Code works in Geany IDE, but segmentation fault in HackerRanks. What's the technical reason for this?

It's a simple program that initializes 3 data types and takes 3 inputs, an int, a double, and a string. Then perform addition on the numbers and prints out the "concatenated" string (doesn't actually have to be concatenated). It works in Geany IDE running on a VM of Ubuntu 16.04, but gets a segmentation fault in HackerRank. Why would this occur?

#include <stdio.h>

#include <string.h>

#include <math.h>

#include <stdlib.h>



int main() {

    int i = 4;

    double d = 4.0;

    char s = "HackerRank ";

    int j, cnt = 0;

    double e;

    char c[100];

    char ch;



    scanf(" %d", &j);

    scanf(" %lf", &e);

    ch = getchar();

    while ((ch = getchar()) != 'n'){

        c[cnt++] = ch;

    }

    c[cnt] = '';

    printf("%dn", i+j);

    printf("%.1lfn", d+e);

    printf("%s%sn", s, c);

    return 0;

}

asked Jan 1 at 19:58

brunshte

236

1

I bet more than 100 chars in the input. And you write outside the bounds

– P__J__
Jan 1 at 20:03

1

Are you sure a newline will terminate the input? Check for EOF as well, but you must change char ch; to int ch; I would use while ((ch = getchar()) != 'n' && ch != EOF) Without a newline, you'll break the array.

– Weather Vane
Jan 1 at 20:04

1

I mean "exceed the bounds of the array c" since without a newline the loop continues until you break something.

– Weather Vane
Jan 1 at 20:09

2

Usually these challenge sites redirect a file to the input of your program. A text file does not have to end with a newline.

– Weather Vane
Jan 1 at 20:10

2

Is it trial and error to check how their files are formatted No, you should carefully read the assignment and implement exactly what it says. If it says your program should read a string, it should read a string. Not a string shorter than 100 characters. Not a string shorter than 1000000 characters. A string.

– n.m.
Jan 1 at 20:27

|
show 7 more comments

#include <stdio.h>

#include <string.h>

#include <math.h>

#include <stdlib.h>



int main() {

    int i = 4;

    double d = 4.0;

    char s = "HackerRank ";

    int j, cnt = 0;

    double e;

    char c[100];

    char ch;



    scanf(" %d", &j);

    scanf(" %lf", &e);

    ch = getchar();

    while ((ch = getchar()) != 'n'){

        c[cnt++] = ch;

    }

    c[cnt] = '';

    printf("%dn", i+j);

    printf("%.1lfn", d+e);

    printf("%s%sn", s, c);

    return 0;

}

asked Jan 1 at 19:58

brunshte

236

1

I bet more than 100 chars in the input. And you write outside the bounds

– P__J__
Jan 1 at 20:03

1

Are you sure a newline will terminate the input? Check for EOF as well, but you must change char ch; to int ch; I would use while ((ch = getchar()) != 'n' && ch != EOF) Without a newline, you'll break the array.

– Weather Vane
Jan 1 at 20:04

1

I mean "exceed the bounds of the array c" since without a newline the loop continues until you break something.

– Weather Vane
Jan 1 at 20:09

2

Usually these challenge sites redirect a file to the input of your program. A text file does not have to end with a newline.

– Weather Vane
Jan 1 at 20:10

2

Is it trial and error to check how their files are formatted No, you should carefully read the assignment and implement exactly what it says. If it says your program should read a string, it should read a string. Not a string shorter than 100 characters. Not a string shorter than 1000000 characters. A string.

– n.m.
Jan 1 at 20:27

|
show 7 more comments

#include <stdio.h>

#include <string.h>

#include <math.h>

#include <stdlib.h>



int main() {

    int i = 4;

    double d = 4.0;

    char s = "HackerRank ";

    int j, cnt = 0;

    double e;

    char c[100];

    char ch;



    scanf(" %d", &j);

    scanf(" %lf", &e);

    ch = getchar();

    while ((ch = getchar()) != 'n'){

        c[cnt++] = ch;

    }

    c[cnt] = '';

    printf("%dn", i+j);

    printf("%.1lfn", d+e);

    printf("%s%sn", s, c);

    return 0;

}

asked Jan 1 at 19:58

brunshte

236

#include <stdio.h>

#include <string.h>

#include <math.h>

#include <stdlib.h>



int main() {

    int i = 4;

    double d = 4.0;

    char s = "HackerRank ";

    int j, cnt = 0;

    double e;

    char c[100];

    char ch;



    scanf(" %d", &j);

    scanf(" %lf", &e);

    ch = getchar();

    while ((ch = getchar()) != 'n'){

        c[cnt++] = ch;

    }

    c[cnt] = '';

    printf("%dn", i+j);

    printf("%.1lfn", d+e);

    printf("%s%sn", s, c);

    return 0;

}

asked Jan 1 at 19:58

brunshte

236

asked Jan 1 at 19:58

brunshte

236

asked Jan 1 at 19:58

brunshte

236

asked Jan 1 at 19:58

brunshte

236

asked Jan 1 at 19:58

brunshte

236

1

I bet more than 100 chars in the input. And you write outside the bounds

– P__J__
Jan 1 at 20:03

1

Are you sure a newline will terminate the input? Check for EOF as well, but you must change char ch; to int ch; I would use while ((ch = getchar()) != 'n' && ch != EOF) Without a newline, you'll break the array.

– Weather Vane
Jan 1 at 20:04

1

I mean "exceed the bounds of the array c" since without a newline the loop continues until you break something.

– Weather Vane
Jan 1 at 20:09

2

Usually these challenge sites redirect a file to the input of your program. A text file does not have to end with a newline.

– Weather Vane
Jan 1 at 20:10

2

Is it trial and error to check how their files are formatted No, you should carefully read the assignment and implement exactly what it says. If it says your program should read a string, it should read a string. Not a string shorter than 100 characters. Not a string shorter than 1000000 characters. A string.

– n.m.
Jan 1 at 20:27

|
show 7 more comments

1

I bet more than 100 chars in the input. And you write outside the bounds

– P__J__
Jan 1 at 20:03

1

Are you sure a newline will terminate the input? Check for EOF as well, but you must change char ch; to int ch; I would use while ((ch = getchar()) != 'n' && ch != EOF) Without a newline, you'll break the array.

– Weather Vane
Jan 1 at 20:04

1

I mean "exceed the bounds of the array c" since without a newline the loop continues until you break something.

– Weather Vane
Jan 1 at 20:09

2

Usually these challenge sites redirect a file to the input of your program. A text file does not have to end with a newline.

– Weather Vane
Jan 1 at 20:10

2

Is it trial and error to check how their files are formatted No, you should carefully read the assignment and implement exactly what it says. If it says your program should read a string, it should read a string. Not a string shorter than 100 characters. Not a string shorter than 1000000 characters. A string.

– n.m.
Jan 1 at 20:27

I bet more than 100 chars in the input. And you write outside the bounds

– P__J__
Jan 1 at 20:03

Are you sure a newline will terminate the input? Check for EOF as well, but you must change char ch; to int ch; I would use while ((ch = getchar()) != 'n' && ch != EOF) Without a newline, you'll break the array.

– Weather Vane
Jan 1 at 20:04

I mean "exceed the bounds of the array c" since without a newline the loop continues until you break something.

– Weather Vane
Jan 1 at 20:09

Usually these challenge sites redirect a file to the input of your program. A text file does not have to end with a newline.

– Weather Vane
Jan 1 at 20:10

Is it trial and error to check how their files are formatted No, you should carefully read the assignment and implement exactly what it says. If it says your program should read a string, it should read a string. Not a string shorter than 100 characters. Not a string shorter than 1000000 characters. A string.

– n.m.
Jan 1 at 20:27

|
show 7 more comments

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