Xpath from next page to scrapy in Stack Overflow












1















I'm trying to crawl Stack Overflow with scrapy, but I'm not clear enough to make the rule to get next page. I don't know if the XPath I choose is right also.



He follows the code:



class StackCrawlerSpider(CrawlSpider):
name = 'stack_crawler'
allowed_domains = ['stackoverflow.com']
start_urls = [
'http://stackoverflow.com/questions?pagesize=50&sort=newest'
]
rules = [
Rule(LinkExtractor(allow=(), restrict_xpaths=('div[@class="pager fl"]/a[@class="page-numbers next"]/@href',)),
callback='parse_item', follow=True)
]


Could someone who understand scrapy an XPath help me to get next page from the following page (http://stackoverflow.com/questions?pagesize=50&sort=newest) and add it to the rule?










share|improve this question





























    1















    I'm trying to crawl Stack Overflow with scrapy, but I'm not clear enough to make the rule to get next page. I don't know if the XPath I choose is right also.



    He follows the code:



    class StackCrawlerSpider(CrawlSpider):
    name = 'stack_crawler'
    allowed_domains = ['stackoverflow.com']
    start_urls = [
    'http://stackoverflow.com/questions?pagesize=50&sort=newest'
    ]
    rules = [
    Rule(LinkExtractor(allow=(), restrict_xpaths=('div[@class="pager fl"]/a[@class="page-numbers next"]/@href',)),
    callback='parse_item', follow=True)
    ]


    Could someone who understand scrapy an XPath help me to get next page from the following page (http://stackoverflow.com/questions?pagesize=50&sort=newest) and add it to the rule?










    share|improve this question



























      1












      1








      1








      I'm trying to crawl Stack Overflow with scrapy, but I'm not clear enough to make the rule to get next page. I don't know if the XPath I choose is right also.



      He follows the code:



      class StackCrawlerSpider(CrawlSpider):
      name = 'stack_crawler'
      allowed_domains = ['stackoverflow.com']
      start_urls = [
      'http://stackoverflow.com/questions?pagesize=50&sort=newest'
      ]
      rules = [
      Rule(LinkExtractor(allow=(), restrict_xpaths=('div[@class="pager fl"]/a[@class="page-numbers next"]/@href',)),
      callback='parse_item', follow=True)
      ]


      Could someone who understand scrapy an XPath help me to get next page from the following page (http://stackoverflow.com/questions?pagesize=50&sort=newest) and add it to the rule?










      share|improve this question
















      I'm trying to crawl Stack Overflow with scrapy, but I'm not clear enough to make the rule to get next page. I don't know if the XPath I choose is right also.



      He follows the code:



      class StackCrawlerSpider(CrawlSpider):
      name = 'stack_crawler'
      allowed_domains = ['stackoverflow.com']
      start_urls = [
      'http://stackoverflow.com/questions?pagesize=50&sort=newest'
      ]
      rules = [
      Rule(LinkExtractor(allow=(), restrict_xpaths=('div[@class="pager fl"]/a[@class="page-numbers next"]/@href',)),
      callback='parse_item', follow=True)
      ]


      Could someone who understand scrapy an XPath help me to get next page from the following page (http://stackoverflow.com/questions?pagesize=50&sort=newest) and add it to the rule?







      xpath web-scraping scrapy






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 26 '18 at 1:42









      Pang

      6,9281664102




      6,9281664102










      asked Nov 21 '18 at 23:34









      Lucas Oliveira CostaLucas Oliveira Costa

      154




      154
























          1 Answer
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          you need to select root element // then go to span containing class page-numbers next and text next then go to it parent .. which is a tag.



          //span[@class="page-numbers next"]/../@href





          share|improve this answer
























          • Wouldn't it be simpler to use //a[@rel="next"]/@href?

            – Casper
            Nov 22 '18 at 13:52











          • yes you're right, above is first way in my mind

            – ewwink
            Nov 22 '18 at 20:16











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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          1














          you need to select root element // then go to span containing class page-numbers next and text next then go to it parent .. which is a tag.



          //span[@class="page-numbers next"]/../@href





          share|improve this answer
























          • Wouldn't it be simpler to use //a[@rel="next"]/@href?

            – Casper
            Nov 22 '18 at 13:52











          • yes you're right, above is first way in my mind

            – ewwink
            Nov 22 '18 at 20:16
















          1














          you need to select root element // then go to span containing class page-numbers next and text next then go to it parent .. which is a tag.



          //span[@class="page-numbers next"]/../@href





          share|improve this answer
























          • Wouldn't it be simpler to use //a[@rel="next"]/@href?

            – Casper
            Nov 22 '18 at 13:52











          • yes you're right, above is first way in my mind

            – ewwink
            Nov 22 '18 at 20:16














          1












          1








          1







          you need to select root element // then go to span containing class page-numbers next and text next then go to it parent .. which is a tag.



          //span[@class="page-numbers next"]/../@href





          share|improve this answer













          you need to select root element // then go to span containing class page-numbers next and text next then go to it parent .. which is a tag.



          //span[@class="page-numbers next"]/../@href






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 '18 at 2:09









          ewwinkewwink

          11.9k22239




          11.9k22239













          • Wouldn't it be simpler to use //a[@rel="next"]/@href?

            – Casper
            Nov 22 '18 at 13:52











          • yes you're right, above is first way in my mind

            – ewwink
            Nov 22 '18 at 20:16



















          • Wouldn't it be simpler to use //a[@rel="next"]/@href?

            – Casper
            Nov 22 '18 at 13:52











          • yes you're right, above is first way in my mind

            – ewwink
            Nov 22 '18 at 20:16

















          Wouldn't it be simpler to use //a[@rel="next"]/@href?

          – Casper
          Nov 22 '18 at 13:52





          Wouldn't it be simpler to use //a[@rel="next"]/@href?

          – Casper
          Nov 22 '18 at 13:52













          yes you're right, above is first way in my mind

          – ewwink
          Nov 22 '18 at 20:16





          yes you're right, above is first way in my mind

          – ewwink
          Nov 22 '18 at 20:16




















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