Mixing
How to assign value to objects in java
-3
How do I add a value to my ArrayList in java then print out the value to each object.
import java.util.ArrayList;
import java.util.Scanner;
public class exercise {
private ArrayList<String> files;
public void ArrayList() {
a = new ArrayList<>();
}
public void addObject() {
a.add("blue")
a.add("green")
a.add("yellow")
}
public void addValue(String Object) {
for (String filenames : a)
Scanner reader = new Scanner(System.in);
int n = reader.nextInt();
a.set(n)
}
}
I want to try assign values by user input to "blue" , "green" and "yellow" so it can be any value
java arraylist java.util.scanner
asked Nov 21 '18 at 23:25
henchnesshenchness
36
add a comment |
-3
How do I add a value to my ArrayList in java then print out the value to each object.
import java.util.ArrayList;
import java.util.Scanner;
public class exercise {
private ArrayList<String> files;
public void ArrayList() {
a = new ArrayList<>();
}
public void addObject() {
a.add("blue")
a.add("green")
a.add("yellow")
}
public void addValue(String Object) {
for (String filenames : a)
Scanner reader = new Scanner(System.in);
int n = reader.nextInt();
a.set(n)
}
}
I want to try assign values by user input to "blue" , "green" and "yellow" so it can be any value
java arraylist java.util.scanner
asked Nov 21 '18 at 23:25
henchnesshenchness
36
Where did you get the ArrayListafrom? Where do you declare it?
– Ishaan Javali
Nov 21 '18 at 23:27
1
Firstly, class declarations cannot have parentheses.
– Logan
Nov 21 '18 at 23:27
private ArrayList<String> a;
– henchness
Nov 21 '18 at 23:35
First, fix compile errors and format your code properly. Second, it is totally unclear what you are trying to achieve with your code. You can use java ArrayList directly without some weird wrappers on top of it.
– Sergei Sirik
Nov 21 '18 at 23:41
add a comment |
-3
-3
-3
How do I add a value to my ArrayList in java then print out the value to each object.
import java.util.ArrayList;
import java.util.Scanner;
public class exercise {
private ArrayList<String> files;
public void ArrayList() {
a = new ArrayList<>();
}
public void addObject() {
a.add("blue")
a.add("green")
a.add("yellow")
}
public void addValue(String Object) {
for (String filenames : a)
Scanner reader = new Scanner(System.in);
int n = reader.nextInt();
a.set(n)
}
}
I want to try assign values by user input to "blue" , "green" and "yellow" so it can be any value
java arraylist java.util.scanner
asked Nov 21 '18 at 23:25
henchnesshenchness
36
How do I add a value to my ArrayList in java then print out the value to each object.
import java.util.ArrayList;
import java.util.Scanner;
public class exercise {
private ArrayList<String> files;
public void ArrayList() {
a = new ArrayList<>();
}
public void addObject() {
a.add("blue")
a.add("green")
a.add("yellow")
}
public void addValue(String Object) {
for (String filenames : a)
Scanner reader = new Scanner(System.in);
int n = reader.nextInt();
a.set(n)
}
}
I want to try assign values by user input to "blue" , "green" and "yellow" so it can be any value
java arraylist java.util.scanner
java arraylist java.util.scanner
asked Nov 21 '18 at 23:25
henchnesshenchness
36
asked Nov 21 '18 at 23:25
henchnesshenchness
36
edited Nov 21 '18 at 23:36
henchness
asked Nov 21 '18 at 23:25
henchnesshenchness
36
asked Nov 21 '18 at 23:25
henchnesshenchness
36
asked Nov 21 '18 at 23:25
henchnesshenchness
36
36
Where did you get the ArrayListafrom? Where do you declare it?
– Ishaan Javali
Nov 21 '18 at 23:27
1
Firstly, class declarations cannot have parentheses.
– Logan
Nov 21 '18 at 23:27
private ArrayList<String> a;
– henchness
Nov 21 '18 at 23:35
First, fix compile errors and format your code properly. Second, it is totally unclear what you are trying to achieve with your code. You can use java ArrayList directly without some weird wrappers on top of it.
– Sergei Sirik
Nov 21 '18 at 23:41
add a comment |
Where did you get the ArrayListafrom? Where do you declare it?
– Ishaan Javali
Nov 21 '18 at 23:27
1
Firstly, class declarations cannot have parentheses.
– Logan
Nov 21 '18 at 23:27
private ArrayList<String> a;
– henchness
Nov 21 '18 at 23:35
First, fix compile errors and format your code properly. Second, it is totally unclear what you are trying to achieve with your code. You can use java ArrayList directly without some weird wrappers on top of it.
– Sergei Sirik
Nov 21 '18 at 23:41
Where did you get the ArrayList
a from? Where do you declare it?– Ishaan Javali
Nov 21 '18 at 23:27
Where did you get the ArrayList
a from? Where do you declare it?– Ishaan Javali
Nov 21 '18 at 23:27
1
1
Firstly, class declarations cannot have parentheses.
– Logan
Nov 21 '18 at 23:27
Firstly, class declarations cannot have parentheses.
– Logan
Nov 21 '18 at 23:27
private ArrayList<String> a;
– henchness
Nov 21 '18 at 23:35
private ArrayList<String> a;
– henchness
Nov 21 '18 at 23:35
First, fix compile errors and format your code properly. Second, it is totally unclear what you are trying to achieve with your code. You can use java ArrayList directly without some weird wrappers on top of it.
– Sergei Sirik
Nov 21 '18 at 23:41
First, fix compile errors and format your code properly. Second, it is totally unclear what you are trying to achieve with your code. You can use java ArrayList directly without some weird wrappers on top of it.
– Sergei Sirik
Nov 21 '18 at 23:41
add a comment |
1 Answer
1
active
oldest
votes
0
Edit:
You want to take user's input and if it's a predefined color, like "blue", then add a predefined number for that color, like 3, to a list? Right?
If that is the case then this code takes user's input from the console, checks if that input is a predefined color and then stores a matching number in the ArrayList.
When the user enters 'stop' then the program prints only the numbers in the list and then terminates.
import java.util.ArrayList;
public class Exercise {
private static ArrayList<Integer> list = new ArrayList<Integer>(); // You can initialize your ArrayList here as well
public static void main(String args) {
String userInput = null;
int number = 0;
do{
// Read inputs as long as user did not entered 'stop'
userInput = readUserInput();
number = createNumberFromColor(userInput);
// add the number to the list if it's not 0
if (number!=0) {
list.add(number);
}
}while (!userInput.equals("stop"));
// If you want afterwards you can print the list elements
System.out.println("The list contains:");
for (int i=0; i<list.size(); i++) {
System.out.print(""+list.get(i)+" ");
}
System.out.println();
}
private static String readUserInput(){
// This is an easier way to read the user input from the console
// than using the Scanner class, which needs to be closed etc...
return System.console().readLine();
}
private static int createNumberFromColor(String input){
switch (input) {
// Add your own cases here, for example case "red": return 1, etc...
case "blue":
return 5;
case "yellow":
return 3;
// If the input was not a known color then return 0
default:
return 0;
}
}
}
answered Nov 21 '18 at 23:58
ThemelisThemelis
755517
Careful the class here is namedExercise, notexercice.
– Themelis
Nov 22 '18 at 0:01
Im trying to add a value to the previous items in the ArrayList such as blue = 5 or yellow = 3 instead of terminated the items in it
– henchness
Nov 22 '18 at 0:08
So if the user inserts 5 you will assign "blue", if he inserts 3 you will assign "yellow" etc?
– Themelis
Nov 22 '18 at 0:11
yes thats exactly what i mean
– henchness
Nov 22 '18 at 0:17
@henchness Check the new code snippet and tell me if that's what you've wanted.
– Themelis
Nov 22 '18 at 0:29
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Edit:
You want to take user's input and if it's a predefined color, like "blue", then add a predefined number for that color, like 3, to a list? Right?
If that is the case then this code takes user's input from the console, checks if that input is a predefined color and then stores a matching number in the ArrayList.
When the user enters 'stop' then the program prints only the numbers in the list and then terminates.
import java.util.ArrayList;
public class Exercise {
private static ArrayList<Integer> list = new ArrayList<Integer>(); // You can initialize your ArrayList here as well
public static void main(String args) {
String userInput = null;
int number = 0;
do{
// Read inputs as long as user did not entered 'stop'
userInput = readUserInput();
number = createNumberFromColor(userInput);
// add the number to the list if it's not 0
if (number!=0) {
list.add(number);
}
}while (!userInput.equals("stop"));
// If you want afterwards you can print the list elements
System.out.println("The list contains:");
for (int i=0; i<list.size(); i++) {
System.out.print(""+list.get(i)+" ");
}
System.out.println();
}
private static String readUserInput(){
// This is an easier way to read the user input from the console
// than using the Scanner class, which needs to be closed etc...
return System.console().readLine();
}
private static int createNumberFromColor(String input){
switch (input) {
// Add your own cases here, for example case "red": return 1, etc...
case "blue":
return 5;
case "yellow":
return 3;
// If the input was not a known color then return 0
default:
return 0;
}
}
}
answered Nov 21 '18 at 23:58
ThemelisThemelis
755517
Careful the class here is namedExercise, notexercice.
– Themelis
Nov 22 '18 at 0:01
Im trying to add a value to the previous items in the ArrayList such as blue = 5 or yellow = 3 instead of terminated the items in it
– henchness
Nov 22 '18 at 0:08
So if the user inserts 5 you will assign "blue", if he inserts 3 you will assign "yellow" etc?
– Themelis
Nov 22 '18 at 0:11
yes thats exactly what i mean
– henchness
Nov 22 '18 at 0:17
@henchness Check the new code snippet and tell me if that's what you've wanted.
– Themelis
Nov 22 '18 at 0:29
add a comment |
0
Edit:
You want to take user's input and if it's a predefined color, like "blue", then add a predefined number for that color, like 3, to a list? Right?
If that is the case then this code takes user's input from the console, checks if that input is a predefined color and then stores a matching number in the ArrayList.
When the user enters 'stop' then the program prints only the numbers in the list and then terminates.
import java.util.ArrayList;
public class Exercise {
private static ArrayList<Integer> list = new ArrayList<Integer>(); // You can initialize your ArrayList here as well
public static void main(String args) {
String userInput = null;
int number = 0;
do{
// Read inputs as long as user did not entered 'stop'
userInput = readUserInput();
number = createNumberFromColor(userInput);
// add the number to the list if it's not 0
if (number!=0) {
list.add(number);
}
}while (!userInput.equals("stop"));
// If you want afterwards you can print the list elements
System.out.println("The list contains:");
for (int i=0; i<list.size(); i++) {
System.out.print(""+list.get(i)+" ");
}
System.out.println();
}
private static String readUserInput(){
// This is an easier way to read the user input from the console
// than using the Scanner class, which needs to be closed etc...
return System.console().readLine();
}
private static int createNumberFromColor(String input){
switch (input) {
// Add your own cases here, for example case "red": return 1, etc...
case "blue":
return 5;
case "yellow":
return 3;
// If the input was not a known color then return 0
default:
return 0;
}
}
}
answered Nov 21 '18 at 23:58
ThemelisThemelis
755517
Careful the class here is namedExercise, notexercice.
– Themelis
Nov 22 '18 at 0:01
Im trying to add a value to the previous items in the ArrayList such as blue = 5 or yellow = 3 instead of terminated the items in it
– henchness
Nov 22 '18 at 0:08
So if the user inserts 5 you will assign "blue", if he inserts 3 you will assign "yellow" etc?
– Themelis
Nov 22 '18 at 0:11
yes thats exactly what i mean
– henchness
Nov 22 '18 at 0:17
@henchness Check the new code snippet and tell me if that's what you've wanted.
– Themelis
Nov 22 '18 at 0:29
add a comment |
0
0
0
Edit:
You want to take user's input and if it's a predefined color, like "blue", then add a predefined number for that color, like 3, to a list? Right?
If that is the case then this code takes user's input from the console, checks if that input is a predefined color and then stores a matching number in the ArrayList.
When the user enters 'stop' then the program prints only the numbers in the list and then terminates.
import java.util.ArrayList;
public class Exercise {
private static ArrayList<Integer> list = new ArrayList<Integer>(); // You can initialize your ArrayList here as well
public static void main(String args) {
String userInput = null;
int number = 0;
do{
// Read inputs as long as user did not entered 'stop'
userInput = readUserInput();
number = createNumberFromColor(userInput);
// add the number to the list if it's not 0
if (number!=0) {
list.add(number);
}
}while (!userInput.equals("stop"));
// If you want afterwards you can print the list elements
System.out.println("The list contains:");
for (int i=0; i<list.size(); i++) {
System.out.print(""+list.get(i)+" ");
}
System.out.println();
}
private static String readUserInput(){
// This is an easier way to read the user input from the console
// than using the Scanner class, which needs to be closed etc...
return System.console().readLine();
}
private static int createNumberFromColor(String input){
switch (input) {
// Add your own cases here, for example case "red": return 1, etc...
case "blue":
return 5;
case "yellow":
return 3;
// If the input was not a known color then return 0
default:
return 0;
}
}
}
answered Nov 21 '18 at 23:58
ThemelisThemelis
755517
Edit:
You want to take user's input and if it's a predefined color, like "blue", then add a predefined number for that color, like 3, to a list? Right?
If that is the case then this code takes user's input from the console, checks if that input is a predefined color and then stores a matching number in the ArrayList.
When the user enters 'stop' then the program prints only the numbers in the list and then terminates.
import java.util.ArrayList;
public class Exercise {
private static ArrayList<Integer> list = new ArrayList<Integer>(); // You can initialize your ArrayList here as well
public static void main(String args) {
String userInput = null;
int number = 0;
do{
// Read inputs as long as user did not entered 'stop'
userInput = readUserInput();
number = createNumberFromColor(userInput);
// add the number to the list if it's not 0
if (number!=0) {
list.add(number);
}
}while (!userInput.equals("stop"));
// If you want afterwards you can print the list elements
System.out.println("The list contains:");
for (int i=0; i<list.size(); i++) {
System.out.print(""+list.get(i)+" ");
}
System.out.println();
}
private static String readUserInput(){
// This is an easier way to read the user input from the console
// than using the Scanner class, which needs to be closed etc...
return System.console().readLine();
}
private static int createNumberFromColor(String input){
switch (input) {
// Add your own cases here, for example case "red": return 1, etc...
case "blue":
return 5;
case "yellow":
return 3;
// If the input was not a known color then return 0
default:
return 0;
}
}
}
answered Nov 21 '18 at 23:58
ThemelisThemelis
755517
edited Nov 22 '18 at 0:28
answered Nov 21 '18 at 23:58
ThemelisThemelis
755517
answered Nov 21 '18 at 23:58
ThemelisThemelis
755517
answered Nov 21 '18 at 23:58
ThemelisThemelis
755517
755517
Careful the class here is namedExercise, notexercice.
– Themelis
Nov 22 '18 at 0:01
Im trying to add a value to the previous items in the ArrayList such as blue = 5 or yellow = 3 instead of terminated the items in it
– henchness
Nov 22 '18 at 0:08
So if the user inserts 5 you will assign "blue", if he inserts 3 you will assign "yellow" etc?
– Themelis
Nov 22 '18 at 0:11
yes thats exactly what i mean
– henchness
Nov 22 '18 at 0:17
@henchness Check the new code snippet and tell me if that's what you've wanted.
– Themelis
Nov 22 '18 at 0:29
add a comment |
Careful the class here is namedExercise, notexercice.
– Themelis
Nov 22 '18 at 0:01
Im trying to add a value to the previous items in the ArrayList such as blue = 5 or yellow = 3 instead of terminated the items in it
– henchness
Nov 22 '18 at 0:08
So if the user inserts 5 you will assign "blue", if he inserts 3 you will assign "yellow" etc?
– Themelis
Nov 22 '18 at 0:11
yes thats exactly what i mean
– henchness
Nov 22 '18 at 0:17
@henchness Check the new code snippet and tell me if that's what you've wanted.
– Themelis
Nov 22 '18 at 0:29
Careful the class here is named
Exercise, not exercice.– Themelis
Nov 22 '18 at 0:01
Careful the class here is named
Exercise, not exercice.– Themelis
Nov 22 '18 at 0:01
Im trying to add a value to the previous items in the ArrayList such as blue = 5 or yellow = 3 instead of terminated the items in it
– henchness
Nov 22 '18 at 0:08
Im trying to add a value to the previous items in the ArrayList such as blue = 5 or yellow = 3 instead of terminated the items in it
– henchness
Nov 22 '18 at 0:08
So if the user inserts 5 you will assign "blue", if he inserts 3 you will assign "yellow" etc?
– Themelis
Nov 22 '18 at 0:11
So if the user inserts 5 you will assign "blue", if he inserts 3 you will assign "yellow" etc?
– Themelis
Nov 22 '18 at 0:11
yes thats exactly what i mean
– henchness
Nov 22 '18 at 0:17
yes thats exactly what i mean
– henchness
Nov 22 '18 at 0:17
@henchness Check the new code snippet and tell me if that's what you've wanted.
– Themelis
Nov 22 '18 at 0:29
@henchness Check the new code snippet and tell me if that's what you've wanted.
– Themelis
Nov 22 '18 at 0:29
add a comment |
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Where did you get the ArrayList
afrom? Where do you declare it?– Ishaan Javali
Nov 21 '18 at 23:27
1
Firstly, class declarations cannot have parentheses.
– Logan
Nov 21 '18 at 23:27
private ArrayList<String> a;
– henchness
Nov 21 '18 at 23:35
First, fix compile errors and format your code properly. Second, it is totally unclear what you are trying to achieve with your code. You can use java ArrayList directly without some weird wrappers on top of it.
– Sergei Sirik
Nov 21 '18 at 23:41