Getting this error : Initializer for conditional binding must have Optional type, not 'Bool'












0















func application(_ app: UIApplication, open url: URL, options:
[UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

if let isDynamicLink = DynamicLinks.dynamicLinks() .shouldHandleDynamicLink(fromCustomSchemeURL: url) {
let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
return handleDynamicLink(dynamicLink)
}
return true
}









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  • 1





    What is the return type of shouldHandleDynamicLink method?

    – Rakesha Shastri
    Nov 20 '18 at 10:33











  • boolean return type

    – Prasann
    Nov 20 '18 at 10:36






  • 1





    Then you don't need to optional-chain it.

    – Rakesha Shastri
    Nov 20 '18 at 10:36











  • What is the return type of dynamicLinks()?

    – Rakesha Shastri
    Nov 20 '18 at 10:38
















0















func application(_ app: UIApplication, open url: URL, options:
[UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

if let isDynamicLink = DynamicLinks.dynamicLinks() .shouldHandleDynamicLink(fromCustomSchemeURL: url) {
let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
return handleDynamicLink(dynamicLink)
}
return true
}









share|improve this question




















  • 1





    What is the return type of shouldHandleDynamicLink method?

    – Rakesha Shastri
    Nov 20 '18 at 10:33











  • boolean return type

    – Prasann
    Nov 20 '18 at 10:36






  • 1





    Then you don't need to optional-chain it.

    – Rakesha Shastri
    Nov 20 '18 at 10:36











  • What is the return type of dynamicLinks()?

    – Rakesha Shastri
    Nov 20 '18 at 10:38














0












0








0








func application(_ app: UIApplication, open url: URL, options:
[UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

if let isDynamicLink = DynamicLinks.dynamicLinks() .shouldHandleDynamicLink(fromCustomSchemeURL: url) {
let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
return handleDynamicLink(dynamicLink)
}
return true
}









share|improve this question
















func application(_ app: UIApplication, open url: URL, options:
[UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

if let isDynamicLink = DynamicLinks.dynamicLinks() .shouldHandleDynamicLink(fromCustomSchemeURL: url) {
let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
return handleDynamicLink(dynamicLink)
}
return true
}






ios swift firebase firebase-dynamic-links






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edited Nov 20 '18 at 14:35









Frank van Puffelen

231k28378402




231k28378402










asked Nov 20 '18 at 10:32









PrasannPrasann

337




337








  • 1





    What is the return type of shouldHandleDynamicLink method?

    – Rakesha Shastri
    Nov 20 '18 at 10:33











  • boolean return type

    – Prasann
    Nov 20 '18 at 10:36






  • 1





    Then you don't need to optional-chain it.

    – Rakesha Shastri
    Nov 20 '18 at 10:36











  • What is the return type of dynamicLinks()?

    – Rakesha Shastri
    Nov 20 '18 at 10:38














  • 1





    What is the return type of shouldHandleDynamicLink method?

    – Rakesha Shastri
    Nov 20 '18 at 10:33











  • boolean return type

    – Prasann
    Nov 20 '18 at 10:36






  • 1





    Then you don't need to optional-chain it.

    – Rakesha Shastri
    Nov 20 '18 at 10:36











  • What is the return type of dynamicLinks()?

    – Rakesha Shastri
    Nov 20 '18 at 10:38








1




1





What is the return type of shouldHandleDynamicLink method?

– Rakesha Shastri
Nov 20 '18 at 10:33





What is the return type of shouldHandleDynamicLink method?

– Rakesha Shastri
Nov 20 '18 at 10:33













boolean return type

– Prasann
Nov 20 '18 at 10:36





boolean return type

– Prasann
Nov 20 '18 at 10:36




1




1





Then you don't need to optional-chain it.

– Rakesha Shastri
Nov 20 '18 at 10:36





Then you don't need to optional-chain it.

– Rakesha Shastri
Nov 20 '18 at 10:36













What is the return type of dynamicLinks()?

– Rakesha Shastri
Nov 20 '18 at 10:38





What is the return type of dynamicLinks()?

– Rakesha Shastri
Nov 20 '18 at 10:38












1 Answer
1






active

oldest

votes


















4














⌥-click on shouldHandleDynamicLink and you will see the declaration




func shouldHandleDynamicLink(fromCustomSchemeURL url: URL) -> Bool



The return type is non-optional. Remove the optional binding



func application(_ app: UIApplication, open url: URL, options:
[UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

if DynamicLinks.dynamicLinks().shouldHandleDynamicLink(fromCustomSchemeURL: url) {
let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
return handleDynamicLink(dynamicLink)
}
return true
}





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    1 Answer
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    active

    oldest

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    4














    ⌥-click on shouldHandleDynamicLink and you will see the declaration




    func shouldHandleDynamicLink(fromCustomSchemeURL url: URL) -> Bool



    The return type is non-optional. Remove the optional binding



    func application(_ app: UIApplication, open url: URL, options:
    [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

    if DynamicLinks.dynamicLinks().shouldHandleDynamicLink(fromCustomSchemeURL: url) {
    let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
    return handleDynamicLink(dynamicLink)
    }
    return true
    }





    share|improve this answer




























      4














      ⌥-click on shouldHandleDynamicLink and you will see the declaration




      func shouldHandleDynamicLink(fromCustomSchemeURL url: URL) -> Bool



      The return type is non-optional. Remove the optional binding



      func application(_ app: UIApplication, open url: URL, options:
      [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

      if DynamicLinks.dynamicLinks().shouldHandleDynamicLink(fromCustomSchemeURL: url) {
      let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
      return handleDynamicLink(dynamicLink)
      }
      return true
      }





      share|improve this answer


























        4












        4








        4







        ⌥-click on shouldHandleDynamicLink and you will see the declaration




        func shouldHandleDynamicLink(fromCustomSchemeURL url: URL) -> Bool



        The return type is non-optional. Remove the optional binding



        func application(_ app: UIApplication, open url: URL, options:
        [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

        if DynamicLinks.dynamicLinks().shouldHandleDynamicLink(fromCustomSchemeURL: url) {
        let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
        return handleDynamicLink(dynamicLink)
        }
        return true
        }





        share|improve this answer













        ⌥-click on shouldHandleDynamicLink and you will see the declaration




        func shouldHandleDynamicLink(fromCustomSchemeURL url: URL) -> Bool



        The return type is non-optional. Remove the optional binding



        func application(_ app: UIApplication, open url: URL, options:
        [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

        if DynamicLinks.dynamicLinks().shouldHandleDynamicLink(fromCustomSchemeURL: url) {
        let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url)
        return handleDynamicLink(dynamicLink)
        }
        return true
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 '18 at 10:38









        vadianvadian

        145k13157175




        145k13157175






























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