Probability and Probability Distributions
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I have a question i need to answer in my assignment.
Question
The machine repair department of Scorpio Press receives an average of 2 calls for service per hour. What is the probability of receiving no service calls in a 45 minute period?
Thanks in advance
statistics
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add a comment |
$begingroup$
I have a question i need to answer in my assignment.
Question
The machine repair department of Scorpio Press receives an average of 2 calls for service per hour. What is the probability of receiving no service calls in a 45 minute period?
Thanks in advance
statistics
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2
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Welcome to MSE! We can be more helpful if you show us what you have been done already.
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– Vasily Mitch
Jan 31 at 19:05
1
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Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
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– lulu
Jan 31 at 19:06
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No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
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– Jean Marie
Jan 31 at 21:03
add a comment |
$begingroup$
I have a question i need to answer in my assignment.
Question
The machine repair department of Scorpio Press receives an average of 2 calls for service per hour. What is the probability of receiving no service calls in a 45 minute period?
Thanks in advance
statistics
$endgroup$
I have a question i need to answer in my assignment.
Question
The machine repair department of Scorpio Press receives an average of 2 calls for service per hour. What is the probability of receiving no service calls in a 45 minute period?
Thanks in advance
statistics
statistics
asked Jan 31 at 19:03
user2941071user2941071
61
61
2
$begingroup$
Welcome to MSE! We can be more helpful if you show us what you have been done already.
$endgroup$
– Vasily Mitch
Jan 31 at 19:05
1
$begingroup$
Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
$endgroup$
– lulu
Jan 31 at 19:06
$begingroup$
No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
$endgroup$
– Jean Marie
Jan 31 at 21:03
add a comment |
2
$begingroup$
Welcome to MSE! We can be more helpful if you show us what you have been done already.
$endgroup$
– Vasily Mitch
Jan 31 at 19:05
1
$begingroup$
Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
$endgroup$
– lulu
Jan 31 at 19:06
$begingroup$
No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
$endgroup$
– Jean Marie
Jan 31 at 21:03
2
2
$begingroup$
Welcome to MSE! We can be more helpful if you show us what you have been done already.
$endgroup$
– Vasily Mitch
Jan 31 at 19:05
$begingroup$
Welcome to MSE! We can be more helpful if you show us what you have been done already.
$endgroup$
– Vasily Mitch
Jan 31 at 19:05
1
1
$begingroup$
Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
$endgroup$
– lulu
Jan 31 at 19:06
$begingroup$
Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
$endgroup$
– lulu
Jan 31 at 19:06
$begingroup$
No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
$endgroup$
– Jean Marie
Jan 31 at 21:03
$begingroup$
No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
$endgroup$
– Jean Marie
Jan 31 at 21:03
add a comment |
1 Answer
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It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
and you seek $P(X = 0).$
In R statistical software, this is computed as follows, where dpois
is a Poisson PDF:
dpois(0, 1.5)
[1] 0.2231302
I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.
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add a comment |
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1 Answer
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1 Answer
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$begingroup$
It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
and you seek $P(X = 0).$
In R statistical software, this is computed as follows, where dpois
is a Poisson PDF:
dpois(0, 1.5)
[1] 0.2231302
I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.
$endgroup$
add a comment |
$begingroup$
It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
and you seek $P(X = 0).$
In R statistical software, this is computed as follows, where dpois
is a Poisson PDF:
dpois(0, 1.5)
[1] 0.2231302
I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.
$endgroup$
add a comment |
$begingroup$
It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
and you seek $P(X = 0).$
In R statistical software, this is computed as follows, where dpois
is a Poisson PDF:
dpois(0, 1.5)
[1] 0.2231302
I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.
$endgroup$
It seems reasonable to assume that repair requests arrive according to a Poisson distribution with mean $lambda = 2.$ The rate per 45.min or 3/4 of an hour is $lambda^prime = 1.5.$ So you have $X sim mathsf{Pois}(1.5)$
and you seek $P(X = 0).$
In R statistical software, this is computed as follows, where dpois
is a Poisson PDF:
dpois(0, 1.5)
[1] 0.2231302
I will leave it to you to look at the formula for the Poisson PDF and show how to compute the answer for your assignment.
answered Feb 3 at 3:32
BruceETBruceET
36.3k71540
36.3k71540
add a comment |
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$begingroup$
Welcome to MSE! We can be more helpful if you show us what you have been done already.
$endgroup$
– Vasily Mitch
Jan 31 at 19:05
1
$begingroup$
Aside from showing what you have tried, it's important to state what assumptions you are making. If, say, one call comes in like clockwork, every $30$ minutes then the answer is $0$. Presumably, though, you mean to assume something like a Poisson process here, but it should be spelled out.
$endgroup$
– lulu
Jan 31 at 19:06
$begingroup$
No answer to the question from Vasily Mich one hour later... Does it mean that you are hard working on this problem, or are you awaiting a "ready-to-eat" answer from us ?
$endgroup$
– Jean Marie
Jan 31 at 21:03