Probability and Probability Distributions












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I have a question i need to answer in my assignment.



Question
The machine repair department of Scorpio Press receives an average of 2 calls for service per hour. What is the probability of receiving no service calls in a 45 minute period?



Thanks in advance










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  • 2




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    Welcome to MSE! We can be more helpful if you show us what you have been done already.
    $endgroup$
    – Vasily Mitch
    Jan 31 at 19:05






  • 1




    $begingroup$
    Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
    $endgroup$
    – lulu
    Jan 31 at 19:06












  • $begingroup$
    No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
    $endgroup$
    – Jean Marie
    Jan 31 at 21:03
















1












$begingroup$


I have a question i need to answer in my assignment.



Question
The machine repair department of Scorpio Press receives an average of 2 calls for service per hour. What is the probability of receiving no service calls in a 45 minute period?



Thanks in advance










share|cite|improve this question









$endgroup$








  • 2




    $begingroup$
    Welcome to MSE! We can be more helpful if you show us what you have been done already.
    $endgroup$
    – Vasily Mitch
    Jan 31 at 19:05






  • 1




    $begingroup$
    Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
    $endgroup$
    – lulu
    Jan 31 at 19:06












  • $begingroup$
    No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
    $endgroup$
    – Jean Marie
    Jan 31 at 21:03














1












1








1


0



$begingroup$


I have a question i need to answer in my assignment.



Question
The machine repair department of Scorpio Press receives an average of 2 calls for service per hour. What is the probability of receiving no service calls in a 45 minute period?



Thanks in advance










share|cite|improve this question









$endgroup$




I have a question i need to answer in my assignment.



Question
The machine repair department of Scorpio Press receives an average of 2 calls for service per hour. What is the probability of receiving no service calls in a 45 minute period?



Thanks in advance







statistics






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share|cite|improve this question











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asked Jan 31 at 19:03









user2941071user2941071

61




61








  • 2




    $begingroup$
    Welcome to MSE! We can be more helpful if you show us what you have been done already.
    $endgroup$
    – Vasily Mitch
    Jan 31 at 19:05






  • 1




    $begingroup$
    Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
    $endgroup$
    – lulu
    Jan 31 at 19:06












  • $begingroup$
    No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
    $endgroup$
    – Jean Marie
    Jan 31 at 21:03














  • 2




    $begingroup$
    Welcome to MSE! We can be more helpful if you show us what you have been done already.
    $endgroup$
    – Vasily Mitch
    Jan 31 at 19:05






  • 1




    $begingroup$
    Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
    $endgroup$
    – lulu
    Jan 31 at 19:06












  • $begingroup$
    No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
    $endgroup$
    – Jean Marie
    Jan 31 at 21:03








2




2




$begingroup$
Welcome to MSE! We can be more helpful if you show us what you have been done already.
$endgroup$
– Vasily Mitch
Jan 31 at 19:05




$begingroup$
Welcome to MSE! We can be more helpful if you show us what you have been done already.
$endgroup$
– Vasily Mitch
Jan 31 at 19:05




1




1




$begingroup$
Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
$endgroup$
– lulu
Jan 31 at 19:06






$begingroup$
Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
$endgroup$
– lulu
Jan 31 at 19:06














$begingroup$
No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
$endgroup$
– Jean Marie
Jan 31 at 21:03




$begingroup$
No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
$endgroup$
– Jean Marie
Jan 31 at 21:03










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It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
and you seek $P(X = 0).$



In R statistical software, this is computed as follows, where dpois is a Poisson PDF:



dpois(0, 1.5)
[1] 0.2231302


I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.






share|cite|improve this answer









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    $begingroup$

    It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
    and you seek $P(X = 0).$



    In R statistical software, this is computed as follows, where dpois is a Poisson PDF:



    dpois(0, 1.5)
    [1] 0.2231302


    I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
      and you seek $P(X = 0).$



      In R statistical software, this is computed as follows, where dpois is a Poisson PDF:



      dpois(0, 1.5)
      [1] 0.2231302


      I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
        and you seek $P(X = 0).$



        In R statistical software, this is computed as follows, where dpois is a Poisson PDF:



        dpois(0, 1.5)
        [1] 0.2231302


        I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.






        share|cite|improve this answer









        $endgroup$



        It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
        and you seek $P(X = 0).$



        In R statistical software, this is computed as follows, where dpois is a Poisson PDF:



        dpois(0, 1.5)
        [1] 0.2231302


        I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Feb 3 at 3:32









        BruceETBruceET

        36.3k71540




        36.3k71540






























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