Sylvester equation over quaternion
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How to solve the Sylvester equation $$ax + xb = c$$ over quaternion? I tried to consider operator $$D = a^2 + acdot(b+overline{b}) + b cdot overline{b} $$ and calculate $Dx$. But it didn't help.
P.S: What is the general meaning of this equation?
Thank you in advance!
abstract-algebra quaternions sylvester-equation
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add a comment |
$begingroup$
How to solve the Sylvester equation $$ax + xb = c$$ over quaternion? I tried to consider operator $$D = a^2 + acdot(b+overline{b}) + b cdot overline{b} $$ and calculate $Dx$. But it didn't help.
P.S: What is the general meaning of this equation?
Thank you in advance!
abstract-algebra quaternions sylvester-equation
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What do you mean by general meaning? It means Sylvester's equation, not in $M_n(K)$, but in the quaternion algebra.
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– Dietrich Burde
Jan 6 at 19:27
add a comment |
$begingroup$
How to solve the Sylvester equation $$ax + xb = c$$ over quaternion? I tried to consider operator $$D = a^2 + acdot(b+overline{b}) + b cdot overline{b} $$ and calculate $Dx$. But it didn't help.
P.S: What is the general meaning of this equation?
Thank you in advance!
abstract-algebra quaternions sylvester-equation
$endgroup$
How to solve the Sylvester equation $$ax + xb = c$$ over quaternion? I tried to consider operator $$D = a^2 + acdot(b+overline{b}) + b cdot overline{b} $$ and calculate $Dx$. But it didn't help.
P.S: What is the general meaning of this equation?
Thank you in advance!
abstract-algebra quaternions sylvester-equation
abstract-algebra quaternions sylvester-equation
asked Jan 6 at 14:01


mathmaniacmathmaniac
18011
18011
$begingroup$
What do you mean by general meaning? It means Sylvester's equation, not in $M_n(K)$, but in the quaternion algebra.
$endgroup$
– Dietrich Burde
Jan 6 at 19:27
add a comment |
$begingroup$
What do you mean by general meaning? It means Sylvester's equation, not in $M_n(K)$, but in the quaternion algebra.
$endgroup$
– Dietrich Burde
Jan 6 at 19:27
$begingroup$
What do you mean by general meaning? It means Sylvester's equation, not in $M_n(K)$, but in the quaternion algebra.
$endgroup$
– Dietrich Burde
Jan 6 at 19:27
$begingroup$
What do you mean by general meaning? It means Sylvester's equation, not in $M_n(K)$, but in the quaternion algebra.
$endgroup$
– Dietrich Burde
Jan 6 at 19:27
add a comment |
1 Answer
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See this paper. I'd interpret $ax+xb=c$ as an equation asking for a quaternion $x=x_0+ x_1i+x_2j+x_3 k$, given quaternions $a$, $b$, and $c$ in a similar way. Write out this equation component wise, and obtain linear equations for the $x_i$. For the existence of a unique solution there will be some assumptions on the parameters $a$, $b$, and $c$.
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1 Answer
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1 Answer
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See this paper. I'd interpret $ax+xb=c$ as an equation asking for a quaternion $x=x_0+ x_1i+x_2j+x_3 k$, given quaternions $a$, $b$, and $c$ in a similar way. Write out this equation component wise, and obtain linear equations for the $x_i$. For the existence of a unique solution there will be some assumptions on the parameters $a$, $b$, and $c$.
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add a comment |
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See this paper. I'd interpret $ax+xb=c$ as an equation asking for a quaternion $x=x_0+ x_1i+x_2j+x_3 k$, given quaternions $a$, $b$, and $c$ in a similar way. Write out this equation component wise, and obtain linear equations for the $x_i$. For the existence of a unique solution there will be some assumptions on the parameters $a$, $b$, and $c$.
$endgroup$
add a comment |
$begingroup$
See this paper. I'd interpret $ax+xb=c$ as an equation asking for a quaternion $x=x_0+ x_1i+x_2j+x_3 k$, given quaternions $a$, $b$, and $c$ in a similar way. Write out this equation component wise, and obtain linear equations for the $x_i$. For the existence of a unique solution there will be some assumptions on the parameters $a$, $b$, and $c$.
$endgroup$
See this paper. I'd interpret $ax+xb=c$ as an equation asking for a quaternion $x=x_0+ x_1i+x_2j+x_3 k$, given quaternions $a$, $b$, and $c$ in a similar way. Write out this equation component wise, and obtain linear equations for the $x_i$. For the existence of a unique solution there will be some assumptions on the parameters $a$, $b$, and $c$.
answered Jan 6 at 19:19


Christian BlatterChristian Blatter
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173k7113326
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$begingroup$
What do you mean by general meaning? It means Sylvester's equation, not in $M_n(K)$, but in the quaternion algebra.
$endgroup$
– Dietrich Burde
Jan 6 at 19:27