Mixing
Three friends problem.
$begingroup$
Once there were 3 friends A, B, C. They went together to have a lunch at a hotel. The lunch they had costed 60 according to the menu. They paid the bill each one contributing 20. But when the waiter brought the sum to the manager, the manager returned 10$ saying today is a special day. But when the waiter went to return the money, he found that the three friends left. So he got the member book and found the address and left to return money via taxi, so he kept 4 dollar for his going and returning and returned 2 dollars to each of the friends. Now Each of the friends got 2 dollar so the money they contributed = 18 dollar So total money =18*3 + 4=58. Where is the remaining 2 dollar?
puzzle
asked May 12 '14 at 17:22
Ravindra SahayRavindra Sahay
34
$endgroup$
add a comment |
$begingroup$
Once there were 3 friends A, B, C. They went together to have a lunch at a hotel. The lunch they had costed 60 according to the menu. They paid the bill each one contributing 20. But when the waiter brought the sum to the manager, the manager returned 10$ saying today is a special day. But when the waiter went to return the money, he found that the three friends left. So he got the member book and found the address and left to return money via taxi, so he kept 4 dollar for his going and returning and returned 2 dollars to each of the friends. Now Each of the friends got 2 dollar so the money they contributed = 18 dollar So total money =18*3 + 4=58. Where is the remaining 2 dollar?
puzzle
asked May 12 '14 at 17:22
Ravindra SahayRavindra Sahay
34
$endgroup$
$begingroup$
In the sleight of hand. More precisely, you're trying to add chicken to geese.
$endgroup$
– TZakrevskiy
May 12 '14 at 17:29
$begingroup$
I know i just want to share interesting questions with everyone.@TZakrevskiy
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:30
1
$begingroup$
How to drive a mathematician crazy. Part deux. IOW: Old hat. Ancient even.
$endgroup$
– Jyrki Lahtonen
May 12 '14 at 17:31
$begingroup$
Well i never read that though cool one. I especially like these one way solution problems.@JyrkiLahtonen
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:33
add a comment |
$begingroup$
Once there were 3 friends A, B, C. They went together to have a lunch at a hotel. The lunch they had costed 60 according to the menu. They paid the bill each one contributing 20. But when the waiter brought the sum to the manager, the manager returned 10$ saying today is a special day. But when the waiter went to return the money, he found that the three friends left. So he got the member book and found the address and left to return money via taxi, so he kept 4 dollar for his going and returning and returned 2 dollars to each of the friends. Now Each of the friends got 2 dollar so the money they contributed = 18 dollar So total money =18*3 + 4=58. Where is the remaining 2 dollar?
puzzle
asked May 12 '14 at 17:22
Ravindra SahayRavindra Sahay
34
$endgroup$
Once there were 3 friends A, B, C. They went together to have a lunch at a hotel. The lunch they had costed 60 according to the menu. They paid the bill each one contributing 20. But when the waiter brought the sum to the manager, the manager returned 10$ saying today is a special day. But when the waiter went to return the money, he found that the three friends left. So he got the member book and found the address and left to return money via taxi, so he kept 4 dollar for his going and returning and returned 2 dollars to each of the friends. Now Each of the friends got 2 dollar so the money they contributed = 18 dollar So total money =18*3 + 4=58. Where is the remaining 2 dollar?
puzzle
puzzle
asked May 12 '14 at 17:22
Ravindra SahayRavindra Sahay
34
asked May 12 '14 at 17:22
Ravindra SahayRavindra Sahay
34
asked May 12 '14 at 17:22
Ravindra SahayRavindra Sahay
34
asked May 12 '14 at 17:22
Ravindra SahayRavindra Sahay
34
asked May 12 '14 at 17:22
Ravindra SahayRavindra Sahay
34
34
$begingroup$
In the sleight of hand. More precisely, you're trying to add chicken to geese.
$endgroup$
– TZakrevskiy
May 12 '14 at 17:29
$begingroup$
I know i just want to share interesting questions with everyone.@TZakrevskiy
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:30
1
$begingroup$
How to drive a mathematician crazy. Part deux. IOW: Old hat. Ancient even.
$endgroup$
– Jyrki Lahtonen
May 12 '14 at 17:31
$begingroup$
Well i never read that though cool one. I especially like these one way solution problems.@JyrkiLahtonen
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:33
add a comment |
$begingroup$
In the sleight of hand. More precisely, you're trying to add chicken to geese.
$endgroup$
– TZakrevskiy
May 12 '14 at 17:29
$begingroup$
I know i just want to share interesting questions with everyone.@TZakrevskiy
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:30
1
$begingroup$
How to drive a mathematician crazy. Part deux. IOW: Old hat. Ancient even.
$endgroup$
– Jyrki Lahtonen
May 12 '14 at 17:31
$begingroup$
Well i never read that though cool one. I especially like these one way solution problems.@JyrkiLahtonen
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:33
$begingroup$
In the sleight of hand. More precisely, you're trying to add chicken to geese.
$endgroup$
– TZakrevskiy
May 12 '14 at 17:29
$begingroup$
In the sleight of hand. More precisely, you're trying to add chicken to geese.
$endgroup$
– TZakrevskiy
May 12 '14 at 17:29
$begingroup$
I know i just want to share interesting questions with everyone.@TZakrevskiy
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:30
$begingroup$
I know i just want to share interesting questions with everyone.@TZakrevskiy
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:30
1
1
$begingroup$
How to drive a mathematician crazy. Part deux. IOW: Old hat. Ancient even.
$endgroup$
– Jyrki Lahtonen
May 12 '14 at 17:31
$begingroup$
How to drive a mathematician crazy. Part deux. IOW: Old hat. Ancient even.
$endgroup$
– Jyrki Lahtonen
May 12 '14 at 17:31
$begingroup$
Well i never read that though cool one. I especially like these one way solution problems.@JyrkiLahtonen
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:33
$begingroup$
Well i never read that though cool one. I especially like these one way solution problems.@JyrkiLahtonen
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:33
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
The $18cdot3+4$ part is wrong. If The money each person initially spends is $20$. Then each person is supposed to get $3frac{1}{3}$ back. However, the waiter takes away $frac43$ per person for coming and going. So Each person therefore actually gets $frac{10}3-frac43=2$ back. In this process the total remains same.
$$text{Thou shalt not think of cheating mathematics.}$$
answered May 12 '14 at 17:47
shaurya guptashaurya gupta
2,40051937
$endgroup$
add a comment |
$begingroup$
This is indeed an old hat. Each of the three paid $$, 18.00$, makes $$,54.00$ in all. $$,4.00$ went to the waiter and $$,50.00$ to the manager. Nothing went lost.
answered May 12 '14 at 18:16
Christian BlatterChristian Blatter
175k8115327
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
The $18cdot3+4$ part is wrong. If The money each person initially spends is $20$. Then each person is supposed to get $3frac{1}{3}$ back. However, the waiter takes away $frac43$ per person for coming and going. So Each person therefore actually gets $frac{10}3-frac43=2$ back. In this process the total remains same.
$$text{Thou shalt not think of cheating mathematics.}$$
answered May 12 '14 at 17:47
shaurya guptashaurya gupta
2,40051937
$endgroup$
add a comment |
$begingroup$
The $18cdot3+4$ part is wrong. If The money each person initially spends is $20$. Then each person is supposed to get $3frac{1}{3}$ back. However, the waiter takes away $frac43$ per person for coming and going. So Each person therefore actually gets $frac{10}3-frac43=2$ back. In this process the total remains same.
$$text{Thou shalt not think of cheating mathematics.}$$
answered May 12 '14 at 17:47
shaurya guptashaurya gupta
2,40051937
$endgroup$
add a comment |
$begingroup$
The $18cdot3+4$ part is wrong. If The money each person initially spends is $20$. Then each person is supposed to get $3frac{1}{3}$ back. However, the waiter takes away $frac43$ per person for coming and going. So Each person therefore actually gets $frac{10}3-frac43=2$ back. In this process the total remains same.
$$text{Thou shalt not think of cheating mathematics.}$$
answered May 12 '14 at 17:47
shaurya guptashaurya gupta
2,40051937
$endgroup$
The $18cdot3+4$ part is wrong. If The money each person initially spends is $20$. Then each person is supposed to get $3frac{1}{3}$ back. However, the waiter takes away $frac43$ per person for coming and going. So Each person therefore actually gets $frac{10}3-frac43=2$ back. In this process the total remains same.
$$text{Thou shalt not think of cheating mathematics.}$$
answered May 12 '14 at 17:47
shaurya guptashaurya gupta
2,40051937
answered May 12 '14 at 17:47
shaurya guptashaurya gupta
2,40051937
answered May 12 '14 at 17:47
shaurya guptashaurya gupta
2,40051937
answered May 12 '14 at 17:47
shaurya guptashaurya gupta
2,40051937
2,40051937
add a comment |
add a comment |
$begingroup$
This is indeed an old hat. Each of the three paid $$, 18.00$, makes $$,54.00$ in all. $$,4.00$ went to the waiter and $$,50.00$ to the manager. Nothing went lost.
answered May 12 '14 at 18:16
Christian BlatterChristian Blatter
175k8115327
$endgroup$
add a comment |
$begingroup$
This is indeed an old hat. Each of the three paid $$, 18.00$, makes $$,54.00$ in all. $$,4.00$ went to the waiter and $$,50.00$ to the manager. Nothing went lost.
answered May 12 '14 at 18:16
Christian BlatterChristian Blatter
175k8115327
$endgroup$
add a comment |
$begingroup$
This is indeed an old hat. Each of the three paid $$, 18.00$, makes $$,54.00$ in all. $$,4.00$ went to the waiter and $$,50.00$ to the manager. Nothing went lost.
answered May 12 '14 at 18:16
Christian BlatterChristian Blatter
175k8115327
$endgroup$
This is indeed an old hat. Each of the three paid $$, 18.00$, makes $$,54.00$ in all. $$,4.00$ went to the waiter and $$,50.00$ to the manager. Nothing went lost.
answered May 12 '14 at 18:16
Christian BlatterChristian Blatter
175k8115327
answered May 12 '14 at 18:16
Christian BlatterChristian Blatter
175k8115327
answered May 12 '14 at 18:16
Christian BlatterChristian Blatter
175k8115327
answered May 12 '14 at 18:16
Christian BlatterChristian Blatter
175k8115327
175k8115327
add a comment |
add a comment |
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$begingroup$
In the sleight of hand. More precisely, you're trying to add chicken to geese.
$endgroup$
– TZakrevskiy
May 12 '14 at 17:29
$begingroup$
I know i just want to share interesting questions with everyone.@TZakrevskiy
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:30
1
$begingroup$
How to drive a mathematician crazy. Part deux. IOW: Old hat. Ancient even.
$endgroup$
– Jyrki Lahtonen
May 12 '14 at 17:31
$begingroup$
Well i never read that though cool one. I especially like these one way solution problems.@JyrkiLahtonen
$endgroup$
– Ravindra Sahay
May 12 '14 at 17:33