Mixing
Parse delimited string using awk and fetch the matched string
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
0
I have a delimited string variable as mentioned below. I would like to grep a matched string. I found some possible solutions on the Internet, but sadly they did not give me the result I was expecting. Can you suggest or correct me.
Input: 123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
Output: src_12
src_23
src_14
src_5
Logic: I need to fetch the string which has 'src_'. It's not always the second item in the list. The position may change. Variable length, delimited.
unix awk sed
edited Jan 3 at 10:33
kvantour
10.7k41732
asked Jan 3 at 6:18
srinathsrinath
447
add a comment |
0
I have a delimited string variable as mentioned below. I would like to grep a matched string. I found some possible solutions on the Internet, but sadly they did not give me the result I was expecting. Can you suggest or correct me.
Input: 123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
Output: src_12
src_23
src_14
src_5
Logic: I need to fetch the string which has 'src_'. It's not always the second item in the list. The position may change. Variable length, delimited.
unix awk sed
edited Jan 3 at 10:33
kvantour
10.7k41732
asked Jan 3 at 6:18
srinathsrinath
447
With GNU grep:grep -Po 'src_.*?b' file?
– Cyrus
Jan 3 at 6:21
Thanks Cyrus for editing the text and comments. i dont have file. input is an variable.
– srinath
Jan 3 at 6:23
1
grep -Po 'bsrc_.*?b' <<< "$variable"?
– Cyrus
Jan 3 at 6:34
What part of this question involvesbashshell and needs the tag?
– Inian
Jan 3 at 6:41
Sorry, this is not the way StackOverflow works. Questions of the form "I want to do X, please give me tips and/or sample code" are considered off-topic. Please visit the help center and read How to Ask, and especially read Why is “Can someone help me?” not an actual question?
– kvantour
Jan 3 at 10:40
add a comment |
0
0
0
1
I have a delimited string variable as mentioned below. I would like to grep a matched string. I found some possible solutions on the Internet, but sadly they did not give me the result I was expecting. Can you suggest or correct me.
Input: 123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
Output: src_12
src_23
src_14
src_5
Logic: I need to fetch the string which has 'src_'. It's not always the second item in the list. The position may change. Variable length, delimited.
unix awk sed
edited Jan 3 at 10:33
kvantour
10.7k41732
asked Jan 3 at 6:18
srinathsrinath
447
I have a delimited string variable as mentioned below. I would like to grep a matched string. I found some possible solutions on the Internet, but sadly they did not give me the result I was expecting. Can you suggest or correct me.
Input: 123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
Output: src_12
src_23
src_14
src_5
Logic: I need to fetch the string which has 'src_'. It's not always the second item in the list. The position may change. Variable length, delimited.
unix awk sed
unix awk sed
edited Jan 3 at 10:33
kvantour
10.7k41732
asked Jan 3 at 6:18
srinathsrinath
447
edited Jan 3 at 10:33
kvantour
10.7k41732
asked Jan 3 at 6:18
srinathsrinath
447
edited Jan 3 at 10:33
kvantour
10.7k41732
edited Jan 3 at 10:33
kvantour
10.7k41732
edited Jan 3 at 10:33
kvantour
10.7k41732
10.7k41732
asked Jan 3 at 6:18
srinathsrinath
447
asked Jan 3 at 6:18
srinathsrinath
447
asked Jan 3 at 6:18
srinathsrinath
447
447
With GNU grep:grep -Po 'src_.*?b' file?
– Cyrus
Jan 3 at 6:21
Thanks Cyrus for editing the text and comments. i dont have file. input is an variable.
– srinath
Jan 3 at 6:23
1
grep -Po 'bsrc_.*?b' <<< "$variable"?
– Cyrus
Jan 3 at 6:34
What part of this question involvesbashshell and needs the tag?
– Inian
Jan 3 at 6:41
Sorry, this is not the way StackOverflow works. Questions of the form "I want to do X, please give me tips and/or sample code" are considered off-topic. Please visit the help center and read How to Ask, and especially read Why is “Can someone help me?” not an actual question?
– kvantour
Jan 3 at 10:40
add a comment |
With GNU grep:grep -Po 'src_.*?b' file?
– Cyrus
Jan 3 at 6:21
Thanks Cyrus for editing the text and comments. i dont have file. input is an variable.
– srinath
Jan 3 at 6:23
1
grep -Po 'bsrc_.*?b' <<< "$variable"?
– Cyrus
Jan 3 at 6:34
What part of this question involvesbashshell and needs the tag?
– Inian
Jan 3 at 6:41
Sorry, this is not the way StackOverflow works. Questions of the form "I want to do X, please give me tips and/or sample code" are considered off-topic. Please visit the help center and read How to Ask, and especially read Why is “Can someone help me?” not an actual question?
– kvantour
Jan 3 at 10:40
With GNU grep:
grep -Po 'src_.*?b' file?– Cyrus
Jan 3 at 6:21
With GNU grep:
grep -Po 'src_.*?b' file?– Cyrus
Jan 3 at 6:21
Thanks Cyrus for editing the text and comments. i dont have file. input is an variable.
– srinath
Jan 3 at 6:23
Thanks Cyrus for editing the text and comments. i dont have file. input is an variable.
– srinath
Jan 3 at 6:23
1
1
grep -Po 'bsrc_.*?b' <<< "$variable"?– Cyrus
Jan 3 at 6:34
grep -Po 'bsrc_.*?b' <<< "$variable"?– Cyrus
Jan 3 at 6:34
What part of this question involves
bash shell and needs the tag?– Inian
Jan 3 at 6:41
What part of this question involves
bash shell and needs the tag?– Inian
Jan 3 at 6:41
Sorry, this is not the way StackOverflow works. Questions of the form "I want to do X, please give me tips and/or sample code" are considered off-topic. Please visit the help center and read How to Ask, and especially read Why is “Can someone help me?” not an actual question?
– kvantour
Jan 3 at 10:40
Sorry, this is not the way StackOverflow works. Questions of the form "I want to do X, please give me tips and/or sample code" are considered off-topic. Please visit the help center and read How to Ask, and especially read Why is “Can someone help me?” not an actual question?
– kvantour
Jan 3 at 10:40
add a comment |
7 Answers
7
active
oldest
votes
1
With simple awk solution:
awk 'match($0,/src_[0-9]+/){print substr($0,RSTART,RLENGTH)}' Input_file
or
awk '{sub(/.*src/,"src");sub(/,.*/,"")} 1' Input_file
edited Jan 3 at 10:31
kvantour
10.7k41732
answered Jan 3 at 6:37
RavinderSingh13RavinderSingh13
30.6k41639
1
When no match scenarios, it gives first string. How to avoid it
– srinath
Jan 4 at 2:14
@srinath, please try to run first command only which should give output when a match is found only.
– RavinderSingh13
Jan 4 at 2:30
first statement fails when i have src_abc (non numeric) one.
– srinath
Jan 4 at 9:11
@srinath, trysrc_[0-9a-zA-Z]+on place ofsrc_[0-9]+/once and let know?
– RavinderSingh13
Jan 4 at 9:13
it worked partial. for src_12_abc i am getting src_12 only. i need data till next delimiter.
– srinath
Jan 4 at 9:24
|
show 2 more comments
1
With bash:
while IFS="," read -a array; do
for element in "${array[@]}"; do
[[ $element =~ ^src_ ]] && echo "$element"
done
done <<< "$variable"
Output:
src_12
src_23
src_14
src_5
answered Jan 3 at 6:38
CyrusCyrus
47.1k43880
add a comment |
1
Using tr
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ A=$(cat srinath.txt2)
$ tr ',' 'n' <<< "$A" | grep ^src
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:39
stack0114106stack0114106
4,9832423
You can avoid thecat, but this will also pick up stuff likevsrc_blabla
– kvantour
Jan 3 at 10:35
I wanted to post about the same answer, only usinggrep "^src_"avoidingvsrc_blabla
– Walter A
Jan 3 at 10:37
Thanks @kvantour for the review.. updated the answer
– stack0114106
Jan 3 at 11:04
@Walter.. thank you.. updated the answer
– stack0114106
Jan 3 at 11:04
add a comment |
0
Using Perl
$ cat srinath.txt
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
$ perl -nle ' /(src_d+)/ and print $1 ' srinath.txt
src_12
src_23
src_14
src_5
If you have more than one src_ in the same line, then use below
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' srinath.txt2
src_12
src_23
src_14
src_5
src_6
src_7
If it is in a variable, then
$ A=$(cat srinath.txt2)
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
or
$ export A="123,src_12,234,456,1,23,34,src_23,4,56,7,src_14,12,12,3,5,src_5,src_6,src_7,16,18"
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
$ perl -le ' $_=$ENV{A}; while( /(src_d+)/g ) { print $1 } '
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:25
stack0114106stack0114106
4,9832423
i need in unix/DOS. its in middle of my program.
– srinath
Jan 3 at 6:26
yes.. you can call perl in middle of the bash program
– stack0114106
Jan 3 at 6:28
updated the answer for working with variables
– stack0114106
Jan 3 at 6:31
Thank you for quick answer @stack0114106. I dont want to increase dependency by using perl. let me figure it out with bash. if nothing is working, i will use your solution.
– srinath
Jan 3 at 6:34
add a comment |
0
This might work for you (GNU sed):
sed '/n/!s/src_[^,]*/n&n/g;/^src_/P;D' file
Surround all candidate strings by newlines and then using the sed commands P and D whittle down each line printing only the candidates with the prefix src_.
answered Jan 3 at 10:23
potongpotong
36.3k43062
add a comment |
0
A simple grep returning only (-o) the matched words (-w)
$ grep -wo 'src_[^,]*' file
src_12
src_23
src_14
src_5
answered Jan 3 at 10:39
kvantourkvantour
10.7k41732
add a comment |
0
Look for ^src_xxx,, ,src_xxx, and ,src_xxx$, and only print the match without the ,.
sed -rn 's/.*(,|^)(src_[^,]*)(,|$).*/2/p'
answered Jan 3 at 10:49
Walter AWalter A
11.1k21132
add a comment |
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7 Answers
7
active
oldest
votes
7 Answers
7
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
With simple awk solution:
awk 'match($0,/src_[0-9]+/){print substr($0,RSTART,RLENGTH)}' Input_file
or
awk '{sub(/.*src/,"src");sub(/,.*/,"")} 1' Input_file
edited Jan 3 at 10:31
kvantour
10.7k41732
answered Jan 3 at 6:37
RavinderSingh13RavinderSingh13
30.6k41639
1
When no match scenarios, it gives first string. How to avoid it
– srinath
Jan 4 at 2:14
@srinath, please try to run first command only which should give output when a match is found only.
– RavinderSingh13
Jan 4 at 2:30
first statement fails when i have src_abc (non numeric) one.
– srinath
Jan 4 at 9:11
@srinath, trysrc_[0-9a-zA-Z]+on place ofsrc_[0-9]+/once and let know?
– RavinderSingh13
Jan 4 at 9:13
it worked partial. for src_12_abc i am getting src_12 only. i need data till next delimiter.
– srinath
Jan 4 at 9:24
|
show 2 more comments
1
With simple awk solution:
awk 'match($0,/src_[0-9]+/){print substr($0,RSTART,RLENGTH)}' Input_file
or
awk '{sub(/.*src/,"src");sub(/,.*/,"")} 1' Input_file
edited Jan 3 at 10:31
kvantour
10.7k41732
answered Jan 3 at 6:37
RavinderSingh13RavinderSingh13
30.6k41639
1
When no match scenarios, it gives first string. How to avoid it
– srinath
Jan 4 at 2:14
@srinath, please try to run first command only which should give output when a match is found only.
– RavinderSingh13
Jan 4 at 2:30
first statement fails when i have src_abc (non numeric) one.
– srinath
Jan 4 at 9:11
@srinath, trysrc_[0-9a-zA-Z]+on place ofsrc_[0-9]+/once and let know?
– RavinderSingh13
Jan 4 at 9:13
it worked partial. for src_12_abc i am getting src_12 only. i need data till next delimiter.
– srinath
Jan 4 at 9:24
|
show 2 more comments
1
1
1
With simple awk solution:
awk 'match($0,/src_[0-9]+/){print substr($0,RSTART,RLENGTH)}' Input_file
or
awk '{sub(/.*src/,"src");sub(/,.*/,"")} 1' Input_file
edited Jan 3 at 10:31
kvantour
10.7k41732
answered Jan 3 at 6:37
RavinderSingh13RavinderSingh13
30.6k41639
With simple awk solution:
awk 'match($0,/src_[0-9]+/){print substr($0,RSTART,RLENGTH)}' Input_file
or
awk '{sub(/.*src/,"src");sub(/,.*/,"")} 1' Input_file
edited Jan 3 at 10:31
kvantour
10.7k41732
answered Jan 3 at 6:37
RavinderSingh13RavinderSingh13
30.6k41639
edited Jan 3 at 10:31
kvantour
10.7k41732
edited Jan 3 at 10:31
kvantour
10.7k41732
edited Jan 3 at 10:31
kvantour
10.7k41732
10.7k41732
answered Jan 3 at 6:37
RavinderSingh13RavinderSingh13
30.6k41639
answered Jan 3 at 6:37
RavinderSingh13RavinderSingh13
30.6k41639
answered Jan 3 at 6:37
RavinderSingh13RavinderSingh13
30.6k41639
30.6k41639
1
When no match scenarios, it gives first string. How to avoid it
– srinath
Jan 4 at 2:14
@srinath, please try to run first command only which should give output when a match is found only.
– RavinderSingh13
Jan 4 at 2:30
first statement fails when i have src_abc (non numeric) one.
– srinath
Jan 4 at 9:11
@srinath, trysrc_[0-9a-zA-Z]+on place ofsrc_[0-9]+/once and let know?
– RavinderSingh13
Jan 4 at 9:13
it worked partial. for src_12_abc i am getting src_12 only. i need data till next delimiter.
– srinath
Jan 4 at 9:24
|
show 2 more comments
1
When no match scenarios, it gives first string. How to avoid it
– srinath
Jan 4 at 2:14
@srinath, please try to run first command only which should give output when a match is found only.
– RavinderSingh13
Jan 4 at 2:30
first statement fails when i have src_abc (non numeric) one.
– srinath
Jan 4 at 9:11
@srinath, trysrc_[0-9a-zA-Z]+on place ofsrc_[0-9]+/once and let know?
– RavinderSingh13
Jan 4 at 9:13
it worked partial. for src_12_abc i am getting src_12 only. i need data till next delimiter.
– srinath
Jan 4 at 9:24
1
1
When no match scenarios, it gives first string. How to avoid it
– srinath
Jan 4 at 2:14
When no match scenarios, it gives first string. How to avoid it
– srinath
Jan 4 at 2:14
@srinath, please try to run first command only which should give output when a match is found only.
– RavinderSingh13
Jan 4 at 2:30
@srinath, please try to run first command only which should give output when a match is found only.
– RavinderSingh13
Jan 4 at 2:30
first statement fails when i have src_abc (non numeric) one.
– srinath
Jan 4 at 9:11
first statement fails when i have src_abc (non numeric) one.
– srinath
Jan 4 at 9:11
@srinath, try
src_[0-9a-zA-Z]+ on place of src_[0-9]+/ once and let know?– RavinderSingh13
Jan 4 at 9:13
@srinath, try
src_[0-9a-zA-Z]+ on place of src_[0-9]+/ once and let know?– RavinderSingh13
Jan 4 at 9:13
it worked partial. for src_12_abc i am getting src_12 only. i need data till next delimiter.
– srinath
Jan 4 at 9:24
it worked partial. for src_12_abc i am getting src_12 only. i need data till next delimiter.
– srinath
Jan 4 at 9:24
|
show 2 more comments
1
With bash:
while IFS="," read -a array; do
for element in "${array[@]}"; do
[[ $element =~ ^src_ ]] && echo "$element"
done
done <<< "$variable"
Output:
src_12
src_23
src_14
src_5
answered Jan 3 at 6:38
CyrusCyrus
47.1k43880
add a comment |
1
With bash:
while IFS="," read -a array; do
for element in "${array[@]}"; do
[[ $element =~ ^src_ ]] && echo "$element"
done
done <<< "$variable"
Output:
src_12
src_23
src_14
src_5
answered Jan 3 at 6:38
CyrusCyrus
47.1k43880
add a comment |
1
1
1
With bash:
while IFS="," read -a array; do
for element in "${array[@]}"; do
[[ $element =~ ^src_ ]] && echo "$element"
done
done <<< "$variable"
Output:
src_12
src_23
src_14
src_5
answered Jan 3 at 6:38
CyrusCyrus
47.1k43880
With bash:
while IFS="," read -a array; do
for element in "${array[@]}"; do
[[ $element =~ ^src_ ]] && echo "$element"
done
done <<< "$variable"
Output:
src_12
src_23
src_14
src_5
answered Jan 3 at 6:38
CyrusCyrus
47.1k43880
answered Jan 3 at 6:38
CyrusCyrus
47.1k43880
answered Jan 3 at 6:38
CyrusCyrus
47.1k43880
answered Jan 3 at 6:38
CyrusCyrus
47.1k43880
47.1k43880
add a comment |
add a comment |
1
Using tr
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ A=$(cat srinath.txt2)
$ tr ',' 'n' <<< "$A" | grep ^src
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:39
stack0114106stack0114106
4,9832423
You can avoid thecat, but this will also pick up stuff likevsrc_blabla
– kvantour
Jan 3 at 10:35
I wanted to post about the same answer, only usinggrep "^src_"avoidingvsrc_blabla
– Walter A
Jan 3 at 10:37
Thanks @kvantour for the review.. updated the answer
– stack0114106
Jan 3 at 11:04
@Walter.. thank you.. updated the answer
– stack0114106
Jan 3 at 11:04
add a comment |
1
Using tr
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ A=$(cat srinath.txt2)
$ tr ',' 'n' <<< "$A" | grep ^src
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:39
stack0114106stack0114106
4,9832423
You can avoid thecat, but this will also pick up stuff likevsrc_blabla
– kvantour
Jan 3 at 10:35
I wanted to post about the same answer, only usinggrep "^src_"avoidingvsrc_blabla
– Walter A
Jan 3 at 10:37
Thanks @kvantour for the review.. updated the answer
– stack0114106
Jan 3 at 11:04
@Walter.. thank you.. updated the answer
– stack0114106
Jan 3 at 11:04
add a comment |
1
1
1
Using tr
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ A=$(cat srinath.txt2)
$ tr ',' 'n' <<< "$A" | grep ^src
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:39
stack0114106stack0114106
4,9832423
Using tr
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ A=$(cat srinath.txt2)
$ tr ',' 'n' <<< "$A" | grep ^src
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:39
stack0114106stack0114106
4,9832423
edited Jan 3 at 11:03
answered Jan 3 at 6:39
stack0114106stack0114106
4,9832423
answered Jan 3 at 6:39
stack0114106stack0114106
4,9832423
answered Jan 3 at 6:39
stack0114106stack0114106
4,9832423
4,9832423
You can avoid thecat, but this will also pick up stuff likevsrc_blabla
– kvantour
Jan 3 at 10:35
I wanted to post about the same answer, only usinggrep "^src_"avoidingvsrc_blabla
– Walter A
Jan 3 at 10:37
Thanks @kvantour for the review.. updated the answer
– stack0114106
Jan 3 at 11:04
@Walter.. thank you.. updated the answer
– stack0114106
Jan 3 at 11:04
add a comment |
You can avoid thecat, but this will also pick up stuff likevsrc_blabla
– kvantour
Jan 3 at 10:35
I wanted to post about the same answer, only usinggrep "^src_"avoidingvsrc_blabla
– Walter A
Jan 3 at 10:37
Thanks @kvantour for the review.. updated the answer
– stack0114106
Jan 3 at 11:04
@Walter.. thank you.. updated the answer
– stack0114106
Jan 3 at 11:04
You can avoid the
cat, but this will also pick up stuff like vsrc_blabla– kvantour
Jan 3 at 10:35
You can avoid the
cat, but this will also pick up stuff like vsrc_blabla– kvantour
Jan 3 at 10:35
I wanted to post about the same answer, only using
grep "^src_" avoiding vsrc_blabla– Walter A
Jan 3 at 10:37
I wanted to post about the same answer, only using
grep "^src_" avoiding vsrc_blabla– Walter A
Jan 3 at 10:37
Thanks @kvantour for the review.. updated the answer
– stack0114106
Jan 3 at 11:04
Thanks @kvantour for the review.. updated the answer
– stack0114106
Jan 3 at 11:04
@Walter.. thank you.. updated the answer
– stack0114106
Jan 3 at 11:04
@Walter.. thank you.. updated the answer
– stack0114106
Jan 3 at 11:04
add a comment |
0
Using Perl
$ cat srinath.txt
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
$ perl -nle ' /(src_d+)/ and print $1 ' srinath.txt
src_12
src_23
src_14
src_5
If you have more than one src_ in the same line, then use below
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' srinath.txt2
src_12
src_23
src_14
src_5
src_6
src_7
If it is in a variable, then
$ A=$(cat srinath.txt2)
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
or
$ export A="123,src_12,234,456,1,23,34,src_23,4,56,7,src_14,12,12,3,5,src_5,src_6,src_7,16,18"
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
$ perl -le ' $_=$ENV{A}; while( /(src_d+)/g ) { print $1 } '
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:25
stack0114106stack0114106
4,9832423
i need in unix/DOS. its in middle of my program.
– srinath
Jan 3 at 6:26
yes.. you can call perl in middle of the bash program
– stack0114106
Jan 3 at 6:28
updated the answer for working with variables
– stack0114106
Jan 3 at 6:31
Thank you for quick answer @stack0114106. I dont want to increase dependency by using perl. let me figure it out with bash. if nothing is working, i will use your solution.
– srinath
Jan 3 at 6:34
add a comment |
0
Using Perl
$ cat srinath.txt
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
$ perl -nle ' /(src_d+)/ and print $1 ' srinath.txt
src_12
src_23
src_14
src_5
If you have more than one src_ in the same line, then use below
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' srinath.txt2
src_12
src_23
src_14
src_5
src_6
src_7
If it is in a variable, then
$ A=$(cat srinath.txt2)
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
or
$ export A="123,src_12,234,456,1,23,34,src_23,4,56,7,src_14,12,12,3,5,src_5,src_6,src_7,16,18"
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
$ perl -le ' $_=$ENV{A}; while( /(src_d+)/g ) { print $1 } '
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:25
stack0114106stack0114106
4,9832423
i need in unix/DOS. its in middle of my program.
– srinath
Jan 3 at 6:26
yes.. you can call perl in middle of the bash program
– stack0114106
Jan 3 at 6:28
updated the answer for working with variables
– stack0114106
Jan 3 at 6:31
Thank you for quick answer @stack0114106. I dont want to increase dependency by using perl. let me figure it out with bash. if nothing is working, i will use your solution.
– srinath
Jan 3 at 6:34
add a comment |
0
0
0
Using Perl
$ cat srinath.txt
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
$ perl -nle ' /(src_d+)/ and print $1 ' srinath.txt
src_12
src_23
src_14
src_5
If you have more than one src_ in the same line, then use below
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' srinath.txt2
src_12
src_23
src_14
src_5
src_6
src_7
If it is in a variable, then
$ A=$(cat srinath.txt2)
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
or
$ export A="123,src_12,234,456,1,23,34,src_23,4,56,7,src_14,12,12,3,5,src_5,src_6,src_7,16,18"
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
$ perl -le ' $_=$ENV{A}; while( /(src_d+)/g ) { print $1 } '
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:25
stack0114106stack0114106
4,9832423
Using Perl
$ cat srinath.txt
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
$ perl -nle ' /(src_d+)/ and print $1 ' srinath.txt
src_12
src_23
src_14
src_5
If you have more than one src_ in the same line, then use below
$ cat srinath.txt2
123,src_12,234,456
1,23,34,src_23,4,56,7
src_14,12
12,3,5,src_5
src_6,src_7,16,18
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' srinath.txt2
src_12
src_23
src_14
src_5
src_6
src_7
If it is in a variable, then
$ A=$(cat srinath.txt2)
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
or
$ export A="123,src_12,234,456,1,23,34,src_23,4,56,7,src_14,12,12,3,5,src_5,src_6,src_7,16,18"
$ perl -nle ' while( /(src_d+)/g ) { print $1 } ' <<< "$A"
src_12
src_23
src_14
src_5
src_6
src_7
$ perl -le ' $_=$ENV{A}; while( /(src_d+)/g ) { print $1 } '
src_12
src_23
src_14
src_5
src_6
src_7
answered Jan 3 at 6:25
stack0114106stack0114106
4,9832423
edited Jan 3 at 6:34
answered Jan 3 at 6:25
stack0114106stack0114106
4,9832423
answered Jan 3 at 6:25
stack0114106stack0114106
4,9832423
answered Jan 3 at 6:25
stack0114106stack0114106
4,9832423
4,9832423
i need in unix/DOS. its in middle of my program.
– srinath
Jan 3 at 6:26
yes.. you can call perl in middle of the bash program
– stack0114106
Jan 3 at 6:28
updated the answer for working with variables
– stack0114106
Jan 3 at 6:31
Thank you for quick answer @stack0114106. I dont want to increase dependency by using perl. let me figure it out with bash. if nothing is working, i will use your solution.
– srinath
Jan 3 at 6:34
add a comment |
i need in unix/DOS. its in middle of my program.
– srinath
Jan 3 at 6:26
yes.. you can call perl in middle of the bash program
– stack0114106
Jan 3 at 6:28
updated the answer for working with variables
– stack0114106
Jan 3 at 6:31
Thank you for quick answer @stack0114106. I dont want to increase dependency by using perl. let me figure it out with bash. if nothing is working, i will use your solution.
– srinath
Jan 3 at 6:34
i need in unix/DOS. its in middle of my program.
– srinath
Jan 3 at 6:26
i need in unix/DOS. its in middle of my program.
– srinath
Jan 3 at 6:26
yes.. you can call perl in middle of the bash program
– stack0114106
Jan 3 at 6:28
yes.. you can call perl in middle of the bash program
– stack0114106
Jan 3 at 6:28
updated the answer for working with variables
– stack0114106
Jan 3 at 6:31
updated the answer for working with variables
– stack0114106
Jan 3 at 6:31
Thank you for quick answer @stack0114106. I dont want to increase dependency by using perl. let me figure it out with bash. if nothing is working, i will use your solution.
– srinath
Jan 3 at 6:34
Thank you for quick answer @stack0114106. I dont want to increase dependency by using perl. let me figure it out with bash. if nothing is working, i will use your solution.
– srinath
Jan 3 at 6:34
add a comment |
0
This might work for you (GNU sed):
sed '/n/!s/src_[^,]*/n&n/g;/^src_/P;D' file
Surround all candidate strings by newlines and then using the sed commands P and D whittle down each line printing only the candidates with the prefix src_.
answered Jan 3 at 10:23
potongpotong
36.3k43062
add a comment |
0
This might work for you (GNU sed):
sed '/n/!s/src_[^,]*/n&n/g;/^src_/P;D' file
Surround all candidate strings by newlines and then using the sed commands P and D whittle down each line printing only the candidates with the prefix src_.
answered Jan 3 at 10:23
potongpotong
36.3k43062
add a comment |
0
0
0
This might work for you (GNU sed):
sed '/n/!s/src_[^,]*/n&n/g;/^src_/P;D' file
Surround all candidate strings by newlines and then using the sed commands P and D whittle down each line printing only the candidates with the prefix src_.
answered Jan 3 at 10:23
potongpotong
36.3k43062
This might work for you (GNU sed):
sed '/n/!s/src_[^,]*/n&n/g;/^src_/P;D' file
Surround all candidate strings by newlines and then using the sed commands P and D whittle down each line printing only the candidates with the prefix src_.
answered Jan 3 at 10:23
potongpotong
36.3k43062
answered Jan 3 at 10:23
potongpotong
36.3k43062
answered Jan 3 at 10:23
potongpotong
36.3k43062
answered Jan 3 at 10:23
potongpotong
36.3k43062
36.3k43062
add a comment |
add a comment |
0
A simple grep returning only (-o) the matched words (-w)
$ grep -wo 'src_[^,]*' file
src_12
src_23
src_14
src_5
answered Jan 3 at 10:39
kvantourkvantour
10.7k41732
add a comment |
0
A simple grep returning only (-o) the matched words (-w)
$ grep -wo 'src_[^,]*' file
src_12
src_23
src_14
src_5
answered Jan 3 at 10:39
kvantourkvantour
10.7k41732
add a comment |
0
0
0
A simple grep returning only (-o) the matched words (-w)
$ grep -wo 'src_[^,]*' file
src_12
src_23
src_14
src_5
answered Jan 3 at 10:39
kvantourkvantour
10.7k41732
A simple grep returning only (-o) the matched words (-w)
$ grep -wo 'src_[^,]*' file
src_12
src_23
src_14
src_5
answered Jan 3 at 10:39
kvantourkvantour
10.7k41732
answered Jan 3 at 10:39
kvantourkvantour
10.7k41732
answered Jan 3 at 10:39
kvantourkvantour
10.7k41732
answered Jan 3 at 10:39
kvantourkvantour
10.7k41732
10.7k41732
add a comment |
add a comment |
0
Look for ^src_xxx,, ,src_xxx, and ,src_xxx$, and only print the match without the ,.
sed -rn 's/.*(,|^)(src_[^,]*)(,|$).*/2/p'
answered Jan 3 at 10:49
Walter AWalter A
11.1k21132
add a comment |
0
Look for ^src_xxx,, ,src_xxx, and ,src_xxx$, and only print the match without the ,.
sed -rn 's/.*(,|^)(src_[^,]*)(,|$).*/2/p'
answered Jan 3 at 10:49
Walter AWalter A
11.1k21132
add a comment |
0
0
0
Look for ^src_xxx,, ,src_xxx, and ,src_xxx$, and only print the match without the ,.
sed -rn 's/.*(,|^)(src_[^,]*)(,|$).*/2/p'
answered Jan 3 at 10:49
Walter AWalter A
11.1k21132
Look for ^src_xxx,, ,src_xxx, and ,src_xxx$, and only print the match without the ,.
sed -rn 's/.*(,|^)(src_[^,]*)(,|$).*/2/p'
answered Jan 3 at 10:49
Walter AWalter A
11.1k21132
answered Jan 3 at 10:49
Walter AWalter A
11.1k21132
answered Jan 3 at 10:49
Walter AWalter A
11.1k21132
answered Jan 3 at 10:49
Walter AWalter A
11.1k21132
11.1k21132
add a comment |
add a comment |
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With GNU grep:
grep -Po 'src_.*?b' file?– Cyrus
Jan 3 at 6:21
Thanks Cyrus for editing the text and comments. i dont have file. input is an variable.
– srinath
Jan 3 at 6:23
1
grep -Po 'bsrc_.*?b' <<< "$variable"?– Cyrus
Jan 3 at 6:34
What part of this question involves
bashshell and needs the tag?– Inian
Jan 3 at 6:41
Sorry, this is not the way StackOverflow works. Questions of the form "I want to do X, please give me tips and/or sample code" are considered off-topic. Please visit the help center and read How to Ask, and especially read Why is “Can someone help me?” not an actual question?
– kvantour
Jan 3 at 10:40