Mixing
How to add a schema version number to a root node xml using data contracts?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I am working with serialization using data contracts and want to add a version number(schema version number in my case) and a check for the same on the very root node of my serialized document.
Something like this :
<ReportDocFormat version="1.0.2">
<FirstNode>
...
Further, I wan't to use this version number to decide whether or not to deserialize that document for that schema.
I have searched through the specification and on other sites but I can't find any possible ways to do it.
Is there any way to achieve this ?
c# .net serialization datacontract
asked Aug 17 '18 at 4:43
No nameNo name
14111
add a comment |
I am working with serialization using data contracts and want to add a version number(schema version number in my case) and a check for the same on the very root node of my serialized document.
Something like this :
<ReportDocFormat version="1.0.2">
<FirstNode>
...
Further, I wan't to use this version number to decide whether or not to deserialize that document for that schema.
I have searched through the specification and on other sites but I can't find any possible ways to do it.
Is there any way to achieve this ?
c# .net serialization datacontract
asked Aug 17 '18 at 4:43
No nameNo name
14111
Is this what you are looking for: stackoverflow.com/questions/12007079/… ?
– o_weisman
Jan 3 at 6:40
@o_weisman The working of 'VersionAttribute' in mentioned question at link is kind of similar I want to have.
– No name
Jan 3 at 6:47
add a comment |
I am working with serialization using data contracts and want to add a version number(schema version number in my case) and a check for the same on the very root node of my serialized document.
Something like this :
<ReportDocFormat version="1.0.2">
<FirstNode>
...
Further, I wan't to use this version number to decide whether or not to deserialize that document for that schema.
I have searched through the specification and on other sites but I can't find any possible ways to do it.
Is there any way to achieve this ?
c# .net serialization datacontract
asked Aug 17 '18 at 4:43
No nameNo name
14111
I am working with serialization using data contracts and want to add a version number(schema version number in my case) and a check for the same on the very root node of my serialized document.
Something like this :
<ReportDocFormat version="1.0.2">
<FirstNode>
...
Further, I wan't to use this version number to decide whether or not to deserialize that document for that schema.
I have searched through the specification and on other sites but I can't find any possible ways to do it.
Is there any way to achieve this ?
c# .net serialization datacontract
c# .net serialization datacontract
asked Aug 17 '18 at 4:43
No nameNo name
14111
asked Aug 17 '18 at 4:43
No nameNo name
14111
edited Jan 9 at 9:33
No name
asked Aug 17 '18 at 4:43
No nameNo name
14111
asked Aug 17 '18 at 4:43
No nameNo name
14111
asked Aug 17 '18 at 4:43
No nameNo name
14111
14111
Is this what you are looking for: stackoverflow.com/questions/12007079/… ?
– o_weisman
Jan 3 at 6:40
@o_weisman The working of 'VersionAttribute' in mentioned question at link is kind of similar I want to have.
– No name
Jan 3 at 6:47
add a comment |
Is this what you are looking for: stackoverflow.com/questions/12007079/… ?
– o_weisman
Jan 3 at 6:40
@o_weisman The working of 'VersionAttribute' in mentioned question at link is kind of similar I want to have.
– No name
Jan 3 at 6:47
Is this what you are looking for: stackoverflow.com/questions/12007079/… ?
– o_weisman
Jan 3 at 6:40
Is this what you are looking for: stackoverflow.com/questions/12007079/… ?
– o_weisman
Jan 3 at 6:40
@o_weisman The working of 'VersionAttribute' in mentioned question at link is kind of similar I want to have.
– No name
Jan 3 at 6:47
@o_weisman The working of 'VersionAttribute' in mentioned question at link is kind of similar I want to have.
– No name
Jan 3 at 6:47
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f51888495%2fhow-to-add-a-schema-version-number-to-a-root-node-xml-using-data-contracts%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f51888495%2fhow-to-add-a-schema-version-number-to-a-root-node-xml-using-data-contracts%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Is this what you are looking for: stackoverflow.com/questions/12007079/… ?
– o_weisman
Jan 3 at 6:40
@o_weisman The working of 'VersionAttribute' in mentioned question at link is kind of similar I want to have.
– No name
Jan 3 at 6:47