Mixing
Regex: Detect Phone numbers that are separated by dashes (-) and/or spaces
I am trying to recognize these types of phone number inputs:
- 0172665476
- +6265476393
- +62-65476393
- +62-654-76393
- +62 65476393
While my regex: (?:d+s*)+ can recognize the 1st 2 sample values, it recognizes the last 3 sample values as multiple matches in each line, instead of recognizing the number as a whole.
How can I modify this to support multiple dashes and/or spaces and still recognize it as 1 whole number instead of multiple matches?
regex
asked Jan 2 at 16:31
DinukaDinuka
1,88833580
add a comment |
I am trying to recognize these types of phone number inputs:
- 0172665476
- +6265476393
- +62-65476393
- +62-654-76393
- +62 65476393
While my regex: (?:d+s*)+ can recognize the 1st 2 sample values, it recognizes the last 3 sample values as multiple matches in each line, instead of recognizing the number as a whole.
How can I modify this to support multiple dashes and/or spaces and still recognize it as 1 whole number instead of multiple matches?
regex
asked Jan 2 at 16:31
DinukaDinuka
1,88833580
@Delgan Close! it includes a trailing space if there's any space after the number: "Hi my number is 0172665476 okay?"
– Dinuka
Jan 2 at 16:40
check this regex101.com/r/wxIiPs/2
– Code Maniac
Jan 2 at 16:44
add a comment |
I am trying to recognize these types of phone number inputs:
- 0172665476
- +6265476393
- +62-65476393
- +62-654-76393
- +62 65476393
While my regex: (?:d+s*)+ can recognize the 1st 2 sample values, it recognizes the last 3 sample values as multiple matches in each line, instead of recognizing the number as a whole.
How can I modify this to support multiple dashes and/or spaces and still recognize it as 1 whole number instead of multiple matches?
regex
asked Jan 2 at 16:31
DinukaDinuka
1,88833580
I am trying to recognize these types of phone number inputs:
- 0172665476
- +6265476393
- +62-65476393
- +62-654-76393
- +62 65476393
While my regex: (?:d+s*)+ can recognize the 1st 2 sample values, it recognizes the last 3 sample values as multiple matches in each line, instead of recognizing the number as a whole.
How can I modify this to support multiple dashes and/or spaces and still recognize it as 1 whole number instead of multiple matches?
regex
regex
asked Jan 2 at 16:31
DinukaDinuka
1,88833580
asked Jan 2 at 16:31
DinukaDinuka
1,88833580
asked Jan 2 at 16:31
DinukaDinuka
1,88833580
asked Jan 2 at 16:31
DinukaDinuka
1,88833580
asked Jan 2 at 16:31
DinukaDinuka
1,88833580
1,88833580
@Delgan Close! it includes a trailing space if there's any space after the number: "Hi my number is 0172665476 okay?"
– Dinuka
Jan 2 at 16:40
check this regex101.com/r/wxIiPs/2
– Code Maniac
Jan 2 at 16:44
add a comment |
@Delgan Close! it includes a trailing space if there's any space after the number: "Hi my number is 0172665476 okay?"
– Dinuka
Jan 2 at 16:40
check this regex101.com/r/wxIiPs/2
– Code Maniac
Jan 2 at 16:44
@Delgan Close! it includes a trailing space if there's any space after the number: "Hi my number is 0172665476 okay?"
– Dinuka
Jan 2 at 16:40
@Delgan Close! it includes a trailing space if there's any space after the number: "Hi my number is 0172665476 okay?"
– Dinuka
Jan 2 at 16:40
check this regex101.com/r/wxIiPs/2
– Code Maniac
Jan 2 at 16:44
check this regex101.com/r/wxIiPs/2
– Code Maniac
Jan 2 at 16:44
add a comment |
4 Answers
4
active
oldest
votes
You may use this regex:
^+?d+(?:[s-]d+)*b
RegEx Details:
^+?: Match optional+at start
d+: match 1+ digits
(?:[s-]d+)*: Match 0 or more groups that start with whitespace or-followed by 1+ digits
$: End (Replaced by word boundary as if there are trailing spaces, that match would be missed.)
edited Jan 3 at 15:07
Deep
193211
answered Jan 2 at 16:51
anubhavaanubhava
533k48331408
add a comment |
This should work:
(?:[d +-]+)+
answered Jan 2 at 16:36
feliksfeliks
1,070316
1
This matches all spaces as well: regex101.com/r/IoWOhp/2
– Dinuka
Jan 2 at 16:38
add a comment |
This would work as per your reqt: (If there are trailing spaces, this regex will ignore.)
Regex: '^(?:[d +-]+)b'
answered Jan 2 at 17:08
DeepDeep
193211
add a comment |
Another option could be to use an alternation to match either 10 digits without a leading plus sign or match the pattern with a +, and optional space or hyphen:
(?:d{10}|+d{2}[- ]?d{3}-?d{5})b
That will match:
(?:Non capturing group
d{10}Match 10 digits
|Or
+d{2}[-s]?d{3}-?d{5}Match+, 2 digits, optional whitespace char or-, 3 digits, optional-, 5 digits
)bClose non capturing group and word boundary
Regex demo
If your language supports negative lookbehinds you could prepend (?<!S) which checks that what comes before is not a non-whitespace character.
answered Jan 2 at 18:37
The fourth birdThe fourth bird
24.5k81629
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
You may use this regex:
^+?d+(?:[s-]d+)*b
RegEx Details:
^+?: Match optional+at start
d+: match 1+ digits
(?:[s-]d+)*: Match 0 or more groups that start with whitespace or-followed by 1+ digits
$: End (Replaced by word boundary as if there are trailing spaces, that match would be missed.)
edited Jan 3 at 15:07
Deep
193211
answered Jan 2 at 16:51
anubhavaanubhava
533k48331408
add a comment |
You may use this regex:
^+?d+(?:[s-]d+)*b
RegEx Details:
^+?: Match optional+at start
d+: match 1+ digits
(?:[s-]d+)*: Match 0 or more groups that start with whitespace or-followed by 1+ digits
$: End (Replaced by word boundary as if there are trailing spaces, that match would be missed.)
edited Jan 3 at 15:07
Deep
193211
answered Jan 2 at 16:51
anubhavaanubhava
533k48331408
add a comment |
You may use this regex:
^+?d+(?:[s-]d+)*b
RegEx Details:
^+?: Match optional+at start
d+: match 1+ digits
(?:[s-]d+)*: Match 0 or more groups that start with whitespace or-followed by 1+ digits
$: End (Replaced by word boundary as if there are trailing spaces, that match would be missed.)
edited Jan 3 at 15:07
Deep
193211
answered Jan 2 at 16:51
anubhavaanubhava
533k48331408
You may use this regex:
^+?d+(?:[s-]d+)*b
RegEx Details:
^+?: Match optional+at start
d+: match 1+ digits
(?:[s-]d+)*: Match 0 or more groups that start with whitespace or-followed by 1+ digits
$: End (Replaced by word boundary as if there are trailing spaces, that match would be missed.)
edited Jan 3 at 15:07
Deep
193211
answered Jan 2 at 16:51
anubhavaanubhava
533k48331408
edited Jan 3 at 15:07
Deep
193211
edited Jan 3 at 15:07
Deep
193211
edited Jan 3 at 15:07
Deep
193211
193211
answered Jan 2 at 16:51
anubhavaanubhava
533k48331408
answered Jan 2 at 16:51
anubhavaanubhava
533k48331408
answered Jan 2 at 16:51
anubhavaanubhava
533k48331408
533k48331408
add a comment |
add a comment |
This should work:
(?:[d +-]+)+
answered Jan 2 at 16:36
feliksfeliks
1,070316
1
This matches all spaces as well: regex101.com/r/IoWOhp/2
– Dinuka
Jan 2 at 16:38
add a comment |
This should work:
(?:[d +-]+)+
answered Jan 2 at 16:36
feliksfeliks
1,070316
1
This matches all spaces as well: regex101.com/r/IoWOhp/2
– Dinuka
Jan 2 at 16:38
add a comment |
This should work:
(?:[d +-]+)+
answered Jan 2 at 16:36
feliksfeliks
1,070316
This should work:
(?:[d +-]+)+
answered Jan 2 at 16:36
feliksfeliks
1,070316
answered Jan 2 at 16:36
feliksfeliks
1,070316
answered Jan 2 at 16:36
feliksfeliks
1,070316
answered Jan 2 at 16:36
feliksfeliks
1,070316
1,070316
1
This matches all spaces as well: regex101.com/r/IoWOhp/2
– Dinuka
Jan 2 at 16:38
add a comment |
1
This matches all spaces as well: regex101.com/r/IoWOhp/2
– Dinuka
Jan 2 at 16:38
1
1
This matches all spaces as well: regex101.com/r/IoWOhp/2
– Dinuka
Jan 2 at 16:38
This matches all spaces as well: regex101.com/r/IoWOhp/2
– Dinuka
Jan 2 at 16:38
add a comment |
This would work as per your reqt: (If there are trailing spaces, this regex will ignore.)
Regex: '^(?:[d +-]+)b'
answered Jan 2 at 17:08
DeepDeep
193211
add a comment |
This would work as per your reqt: (If there are trailing spaces, this regex will ignore.)
Regex: '^(?:[d +-]+)b'
answered Jan 2 at 17:08
DeepDeep
193211
add a comment |
This would work as per your reqt: (If there are trailing spaces, this regex will ignore.)
Regex: '^(?:[d +-]+)b'
answered Jan 2 at 17:08
DeepDeep
193211
This would work as per your reqt: (If there are trailing spaces, this regex will ignore.)
Regex: '^(?:[d +-]+)b'
answered Jan 2 at 17:08
DeepDeep
193211
edited Jan 2 at 18:11
answered Jan 2 at 17:08
DeepDeep
193211
answered Jan 2 at 17:08
DeepDeep
193211
answered Jan 2 at 17:08
DeepDeep
193211
193211
add a comment |
add a comment |
Another option could be to use an alternation to match either 10 digits without a leading plus sign or match the pattern with a +, and optional space or hyphen:
(?:d{10}|+d{2}[- ]?d{3}-?d{5})b
That will match:
(?:Non capturing group
d{10}Match 10 digits
|Or
+d{2}[-s]?d{3}-?d{5}Match+, 2 digits, optional whitespace char or-, 3 digits, optional-, 5 digits
)bClose non capturing group and word boundary
Regex demo
If your language supports negative lookbehinds you could prepend (?<!S) which checks that what comes before is not a non-whitespace character.
answered Jan 2 at 18:37
The fourth birdThe fourth bird
24.5k81629
add a comment |
Another option could be to use an alternation to match either 10 digits without a leading plus sign or match the pattern with a +, and optional space or hyphen:
(?:d{10}|+d{2}[- ]?d{3}-?d{5})b
That will match:
(?:Non capturing group
d{10}Match 10 digits
|Or
+d{2}[-s]?d{3}-?d{5}Match+, 2 digits, optional whitespace char or-, 3 digits, optional-, 5 digits
)bClose non capturing group and word boundary
Regex demo
If your language supports negative lookbehinds you could prepend (?<!S) which checks that what comes before is not a non-whitespace character.
answered Jan 2 at 18:37
The fourth birdThe fourth bird
24.5k81629
add a comment |
Another option could be to use an alternation to match either 10 digits without a leading plus sign or match the pattern with a +, and optional space or hyphen:
(?:d{10}|+d{2}[- ]?d{3}-?d{5})b
That will match:
(?:Non capturing group
d{10}Match 10 digits
|Or
+d{2}[-s]?d{3}-?d{5}Match+, 2 digits, optional whitespace char or-, 3 digits, optional-, 5 digits
)bClose non capturing group and word boundary
Regex demo
If your language supports negative lookbehinds you could prepend (?<!S) which checks that what comes before is not a non-whitespace character.
answered Jan 2 at 18:37
The fourth birdThe fourth bird
24.5k81629
Another option could be to use an alternation to match either 10 digits without a leading plus sign or match the pattern with a +, and optional space or hyphen:
(?:d{10}|+d{2}[- ]?d{3}-?d{5})b
That will match:
(?:Non capturing group
d{10}Match 10 digits
|Or
+d{2}[-s]?d{3}-?d{5}Match+, 2 digits, optional whitespace char or-, 3 digits, optional-, 5 digits
)bClose non capturing group and word boundary
Regex demo
If your language supports negative lookbehinds you could prepend (?<!S) which checks that what comes before is not a non-whitespace character.
answered Jan 2 at 18:37
The fourth birdThe fourth bird
24.5k81629
edited Jan 2 at 19:51
answered Jan 2 at 18:37
The fourth birdThe fourth bird
24.5k81629
answered Jan 2 at 18:37
The fourth birdThe fourth bird
24.5k81629
answered Jan 2 at 18:37
The fourth birdThe fourth bird
24.5k81629
24.5k81629
add a comment |
add a comment |
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@Delgan Close! it includes a trailing space if there's any space after the number: "Hi my number is 0172665476 okay?"
– Dinuka
Jan 2 at 16:40
check this regex101.com/r/wxIiPs/2
– Code Maniac
Jan 2 at 16:44