Mixing
Find the x intercepts of $f(x)=tanleft(xright)-tanleft(4xright)$
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I'm having serious trouble finding the x-intercepts of this funtion $$f(x)=tan(x)-tan(4x)$$ I'm unable to solve it for zero. What am I missing here?
functions trigonometry
edited Jan 18 at 15:46
Blue
48.6k870156
asked Jan 18 at 15:28
Daniel OscarDaniel Oscar
32810
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add a comment |
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I'm having serious trouble finding the x-intercepts of this funtion $$f(x)=tan(x)-tan(4x)$$ I'm unable to solve it for zero. What am I missing here?
functions trigonometry
edited Jan 18 at 15:46
Blue
48.6k870156
asked Jan 18 at 15:28
Daniel OscarDaniel Oscar
32810
$endgroup$
add a comment |
$begingroup$
I'm having serious trouble finding the x-intercepts of this funtion $$f(x)=tan(x)-tan(4x)$$ I'm unable to solve it for zero. What am I missing here?
functions trigonometry
edited Jan 18 at 15:46
Blue
48.6k870156
asked Jan 18 at 15:28
Daniel OscarDaniel Oscar
32810
$endgroup$
I'm having serious trouble finding the x-intercepts of this funtion $$f(x)=tan(x)-tan(4x)$$ I'm unable to solve it for zero. What am I missing here?
functions trigonometry
functions trigonometry
edited Jan 18 at 15:46
Blue
48.6k870156
asked Jan 18 at 15:28
Daniel OscarDaniel Oscar
32810
edited Jan 18 at 15:46
Blue
48.6k870156
asked Jan 18 at 15:28
Daniel OscarDaniel Oscar
32810
edited Jan 18 at 15:46
Blue
48.6k870156
edited Jan 18 at 15:46
Blue
48.6k870156
edited Jan 18 at 15:46
Blue
48.6k870156
48.6k870156
asked Jan 18 at 15:28
Daniel OscarDaniel Oscar
32810
asked Jan 18 at 15:28
Daniel OscarDaniel Oscar
32810
asked Jan 18 at 15:28
Daniel OscarDaniel Oscar
32810
32810
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Hint
$$tan a =tan biff a=kpi +b$$
answered Jan 18 at 15:38
Mostafa AyazMostafa Ayaz
15.6k3939
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add a comment |
$begingroup$
Simplify:
$$fleft(xright)=tanleft(xright)-tanleft(4xright)=frac{sin xcos 4x-sin 4xcos x}{cos xcos 4x}=cdots$$
answered Jan 18 at 15:41
farruhotafarruhota
20.5k2739
$endgroup$
$begingroup$
Wait! Your first comment was it! I wasn't familiarized with that trigonometric identity!
$endgroup$
– Daniel Oscar
Jan 18 at 15:48
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint
$$tan a =tan biff a=kpi +b$$
answered Jan 18 at 15:38
Mostafa AyazMostafa Ayaz
15.6k3939
$endgroup$
add a comment |
$begingroup$
Hint
$$tan a =tan biff a=kpi +b$$
answered Jan 18 at 15:38
Mostafa AyazMostafa Ayaz
15.6k3939
$endgroup$
add a comment |
$begingroup$
Hint
$$tan a =tan biff a=kpi +b$$
answered Jan 18 at 15:38
Mostafa AyazMostafa Ayaz
15.6k3939
$endgroup$
Hint
$$tan a =tan biff a=kpi +b$$
answered Jan 18 at 15:38
Mostafa AyazMostafa Ayaz
15.6k3939
answered Jan 18 at 15:38
Mostafa AyazMostafa Ayaz
15.6k3939
answered Jan 18 at 15:38
Mostafa AyazMostafa Ayaz
15.6k3939
answered Jan 18 at 15:38
Mostafa AyazMostafa Ayaz
15.6k3939
15.6k3939
add a comment |
add a comment |
$begingroup$
Simplify:
$$fleft(xright)=tanleft(xright)-tanleft(4xright)=frac{sin xcos 4x-sin 4xcos x}{cos xcos 4x}=cdots$$
answered Jan 18 at 15:41
farruhotafarruhota
20.5k2739
$endgroup$
$begingroup$
Wait! Your first comment was it! I wasn't familiarized with that trigonometric identity!
$endgroup$
– Daniel Oscar
Jan 18 at 15:48
add a comment |
$begingroup$
Simplify:
$$fleft(xright)=tanleft(xright)-tanleft(4xright)=frac{sin xcos 4x-sin 4xcos x}{cos xcos 4x}=cdots$$
answered Jan 18 at 15:41
farruhotafarruhota
20.5k2739
$endgroup$
$begingroup$
Wait! Your first comment was it! I wasn't familiarized with that trigonometric identity!
$endgroup$
– Daniel Oscar
Jan 18 at 15:48
add a comment |
$begingroup$
Simplify:
$$fleft(xright)=tanleft(xright)-tanleft(4xright)=frac{sin xcos 4x-sin 4xcos x}{cos xcos 4x}=cdots$$
answered Jan 18 at 15:41
farruhotafarruhota
20.5k2739
$endgroup$
Simplify:
$$fleft(xright)=tanleft(xright)-tanleft(4xright)=frac{sin xcos 4x-sin 4xcos x}{cos xcos 4x}=cdots$$
answered Jan 18 at 15:41
farruhotafarruhota
20.5k2739
answered Jan 18 at 15:41
farruhotafarruhota
20.5k2739
answered Jan 18 at 15:41
farruhotafarruhota
20.5k2739
answered Jan 18 at 15:41
farruhotafarruhota
20.5k2739
20.5k2739
$begingroup$
Wait! Your first comment was it! I wasn't familiarized with that trigonometric identity!
$endgroup$
– Daniel Oscar
Jan 18 at 15:48
add a comment |
$begingroup$
Wait! Your first comment was it! I wasn't familiarized with that trigonometric identity!
$endgroup$
– Daniel Oscar
Jan 18 at 15:48
$begingroup$
Wait! Your first comment was it! I wasn't familiarized with that trigonometric identity!
$endgroup$
– Daniel Oscar
Jan 18 at 15:48
$begingroup$
Wait! Your first comment was it! I wasn't familiarized with that trigonometric identity!
$endgroup$
– Daniel Oscar
Jan 18 at 15:48
add a comment |
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