Mixing
find $T(t), N(t),$ and $K$ of given $r(t)$
$begingroup$
$r(t)=(t+cos (t))hat{i}+(1-sin (t))hat{j}$
I tried to find $T(t)$ but I hit a roadblock. I know the equations to plug everything in but I need some help in simplifying things.
I've gotten r'(t)=(1-sint)i+(-cost)j
I ended up with $T(t)=large frac{r'(t)}{|sqrt{2-2sin (t)}|}$
calculus multivariable-calculus
asked Jan 31 at 20:30
ufotinkufotink
146
$endgroup$
add a comment |
$begingroup$
$r(t)=(t+cos (t))hat{i}+(1-sin (t))hat{j}$
I tried to find $T(t)$ but I hit a roadblock. I know the equations to plug everything in but I need some help in simplifying things.
I've gotten r'(t)=(1-sint)i+(-cost)j
I ended up with $T(t)=large frac{r'(t)}{|sqrt{2-2sin (t)}|}$
calculus multivariable-calculus
asked Jan 31 at 20:30
ufotinkufotink
146
$endgroup$
$begingroup$
A trigonometric identity simplifies your denominator. Also, you can show your attempt to compute the derivative in the numerator.
$endgroup$
– GEdgar
Jan 31 at 20:48
$begingroup$
@GEdgar could you tell me which trig identity because I've been searching and I can't find one that fits
$endgroup$
– ufotink
Jan 31 at 21:05
add a comment |
$begingroup$
$r(t)=(t+cos (t))hat{i}+(1-sin (t))hat{j}$
I tried to find $T(t)$ but I hit a roadblock. I know the equations to plug everything in but I need some help in simplifying things.
I've gotten r'(t)=(1-sint)i+(-cost)j
I ended up with $T(t)=large frac{r'(t)}{|sqrt{2-2sin (t)}|}$
calculus multivariable-calculus
asked Jan 31 at 20:30
ufotinkufotink
146
$endgroup$
$r(t)=(t+cos (t))hat{i}+(1-sin (t))hat{j}$
I tried to find $T(t)$ but I hit a roadblock. I know the equations to plug everything in but I need some help in simplifying things.
I've gotten r'(t)=(1-sint)i+(-cost)j
I ended up with $T(t)=large frac{r'(t)}{|sqrt{2-2sin (t)}|}$
calculus multivariable-calculus
calculus multivariable-calculus
asked Jan 31 at 20:30
ufotinkufotink
146
asked Jan 31 at 20:30
ufotinkufotink
146
edited Jan 31 at 21:02
ufotink
asked Jan 31 at 20:30
ufotinkufotink
146
asked Jan 31 at 20:30
ufotinkufotink
146
asked Jan 31 at 20:30
ufotinkufotink
146
146
$begingroup$
A trigonometric identity simplifies your denominator. Also, you can show your attempt to compute the derivative in the numerator.
$endgroup$
– GEdgar
Jan 31 at 20:48
$begingroup$
@GEdgar could you tell me which trig identity because I've been searching and I can't find one that fits
$endgroup$
– ufotink
Jan 31 at 21:05
add a comment |
$begingroup$
A trigonometric identity simplifies your denominator. Also, you can show your attempt to compute the derivative in the numerator.
$endgroup$
– GEdgar
Jan 31 at 20:48
$begingroup$
@GEdgar could you tell me which trig identity because I've been searching and I can't find one that fits
$endgroup$
– ufotink
Jan 31 at 21:05
$begingroup$
A trigonometric identity simplifies your denominator. Also, you can show your attempt to compute the derivative in the numerator.
$endgroup$
– GEdgar
Jan 31 at 20:48
$begingroup$
A trigonometric identity simplifies your denominator. Also, you can show your attempt to compute the derivative in the numerator.
$endgroup$
– GEdgar
Jan 31 at 20:48
$begingroup$
@GEdgar could you tell me which trig identity because I've been searching and I can't find one that fits
$endgroup$
– ufotink
Jan 31 at 21:05
$begingroup$
@GEdgar could you tell me which trig identity because I've been searching and I can't find one that fits
$endgroup$
– ufotink
Jan 31 at 21:05
add a comment |
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$begingroup$
A trigonometric identity simplifies your denominator. Also, you can show your attempt to compute the derivative in the numerator.
$endgroup$
– GEdgar
Jan 31 at 20:48
$begingroup$
@GEdgar could you tell me which trig identity because I've been searching and I can't find one that fits
$endgroup$
– ufotink
Jan 31 at 21:05