How can I generate a structured list of 2 digit integers in Python? [duplicate]
This question already has an answer here:
How to get all possible combinations of a list’s elements?
24 answers
I'm attempting to replicate the attached piece of C# code in Python, but unfortunately I know a lot less about Python than I do with the former. The code essentially generates a list of 2 character/digit values e.g. aa, ab, ac, ad, etc. It includes combinations of A-Z, a-z, and 0-9.
I've looked into django.utils.crypto module, but that creates a randomised output, and the output from my C# code gives the exact amount of combinations when run. This is what I tried with Django's module:
get_random_string(length=2,
allowed_chars=u'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789')
Other options I tried do something similar, so I'm at a bit of a loss. I know the basics of Python, but unfortunately I haven't found enough to be able to replicate my C# code in Python. The C# code:
var alpha =
"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
var q = alpha.Select(x => x.ToString());
int size = 2;
for (int i = 0; i < size - 1; i++)
q = q.SelectMany(x => alphabet, (x, y) => x + y);
foreach (var item in q)
Console.WriteLine(item);
Converted into python, the function should generate about 62^2 combinations of the values in 2 digit integers.
c# python
marked as duplicate by U9-Forward, martineau
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Jan 2 at 9:19
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
How to get all possible combinations of a list’s elements?
24 answers
I'm attempting to replicate the attached piece of C# code in Python, but unfortunately I know a lot less about Python than I do with the former. The code essentially generates a list of 2 character/digit values e.g. aa, ab, ac, ad, etc. It includes combinations of A-Z, a-z, and 0-9.
I've looked into django.utils.crypto module, but that creates a randomised output, and the output from my C# code gives the exact amount of combinations when run. This is what I tried with Django's module:
get_random_string(length=2,
allowed_chars=u'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789')
Other options I tried do something similar, so I'm at a bit of a loss. I know the basics of Python, but unfortunately I haven't found enough to be able to replicate my C# code in Python. The C# code:
var alpha =
"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
var q = alpha.Select(x => x.ToString());
int size = 2;
for (int i = 0; i < size - 1; i++)
q = q.SelectMany(x => alphabet, (x, y) => x + y);
foreach (var item in q)
Console.WriteLine(item);
Converted into python, the function should generate about 62^2 combinations of the values in 2 digit integers.
c# python
marked as duplicate by U9-Forward, martineau
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Jan 2 at 9:19
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
How to get all possible combinations of a list’s elements?
24 answers
I'm attempting to replicate the attached piece of C# code in Python, but unfortunately I know a lot less about Python than I do with the former. The code essentially generates a list of 2 character/digit values e.g. aa, ab, ac, ad, etc. It includes combinations of A-Z, a-z, and 0-9.
I've looked into django.utils.crypto module, but that creates a randomised output, and the output from my C# code gives the exact amount of combinations when run. This is what I tried with Django's module:
get_random_string(length=2,
allowed_chars=u'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789')
Other options I tried do something similar, so I'm at a bit of a loss. I know the basics of Python, but unfortunately I haven't found enough to be able to replicate my C# code in Python. The C# code:
var alpha =
"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
var q = alpha.Select(x => x.ToString());
int size = 2;
for (int i = 0; i < size - 1; i++)
q = q.SelectMany(x => alphabet, (x, y) => x + y);
foreach (var item in q)
Console.WriteLine(item);
Converted into python, the function should generate about 62^2 combinations of the values in 2 digit integers.
c# python
This question already has an answer here:
How to get all possible combinations of a list’s elements?
24 answers
I'm attempting to replicate the attached piece of C# code in Python, but unfortunately I know a lot less about Python than I do with the former. The code essentially generates a list of 2 character/digit values e.g. aa, ab, ac, ad, etc. It includes combinations of A-Z, a-z, and 0-9.
I've looked into django.utils.crypto module, but that creates a randomised output, and the output from my C# code gives the exact amount of combinations when run. This is what I tried with Django's module:
get_random_string(length=2,
allowed_chars=u'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789')
Other options I tried do something similar, so I'm at a bit of a loss. I know the basics of Python, but unfortunately I haven't found enough to be able to replicate my C# code in Python. The C# code:
var alpha =
"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
var q = alpha.Select(x => x.ToString());
int size = 2;
for (int i = 0; i < size - 1; i++)
q = q.SelectMany(x => alphabet, (x, y) => x + y);
foreach (var item in q)
Console.WriteLine(item);
Converted into python, the function should generate about 62^2 combinations of the values in 2 digit integers.
This question already has an answer here:
How to get all possible combinations of a list’s elements?
24 answers
c# python
c# python
edited Jan 2 at 10:26
Alex Gho
asked Jan 2 at 9:11
Alex GhoAlex Gho
163
163
marked as duplicate by U9-Forward, martineau
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Jan 2 at 9:19
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by U9-Forward, martineau
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Jan 2 at 9:19
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Here's an example
alpha = 'abc'
from itertools import permutations, combinations_with_replacement
[''.join(i) for i in list(set(combinations_with_replacement(alpha, 2)) | set(permutations(alpha, 2)))]
# Output -> ['ab', 'ba', 'aa', 'cc', 'bb', 'cb', 'ac', 'ca', 'bc'] which is 3^2
Now create alpha
as suggested by @Adam Feor in comment
import string
alpha = string.ascii_letters + string.digits
print(alpha)
Output -> abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
1
You can also import the string module which contains ascii_letters and digits to get the characters you want. characters = string.ascii_letters + string.digits
– Adam Feor
Jan 2 at 9:23
This is what I was looking for, thanks! Although I'm attempting to run this code but it doesn't seem to output when I attempt to print. I'm probably missing something simple here (not great with Python).
– Alex Gho
Jan 2 at 9:47
@AlexGho store the last line which goes like[''.join..
into a variable sayout = [''.join..
and then useprint(out)
– meW
Jan 2 at 9:52
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here's an example
alpha = 'abc'
from itertools import permutations, combinations_with_replacement
[''.join(i) for i in list(set(combinations_with_replacement(alpha, 2)) | set(permutations(alpha, 2)))]
# Output -> ['ab', 'ba', 'aa', 'cc', 'bb', 'cb', 'ac', 'ca', 'bc'] which is 3^2
Now create alpha
as suggested by @Adam Feor in comment
import string
alpha = string.ascii_letters + string.digits
print(alpha)
Output -> abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
1
You can also import the string module which contains ascii_letters and digits to get the characters you want. characters = string.ascii_letters + string.digits
– Adam Feor
Jan 2 at 9:23
This is what I was looking for, thanks! Although I'm attempting to run this code but it doesn't seem to output when I attempt to print. I'm probably missing something simple here (not great with Python).
– Alex Gho
Jan 2 at 9:47
@AlexGho store the last line which goes like[''.join..
into a variable sayout = [''.join..
and then useprint(out)
– meW
Jan 2 at 9:52
add a comment |
Here's an example
alpha = 'abc'
from itertools import permutations, combinations_with_replacement
[''.join(i) for i in list(set(combinations_with_replacement(alpha, 2)) | set(permutations(alpha, 2)))]
# Output -> ['ab', 'ba', 'aa', 'cc', 'bb', 'cb', 'ac', 'ca', 'bc'] which is 3^2
Now create alpha
as suggested by @Adam Feor in comment
import string
alpha = string.ascii_letters + string.digits
print(alpha)
Output -> abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
1
You can also import the string module which contains ascii_letters and digits to get the characters you want. characters = string.ascii_letters + string.digits
– Adam Feor
Jan 2 at 9:23
This is what I was looking for, thanks! Although I'm attempting to run this code but it doesn't seem to output when I attempt to print. I'm probably missing something simple here (not great with Python).
– Alex Gho
Jan 2 at 9:47
@AlexGho store the last line which goes like[''.join..
into a variable sayout = [''.join..
and then useprint(out)
– meW
Jan 2 at 9:52
add a comment |
Here's an example
alpha = 'abc'
from itertools import permutations, combinations_with_replacement
[''.join(i) for i in list(set(combinations_with_replacement(alpha, 2)) | set(permutations(alpha, 2)))]
# Output -> ['ab', 'ba', 'aa', 'cc', 'bb', 'cb', 'ac', 'ca', 'bc'] which is 3^2
Now create alpha
as suggested by @Adam Feor in comment
import string
alpha = string.ascii_letters + string.digits
print(alpha)
Output -> abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
Here's an example
alpha = 'abc'
from itertools import permutations, combinations_with_replacement
[''.join(i) for i in list(set(combinations_with_replacement(alpha, 2)) | set(permutations(alpha, 2)))]
# Output -> ['ab', 'ba', 'aa', 'cc', 'bb', 'cb', 'ac', 'ca', 'bc'] which is 3^2
Now create alpha
as suggested by @Adam Feor in comment
import string
alpha = string.ascii_letters + string.digits
print(alpha)
Output -> abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
edited Jan 2 at 9:26
answered Jan 2 at 9:21
meWmeW
2,858120
2,858120
1
You can also import the string module which contains ascii_letters and digits to get the characters you want. characters = string.ascii_letters + string.digits
– Adam Feor
Jan 2 at 9:23
This is what I was looking for, thanks! Although I'm attempting to run this code but it doesn't seem to output when I attempt to print. I'm probably missing something simple here (not great with Python).
– Alex Gho
Jan 2 at 9:47
@AlexGho store the last line which goes like[''.join..
into a variable sayout = [''.join..
and then useprint(out)
– meW
Jan 2 at 9:52
add a comment |
1
You can also import the string module which contains ascii_letters and digits to get the characters you want. characters = string.ascii_letters + string.digits
– Adam Feor
Jan 2 at 9:23
This is what I was looking for, thanks! Although I'm attempting to run this code but it doesn't seem to output when I attempt to print. I'm probably missing something simple here (not great with Python).
– Alex Gho
Jan 2 at 9:47
@AlexGho store the last line which goes like[''.join..
into a variable sayout = [''.join..
and then useprint(out)
– meW
Jan 2 at 9:52
1
1
You can also import the string module which contains ascii_letters and digits to get the characters you want. characters = string.ascii_letters + string.digits
– Adam Feor
Jan 2 at 9:23
You can also import the string module which contains ascii_letters and digits to get the characters you want. characters = string.ascii_letters + string.digits
– Adam Feor
Jan 2 at 9:23
This is what I was looking for, thanks! Although I'm attempting to run this code but it doesn't seem to output when I attempt to print. I'm probably missing something simple here (not great with Python).
– Alex Gho
Jan 2 at 9:47
This is what I was looking for, thanks! Although I'm attempting to run this code but it doesn't seem to output when I attempt to print. I'm probably missing something simple here (not great with Python).
– Alex Gho
Jan 2 at 9:47
@AlexGho store the last line which goes like
[''.join..
into a variable say out = [''.join..
and then use print(out)
– meW
Jan 2 at 9:52
@AlexGho store the last line which goes like
[''.join..
into a variable say out = [''.join..
and then use print(out)
– meW
Jan 2 at 9:52
add a comment |