Mixing
The Elimination Method
$begingroup$
I know how to use the elimination method - just that I can't quite figure it out on these type of linear systems:
$$
begin{array}{ccc}
y &=& –frac{5}{3}x + 3 \
y &=& frac{1}{3}x - 3
end{array}
$$
They do line up perfectly, so does this mean it becomes:
$
0 = dfrac{-4x}{3}
$??
linear-algebra systems-of-equations
edited Jan 28 at 12:43
Harry Peter
5,48911439
asked Jan 24 at 13:22
Kelly ChoiKelly Choi
121
$endgroup$
add a comment |
$begingroup$
I know how to use the elimination method - just that I can't quite figure it out on these type of linear systems:
$$
begin{array}{ccc}
y &=& –frac{5}{3}x + 3 \
y &=& frac{1}{3}x - 3
end{array}
$$
They do line up perfectly, so does this mean it becomes:
$
0 = dfrac{-4x}{3}
$??
linear-algebra systems-of-equations
edited Jan 28 at 12:43
Harry Peter
5,48911439
asked Jan 24 at 13:22
Kelly ChoiKelly Choi
121
$endgroup$
1
$begingroup$
Look again. It would be $0 = 2x - 6$.
$endgroup$
– steven gregory
Jan 24 at 13:38
add a comment |
$begingroup$
I know how to use the elimination method - just that I can't quite figure it out on these type of linear systems:
$$
begin{array}{ccc}
y &=& –frac{5}{3}x + 3 \
y &=& frac{1}{3}x - 3
end{array}
$$
They do line up perfectly, so does this mean it becomes:
$
0 = dfrac{-4x}{3}
$??
linear-algebra systems-of-equations
edited Jan 28 at 12:43
Harry Peter
5,48911439
asked Jan 24 at 13:22
Kelly ChoiKelly Choi
121
$endgroup$
I know how to use the elimination method - just that I can't quite figure it out on these type of linear systems:
$$
begin{array}{ccc}
y &=& –frac{5}{3}x + 3 \
y &=& frac{1}{3}x - 3
end{array}
$$
They do line up perfectly, so does this mean it becomes:
$
0 = dfrac{-4x}{3}
$??
linear-algebra systems-of-equations
linear-algebra systems-of-equations
edited Jan 28 at 12:43
Harry Peter
5,48911439
asked Jan 24 at 13:22
Kelly ChoiKelly Choi
121
edited Jan 28 at 12:43
Harry Peter
5,48911439
asked Jan 24 at 13:22
Kelly ChoiKelly Choi
121
edited Jan 28 at 12:43
Harry Peter
5,48911439
edited Jan 28 at 12:43
Harry Peter
5,48911439
edited Jan 28 at 12:43
Harry Peter
5,48911439
5,48911439
asked Jan 24 at 13:22
Kelly ChoiKelly Choi
121
asked Jan 24 at 13:22
Kelly ChoiKelly Choi
121
asked Jan 24 at 13:22
Kelly ChoiKelly Choi
121
121
1
$begingroup$
Look again. It would be $0 = 2x - 6$.
$endgroup$
– steven gregory
Jan 24 at 13:38
add a comment |
1
$begingroup$
Look again. It would be $0 = 2x - 6$.
$endgroup$
– steven gregory
Jan 24 at 13:38
1
1
$begingroup$
Look again. It would be $0 = 2x - 6$.
$endgroup$
– steven gregory
Jan 24 at 13:38
$begingroup$
Look again. It would be $0 = 2x - 6$.
$endgroup$
– steven gregory
Jan 24 at 13:38
add a comment |
1 Answer
1
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$begingroup$
Looks like you added the equations since the 3's cancelled. Then left side is $2y$ not $0.$ Try subtracting instead.
answered Jan 24 at 13:26
coffeemathcoffeemath
2,8971415
$endgroup$
1
$begingroup$
Oh shoot; thanks :)
$endgroup$
– Kelly Choi
Jan 24 at 23:28
add a comment |
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1 Answer
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1 Answer
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votes
$begingroup$
Looks like you added the equations since the 3's cancelled. Then left side is $2y$ not $0.$ Try subtracting instead.
answered Jan 24 at 13:26
coffeemathcoffeemath
2,8971415
$endgroup$
1
$begingroup$
Oh shoot; thanks :)
$endgroup$
– Kelly Choi
Jan 24 at 23:28
add a comment |
$begingroup$
Looks like you added the equations since the 3's cancelled. Then left side is $2y$ not $0.$ Try subtracting instead.
answered Jan 24 at 13:26
coffeemathcoffeemath
2,8971415
$endgroup$
1
$begingroup$
Oh shoot; thanks :)
$endgroup$
– Kelly Choi
Jan 24 at 23:28
add a comment |
$begingroup$
Looks like you added the equations since the 3's cancelled. Then left side is $2y$ not $0.$ Try subtracting instead.
answered Jan 24 at 13:26
coffeemathcoffeemath
2,8971415
$endgroup$
Looks like you added the equations since the 3's cancelled. Then left side is $2y$ not $0.$ Try subtracting instead.
answered Jan 24 at 13:26
coffeemathcoffeemath
2,8971415
answered Jan 24 at 13:26
coffeemathcoffeemath
2,8971415
answered Jan 24 at 13:26
coffeemathcoffeemath
2,8971415
answered Jan 24 at 13:26
coffeemathcoffeemath
2,8971415
2,8971415
1
$begingroup$
Oh shoot; thanks :)
$endgroup$
– Kelly Choi
Jan 24 at 23:28
add a comment |
1
$begingroup$
Oh shoot; thanks :)
$endgroup$
– Kelly Choi
Jan 24 at 23:28
1
1
$begingroup$
Oh shoot; thanks :)
$endgroup$
– Kelly Choi
Jan 24 at 23:28
$begingroup$
Oh shoot; thanks :)
$endgroup$
– Kelly Choi
Jan 24 at 23:28
add a comment |
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1
$begingroup$
Look again. It would be $0 = 2x - 6$.
$endgroup$
– steven gregory
Jan 24 at 13:38