inner automorphisms unequal to the inverse except at identity












3












$begingroup$


Let $N$ be a normal subgroup of a finite group $G$. Then for each $g in G$ there exists an automorphism of $N$ given by $phi_g(n)=g^{-1}ng$. Suppose we impose the following condition: $$phi_g(n) neq n^{-1},~~~forall gin G,~~~ forall n in N backslash {1}.$$
What I can show so far is that for this condition to hold, it is necessary that $N$ have odd order. If $N$ is contained in the center of $G$, this is also sufficient.



My question is that whether you have seen such a condition before in group theory literature, and if not, what would be an appropriate terminology to use for such a normal subgroup?










share|cite|improve this question









$endgroup$








  • 2




    $begingroup$
    I've seen some works on checking groups in which no element is automorphic to its inverse ("automorphic to its inverse" means there exists $phiinmathrm{Aut}(G)$ such that $phi(n)=n^{-1}$). Since $G/C_G(N)$ embeds into $mathrm{Aut}(N)$, this looks related.
    $endgroup$
    – Arturo Magidin
    Feb 1 at 17:54










  • $begingroup$
    @ArturoMagidin that definitely seems related. Would you be able to give any reference where these groups are mentioned?
    $endgroup$
    – Marco
    Feb 3 at 20:23
















3












$begingroup$


Let $N$ be a normal subgroup of a finite group $G$. Then for each $g in G$ there exists an automorphism of $N$ given by $phi_g(n)=g^{-1}ng$. Suppose we impose the following condition: $$phi_g(n) neq n^{-1},~~~forall gin G,~~~ forall n in N backslash {1}.$$
What I can show so far is that for this condition to hold, it is necessary that $N$ have odd order. If $N$ is contained in the center of $G$, this is also sufficient.



My question is that whether you have seen such a condition before in group theory literature, and if not, what would be an appropriate terminology to use for such a normal subgroup?










share|cite|improve this question









$endgroup$








  • 2




    $begingroup$
    I've seen some works on checking groups in which no element is automorphic to its inverse ("automorphic to its inverse" means there exists $phiinmathrm{Aut}(G)$ such that $phi(n)=n^{-1}$). Since $G/C_G(N)$ embeds into $mathrm{Aut}(N)$, this looks related.
    $endgroup$
    – Arturo Magidin
    Feb 1 at 17:54










  • $begingroup$
    @ArturoMagidin that definitely seems related. Would you be able to give any reference where these groups are mentioned?
    $endgroup$
    – Marco
    Feb 3 at 20:23














3












3








3


2



$begingroup$


Let $N$ be a normal subgroup of a finite group $G$. Then for each $g in G$ there exists an automorphism of $N$ given by $phi_g(n)=g^{-1}ng$. Suppose we impose the following condition: $$phi_g(n) neq n^{-1},~~~forall gin G,~~~ forall n in N backslash {1}.$$
What I can show so far is that for this condition to hold, it is necessary that $N$ have odd order. If $N$ is contained in the center of $G$, this is also sufficient.



My question is that whether you have seen such a condition before in group theory literature, and if not, what would be an appropriate terminology to use for such a normal subgroup?










share|cite|improve this question









$endgroup$




Let $N$ be a normal subgroup of a finite group $G$. Then for each $g in G$ there exists an automorphism of $N$ given by $phi_g(n)=g^{-1}ng$. Suppose we impose the following condition: $$phi_g(n) neq n^{-1},~~~forall gin G,~~~ forall n in N backslash {1}.$$
What I can show so far is that for this condition to hold, it is necessary that $N$ have odd order. If $N$ is contained in the center of $G$, this is also sufficient.



My question is that whether you have seen such a condition before in group theory literature, and if not, what would be an appropriate terminology to use for such a normal subgroup?







group-theory terminology






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 31 at 20:22









MarcoMarco

1,981112




1,981112








  • 2




    $begingroup$
    I've seen some works on checking groups in which no element is automorphic to its inverse ("automorphic to its inverse" means there exists $phiinmathrm{Aut}(G)$ such that $phi(n)=n^{-1}$). Since $G/C_G(N)$ embeds into $mathrm{Aut}(N)$, this looks related.
    $endgroup$
    – Arturo Magidin
    Feb 1 at 17:54










  • $begingroup$
    @ArturoMagidin that definitely seems related. Would you be able to give any reference where these groups are mentioned?
    $endgroup$
    – Marco
    Feb 3 at 20:23














  • 2




    $begingroup$
    I've seen some works on checking groups in which no element is automorphic to its inverse ("automorphic to its inverse" means there exists $phiinmathrm{Aut}(G)$ such that $phi(n)=n^{-1}$). Since $G/C_G(N)$ embeds into $mathrm{Aut}(N)$, this looks related.
    $endgroup$
    – Arturo Magidin
    Feb 1 at 17:54










  • $begingroup$
    @ArturoMagidin that definitely seems related. Would you be able to give any reference where these groups are mentioned?
    $endgroup$
    – Marco
    Feb 3 at 20:23








2




2




$begingroup$
I've seen some works on checking groups in which no element is automorphic to its inverse ("automorphic to its inverse" means there exists $phiinmathrm{Aut}(G)$ such that $phi(n)=n^{-1}$). Since $G/C_G(N)$ embeds into $mathrm{Aut}(N)$, this looks related.
$endgroup$
– Arturo Magidin
Feb 1 at 17:54




$begingroup$
I've seen some works on checking groups in which no element is automorphic to its inverse ("automorphic to its inverse" means there exists $phiinmathrm{Aut}(G)$ such that $phi(n)=n^{-1}$). Since $G/C_G(N)$ embeds into $mathrm{Aut}(N)$, this looks related.
$endgroup$
– Arturo Magidin
Feb 1 at 17:54












$begingroup$
@ArturoMagidin that definitely seems related. Would you be able to give any reference where these groups are mentioned?
$endgroup$
– Marco
Feb 3 at 20:23




$begingroup$
@ArturoMagidin that definitely seems related. Would you be able to give any reference where these groups are mentioned?
$endgroup$
– Marco
Feb 3 at 20:23










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