How to use converters with RelativeLayout.XConstraint?












0















I want to center an image inside its RelativeLayout



the equation for the X point should be = (width of parent - width of the view)/2..



I tried to write it in XAML:



 <RelativeLayout x:Name="rel1">
<Image x:Name="image1" Aspect="AspectFit"
RelativeLayout.XConstraint="{ConstraintExpression Type=Constant,
Constant={Binding Source=rel1, Path=Width, Converter={StaticResource centerFromWidth},
ConverterParameter={Binding Source=image1, Path=Width}}}"
RelativeLayout.YConstraint="{ConstraintExpression Type=RelativeToParent,
Property=Height, Factor=0.5, Constant=0}"
Source="{Binding File1, Converter={StaticResource base64ToImage}}">
</Image>
<RelativeLayout.GestureRecognizers>
<TapGestureRecognizer Command="{Binding OpenImagePopupCommand}" CommandParameter="1"/>
</RelativeLayout.GestureRecognizers>

</RelativeLayout>


and this is the converter:



 public class FromDimensionToCenter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
var parentWidth = (double)value;
var viewWidth = (double)parameter;
return (parentWidth - viewWidth) / 2;
}

public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}


But I get this error:




No property, bindable property, or event found for 'Constant', or
mismatching type between value and property.











share|improve this question























  • You could see in the source code that "Constant" is not BindableProperty,so I think that is where the error is, maybe you could customize Relelayout by adding a property of type BindableProperty .

    – Leo Zhu - MSFT
    Jan 2 at 3:04











  • You could refer to this link to center your Image :stackoverflow.com/questions/40942691/…

    – Leo Zhu - MSFT
    Jan 2 at 6:35
















0















I want to center an image inside its RelativeLayout



the equation for the X point should be = (width of parent - width of the view)/2..



I tried to write it in XAML:



 <RelativeLayout x:Name="rel1">
<Image x:Name="image1" Aspect="AspectFit"
RelativeLayout.XConstraint="{ConstraintExpression Type=Constant,
Constant={Binding Source=rel1, Path=Width, Converter={StaticResource centerFromWidth},
ConverterParameter={Binding Source=image1, Path=Width}}}"
RelativeLayout.YConstraint="{ConstraintExpression Type=RelativeToParent,
Property=Height, Factor=0.5, Constant=0}"
Source="{Binding File1, Converter={StaticResource base64ToImage}}">
</Image>
<RelativeLayout.GestureRecognizers>
<TapGestureRecognizer Command="{Binding OpenImagePopupCommand}" CommandParameter="1"/>
</RelativeLayout.GestureRecognizers>

</RelativeLayout>


and this is the converter:



 public class FromDimensionToCenter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
var parentWidth = (double)value;
var viewWidth = (double)parameter;
return (parentWidth - viewWidth) / 2;
}

public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}


But I get this error:




No property, bindable property, or event found for 'Constant', or
mismatching type between value and property.











share|improve this question























  • You could see in the source code that "Constant" is not BindableProperty,so I think that is where the error is, maybe you could customize Relelayout by adding a property of type BindableProperty .

    – Leo Zhu - MSFT
    Jan 2 at 3:04











  • You could refer to this link to center your Image :stackoverflow.com/questions/40942691/…

    – Leo Zhu - MSFT
    Jan 2 at 6:35














0












0








0








I want to center an image inside its RelativeLayout



the equation for the X point should be = (width of parent - width of the view)/2..



I tried to write it in XAML:



 <RelativeLayout x:Name="rel1">
<Image x:Name="image1" Aspect="AspectFit"
RelativeLayout.XConstraint="{ConstraintExpression Type=Constant,
Constant={Binding Source=rel1, Path=Width, Converter={StaticResource centerFromWidth},
ConverterParameter={Binding Source=image1, Path=Width}}}"
RelativeLayout.YConstraint="{ConstraintExpression Type=RelativeToParent,
Property=Height, Factor=0.5, Constant=0}"
Source="{Binding File1, Converter={StaticResource base64ToImage}}">
</Image>
<RelativeLayout.GestureRecognizers>
<TapGestureRecognizer Command="{Binding OpenImagePopupCommand}" CommandParameter="1"/>
</RelativeLayout.GestureRecognizers>

</RelativeLayout>


and this is the converter:



 public class FromDimensionToCenter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
var parentWidth = (double)value;
var viewWidth = (double)parameter;
return (parentWidth - viewWidth) / 2;
}

public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}


But I get this error:




No property, bindable property, or event found for 'Constant', or
mismatching type between value and property.











share|improve this question














I want to center an image inside its RelativeLayout



the equation for the X point should be = (width of parent - width of the view)/2..



I tried to write it in XAML:



 <RelativeLayout x:Name="rel1">
<Image x:Name="image1" Aspect="AspectFit"
RelativeLayout.XConstraint="{ConstraintExpression Type=Constant,
Constant={Binding Source=rel1, Path=Width, Converter={StaticResource centerFromWidth},
ConverterParameter={Binding Source=image1, Path=Width}}}"
RelativeLayout.YConstraint="{ConstraintExpression Type=RelativeToParent,
Property=Height, Factor=0.5, Constant=0}"
Source="{Binding File1, Converter={StaticResource base64ToImage}}">
</Image>
<RelativeLayout.GestureRecognizers>
<TapGestureRecognizer Command="{Binding OpenImagePopupCommand}" CommandParameter="1"/>
</RelativeLayout.GestureRecognizers>

</RelativeLayout>


and this is the converter:



 public class FromDimensionToCenter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
var parentWidth = (double)value;
var viewWidth = (double)parameter;
return (parentWidth - viewWidth) / 2;
}

public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}


But I get this error:




No property, bindable property, or event found for 'Constant', or
mismatching type between value and property.








c# xamarin xamarin.forms relativelayout






share|improve this question













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asked Jan 1 at 13:27









mshwfmshwf

2,29142156




2,29142156













  • You could see in the source code that "Constant" is not BindableProperty,so I think that is where the error is, maybe you could customize Relelayout by adding a property of type BindableProperty .

    – Leo Zhu - MSFT
    Jan 2 at 3:04











  • You could refer to this link to center your Image :stackoverflow.com/questions/40942691/…

    – Leo Zhu - MSFT
    Jan 2 at 6:35



















  • You could see in the source code that "Constant" is not BindableProperty,so I think that is where the error is, maybe you could customize Relelayout by adding a property of type BindableProperty .

    – Leo Zhu - MSFT
    Jan 2 at 3:04











  • You could refer to this link to center your Image :stackoverflow.com/questions/40942691/…

    – Leo Zhu - MSFT
    Jan 2 at 6:35

















You could see in the source code that "Constant" is not BindableProperty,so I think that is where the error is, maybe you could customize Relelayout by adding a property of type BindableProperty .

– Leo Zhu - MSFT
Jan 2 at 3:04





You could see in the source code that "Constant" is not BindableProperty,so I think that is where the error is, maybe you could customize Relelayout by adding a property of type BindableProperty .

– Leo Zhu - MSFT
Jan 2 at 3:04













You could refer to this link to center your Image :stackoverflow.com/questions/40942691/…

– Leo Zhu - MSFT
Jan 2 at 6:35





You could refer to this link to center your Image :stackoverflow.com/questions/40942691/…

– Leo Zhu - MSFT
Jan 2 at 6:35












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