Is the following cyclic group test wrong in WolframAlpha?












6














Please see here
Cyclic group test



Isn't this a mistake? Isn't this a cyclic group generated by $(5,1)$ ? thank you!










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  • no one knows? :(
    – Loli
    Nov 22 '18 at 1:07










  • Try posting this on mathematica.se.
    – rogerl
    Nov 22 '18 at 2:27
















6














Please see here
Cyclic group test



Isn't this a mistake? Isn't this a cyclic group generated by $(5,1)$ ? thank you!










share|cite|improve this question
























  • no one knows? :(
    – Loli
    Nov 22 '18 at 1:07










  • Try posting this on mathematica.se.
    – rogerl
    Nov 22 '18 at 2:27














6












6








6


1





Please see here
Cyclic group test



Isn't this a mistake? Isn't this a cyclic group generated by $(5,1)$ ? thank you!










share|cite|improve this question















Please see here
Cyclic group test



Isn't this a mistake? Isn't this a cyclic group generated by $(5,1)$ ? thank you!







group-theory cyclic-groups direct-product






share|cite|improve this question















share|cite|improve this question













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edited Nov 22 '18 at 2:48









Chinnapparaj R

5,2481828




5,2481828










asked Nov 22 '18 at 0:48









LoliLoli

342310




342310












  • no one knows? :(
    – Loli
    Nov 22 '18 at 1:07










  • Try posting this on mathematica.se.
    – rogerl
    Nov 22 '18 at 2:27


















  • no one knows? :(
    – Loli
    Nov 22 '18 at 1:07










  • Try posting this on mathematica.se.
    – rogerl
    Nov 22 '18 at 2:27
















no one knows? :(
– Loli
Nov 22 '18 at 1:07




no one knows? :(
– Loli
Nov 22 '18 at 1:07












Try posting this on mathematica.se.
– rogerl
Nov 22 '18 at 2:27




Try posting this on mathematica.se.
– rogerl
Nov 22 '18 at 2:27










1 Answer
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Yes! Wolfram alpha is wrong. It says also the group $Bbb Z_3 times Bbb Z_2$ is not cyclic! , which is false.





The group $Bbb Z_{13} times Bbb Z_{12}$ is cyclic of order $156$ since $gcd{13,12}=1$ and $(5,1)$ is of order $ text{lcm}{13,12}=156$, so $$langle (5,1) rangle=Bbb Z_{13} times Bbb Z_{12}$$






share|cite|improve this answer





















  • Also see this link . It already says $Bbb{Z}_3 times Bbb{Z}_2$ is not cyclic but in this link, it list the six elements of this group as $1,a,a^2,a^3,a^4,a^5$. That is every element can be written as $a^n$ .which is exactly the cyclic group notation but nevertheless it says the group is not cyclic! which is false!
    – Chinnapparaj R
    Nov 22 '18 at 2:58













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4














Yes! Wolfram alpha is wrong. It says also the group $Bbb Z_3 times Bbb Z_2$ is not cyclic! , which is false.





The group $Bbb Z_{13} times Bbb Z_{12}$ is cyclic of order $156$ since $gcd{13,12}=1$ and $(5,1)$ is of order $ text{lcm}{13,12}=156$, so $$langle (5,1) rangle=Bbb Z_{13} times Bbb Z_{12}$$






share|cite|improve this answer





















  • Also see this link . It already says $Bbb{Z}_3 times Bbb{Z}_2$ is not cyclic but in this link, it list the six elements of this group as $1,a,a^2,a^3,a^4,a^5$. That is every element can be written as $a^n$ .which is exactly the cyclic group notation but nevertheless it says the group is not cyclic! which is false!
    – Chinnapparaj R
    Nov 22 '18 at 2:58


















4














Yes! Wolfram alpha is wrong. It says also the group $Bbb Z_3 times Bbb Z_2$ is not cyclic! , which is false.





The group $Bbb Z_{13} times Bbb Z_{12}$ is cyclic of order $156$ since $gcd{13,12}=1$ and $(5,1)$ is of order $ text{lcm}{13,12}=156$, so $$langle (5,1) rangle=Bbb Z_{13} times Bbb Z_{12}$$






share|cite|improve this answer





















  • Also see this link . It already says $Bbb{Z}_3 times Bbb{Z}_2$ is not cyclic but in this link, it list the six elements of this group as $1,a,a^2,a^3,a^4,a^5$. That is every element can be written as $a^n$ .which is exactly the cyclic group notation but nevertheless it says the group is not cyclic! which is false!
    – Chinnapparaj R
    Nov 22 '18 at 2:58
















4












4








4






Yes! Wolfram alpha is wrong. It says also the group $Bbb Z_3 times Bbb Z_2$ is not cyclic! , which is false.





The group $Bbb Z_{13} times Bbb Z_{12}$ is cyclic of order $156$ since $gcd{13,12}=1$ and $(5,1)$ is of order $ text{lcm}{13,12}=156$, so $$langle (5,1) rangle=Bbb Z_{13} times Bbb Z_{12}$$






share|cite|improve this answer












Yes! Wolfram alpha is wrong. It says also the group $Bbb Z_3 times Bbb Z_2$ is not cyclic! , which is false.





The group $Bbb Z_{13} times Bbb Z_{12}$ is cyclic of order $156$ since $gcd{13,12}=1$ and $(5,1)$ is of order $ text{lcm}{13,12}=156$, so $$langle (5,1) rangle=Bbb Z_{13} times Bbb Z_{12}$$







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 22 '18 at 2:42









Chinnapparaj RChinnapparaj R

5,2481828




5,2481828












  • Also see this link . It already says $Bbb{Z}_3 times Bbb{Z}_2$ is not cyclic but in this link, it list the six elements of this group as $1,a,a^2,a^3,a^4,a^5$. That is every element can be written as $a^n$ .which is exactly the cyclic group notation but nevertheless it says the group is not cyclic! which is false!
    – Chinnapparaj R
    Nov 22 '18 at 2:58




















  • Also see this link . It already says $Bbb{Z}_3 times Bbb{Z}_2$ is not cyclic but in this link, it list the six elements of this group as $1,a,a^2,a^3,a^4,a^5$. That is every element can be written as $a^n$ .which is exactly the cyclic group notation but nevertheless it says the group is not cyclic! which is false!
    – Chinnapparaj R
    Nov 22 '18 at 2:58


















Also see this link . It already says $Bbb{Z}_3 times Bbb{Z}_2$ is not cyclic but in this link, it list the six elements of this group as $1,a,a^2,a^3,a^4,a^5$. That is every element can be written as $a^n$ .which is exactly the cyclic group notation but nevertheless it says the group is not cyclic! which is false!
– Chinnapparaj R
Nov 22 '18 at 2:58






Also see this link . It already says $Bbb{Z}_3 times Bbb{Z}_2$ is not cyclic but in this link, it list the six elements of this group as $1,a,a^2,a^3,a^4,a^5$. That is every element can be written as $a^n$ .which is exactly the cyclic group notation but nevertheless it says the group is not cyclic! which is false!
– Chinnapparaj R
Nov 22 '18 at 2:58




















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