Does a given First Passage Time Distribution imply a single possible Fokker-Planck equation?












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Consider a 1-dimensional Continuous Markov Process $X(t)$ with fixed and constant absorbing boundaries, let's say at $pm theta$, and with starting point at $X(t=0)=0$. This setting will lead to a given First Passage Time (FPT) distribution at each boundary. Let us call the densities $g_{pm}(t,pm theta)$ respectively.



Suppose now that one could change the value of $theta$ and obtain the family of FPT distributions for all possible values of $theta$ (doesn't really matter whether one can obtain a parametric form or not). My question is, then: Would this family of distributions $g_{pm}(t,pm theta)$ imply the unicity of the underlying Fokker-Planck equation (or equivalently the form of the drift and diffusion coefficients $A(x,t)$ and $D(x,t)$)? My intuition tells me this must be the case, but I haven't found a theorem or a way to prove this claim.



Bonus question: Would this extend to a 2-dimensional case?










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    0












    $begingroup$


    Consider a 1-dimensional Continuous Markov Process $X(t)$ with fixed and constant absorbing boundaries, let's say at $pm theta$, and with starting point at $X(t=0)=0$. This setting will lead to a given First Passage Time (FPT) distribution at each boundary. Let us call the densities $g_{pm}(t,pm theta)$ respectively.



    Suppose now that one could change the value of $theta$ and obtain the family of FPT distributions for all possible values of $theta$ (doesn't really matter whether one can obtain a parametric form or not). My question is, then: Would this family of distributions $g_{pm}(t,pm theta)$ imply the unicity of the underlying Fokker-Planck equation (or equivalently the form of the drift and diffusion coefficients $A(x,t)$ and $D(x,t)$)? My intuition tells me this must be the case, but I haven't found a theorem or a way to prove this claim.



    Bonus question: Would this extend to a 2-dimensional case?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Consider a 1-dimensional Continuous Markov Process $X(t)$ with fixed and constant absorbing boundaries, let's say at $pm theta$, and with starting point at $X(t=0)=0$. This setting will lead to a given First Passage Time (FPT) distribution at each boundary. Let us call the densities $g_{pm}(t,pm theta)$ respectively.



      Suppose now that one could change the value of $theta$ and obtain the family of FPT distributions for all possible values of $theta$ (doesn't really matter whether one can obtain a parametric form or not). My question is, then: Would this family of distributions $g_{pm}(t,pm theta)$ imply the unicity of the underlying Fokker-Planck equation (or equivalently the form of the drift and diffusion coefficients $A(x,t)$ and $D(x,t)$)? My intuition tells me this must be the case, but I haven't found a theorem or a way to prove this claim.



      Bonus question: Would this extend to a 2-dimensional case?










      share|cite|improve this question









      $endgroup$




      Consider a 1-dimensional Continuous Markov Process $X(t)$ with fixed and constant absorbing boundaries, let's say at $pm theta$, and with starting point at $X(t=0)=0$. This setting will lead to a given First Passage Time (FPT) distribution at each boundary. Let us call the densities $g_{pm}(t,pm theta)$ respectively.



      Suppose now that one could change the value of $theta$ and obtain the family of FPT distributions for all possible values of $theta$ (doesn't really matter whether one can obtain a parametric form or not). My question is, then: Would this family of distributions $g_{pm}(t,pm theta)$ imply the unicity of the underlying Fokker-Planck equation (or equivalently the form of the drift and diffusion coefficients $A(x,t)$ and $D(x,t)$)? My intuition tells me this must be the case, but I haven't found a theorem or a way to prove this claim.



      Bonus question: Would this extend to a 2-dimensional case?







      stochastic-processes stochastic-calculus markov-process






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      share|cite|improve this question











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      asked Jan 16 at 11:15









      J. R. C.J. R. C.

      718




      718






















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