Spring Data JPA @Query with foreign key: Parameter not matched





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







3















I have a table "Signal" with id, volume and object_id columns.



Object_id is a foreign key. I need to retrieve each signal that has a particular object_id.



Im trying to use this Query



public interface SignalRepository extends JpaRepository<Signal, Integer> {
@Query("select s from Signal s where s.object = ?1")
Optional<List<Signal>> findSignalByObjectId(Integer objectId);

}


It doens't work. If I change "?1" to 1 it gets the hardcoded value. If I try to query the "volume", it works fine.



I get this error:




Blockquote
nested exception is java.lang.IllegalArgumentException: Parameter value [1] did not match expected type











share|improve this question































    3















    I have a table "Signal" with id, volume and object_id columns.



    Object_id is a foreign key. I need to retrieve each signal that has a particular object_id.



    Im trying to use this Query



    public interface SignalRepository extends JpaRepository<Signal, Integer> {
    @Query("select s from Signal s where s.object = ?1")
    Optional<List<Signal>> findSignalByObjectId(Integer objectId);

    }


    It doens't work. If I change "?1" to 1 it gets the hardcoded value. If I try to query the "volume", it works fine.



    I get this error:




    Blockquote
    nested exception is java.lang.IllegalArgumentException: Parameter value [1] did not match expected type











    share|improve this question



























      3












      3








      3








      I have a table "Signal" with id, volume and object_id columns.



      Object_id is a foreign key. I need to retrieve each signal that has a particular object_id.



      Im trying to use this Query



      public interface SignalRepository extends JpaRepository<Signal, Integer> {
      @Query("select s from Signal s where s.object = ?1")
      Optional<List<Signal>> findSignalByObjectId(Integer objectId);

      }


      It doens't work. If I change "?1" to 1 it gets the hardcoded value. If I try to query the "volume", it works fine.



      I get this error:




      Blockquote
      nested exception is java.lang.IllegalArgumentException: Parameter value [1] did not match expected type











      share|improve this question
















      I have a table "Signal" with id, volume and object_id columns.



      Object_id is a foreign key. I need to retrieve each signal that has a particular object_id.



      Im trying to use this Query



      public interface SignalRepository extends JpaRepository<Signal, Integer> {
      @Query("select s from Signal s where s.object = ?1")
      Optional<List<Signal>> findSignalByObjectId(Integer objectId);

      }


      It doens't work. If I change "?1" to 1 it gets the hardcoded value. If I try to query the "volume", it works fine.



      I get this error:




      Blockquote
      nested exception is java.lang.IllegalArgumentException: Parameter value [1] did not match expected type








      java spring hibernate spring-data-jpa jpql






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 3 at 7:25







      user3973283

















      asked Jan 2 at 22:49









      Thadeu Antonio Ferreira MeloThadeu Antonio Ferreira Melo

      306414




      306414
























          2 Answers
          2






          active

          oldest

          votes


















          1














          You can use Spring data to generate the underlying query like this :



          public interface SignalRepository extends JpaRepository<Signal, Integer> {
          List<Signal> findSignalByObjectId(Integer objectId);
          }


          or you can write the query with this return type and parameter:



          public interface SignalRepository extends JpaRepository<Signal, Integer> {
          @Query("select s from Signal s where s.object = :id")
          List<Signal> findSignalByObjectId(@Param("id") Integer objectId);
          }





          share|improve this answer
























          • Thank you. It works perfectly.

            – Thadeu Antonio Ferreira Melo
            Jan 3 at 19:31











          • Sure, happy to help, would be really great, if you mark it as accepted answer

            – Gaurav Agarwal
            Jan 4 at 20:23



















          1














          I'd recommend you omit the query and let spring data generate one for you. So your case may be represented somehow like that (in case of proper relation mapping defined):



          public interface SignalRepository extends JpaRepository<Signal, Integer> {
          Optional<Signal> findByObject(YourObjectType object);
          }


          If you provide more info e.g. your entities - you can get more help.






          share|improve this answer
























            Your Answer






            StackExchange.ifUsing("editor", function () {
            StackExchange.using("externalEditor", function () {
            StackExchange.using("snippets", function () {
            StackExchange.snippets.init();
            });
            });
            }, "code-snippets");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "1"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54014183%2fspring-data-jpa-query-with-foreign-key-parameter-not-matched%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            You can use Spring data to generate the underlying query like this :



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            List<Signal> findSignalByObjectId(Integer objectId);
            }


            or you can write the query with this return type and parameter:



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            @Query("select s from Signal s where s.object = :id")
            List<Signal> findSignalByObjectId(@Param("id") Integer objectId);
            }





            share|improve this answer
























            • Thank you. It works perfectly.

              – Thadeu Antonio Ferreira Melo
              Jan 3 at 19:31











            • Sure, happy to help, would be really great, if you mark it as accepted answer

              – Gaurav Agarwal
              Jan 4 at 20:23
















            1














            You can use Spring data to generate the underlying query like this :



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            List<Signal> findSignalByObjectId(Integer objectId);
            }


            or you can write the query with this return type and parameter:



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            @Query("select s from Signal s where s.object = :id")
            List<Signal> findSignalByObjectId(@Param("id") Integer objectId);
            }





            share|improve this answer
























            • Thank you. It works perfectly.

              – Thadeu Antonio Ferreira Melo
              Jan 3 at 19:31











            • Sure, happy to help, would be really great, if you mark it as accepted answer

              – Gaurav Agarwal
              Jan 4 at 20:23














            1












            1








            1







            You can use Spring data to generate the underlying query like this :



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            List<Signal> findSignalByObjectId(Integer objectId);
            }


            or you can write the query with this return type and parameter:



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            @Query("select s from Signal s where s.object = :id")
            List<Signal> findSignalByObjectId(@Param("id") Integer objectId);
            }





            share|improve this answer













            You can use Spring data to generate the underlying query like this :



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            List<Signal> findSignalByObjectId(Integer objectId);
            }


            or you can write the query with this return type and parameter:



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            @Query("select s from Signal s where s.object = :id")
            List<Signal> findSignalByObjectId(@Param("id") Integer objectId);
            }






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Jan 2 at 23:12









            Gaurav AgarwalGaurav Agarwal

            11319




            11319













            • Thank you. It works perfectly.

              – Thadeu Antonio Ferreira Melo
              Jan 3 at 19:31











            • Sure, happy to help, would be really great, if you mark it as accepted answer

              – Gaurav Agarwal
              Jan 4 at 20:23



















            • Thank you. It works perfectly.

              – Thadeu Antonio Ferreira Melo
              Jan 3 at 19:31











            • Sure, happy to help, would be really great, if you mark it as accepted answer

              – Gaurav Agarwal
              Jan 4 at 20:23

















            Thank you. It works perfectly.

            – Thadeu Antonio Ferreira Melo
            Jan 3 at 19:31





            Thank you. It works perfectly.

            – Thadeu Antonio Ferreira Melo
            Jan 3 at 19:31













            Sure, happy to help, would be really great, if you mark it as accepted answer

            – Gaurav Agarwal
            Jan 4 at 20:23





            Sure, happy to help, would be really great, if you mark it as accepted answer

            – Gaurav Agarwal
            Jan 4 at 20:23













            1














            I'd recommend you omit the query and let spring data generate one for you. So your case may be represented somehow like that (in case of proper relation mapping defined):



            public interface SignalRepository extends JpaRepository<Signal, Integer> {
            Optional<Signal> findByObject(YourObjectType object);
            }


            If you provide more info e.g. your entities - you can get more help.






            share|improve this answer




























              1














              I'd recommend you omit the query and let spring data generate one for you. So your case may be represented somehow like that (in case of proper relation mapping defined):



              public interface SignalRepository extends JpaRepository<Signal, Integer> {
              Optional<Signal> findByObject(YourObjectType object);
              }


              If you provide more info e.g. your entities - you can get more help.






              share|improve this answer


























                1












                1








                1







                I'd recommend you omit the query and let spring data generate one for you. So your case may be represented somehow like that (in case of proper relation mapping defined):



                public interface SignalRepository extends JpaRepository<Signal, Integer> {
                Optional<Signal> findByObject(YourObjectType object);
                }


                If you provide more info e.g. your entities - you can get more help.






                share|improve this answer













                I'd recommend you omit the query and let spring data generate one for you. So your case may be represented somehow like that (in case of proper relation mapping defined):



                public interface SignalRepository extends JpaRepository<Signal, Integer> {
                Optional<Signal> findByObject(YourObjectType object);
                }


                If you provide more info e.g. your entities - you can get more help.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Jan 2 at 23:06









                Anton HlinistyAnton Hlinisty

                98611324




                98611324






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Stack Overflow!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54014183%2fspring-data-jpa-query-with-foreign-key-parameter-not-matched%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    MongoDB - Not Authorized To Execute Command

                    in spring boot 2.1 many test slices are not allowed anymore due to multiple @BootstrapWith

                    How to fix TextFormField cause rebuild widget in Flutter