Mixing
How to UN-log a client if the application crashes
In my application, I use access database in a server, in which I log the user activity of all my clients, logging in when they start the client app and logging out when they close the main form.
I do that changing a field in the database to: logged - YES, or logged - NO
But when the application crashes for random reasons, the client doesn´t un-log, how I can do to un-log the client in case of an exception (or crash)?
Using Lazarus and ZEOS / SQL / ODBC / ADO to comm with access.
Thanks,
Leonardo
sql crash client lazarus freepascal
asked Jan 1 at 20:07
Leonardo FlorianoLeonardo Floriano
64
add a comment |
In my application, I use access database in a server, in which I log the user activity of all my clients, logging in when they start the client app and logging out when they close the main form.
I do that changing a field in the database to: logged - YES, or logged - NO
But when the application crashes for random reasons, the client doesn´t un-log, how I can do to un-log the client in case of an exception (or crash)?
Using Lazarus and ZEOS / SQL / ODBC / ADO to comm with access.
Thanks,
Leonardo
sql crash client lazarus freepascal
asked Jan 1 at 20:07
Leonardo FlorianoLeonardo Floriano
64
add a comment |
In my application, I use access database in a server, in which I log the user activity of all my clients, logging in when they start the client app and logging out when they close the main form.
I do that changing a field in the database to: logged - YES, or logged - NO
But when the application crashes for random reasons, the client doesn´t un-log, how I can do to un-log the client in case of an exception (or crash)?
Using Lazarus and ZEOS / SQL / ODBC / ADO to comm with access.
Thanks,
Leonardo
sql crash client lazarus freepascal
asked Jan 1 at 20:07
Leonardo FlorianoLeonardo Floriano
64
In my application, I use access database in a server, in which I log the user activity of all my clients, logging in when they start the client app and logging out when they close the main form.
I do that changing a field in the database to: logged - YES, or logged - NO
But when the application crashes for random reasons, the client doesn´t un-log, how I can do to un-log the client in case of an exception (or crash)?
Using Lazarus and ZEOS / SQL / ODBC / ADO to comm with access.
Thanks,
Leonardo
sql crash client lazarus freepascal
sql crash client lazarus freepascal
asked Jan 1 at 20:07
Leonardo FlorianoLeonardo Floriano
64
asked Jan 1 at 20:07
Leonardo FlorianoLeonardo Floriano
64
asked Jan 1 at 20:07
Leonardo FlorianoLeonardo Floriano
64
asked Jan 1 at 20:07
Leonardo FlorianoLeonardo Floriano
64
asked Jan 1 at 20:07
Leonardo FlorianoLeonardo Floriano
64
64
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I believe with a timeout. In general. If you have say MySQL server and you throw in 'A logged in' 'A logged out', than you'd probable need some nasty middleware which will do those two records for you: log in is straight forward. Log out: IF on event xyz customer has logged out, log out. Every hour say receive a ping on whoever is logged in. Or on MAX COOKIES TIMOUT TIME.... haven't received a ping? Log out. So you'd probably keep KEEP ALIVE times for your logged in users and once a while do a batch job which logs them out.
answered Jan 1 at 20:20
Vitali PomanitskiVitali Pomanitski
276
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53998574%2fhow-to-un-log-a-client-if-the-application-crashes%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I believe with a timeout. In general. If you have say MySQL server and you throw in 'A logged in' 'A logged out', than you'd probable need some nasty middleware which will do those two records for you: log in is straight forward. Log out: IF on event xyz customer has logged out, log out. Every hour say receive a ping on whoever is logged in. Or on MAX COOKIES TIMOUT TIME.... haven't received a ping? Log out. So you'd probably keep KEEP ALIVE times for your logged in users and once a while do a batch job which logs them out.
answered Jan 1 at 20:20
Vitali PomanitskiVitali Pomanitski
276
add a comment |
I believe with a timeout. In general. If you have say MySQL server and you throw in 'A logged in' 'A logged out', than you'd probable need some nasty middleware which will do those two records for you: log in is straight forward. Log out: IF on event xyz customer has logged out, log out. Every hour say receive a ping on whoever is logged in. Or on MAX COOKIES TIMOUT TIME.... haven't received a ping? Log out. So you'd probably keep KEEP ALIVE times for your logged in users and once a while do a batch job which logs them out.
answered Jan 1 at 20:20
Vitali PomanitskiVitali Pomanitski
276
add a comment |
I believe with a timeout. In general. If you have say MySQL server and you throw in 'A logged in' 'A logged out', than you'd probable need some nasty middleware which will do those two records for you: log in is straight forward. Log out: IF on event xyz customer has logged out, log out. Every hour say receive a ping on whoever is logged in. Or on MAX COOKIES TIMOUT TIME.... haven't received a ping? Log out. So you'd probably keep KEEP ALIVE times for your logged in users and once a while do a batch job which logs them out.
answered Jan 1 at 20:20
Vitali PomanitskiVitali Pomanitski
276
I believe with a timeout. In general. If you have say MySQL server and you throw in 'A logged in' 'A logged out', than you'd probable need some nasty middleware which will do those two records for you: log in is straight forward. Log out: IF on event xyz customer has logged out, log out. Every hour say receive a ping on whoever is logged in. Or on MAX COOKIES TIMOUT TIME.... haven't received a ping? Log out. So you'd probably keep KEEP ALIVE times for your logged in users and once a while do a batch job which logs them out.
answered Jan 1 at 20:20
Vitali PomanitskiVitali Pomanitski
276
answered Jan 1 at 20:20
Vitali PomanitskiVitali Pomanitski
276
answered Jan 1 at 20:20
Vitali PomanitskiVitali Pomanitski
276
answered Jan 1 at 20:20
Vitali PomanitskiVitali Pomanitski
276
276
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53998574%2fhow-to-un-log-a-client-if-the-application-crashes%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
