Mixing
Getting values from JSON multidimensional array?
I have a JSON array that looks like this:
{
"id": 258,
"rawId": null,
"displayName": null,
"name": {
"givenName": "my ame",
"honorificSuffix": "",
"formatted": "my ame",
"middleName": "",
"familyName": "",
"honorificPrefix": ""
},
"nickname": "",
"phoneNumbers": [{
"value": "23423442342424",
"pref": false,
"id": 0,
"type": "mobile"
}],
"emails": null,
"addresses": null,
"ims": null,
"organizations": [{
"pref": "false",
"title": "",
"name": "",
"department": "",
"type": null
}],
"birthday": null,
"note": "",
"photos": null,
"categories": null,
"urls": null
}
I need to get the phoneNumbers >> value from this JSON.
SO I TRIED SOMETHING LIKE THIS:
var d = JSON.parse(test);
alert(test[0].phoneNumbers.value);
The variable test is the JSON shown above.
and I also tried:
alert(d[0].phoneNumbers.value);
and
alert(test.phoneNumbers.value);
But none of the above work.
Is there something that I am missing in my code?
Thanks in advance.
javascript json
edited Jan 2 at 18:25
skellertor
360217
asked Jan 2 at 16:11
James JuanjieJames Juanjie
738
add a comment |
I have a JSON array that looks like this:
{
"id": 258,
"rawId": null,
"displayName": null,
"name": {
"givenName": "my ame",
"honorificSuffix": "",
"formatted": "my ame",
"middleName": "",
"familyName": "",
"honorificPrefix": ""
},
"nickname": "",
"phoneNumbers": [{
"value": "23423442342424",
"pref": false,
"id": 0,
"type": "mobile"
}],
"emails": null,
"addresses": null,
"ims": null,
"organizations": [{
"pref": "false",
"title": "",
"name": "",
"department": "",
"type": null
}],
"birthday": null,
"note": "",
"photos": null,
"categories": null,
"urls": null
}
I need to get the phoneNumbers >> value from this JSON.
SO I TRIED SOMETHING LIKE THIS:
var d = JSON.parse(test);
alert(test[0].phoneNumbers.value);
The variable test is the JSON shown above.
and I also tried:
alert(d[0].phoneNumbers.value);
and
alert(test.phoneNumbers.value);
But none of the above work.
Is there something that I am missing in my code?
Thanks in advance.
javascript json
edited Jan 2 at 18:25
skellertor
360217
asked Jan 2 at 16:11
James JuanjieJames Juanjie
738
6
d.phoneNumbers[0].value
– Robin Zigmond
Jan 2 at 16:13
1
phoneNumbers is an array so you should iterate that to get the value.
– Alex G
Jan 2 at 16:13
add a comment |
I have a JSON array that looks like this:
{
"id": 258,
"rawId": null,
"displayName": null,
"name": {
"givenName": "my ame",
"honorificSuffix": "",
"formatted": "my ame",
"middleName": "",
"familyName": "",
"honorificPrefix": ""
},
"nickname": "",
"phoneNumbers": [{
"value": "23423442342424",
"pref": false,
"id": 0,
"type": "mobile"
}],
"emails": null,
"addresses": null,
"ims": null,
"organizations": [{
"pref": "false",
"title": "",
"name": "",
"department": "",
"type": null
}],
"birthday": null,
"note": "",
"photos": null,
"categories": null,
"urls": null
}
I need to get the phoneNumbers >> value from this JSON.
SO I TRIED SOMETHING LIKE THIS:
var d = JSON.parse(test);
alert(test[0].phoneNumbers.value);
The variable test is the JSON shown above.
and I also tried:
alert(d[0].phoneNumbers.value);
and
alert(test.phoneNumbers.value);
But none of the above work.
Is there something that I am missing in my code?
Thanks in advance.
javascript json
edited Jan 2 at 18:25
skellertor
360217
asked Jan 2 at 16:11
James JuanjieJames Juanjie
738
I have a JSON array that looks like this:
{
"id": 258,
"rawId": null,
"displayName": null,
"name": {
"givenName": "my ame",
"honorificSuffix": "",
"formatted": "my ame",
"middleName": "",
"familyName": "",
"honorificPrefix": ""
},
"nickname": "",
"phoneNumbers": [{
"value": "23423442342424",
"pref": false,
"id": 0,
"type": "mobile"
}],
"emails": null,
"addresses": null,
"ims": null,
"organizations": [{
"pref": "false",
"title": "",
"name": "",
"department": "",
"type": null
}],
"birthday": null,
"note": "",
"photos": null,
"categories": null,
"urls": null
}
I need to get the phoneNumbers >> value from this JSON.
SO I TRIED SOMETHING LIKE THIS:
var d = JSON.parse(test);
alert(test[0].phoneNumbers.value);
The variable test is the JSON shown above.
and I also tried:
alert(d[0].phoneNumbers.value);
and
alert(test.phoneNumbers.value);
But none of the above work.
Is there something that I am missing in my code?
Thanks in advance.
javascript json
javascript json
edited Jan 2 at 18:25
skellertor
360217
asked Jan 2 at 16:11
James JuanjieJames Juanjie
738
edited Jan 2 at 18:25
skellertor
360217
asked Jan 2 at 16:11
James JuanjieJames Juanjie
738
edited Jan 2 at 18:25
skellertor
360217
edited Jan 2 at 18:25
skellertor
360217
edited Jan 2 at 18:25
skellertor
360217
360217
asked Jan 2 at 16:11
James JuanjieJames Juanjie
738
asked Jan 2 at 16:11
James JuanjieJames Juanjie
738
asked Jan 2 at 16:11
James JuanjieJames Juanjie
738
738
6
d.phoneNumbers[0].value
– Robin Zigmond
Jan 2 at 16:13
1
phoneNumbers is an array so you should iterate that to get the value.
– Alex G
Jan 2 at 16:13
add a comment |
6
d.phoneNumbers[0].value
– Robin Zigmond
Jan 2 at 16:13
1
phoneNumbers is an array so you should iterate that to get the value.
– Alex G
Jan 2 at 16:13
6
6
d.phoneNumbers[0].value– Robin Zigmond
Jan 2 at 16:13
d.phoneNumbers[0].value– Robin Zigmond
Jan 2 at 16:13
1
1
phoneNumbers is an array so you should iterate that to get the value.
– Alex G
Jan 2 at 16:13
phoneNumbers is an array so you should iterate that to get the value.
– Alex G
Jan 2 at 16:13
add a comment |
1 Answer
1
active
oldest
votes
What you showed us is a JSON string (giving a JS object after parsing), not an array.
So d[0].phoneNumbers will not work and d.phoneNumbers will work and will give you an array.
And because it will give you an array, d.phoneNumbers.value will not work, and d.phoneNumbers[0].value will.
answered Jan 2 at 16:16
iArcadiaiArcadia
1,151619
1
testis the original string, the OP has given the namedto the object formed by parsing it
– Robin Zigmond
Jan 2 at 16:33
Corrected, thanks
– iArcadia
Jan 2 at 16:35
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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oldest
votes
What you showed us is a JSON string (giving a JS object after parsing), not an array.
So d[0].phoneNumbers will not work and d.phoneNumbers will work and will give you an array.
And because it will give you an array, d.phoneNumbers.value will not work, and d.phoneNumbers[0].value will.
answered Jan 2 at 16:16
iArcadiaiArcadia
1,151619
1
testis the original string, the OP has given the namedto the object formed by parsing it
– Robin Zigmond
Jan 2 at 16:33
Corrected, thanks
– iArcadia
Jan 2 at 16:35
add a comment |
What you showed us is a JSON string (giving a JS object after parsing), not an array.
So d[0].phoneNumbers will not work and d.phoneNumbers will work and will give you an array.
And because it will give you an array, d.phoneNumbers.value will not work, and d.phoneNumbers[0].value will.
answered Jan 2 at 16:16
iArcadiaiArcadia
1,151619
1
testis the original string, the OP has given the namedto the object formed by parsing it
– Robin Zigmond
Jan 2 at 16:33
Corrected, thanks
– iArcadia
Jan 2 at 16:35
add a comment |
What you showed us is a JSON string (giving a JS object after parsing), not an array.
So d[0].phoneNumbers will not work and d.phoneNumbers will work and will give you an array.
And because it will give you an array, d.phoneNumbers.value will not work, and d.phoneNumbers[0].value will.
answered Jan 2 at 16:16
iArcadiaiArcadia
1,151619
What you showed us is a JSON string (giving a JS object after parsing), not an array.
So d[0].phoneNumbers will not work and d.phoneNumbers will work and will give you an array.
And because it will give you an array, d.phoneNumbers.value will not work, and d.phoneNumbers[0].value will.
answered Jan 2 at 16:16
iArcadiaiArcadia
1,151619
edited Jan 2 at 16:34
answered Jan 2 at 16:16
iArcadiaiArcadia
1,151619
answered Jan 2 at 16:16
iArcadiaiArcadia
1,151619
answered Jan 2 at 16:16
iArcadiaiArcadia
1,151619
1,151619
1
testis the original string, the OP has given the namedto the object formed by parsing it
– Robin Zigmond
Jan 2 at 16:33
Corrected, thanks
– iArcadia
Jan 2 at 16:35
add a comment |
1
testis the original string, the OP has given the namedto the object formed by parsing it
– Robin Zigmond
Jan 2 at 16:33
Corrected, thanks
– iArcadia
Jan 2 at 16:35
1
1
test is the original string, the OP has given the name d to the object formed by parsing it– Robin Zigmond
Jan 2 at 16:33
test is the original string, the OP has given the name d to the object formed by parsing it– Robin Zigmond
Jan 2 at 16:33
Corrected, thanks
– iArcadia
Jan 2 at 16:35
Corrected, thanks
– iArcadia
Jan 2 at 16:35
add a comment |
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6
d.phoneNumbers[0].value– Robin Zigmond
Jan 2 at 16:13
1
phoneNumbers is an array so you should iterate that to get the value.
– Alex G
Jan 2 at 16:13