry to ask one query Is it my question is wrong or inappropriate as its given -1?

– Abhirock
Jan 2 at 17:51

@Abhirock Who knows :) Mb the downvoter assumes you haven't done your research or whatever.

– Yury Tarabanko
Jan 2 at 18:04

Ok Thanks I will take care about it:-)

– Abhirock
Jan 2 at 18:11

Thanks@Yury its awesome. you make my life easy

– Abhirock
Jan 2 at 17:45

@Abhirock Glad I could help.

– Yury Tarabanko
Jan 2 at 17:49

sorry to ask one query Is it my question is wrong or inappropriate as its given -1?

– Abhirock
Jan 2 at 17:51

@Abhirock Who knows :) Mb the downvoter assumes you haven't done your research or whatever.

– Yury Tarabanko
Jan 2 at 18:04

Ok Thanks I will take care about it:-)

– Abhirock
Jan 2 at 18:11

add a comment |

I would just do this:

    function interwoven(str) {

        return str.split('').reduce((acc, cur, idx, src) => 

            acc + cur + src[src.length - (idx + 1)], '');

    }



    console.log(interwoven('ab12'))

answered Jan 2 at 17:35

dave

36.5k13965

Thanks@Dave it really helpful

– Abhirock
Jan 2 at 17:46

add a comment |

I would just do this:

    function interwoven(str) {

        return str.split('').reduce((acc, cur, idx, src) => 

            acc + cur + src[src.length - (idx + 1)], '');

    }



    console.log(interwoven('ab12'))

answered Jan 2 at 17:35

dave

36.5k13965

Thanks@Dave it really helpful

– Abhirock
Jan 2 at 17:46

add a comment |

I would just do this:

    function interwoven(str) {

        return str.split('').reduce((acc, cur, idx, src) => 

            acc + cur + src[src.length - (idx + 1)], '');

    }



    console.log(interwoven('ab12'))

answered Jan 2 at 17:35

dave

36.5k13965

I would just do this:

    function interwoven(str) {

        return str.split('').reduce((acc, cur, idx, src) => 

            acc + cur + src[src.length - (idx + 1)], '');

    }



    console.log(interwoven('ab12'))

    function interwoven(str) {

        return str.split('').reduce((acc, cur, idx, src) => 

            acc + cur + src[src.length - (idx + 1)], '');

    }



    console.log(interwoven('ab12'))

    function interwoven(str) {

        return str.split('').reduce((acc, cur, idx, src) => 

            acc + cur + src[src.length - (idx + 1)], '');

    }



    console.log(interwoven('ab12'))

answered Jan 2 at 17:35

dave

36.5k13965

answered Jan 2 at 17:35

dave

36.5k13965

answered Jan 2 at 17:35

dave

36.5k13965

answered Jan 2 at 17:35

dave

36.5k13965

Thanks@Dave it really helpful

– Abhirock
Jan 2 at 17:46

add a comment |

Thanks@Dave it really helpful

– Abhirock
Jan 2 at 17:46

Thanks@Dave it really helpful

– Abhirock
Jan 2 at 17:46

add a comment |

    function interwoven(string) {

    // store string in array string-array

    let string-array = string.split('');

    // copy string-array, reverse, and store in string-array-reverse

    let string-array-reverse = string-array.reverse();

    let interwoven-array = ;

    let index;

    for (index = 0; index < string-array.length; index++) {

        interwoven-array.push(string-array[index]);

        interwoven-array.push(string-array-reverse[index]);

    }



    return interwoven-array;

}



interwoven('ab12');

edited Jan 2 at 17:45

answered Jan 2 at 17:39

rpivovar

81311031

Thanks@rpivovar it really helpful

– Abhirock
Jan 2 at 17:45

add a comment |

    function interwoven(string) {

    // store string in array string-array

    let string-array = string.split('');

    // copy string-array, reverse, and store in string-array-reverse

    let string-array-reverse = string-array.reverse();

    let interwoven-array = ;

    let index;

    for (index = 0; index < string-array.length; index++) {

        interwoven-array.push(string-array[index]);

        interwoven-array.push(string-array-reverse[index]);

    }



    return interwoven-array;

}



interwoven('ab12');

edited Jan 2 at 17:45

answered Jan 2 at 17:39

rpivovar

81311031

Thanks@rpivovar it really helpful

– Abhirock
Jan 2 at 17:45

add a comment |

    function interwoven(string) {

    // store string in array string-array

    let string-array = string.split('');

    // copy string-array, reverse, and store in string-array-reverse

    let string-array-reverse = string-array.reverse();

    let interwoven-array = ;

    let index;

    for (index = 0; index < string-array.length; index++) {

        interwoven-array.push(string-array[index]);

        interwoven-array.push(string-array-reverse[index]);

    }



    return interwoven-array;

}



interwoven('ab12');

edited Jan 2 at 17:45

answered Jan 2 at 17:39

rpivovar

81311031

    function interwoven(string) {

    // store string in array string-array

    let string-array = string.split('');

    // copy string-array, reverse, and store in string-array-reverse

    let string-array-reverse = string-array.reverse();

    let interwoven-array = ;

    let index;

    for (index = 0; index < string-array.length; index++) {

        interwoven-array.push(string-array[index]);

        interwoven-array.push(string-array-reverse[index]);

    }



    return interwoven-array;

}



interwoven('ab12');

edited Jan 2 at 17:45

answered Jan 2 at 17:39

rpivovar

81311031

edited Jan 2 at 17:45

answered Jan 2 at 17:39

rpivovar

81311031

answered Jan 2 at 17:39

rpivovar

81311031

answered Jan 2 at 17:39

rpivovar

81311031

Thanks@rpivovar it really helpful

– Abhirock
Jan 2 at 17:45

add a comment |

Thanks@rpivovar it really helpful

– Abhirock
Jan 2 at 17:45

Thanks@rpivovar it really helpful

– Abhirock
Jan 2 at 17:45

add a comment |

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