Mixing
Flutter cannot parse regex
Flutter cannot parse this working regex, and doesn't return any error or info.
(?<=id=)[^&]+
However, when I add it into my Flutter app:
print("before");
new RegExp(r'(?<=id=)[^&]+');
print("after");
It doesn't do anything, doesn't return any error. The print("after"); never gets executed. It doesn't completly freeze the app, because it's in async.
regex dart
flutter edited Jan 2 at 7:49
Wiktor Stribiżew
324k16146226
asked Dec 31 '18 at 10:34
Makalone LOgmanMakalone LOgman
1078
add a comment |
Flutter cannot parse this working regex, and doesn't return any error or info.
(?<=id=)[^&]+
However, when I add it into my Flutter app:
print("before");
new RegExp(r'(?<=id=)[^&]+');
print("after");
It doesn't do anything, doesn't return any error. The print("after"); never gets executed. It doesn't completly freeze the app, because it's in async.
regex dart
flutter edited Jan 2 at 7:49
Wiktor Stribiżew
324k16146226
asked Dec 31 '18 at 10:34
Makalone LOgmanMakalone LOgman
1078
add a comment |
Flutter cannot parse this working regex, and doesn't return any error or info.
(?<=id=)[^&]+
However, when I add it into my Flutter app:
print("before");
new RegExp(r'(?<=id=)[^&]+');
print("after");
It doesn't do anything, doesn't return any error. The print("after"); never gets executed. It doesn't completly freeze the app, because it's in async.
regex dart
flutter edited Jan 2 at 7:49
Wiktor Stribiżew
324k16146226
asked Dec 31 '18 at 10:34
Makalone LOgmanMakalone LOgman
1078
Flutter cannot parse this working regex, and doesn't return any error or info.
(?<=id=)[^&]+
However, when I add it into my Flutter app:
print("before");
new RegExp(r'(?<=id=)[^&]+');
print("after");
It doesn't do anything, doesn't return any error. The print("after"); never gets executed. It doesn't completly freeze the app, because it's in async.
regex dart
flutter regex dart
flutter edited Jan 2 at 7:49
Wiktor Stribiżew
324k16146226
asked Dec 31 '18 at 10:34
Makalone LOgmanMakalone LOgman
1078
edited Jan 2 at 7:49
Wiktor Stribiżew
324k16146226
asked Dec 31 '18 at 10:34
Makalone LOgmanMakalone LOgman
1078
edited Jan 2 at 7:49
Wiktor Stribiżew
324k16146226
edited Jan 2 at 7:49
Wiktor Stribiżew
324k16146226
edited Jan 2 at 7:49
Wiktor Stribiżew
324k16146226
324k16146226
asked Dec 31 '18 at 10:34
Makalone LOgmanMakalone LOgman
1078
asked Dec 31 '18 at 10:34
Makalone LOgmanMakalone LOgman
1078
asked Dec 31 '18 at 10:34
Makalone LOgmanMakalone LOgman
1078
1078
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Dart compiled for the Web supports lokbehinds, but the current version of native Dart (including Flutter) does not support lookbehinds (source).
In your case, you want to match a string after a specific string. All you need is to declare a capturing group in your pattern and then access that submatch:
RegExp regExp = new RegExp(r"id=([^&]+)");
String s = "http://example.com?id=some.thing.com&other=parameter; http://example.com?id=some.thing.com";
Iterable<Match> matches = regExp.allMatches(s);
for (Match match in matches) {
print(match.group(1));
}
Output:
some.thing.com
some.thing.com
Here, id=([^&]+) matches id= and then the ([^&]+) capturing group #1 matches and captures into Group 1 any one or more chars other than &. Note you may make it safer if you add [?&] before id to only match id and not thisid query param: [?&]id=([^&]+).
answered Dec 31 '18 at 12:15
Wiktor StribiżewWiktor Stribiżew
324k16146226
add a comment |
I assume this is https://github.com/dart-lang/sdk/issues/34935
Bring Dart's RegExp support in line with JavaScript: lookbehinds, property escapes, and named groups.
answered Dec 31 '18 at 10:37
Günter ZöchbauerGünter Zöchbauer
332k701006941
So... Its not supported in current version of Flutter? So I will have to use justid=[^&]+and then ReplaceAllid=with''.
– Makalone LOgman
Dec 31 '18 at 10:40
1
Yes, Flutter depends on Dart for RegExp and Dart limits itself to what is supported in the browser, but they are a bit behind, because I think your example is now supported in recent browser versions, but not yet in Dart. I don't have deep RegExp knowledge and I'm not sure what a good workaround would be.
– Günter Zöchbauer
Dec 31 '18 at 10:47
Ok, thanks then.
– Makalone LOgman
Dec 31 '18 at 11:15
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Dart compiled for the Web supports lokbehinds, but the current version of native Dart (including Flutter) does not support lookbehinds (source).
In your case, you want to match a string after a specific string. All you need is to declare a capturing group in your pattern and then access that submatch:
RegExp regExp = new RegExp(r"id=([^&]+)");
String s = "http://example.com?id=some.thing.com&other=parameter; http://example.com?id=some.thing.com";
Iterable<Match> matches = regExp.allMatches(s);
for (Match match in matches) {
print(match.group(1));
}
Output:
some.thing.com
some.thing.com
Here, id=([^&]+) matches id= and then the ([^&]+) capturing group #1 matches and captures into Group 1 any one or more chars other than &. Note you may make it safer if you add [?&] before id to only match id and not thisid query param: [?&]id=([^&]+).
answered Dec 31 '18 at 12:15
Wiktor StribiżewWiktor Stribiżew
324k16146226
add a comment |
Dart compiled for the Web supports lokbehinds, but the current version of native Dart (including Flutter) does not support lookbehinds (source).
In your case, you want to match a string after a specific string. All you need is to declare a capturing group in your pattern and then access that submatch:
RegExp regExp = new RegExp(r"id=([^&]+)");
String s = "http://example.com?id=some.thing.com&other=parameter; http://example.com?id=some.thing.com";
Iterable<Match> matches = regExp.allMatches(s);
for (Match match in matches) {
print(match.group(1));
}
Output:
some.thing.com
some.thing.com
Here, id=([^&]+) matches id= and then the ([^&]+) capturing group #1 matches and captures into Group 1 any one or more chars other than &. Note you may make it safer if you add [?&] before id to only match id and not thisid query param: [?&]id=([^&]+).
answered Dec 31 '18 at 12:15
Wiktor StribiżewWiktor Stribiżew
324k16146226
add a comment |
Dart compiled for the Web supports lokbehinds, but the current version of native Dart (including Flutter) does not support lookbehinds (source).
In your case, you want to match a string after a specific string. All you need is to declare a capturing group in your pattern and then access that submatch:
RegExp regExp = new RegExp(r"id=([^&]+)");
String s = "http://example.com?id=some.thing.com&other=parameter; http://example.com?id=some.thing.com";
Iterable<Match> matches = regExp.allMatches(s);
for (Match match in matches) {
print(match.group(1));
}
Output:
some.thing.com
some.thing.com
Here, id=([^&]+) matches id= and then the ([^&]+) capturing group #1 matches and captures into Group 1 any one or more chars other than &. Note you may make it safer if you add [?&] before id to only match id and not thisid query param: [?&]id=([^&]+).
answered Dec 31 '18 at 12:15
Wiktor StribiżewWiktor Stribiżew
324k16146226
Dart compiled for the Web supports lokbehinds, but the current version of native Dart (including Flutter) does not support lookbehinds (source).
In your case, you want to match a string after a specific string. All you need is to declare a capturing group in your pattern and then access that submatch:
RegExp regExp = new RegExp(r"id=([^&]+)");
String s = "http://example.com?id=some.thing.com&other=parameter; http://example.com?id=some.thing.com";
Iterable<Match> matches = regExp.allMatches(s);
for (Match match in matches) {
print(match.group(1));
}
Output:
some.thing.com
some.thing.com
Here, id=([^&]+) matches id= and then the ([^&]+) capturing group #1 matches and captures into Group 1 any one or more chars other than &. Note you may make it safer if you add [?&] before id to only match id and not thisid query param: [?&]id=([^&]+).
answered Dec 31 '18 at 12:15
Wiktor StribiżewWiktor Stribiżew
324k16146226
answered Dec 31 '18 at 12:15
Wiktor StribiżewWiktor Stribiżew
324k16146226
answered Dec 31 '18 at 12:15
Wiktor StribiżewWiktor Stribiżew
324k16146226
answered Dec 31 '18 at 12:15
Wiktor StribiżewWiktor Stribiżew
324k16146226
324k16146226
add a comment |
add a comment |
I assume this is https://github.com/dart-lang/sdk/issues/34935
Bring Dart's RegExp support in line with JavaScript: lookbehinds, property escapes, and named groups.
answered Dec 31 '18 at 10:37
Günter ZöchbauerGünter Zöchbauer
332k701006941
So... Its not supported in current version of Flutter? So I will have to use justid=[^&]+and then ReplaceAllid=with''.
– Makalone LOgman
Dec 31 '18 at 10:40
1
Yes, Flutter depends on Dart for RegExp and Dart limits itself to what is supported in the browser, but they are a bit behind, because I think your example is now supported in recent browser versions, but not yet in Dart. I don't have deep RegExp knowledge and I'm not sure what a good workaround would be.
– Günter Zöchbauer
Dec 31 '18 at 10:47
Ok, thanks then.
– Makalone LOgman
Dec 31 '18 at 11:15
add a comment |
I assume this is https://github.com/dart-lang/sdk/issues/34935
Bring Dart's RegExp support in line with JavaScript: lookbehinds, property escapes, and named groups.
answered Dec 31 '18 at 10:37
Günter ZöchbauerGünter Zöchbauer
332k701006941
So... Its not supported in current version of Flutter? So I will have to use justid=[^&]+and then ReplaceAllid=with''.
– Makalone LOgman
Dec 31 '18 at 10:40
1
Yes, Flutter depends on Dart for RegExp and Dart limits itself to what is supported in the browser, but they are a bit behind, because I think your example is now supported in recent browser versions, but not yet in Dart. I don't have deep RegExp knowledge and I'm not sure what a good workaround would be.
– Günter Zöchbauer
Dec 31 '18 at 10:47
Ok, thanks then.
– Makalone LOgman
Dec 31 '18 at 11:15
add a comment |
I assume this is https://github.com/dart-lang/sdk/issues/34935
Bring Dart's RegExp support in line with JavaScript: lookbehinds, property escapes, and named groups.
answered Dec 31 '18 at 10:37
Günter ZöchbauerGünter Zöchbauer
332k701006941
I assume this is https://github.com/dart-lang/sdk/issues/34935
Bring Dart's RegExp support in line with JavaScript: lookbehinds, property escapes, and named groups.
answered Dec 31 '18 at 10:37
Günter ZöchbauerGünter Zöchbauer
332k701006941
answered Dec 31 '18 at 10:37
Günter ZöchbauerGünter Zöchbauer
332k701006941
answered Dec 31 '18 at 10:37
Günter ZöchbauerGünter Zöchbauer
332k701006941
answered Dec 31 '18 at 10:37
Günter ZöchbauerGünter Zöchbauer
332k701006941
332k701006941
So... Its not supported in current version of Flutter? So I will have to use justid=[^&]+and then ReplaceAllid=with''.
– Makalone LOgman
Dec 31 '18 at 10:40
1
Yes, Flutter depends on Dart for RegExp and Dart limits itself to what is supported in the browser, but they are a bit behind, because I think your example is now supported in recent browser versions, but not yet in Dart. I don't have deep RegExp knowledge and I'm not sure what a good workaround would be.
– Günter Zöchbauer
Dec 31 '18 at 10:47
Ok, thanks then.
– Makalone LOgman
Dec 31 '18 at 11:15
add a comment |
So... Its not supported in current version of Flutter? So I will have to use justid=[^&]+and then ReplaceAllid=with''.
– Makalone LOgman
Dec 31 '18 at 10:40
1
Yes, Flutter depends on Dart for RegExp and Dart limits itself to what is supported in the browser, but they are a bit behind, because I think your example is now supported in recent browser versions, but not yet in Dart. I don't have deep RegExp knowledge and I'm not sure what a good workaround would be.
– Günter Zöchbauer
Dec 31 '18 at 10:47
Ok, thanks then.
– Makalone LOgman
Dec 31 '18 at 11:15
So... Its not supported in current version of Flutter? So I will have to use just
id=[^&]+ and then ReplaceAll id= with '' .– Makalone LOgman
Dec 31 '18 at 10:40
So... Its not supported in current version of Flutter? So I will have to use just
id=[^&]+ and then ReplaceAll id= with '' .– Makalone LOgman
Dec 31 '18 at 10:40
1
1
Yes, Flutter depends on Dart for RegExp and Dart limits itself to what is supported in the browser, but they are a bit behind, because I think your example is now supported in recent browser versions, but not yet in Dart. I don't have deep RegExp knowledge and I'm not sure what a good workaround would be.
– Günter Zöchbauer
Dec 31 '18 at 10:47
Yes, Flutter depends on Dart for RegExp and Dart limits itself to what is supported in the browser, but they are a bit behind, because I think your example is now supported in recent browser versions, but not yet in Dart. I don't have deep RegExp knowledge and I'm not sure what a good workaround would be.
– Günter Zöchbauer
Dec 31 '18 at 10:47
Ok, thanks then.
– Makalone LOgman
Dec 31 '18 at 11:15
Ok, thanks then.
– Makalone LOgman
Dec 31 '18 at 11:15
add a comment |
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