Mixing
Unix command to grep only a substring starting with “xyz…” up to the first space?
I have a text:
This is my=test and class=76
This is my=test and class=78
This is my=test2 and class=76
This is my=test3 and class=75
This is my=test1 and class=79.
I want to grep all the word starting with "class=" with the values without printing the whole line the output should be:
class=76
class=78
class=76
class=75
class=79
any command that can help me on this?
I tried this :
grep -E '(^|s+)class=(?=s|$)' file
but was not getting any output.
regex unix grep
edited Nov 22 '18 at 10:36
Wiktor Stribiżew
319k16140222
asked Nov 22 '18 at 8:20
A. GuptaA. Gupta
277
add a comment |
I have a text:
This is my=test and class=76
This is my=test and class=78
This is my=test2 and class=76
This is my=test3 and class=75
This is my=test1 and class=79.
I want to grep all the word starting with "class=" with the values without printing the whole line the output should be:
class=76
class=78
class=76
class=75
class=79
any command that can help me on this?
I tried this :
grep -E '(^|s+)class=(?=s|$)' file
but was not getting any output.
regex unix grep
edited Nov 22 '18 at 10:36
Wiktor Stribiżew
319k16140222
asked Nov 22 '18 at 8:20
A. GuptaA. Gupta
277
1
Possible duplicate of Can grep show only words that match search pattern?
– tripleee
Nov 22 '18 at 8:39
Possible duplicate of stackoverflow.com/questions/45965192/…
– tripleee
Nov 22 '18 at 8:39
add a comment |
I have a text:
This is my=test and class=76
This is my=test and class=78
This is my=test2 and class=76
This is my=test3 and class=75
This is my=test1 and class=79.
I want to grep all the word starting with "class=" with the values without printing the whole line the output should be:
class=76
class=78
class=76
class=75
class=79
any command that can help me on this?
I tried this :
grep -E '(^|s+)class=(?=s|$)' file
but was not getting any output.
regex unix grep
edited Nov 22 '18 at 10:36
Wiktor Stribiżew
319k16140222
asked Nov 22 '18 at 8:20
A. GuptaA. Gupta
277
I have a text:
This is my=test and class=76
This is my=test and class=78
This is my=test2 and class=76
This is my=test3 and class=75
This is my=test1 and class=79.
I want to grep all the word starting with "class=" with the values without printing the whole line the output should be:
class=76
class=78
class=76
class=75
class=79
any command that can help me on this?
I tried this :
grep -E '(^|s+)class=(?=s|$)' file
but was not getting any output.
regex unix grep
regex unix grep
edited Nov 22 '18 at 10:36
Wiktor Stribiżew
319k16140222
asked Nov 22 '18 at 8:20
A. GuptaA. Gupta
277
edited Nov 22 '18 at 10:36
Wiktor Stribiżew
319k16140222
asked Nov 22 '18 at 8:20
A. GuptaA. Gupta
277
edited Nov 22 '18 at 10:36
Wiktor Stribiżew
319k16140222
edited Nov 22 '18 at 10:36
Wiktor Stribiżew
319k16140222
edited Nov 22 '18 at 10:36
Wiktor Stribiżew
319k16140222
319k16140222
asked Nov 22 '18 at 8:20
A. GuptaA. Gupta
277
asked Nov 22 '18 at 8:20
A. GuptaA. Gupta
277
asked Nov 22 '18 at 8:20
A. GuptaA. Gupta
277
277
1
Possible duplicate of Can grep show only words that match search pattern?
– tripleee
Nov 22 '18 at 8:39
Possible duplicate of stackoverflow.com/questions/45965192/…
– tripleee
Nov 22 '18 at 8:39
add a comment |
1
Possible duplicate of Can grep show only words that match search pattern?
– tripleee
Nov 22 '18 at 8:39
Possible duplicate of stackoverflow.com/questions/45965192/…
– tripleee
Nov 22 '18 at 8:39
1
1
Possible duplicate of Can grep show only words that match search pattern?
– tripleee
Nov 22 '18 at 8:39
Possible duplicate of Can grep show only words that match search pattern?
– tripleee
Nov 22 '18 at 8:39
Possible duplicate of stackoverflow.com/questions/45965192/…
– tripleee
Nov 22 '18 at 8:39
Possible duplicate of stackoverflow.com/questions/45965192/…
– tripleee
Nov 22 '18 at 8:39
add a comment |
2 Answers
2
active
oldest
votes
Your (^|s+)class=(?=s|$) pattern is not POSIX compliant because it contains a positive lookahead (?=s|$) that is meant to match a location that is followed with a whitespace or end of string position. As you want to match digits right after class=, this lookahead makes no sense even in a PCRE regex. The (^|s+) group is meant to match start of string or 1 or more whitespaces, but it seems a mere word boundary will do here.
You may use
grep -oE '<class=[^ ]+' file
See the online demo
Details
o- enables the output mode, only outputs matches
E- enables POSIX ERE syntax
<- a word boundary (alsobcan be used instead)
class=- a literal string
[^ ]+- 1 or more chars other than space
Equivalent BRE POSIX version:
grep -o '<class=[^ ]*' file
Tested with grep (GNU grep) 2.27.
answered Nov 22 '18 at 8:25
Wiktor StribiżewWiktor Stribiżew
319k16140222
Thank you so much that worked,Now, lets say i want to get the string after "class=" but before the first space occurence. Then what would be the modified command?
– A. Gupta
Nov 22 '18 at 9:11
grep -oE '<class=[^[:space:]]+' file. OrS+, or[^ ]+.
– Wiktor Stribiżew
Nov 22 '18 at 9:18
add a comment |
Using Perl-oneliner
> data="This is my=test and class=76 This is my=test and class=78 This is my=test2 and n class=76 This is my=test3 and class=75 This is my=test1 and class=79."
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' <<< "$data"
class=76
class=78
class=76
class=75
class=79
>
Works, even if you have the data in a file
> echo "$data" > gupta.txt
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' gupta.txt
class=76
class=78
class=76
class=75
class=79
>
answered Nov 22 '18 at 9:24
stack0114106stack0114106
3,8282420
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your (^|s+)class=(?=s|$) pattern is not POSIX compliant because it contains a positive lookahead (?=s|$) that is meant to match a location that is followed with a whitespace or end of string position. As you want to match digits right after class=, this lookahead makes no sense even in a PCRE regex. The (^|s+) group is meant to match start of string or 1 or more whitespaces, but it seems a mere word boundary will do here.
You may use
grep -oE '<class=[^ ]+' file
See the online demo
Details
o- enables the output mode, only outputs matches
E- enables POSIX ERE syntax
<- a word boundary (alsobcan be used instead)
class=- a literal string
[^ ]+- 1 or more chars other than space
Equivalent BRE POSIX version:
grep -o '<class=[^ ]*' file
Tested with grep (GNU grep) 2.27.
answered Nov 22 '18 at 8:25
Wiktor StribiżewWiktor Stribiżew
319k16140222
Thank you so much that worked,Now, lets say i want to get the string after "class=" but before the first space occurence. Then what would be the modified command?
– A. Gupta
Nov 22 '18 at 9:11
grep -oE '<class=[^[:space:]]+' file. OrS+, or[^ ]+.
– Wiktor Stribiżew
Nov 22 '18 at 9:18
add a comment |
Your (^|s+)class=(?=s|$) pattern is not POSIX compliant because it contains a positive lookahead (?=s|$) that is meant to match a location that is followed with a whitespace or end of string position. As you want to match digits right after class=, this lookahead makes no sense even in a PCRE regex. The (^|s+) group is meant to match start of string or 1 or more whitespaces, but it seems a mere word boundary will do here.
You may use
grep -oE '<class=[^ ]+' file
See the online demo
Details
o- enables the output mode, only outputs matches
E- enables POSIX ERE syntax
<- a word boundary (alsobcan be used instead)
class=- a literal string
[^ ]+- 1 or more chars other than space
Equivalent BRE POSIX version:
grep -o '<class=[^ ]*' file
Tested with grep (GNU grep) 2.27.
answered Nov 22 '18 at 8:25
Wiktor StribiżewWiktor Stribiżew
319k16140222
Thank you so much that worked,Now, lets say i want to get the string after "class=" but before the first space occurence. Then what would be the modified command?
– A. Gupta
Nov 22 '18 at 9:11
grep -oE '<class=[^[:space:]]+' file. OrS+, or[^ ]+.
– Wiktor Stribiżew
Nov 22 '18 at 9:18
add a comment |
Your (^|s+)class=(?=s|$) pattern is not POSIX compliant because it contains a positive lookahead (?=s|$) that is meant to match a location that is followed with a whitespace or end of string position. As you want to match digits right after class=, this lookahead makes no sense even in a PCRE regex. The (^|s+) group is meant to match start of string or 1 or more whitespaces, but it seems a mere word boundary will do here.
You may use
grep -oE '<class=[^ ]+' file
See the online demo
Details
o- enables the output mode, only outputs matches
E- enables POSIX ERE syntax
<- a word boundary (alsobcan be used instead)
class=- a literal string
[^ ]+- 1 or more chars other than space
Equivalent BRE POSIX version:
grep -o '<class=[^ ]*' file
Tested with grep (GNU grep) 2.27.
answered Nov 22 '18 at 8:25
Wiktor StribiżewWiktor Stribiżew
319k16140222
Your (^|s+)class=(?=s|$) pattern is not POSIX compliant because it contains a positive lookahead (?=s|$) that is meant to match a location that is followed with a whitespace or end of string position. As you want to match digits right after class=, this lookahead makes no sense even in a PCRE regex. The (^|s+) group is meant to match start of string or 1 or more whitespaces, but it seems a mere word boundary will do here.
You may use
grep -oE '<class=[^ ]+' file
See the online demo
Details
o- enables the output mode, only outputs matches
E- enables POSIX ERE syntax
<- a word boundary (alsobcan be used instead)
class=- a literal string
[^ ]+- 1 or more chars other than space
Equivalent BRE POSIX version:
grep -o '<class=[^ ]*' file
Tested with grep (GNU grep) 2.27.
answered Nov 22 '18 at 8:25
Wiktor StribiżewWiktor Stribiżew
319k16140222
edited Nov 22 '18 at 9:19
answered Nov 22 '18 at 8:25
Wiktor StribiżewWiktor Stribiżew
319k16140222
answered Nov 22 '18 at 8:25
Wiktor StribiżewWiktor Stribiżew
319k16140222
answered Nov 22 '18 at 8:25
Wiktor StribiżewWiktor Stribiżew
319k16140222
319k16140222
Thank you so much that worked,Now, lets say i want to get the string after "class=" but before the first space occurence. Then what would be the modified command?
– A. Gupta
Nov 22 '18 at 9:11
grep -oE '<class=[^[:space:]]+' file. OrS+, or[^ ]+.
– Wiktor Stribiżew
Nov 22 '18 at 9:18
add a comment |
Thank you so much that worked,Now, lets say i want to get the string after "class=" but before the first space occurence. Then what would be the modified command?
– A. Gupta
Nov 22 '18 at 9:11
grep -oE '<class=[^[:space:]]+' file. OrS+, or[^ ]+.
– Wiktor Stribiżew
Nov 22 '18 at 9:18
Thank you so much that worked,Now, lets say i want to get the string after "class=" but before the first space occurence. Then what would be the modified command?
– A. Gupta
Nov 22 '18 at 9:11
Thank you so much that worked,Now, lets say i want to get the string after "class=" but before the first space occurence. Then what would be the modified command?
– A. Gupta
Nov 22 '18 at 9:11
grep -oE '<class=[^[:space:]]+' file. Or S+, or [^ ]+.– Wiktor Stribiżew
Nov 22 '18 at 9:18
grep -oE '<class=[^[:space:]]+' file. Or S+, or [^ ]+.– Wiktor Stribiżew
Nov 22 '18 at 9:18
add a comment |
Using Perl-oneliner
> data="This is my=test and class=76 This is my=test and class=78 This is my=test2 and n class=76 This is my=test3 and class=75 This is my=test1 and class=79."
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' <<< "$data"
class=76
class=78
class=76
class=75
class=79
>
Works, even if you have the data in a file
> echo "$data" > gupta.txt
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' gupta.txt
class=76
class=78
class=76
class=75
class=79
>
answered Nov 22 '18 at 9:24
stack0114106stack0114106
3,8282420
add a comment |
Using Perl-oneliner
> data="This is my=test and class=76 This is my=test and class=78 This is my=test2 and n class=76 This is my=test3 and class=75 This is my=test1 and class=79."
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' <<< "$data"
class=76
class=78
class=76
class=75
class=79
>
Works, even if you have the data in a file
> echo "$data" > gupta.txt
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' gupta.txt
class=76
class=78
class=76
class=75
class=79
>
answered Nov 22 '18 at 9:24
stack0114106stack0114106
3,8282420
add a comment |
Using Perl-oneliner
> data="This is my=test and class=76 This is my=test and class=78 This is my=test2 and n class=76 This is my=test3 and class=75 This is my=test1 and class=79."
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' <<< "$data"
class=76
class=78
class=76
class=75
class=79
>
Works, even if you have the data in a file
> echo "$data" > gupta.txt
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' gupta.txt
class=76
class=78
class=76
class=75
class=79
>
answered Nov 22 '18 at 9:24
stack0114106stack0114106
3,8282420
Using Perl-oneliner
> data="This is my=test and class=76 This is my=test and class=78 This is my=test2 and n class=76 This is my=test3 and class=75 This is my=test1 and class=79."
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' <<< "$data"
class=76
class=78
class=76
class=75
class=79
>
Works, even if you have the data in a file
> echo "$data" > gupta.txt
> perl -0777 -ne ' { while(/(class=(d+))/g) { print "$1n" } } ' gupta.txt
class=76
class=78
class=76
class=75
class=79
>
answered Nov 22 '18 at 9:24
stack0114106stack0114106
3,8282420
answered Nov 22 '18 at 9:24
stack0114106stack0114106
3,8282420
answered Nov 22 '18 at 9:24
stack0114106stack0114106
3,8282420
answered Nov 22 '18 at 9:24
stack0114106stack0114106
3,8282420
3,8282420
add a comment |
add a comment |
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1
Possible duplicate of Can grep show only words that match search pattern?
– tripleee
Nov 22 '18 at 8:39
Possible duplicate of stackoverflow.com/questions/45965192/…
– tripleee
Nov 22 '18 at 8:39