Angle between sum of vectors












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Let $u,v$ and $w$ be vectors in $mathbb{R}^n$ and let $theta(u,w), theta(v,w)$ and $theta(u+v,w)$ represent the angle between each listed pair of vectors. Does it hold that one of the following two statements must be true:
$$theta(u,w) geq theta(u+v,w)$$ Or:
$$theta(v,w) geq theta(u+v,w)$$
I feel this must be true and that it follows from some simple property that I'm forgetting. If it is true, does it generalize to any finite list of vectors?










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    0












    $begingroup$


    Let $u,v$ and $w$ be vectors in $mathbb{R}^n$ and let $theta(u,w), theta(v,w)$ and $theta(u+v,w)$ represent the angle between each listed pair of vectors. Does it hold that one of the following two statements must be true:
    $$theta(u,w) geq theta(u+v,w)$$ Or:
    $$theta(v,w) geq theta(u+v,w)$$
    I feel this must be true and that it follows from some simple property that I'm forgetting. If it is true, does it generalize to any finite list of vectors?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Let $u,v$ and $w$ be vectors in $mathbb{R}^n$ and let $theta(u,w), theta(v,w)$ and $theta(u+v,w)$ represent the angle between each listed pair of vectors. Does it hold that one of the following two statements must be true:
      $$theta(u,w) geq theta(u+v,w)$$ Or:
      $$theta(v,w) geq theta(u+v,w)$$
      I feel this must be true and that it follows from some simple property that I'm forgetting. If it is true, does it generalize to any finite list of vectors?










      share|cite|improve this question









      $endgroup$




      Let $u,v$ and $w$ be vectors in $mathbb{R}^n$ and let $theta(u,w), theta(v,w)$ and $theta(u+v,w)$ represent the angle between each listed pair of vectors. Does it hold that one of the following two statements must be true:
      $$theta(u,w) geq theta(u+v,w)$$ Or:
      $$theta(v,w) geq theta(u+v,w)$$
      I feel this must be true and that it follows from some simple property that I'm forgetting. If it is true, does it generalize to any finite list of vectors?







      geometry vectors






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      asked Jan 18 at 15:48









      ghiufheghiufhe

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          I don't think this is true. Take the vectors $u=langle-1, 1rangle$, $v=langle 1, 1rangle$ and $w=langle 0, -1rangle$ in $mathbb{R}^2$. Then $u+v=langle 0, 2rangle$, and $theta(u+v, w)=pi$, while both $theta(u,w)$ and $theta(v,w)=frac{3pi}{4}$.






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            1 Answer
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            $begingroup$

            I don't think this is true. Take the vectors $u=langle-1, 1rangle$, $v=langle 1, 1rangle$ and $w=langle 0, -1rangle$ in $mathbb{R}^2$. Then $u+v=langle 0, 2rangle$, and $theta(u+v, w)=pi$, while both $theta(u,w)$ and $theta(v,w)=frac{3pi}{4}$.






            share|cite|improve this answer









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              2












              $begingroup$

              I don't think this is true. Take the vectors $u=langle-1, 1rangle$, $v=langle 1, 1rangle$ and $w=langle 0, -1rangle$ in $mathbb{R}^2$. Then $u+v=langle 0, 2rangle$, and $theta(u+v, w)=pi$, while both $theta(u,w)$ and $theta(v,w)=frac{3pi}{4}$.






              share|cite|improve this answer









              $endgroup$
















                2












                2








                2





                $begingroup$

                I don't think this is true. Take the vectors $u=langle-1, 1rangle$, $v=langle 1, 1rangle$ and $w=langle 0, -1rangle$ in $mathbb{R}^2$. Then $u+v=langle 0, 2rangle$, and $theta(u+v, w)=pi$, while both $theta(u,w)$ and $theta(v,w)=frac{3pi}{4}$.






                share|cite|improve this answer









                $endgroup$



                I don't think this is true. Take the vectors $u=langle-1, 1rangle$, $v=langle 1, 1rangle$ and $w=langle 0, -1rangle$ in $mathbb{R}^2$. Then $u+v=langle 0, 2rangle$, and $theta(u+v, w)=pi$, while both $theta(u,w)$ and $theta(v,w)=frac{3pi}{4}$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Jan 18 at 16:09









                Calvin GodfreyCalvin Godfrey

                633311




                633311






























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