Does Bash imitate Locale-Specific Translation from C?
Bash manual mentions that
3.1.2.5 Locale-Specific Translation
A double-quoted string preceded by a dollar sign (‘$’) will cause the
string to be translated according to the current locale. If the
current locale is C or POSIX, the dollar sign is ignored. If the
string is translated and replaced, the replacement is double-quoted.
Does this way of specifying a string literal exist in C language or some C library?
Does bash imitate this way from C?
bash string c
add a comment |
Bash manual mentions that
3.1.2.5 Locale-Specific Translation
A double-quoted string preceded by a dollar sign (‘$’) will cause the
string to be translated according to the current locale. If the
current locale is C or POSIX, the dollar sign is ignored. If the
string is translated and replaced, the replacement is double-quoted.
Does this way of specifying a string literal exist in C language or some C library?
Does bash imitate this way from C?
bash string c
add a comment |
Bash manual mentions that
3.1.2.5 Locale-Specific Translation
A double-quoted string preceded by a dollar sign (‘$’) will cause the
string to be translated according to the current locale. If the
current locale is C or POSIX, the dollar sign is ignored. If the
string is translated and replaced, the replacement is double-quoted.
Does this way of specifying a string literal exist in C language or some C library?
Does bash imitate this way from C?
bash string c
Bash manual mentions that
3.1.2.5 Locale-Specific Translation
A double-quoted string preceded by a dollar sign (‘$’) will cause the
string to be translated according to the current locale. If the
current locale is C or POSIX, the dollar sign is ignored. If the
string is translated and replaced, the replacement is double-quoted.
Does this way of specifying a string literal exist in C language or some C library?
Does bash imitate this way from C?
bash string c
bash string c
asked Nov 19 '18 at 23:09
Ben
2749
2749
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$"..."
is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...")
or _("...")
. Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $"
syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $'
ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "106"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f482859%2fdoes-bash-imitate-locale-specific-translation-from-c%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$"..."
is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...")
or _("...")
. Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $"
syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $'
ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
add a comment |
$"..."
is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...")
or _("...")
. Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $"
syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $'
ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
add a comment |
$"..."
is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...")
or _("...")
. Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $"
syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $'
ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
$"..."
is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...")
or _("...")
. Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $"
syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $'
ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
answered Nov 19 '18 at 23:32


Michael Homer
45.8k8121160
45.8k8121160
add a comment |
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f482859%2fdoes-bash-imitate-locale-specific-translation-from-c%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown