Trying to create diagonal patterns using graphics












1















I am trying to create a diagonal pattern using graphics, but only half of the pattern is filled. I am also trying to make it so that the same pattern fills the whole 500x500 but have no idea how.
EDIT: Sorry I don't mean all of it filled, like from (0-100,500) has the line pattern and then the (100-200,500) is empty and so on.



from graphics import *

def patchwork():
win = GraphWin('Lines test',500,500)
for x in range(0,101,20):
line = Line(Point(x,0), Point(100,100-x))
line.setFill('red')
line.draw(win)

for x2 in range(101,0,-20):
line2 = Line(Point(100,0+x2), Point(x2,100))
line2.setFill('red')
line2.draw(win)


I expected the pattern to fully fill the 100x100 with diagonal lines but only have of it is filled.










share|improve this question





























    1















    I am trying to create a diagonal pattern using graphics, but only half of the pattern is filled. I am also trying to make it so that the same pattern fills the whole 500x500 but have no idea how.
    EDIT: Sorry I don't mean all of it filled, like from (0-100,500) has the line pattern and then the (100-200,500) is empty and so on.



    from graphics import *

    def patchwork():
    win = GraphWin('Lines test',500,500)
    for x in range(0,101,20):
    line = Line(Point(x,0), Point(100,100-x))
    line.setFill('red')
    line.draw(win)

    for x2 in range(101,0,-20):
    line2 = Line(Point(100,0+x2), Point(x2,100))
    line2.setFill('red')
    line2.draw(win)


    I expected the pattern to fully fill the 100x100 with diagonal lines but only have of it is filled.










    share|improve this question



























      1












      1








      1








      I am trying to create a diagonal pattern using graphics, but only half of the pattern is filled. I am also trying to make it so that the same pattern fills the whole 500x500 but have no idea how.
      EDIT: Sorry I don't mean all of it filled, like from (0-100,500) has the line pattern and then the (100-200,500) is empty and so on.



      from graphics import *

      def patchwork():
      win = GraphWin('Lines test',500,500)
      for x in range(0,101,20):
      line = Line(Point(x,0), Point(100,100-x))
      line.setFill('red')
      line.draw(win)

      for x2 in range(101,0,-20):
      line2 = Line(Point(100,0+x2), Point(x2,100))
      line2.setFill('red')
      line2.draw(win)


      I expected the pattern to fully fill the 100x100 with diagonal lines but only have of it is filled.










      share|improve this question
















      I am trying to create a diagonal pattern using graphics, but only half of the pattern is filled. I am also trying to make it so that the same pattern fills the whole 500x500 but have no idea how.
      EDIT: Sorry I don't mean all of it filled, like from (0-100,500) has the line pattern and then the (100-200,500) is empty and so on.



      from graphics import *

      def patchwork():
      win = GraphWin('Lines test',500,500)
      for x in range(0,101,20):
      line = Line(Point(x,0), Point(100,100-x))
      line.setFill('red')
      line.draw(win)

      for x2 in range(101,0,-20):
      line2 = Line(Point(100,0+x2), Point(x2,100))
      line2.setFill('red')
      line2.draw(win)


      I expected the pattern to fully fill the 100x100 with diagonal lines but only have of it is filled.







      python graphics






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 1 at 21:47







      Nab

















      asked Jan 1 at 20:56









      NabNab

      405




      405
























          1 Answer
          1






          active

          oldest

          votes


















          2














          You can do it by drawing four sets of lines inside a single for loop, as shown below. The code is written in terms of the window size L, so that it can be easily changed if needed.



          from graphics import *

          def patchwork():
          L = 500;
          win = GraphWin('Lines test',L,L)
          for s in range(0,L+1,20):
          line1 = Line(Point(s,0), Point(L,L-s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(L,s), Point(s,L))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(s,L), Point(0,L-s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(0,s), Point(s,0))
          line4.setFill('red')
          line4.draw(win)




          Updated code to generate a piecewise pattern:



          from graphics import *

          def patchwork():
          L = 500;
          W = 100;
          f = L/W;
          win = GraphWin('Lines test',L,L)
          for xL in [0,200,400]:
          xR = xL + W;
          for s in range(0,W+1,20):
          line1 = Line(Point(xL + s,0), Point(xL,f*s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(xL + s,0), Point(xR,L - f*s))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(xL + s,L), Point(xL,L - f*s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(xL + s,L), Point(xR,f*s))
          line4.setFill('red')
          line4.draw(win)





          share|improve this answer


























          • Oh thank you for answering the question.I am sorry, because what I was meant to say was how to make the first (0-100,500) collum line pattern and then the (100-200,500) collum to be empty

            – Nab
            Jan 1 at 21:50











          • When you say (0-100, 500) do you mean the rectangular area from x = 0 to x = 100 and y = 0 to y = 500?

            – Savithru
            Jan 1 at 22:00











          • Yes that is what I meant sorry

            – Nab
            Jan 1 at 22:01











          • And then do you want to continue that on/off pattern? I mean does (200-300) have the pattern, (300-400) is empty, and (400-500) have the pattern?

            – Savithru
            Jan 1 at 22:03











          • Yes just like that

            – Nab
            Jan 1 at 23:08











          Your Answer






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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

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          active

          oldest

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          2














          You can do it by drawing four sets of lines inside a single for loop, as shown below. The code is written in terms of the window size L, so that it can be easily changed if needed.



          from graphics import *

          def patchwork():
          L = 500;
          win = GraphWin('Lines test',L,L)
          for s in range(0,L+1,20):
          line1 = Line(Point(s,0), Point(L,L-s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(L,s), Point(s,L))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(s,L), Point(0,L-s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(0,s), Point(s,0))
          line4.setFill('red')
          line4.draw(win)




          Updated code to generate a piecewise pattern:



          from graphics import *

          def patchwork():
          L = 500;
          W = 100;
          f = L/W;
          win = GraphWin('Lines test',L,L)
          for xL in [0,200,400]:
          xR = xL + W;
          for s in range(0,W+1,20):
          line1 = Line(Point(xL + s,0), Point(xL,f*s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(xL + s,0), Point(xR,L - f*s))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(xL + s,L), Point(xL,L - f*s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(xL + s,L), Point(xR,f*s))
          line4.setFill('red')
          line4.draw(win)





          share|improve this answer


























          • Oh thank you for answering the question.I am sorry, because what I was meant to say was how to make the first (0-100,500) collum line pattern and then the (100-200,500) collum to be empty

            – Nab
            Jan 1 at 21:50











          • When you say (0-100, 500) do you mean the rectangular area from x = 0 to x = 100 and y = 0 to y = 500?

            – Savithru
            Jan 1 at 22:00











          • Yes that is what I meant sorry

            – Nab
            Jan 1 at 22:01











          • And then do you want to continue that on/off pattern? I mean does (200-300) have the pattern, (300-400) is empty, and (400-500) have the pattern?

            – Savithru
            Jan 1 at 22:03











          • Yes just like that

            – Nab
            Jan 1 at 23:08
















          2














          You can do it by drawing four sets of lines inside a single for loop, as shown below. The code is written in terms of the window size L, so that it can be easily changed if needed.



          from graphics import *

          def patchwork():
          L = 500;
          win = GraphWin('Lines test',L,L)
          for s in range(0,L+1,20):
          line1 = Line(Point(s,0), Point(L,L-s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(L,s), Point(s,L))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(s,L), Point(0,L-s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(0,s), Point(s,0))
          line4.setFill('red')
          line4.draw(win)




          Updated code to generate a piecewise pattern:



          from graphics import *

          def patchwork():
          L = 500;
          W = 100;
          f = L/W;
          win = GraphWin('Lines test',L,L)
          for xL in [0,200,400]:
          xR = xL + W;
          for s in range(0,W+1,20):
          line1 = Line(Point(xL + s,0), Point(xL,f*s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(xL + s,0), Point(xR,L - f*s))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(xL + s,L), Point(xL,L - f*s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(xL + s,L), Point(xR,f*s))
          line4.setFill('red')
          line4.draw(win)





          share|improve this answer


























          • Oh thank you for answering the question.I am sorry, because what I was meant to say was how to make the first (0-100,500) collum line pattern and then the (100-200,500) collum to be empty

            – Nab
            Jan 1 at 21:50











          • When you say (0-100, 500) do you mean the rectangular area from x = 0 to x = 100 and y = 0 to y = 500?

            – Savithru
            Jan 1 at 22:00











          • Yes that is what I meant sorry

            – Nab
            Jan 1 at 22:01











          • And then do you want to continue that on/off pattern? I mean does (200-300) have the pattern, (300-400) is empty, and (400-500) have the pattern?

            – Savithru
            Jan 1 at 22:03











          • Yes just like that

            – Nab
            Jan 1 at 23:08














          2












          2








          2







          You can do it by drawing four sets of lines inside a single for loop, as shown below. The code is written in terms of the window size L, so that it can be easily changed if needed.



          from graphics import *

          def patchwork():
          L = 500;
          win = GraphWin('Lines test',L,L)
          for s in range(0,L+1,20):
          line1 = Line(Point(s,0), Point(L,L-s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(L,s), Point(s,L))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(s,L), Point(0,L-s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(0,s), Point(s,0))
          line4.setFill('red')
          line4.draw(win)




          Updated code to generate a piecewise pattern:



          from graphics import *

          def patchwork():
          L = 500;
          W = 100;
          f = L/W;
          win = GraphWin('Lines test',L,L)
          for xL in [0,200,400]:
          xR = xL + W;
          for s in range(0,W+1,20):
          line1 = Line(Point(xL + s,0), Point(xL,f*s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(xL + s,0), Point(xR,L - f*s))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(xL + s,L), Point(xL,L - f*s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(xL + s,L), Point(xR,f*s))
          line4.setFill('red')
          line4.draw(win)





          share|improve this answer















          You can do it by drawing four sets of lines inside a single for loop, as shown below. The code is written in terms of the window size L, so that it can be easily changed if needed.



          from graphics import *

          def patchwork():
          L = 500;
          win = GraphWin('Lines test',L,L)
          for s in range(0,L+1,20):
          line1 = Line(Point(s,0), Point(L,L-s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(L,s), Point(s,L))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(s,L), Point(0,L-s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(0,s), Point(s,0))
          line4.setFill('red')
          line4.draw(win)




          Updated code to generate a piecewise pattern:



          from graphics import *

          def patchwork():
          L = 500;
          W = 100;
          f = L/W;
          win = GraphWin('Lines test',L,L)
          for xL in [0,200,400]:
          xR = xL + W;
          for s in range(0,W+1,20):
          line1 = Line(Point(xL + s,0), Point(xL,f*s))
          line1.setFill('red')
          line1.draw(win)

          line2 = Line(Point(xL + s,0), Point(xR,L - f*s))
          line2.setFill('red')
          line2.draw(win)

          line3 = Line(Point(xL + s,L), Point(xL,L - f*s))
          line3.setFill('red')
          line3.draw(win)

          line4 = Line(Point(xL + s,L), Point(xR,f*s))
          line4.setFill('red')
          line4.draw(win)






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 1 at 23:53

























          answered Jan 1 at 21:24









          SavithruSavithru

          602511




          602511













          • Oh thank you for answering the question.I am sorry, because what I was meant to say was how to make the first (0-100,500) collum line pattern and then the (100-200,500) collum to be empty

            – Nab
            Jan 1 at 21:50











          • When you say (0-100, 500) do you mean the rectangular area from x = 0 to x = 100 and y = 0 to y = 500?

            – Savithru
            Jan 1 at 22:00











          • Yes that is what I meant sorry

            – Nab
            Jan 1 at 22:01











          • And then do you want to continue that on/off pattern? I mean does (200-300) have the pattern, (300-400) is empty, and (400-500) have the pattern?

            – Savithru
            Jan 1 at 22:03











          • Yes just like that

            – Nab
            Jan 1 at 23:08



















          • Oh thank you for answering the question.I am sorry, because what I was meant to say was how to make the first (0-100,500) collum line pattern and then the (100-200,500) collum to be empty

            – Nab
            Jan 1 at 21:50











          • When you say (0-100, 500) do you mean the rectangular area from x = 0 to x = 100 and y = 0 to y = 500?

            – Savithru
            Jan 1 at 22:00











          • Yes that is what I meant sorry

            – Nab
            Jan 1 at 22:01











          • And then do you want to continue that on/off pattern? I mean does (200-300) have the pattern, (300-400) is empty, and (400-500) have the pattern?

            – Savithru
            Jan 1 at 22:03











          • Yes just like that

            – Nab
            Jan 1 at 23:08

















          Oh thank you for answering the question.I am sorry, because what I was meant to say was how to make the first (0-100,500) collum line pattern and then the (100-200,500) collum to be empty

          – Nab
          Jan 1 at 21:50





          Oh thank you for answering the question.I am sorry, because what I was meant to say was how to make the first (0-100,500) collum line pattern and then the (100-200,500) collum to be empty

          – Nab
          Jan 1 at 21:50













          When you say (0-100, 500) do you mean the rectangular area from x = 0 to x = 100 and y = 0 to y = 500?

          – Savithru
          Jan 1 at 22:00





          When you say (0-100, 500) do you mean the rectangular area from x = 0 to x = 100 and y = 0 to y = 500?

          – Savithru
          Jan 1 at 22:00













          Yes that is what I meant sorry

          – Nab
          Jan 1 at 22:01





          Yes that is what I meant sorry

          – Nab
          Jan 1 at 22:01













          And then do you want to continue that on/off pattern? I mean does (200-300) have the pattern, (300-400) is empty, and (400-500) have the pattern?

          – Savithru
          Jan 1 at 22:03





          And then do you want to continue that on/off pattern? I mean does (200-300) have the pattern, (300-400) is empty, and (400-500) have the pattern?

          – Savithru
          Jan 1 at 22:03













          Yes just like that

          – Nab
          Jan 1 at 23:08





          Yes just like that

          – Nab
          Jan 1 at 23:08




















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