Mixing
How to turn a binary string into a byte?
If I take the letter 'à' and encode it in UTF-8 I obtain the following result:
'à'.encode('utf-8')
>> b'xc3xa0'
Now from a bytearray I would like to convert 'à' into a binary string and turn it back into 'à'. To do so I execute the following code:
byte = bytearray('à','utf-8')
for x in byte:
print(bin(x))
I get 0b11000011and0b10100000, which is 195 and 160. Then, I fuse them together and take the 0b part out. Now I execute this code:
s = '1100001110100000'
value1 = s[0:8].encode('utf-8')
value2 = s[9:16].encode('utf-8')
value = value1 + value2
print(chr(int(value, 2)))
>> 憠
No matter how I develop the later part I get symbols and never seem to be able to get back my 'à'. I would like to know why is that? And how can I get an 'à'.
python unicode utf-8 utf
asked Nov 21 '18 at 23:44
jatrp5jatrp5
142
add a comment |
If I take the letter 'à' and encode it in UTF-8 I obtain the following result:
'à'.encode('utf-8')
>> b'xc3xa0'
Now from a bytearray I would like to convert 'à' into a binary string and turn it back into 'à'. To do so I execute the following code:
byte = bytearray('à','utf-8')
for x in byte:
print(bin(x))
I get 0b11000011and0b10100000, which is 195 and 160. Then, I fuse them together and take the 0b part out. Now I execute this code:
s = '1100001110100000'
value1 = s[0:8].encode('utf-8')
value2 = s[9:16].encode('utf-8')
value = value1 + value2
print(chr(int(value, 2)))
>> 憠
No matter how I develop the later part I get symbols and never seem to be able to get back my 'à'. I would like to know why is that? And how can I get an 'à'.
python unicode utf-8 utf
asked Nov 21 '18 at 23:44
jatrp5jatrp5
142
add a comment |
If I take the letter 'à' and encode it in UTF-8 I obtain the following result:
'à'.encode('utf-8')
>> b'xc3xa0'
Now from a bytearray I would like to convert 'à' into a binary string and turn it back into 'à'. To do so I execute the following code:
byte = bytearray('à','utf-8')
for x in byte:
print(bin(x))
I get 0b11000011and0b10100000, which is 195 and 160. Then, I fuse them together and take the 0b part out. Now I execute this code:
s = '1100001110100000'
value1 = s[0:8].encode('utf-8')
value2 = s[9:16].encode('utf-8')
value = value1 + value2
print(chr(int(value, 2)))
>> 憠
No matter how I develop the later part I get symbols and never seem to be able to get back my 'à'. I would like to know why is that? And how can I get an 'à'.
python unicode utf-8 utf
asked Nov 21 '18 at 23:44
jatrp5jatrp5
142
If I take the letter 'à' and encode it in UTF-8 I obtain the following result:
'à'.encode('utf-8')
>> b'xc3xa0'
Now from a bytearray I would like to convert 'à' into a binary string and turn it back into 'à'. To do so I execute the following code:
byte = bytearray('à','utf-8')
for x in byte:
print(bin(x))
I get 0b11000011and0b10100000, which is 195 and 160. Then, I fuse them together and take the 0b part out. Now I execute this code:
s = '1100001110100000'
value1 = s[0:8].encode('utf-8')
value2 = s[9:16].encode('utf-8')
value = value1 + value2
print(chr(int(value, 2)))
>> 憠
No matter how I develop the later part I get symbols and never seem to be able to get back my 'à'. I would like to know why is that? And how can I get an 'à'.
python unicode utf-8 utf
python unicode utf-8 utf
asked Nov 21 '18 at 23:44
jatrp5jatrp5
142
asked Nov 21 '18 at 23:44
jatrp5jatrp5
142
asked Nov 21 '18 at 23:44
jatrp5jatrp5
142
asked Nov 21 '18 at 23:44
jatrp5jatrp5
142
asked Nov 21 '18 at 23:44
jatrp5jatrp5
142
142
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
>>> bytes(int(s[i:i+8], 2) for i in range(0, len(s), 8)).decode('utf-8')
'à'
There are multiple parts to this. The bytes constructor creates a byte string from a sequence of integers. The integers are formed from strings using int with a base of 2. The range combined with the slicing peels off 8 characters at a time. Finally decode converts those bytes back into Unicode characters.
answered Nov 21 '18 at 23:50
Mark RansomMark Ransom
225k29283509
1
Note also that the OP can use''.join('{:08b}'.format(i) for i in byte)on the original byte-array object. This is pretty similar: we take the byte-array apart, one byte at a time, and format each one using:08bto get an eight-bit zero-filled string representation, then join all the strings without whitespace.
– torek
Nov 22 '18 at 0:03
add a comment |
you need your second bits to be s[8:16] (or just s[8:]) otherwise you get 0100000
you also need to convert you "bit string" back to an integer before thinking of it as a byte with int("0010101",2)
s = '1100001110100000'
value1 = bytearray([int(s[:8],2), # bits 0..7 (8 total)
int(s[8:],2)] # bits 8..15 (8 total)
)
print(value1.decode("utf8"))
answered Nov 21 '18 at 23:51
Joran BeasleyJoran Beasley
73.4k679120
add a comment |
Convert the base-2 value back to an integer with int(s,2), convert that integer to a number of bytes (int.to_bytes) based on the original length divided by 8 and big-endian conversion to keep the bytes in the right order, then .decode() it (default in Python 3 is utf8):
>>> s = '1100001110100000'
>>> int(s,2)
50080
>>> int(s,2).to_bytes(len(s)//8,'big')
b'xc3xa0'
>>> int(s,2).to_bytes(len(s)//8,'big').decode()
'à'
answered Nov 22 '18 at 7:29
Mark TolonenMark Tolonen
94.2k12114176
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
>>> bytes(int(s[i:i+8], 2) for i in range(0, len(s), 8)).decode('utf-8')
'à'
There are multiple parts to this. The bytes constructor creates a byte string from a sequence of integers. The integers are formed from strings using int with a base of 2. The range combined with the slicing peels off 8 characters at a time. Finally decode converts those bytes back into Unicode characters.
answered Nov 21 '18 at 23:50
Mark RansomMark Ransom
225k29283509
1
Note also that the OP can use''.join('{:08b}'.format(i) for i in byte)on the original byte-array object. This is pretty similar: we take the byte-array apart, one byte at a time, and format each one using:08bto get an eight-bit zero-filled string representation, then join all the strings without whitespace.
– torek
Nov 22 '18 at 0:03
add a comment |
>>> bytes(int(s[i:i+8], 2) for i in range(0, len(s), 8)).decode('utf-8')
'à'
There are multiple parts to this. The bytes constructor creates a byte string from a sequence of integers. The integers are formed from strings using int with a base of 2. The range combined with the slicing peels off 8 characters at a time. Finally decode converts those bytes back into Unicode characters.
answered Nov 21 '18 at 23:50
Mark RansomMark Ransom
225k29283509
1
Note also that the OP can use''.join('{:08b}'.format(i) for i in byte)on the original byte-array object. This is pretty similar: we take the byte-array apart, one byte at a time, and format each one using:08bto get an eight-bit zero-filled string representation, then join all the strings without whitespace.
– torek
Nov 22 '18 at 0:03
add a comment |
>>> bytes(int(s[i:i+8], 2) for i in range(0, len(s), 8)).decode('utf-8')
'à'
There are multiple parts to this. The bytes constructor creates a byte string from a sequence of integers. The integers are formed from strings using int with a base of 2. The range combined with the slicing peels off 8 characters at a time. Finally decode converts those bytes back into Unicode characters.
answered Nov 21 '18 at 23:50
Mark RansomMark Ransom
225k29283509
>>> bytes(int(s[i:i+8], 2) for i in range(0, len(s), 8)).decode('utf-8')
'à'
There are multiple parts to this. The bytes constructor creates a byte string from a sequence of integers. The integers are formed from strings using int with a base of 2. The range combined with the slicing peels off 8 characters at a time. Finally decode converts those bytes back into Unicode characters.
answered Nov 21 '18 at 23:50
Mark RansomMark Ransom
225k29283509
answered Nov 21 '18 at 23:50
Mark RansomMark Ransom
225k29283509
answered Nov 21 '18 at 23:50
Mark RansomMark Ransom
225k29283509
answered Nov 21 '18 at 23:50
Mark RansomMark Ransom
225k29283509
225k29283509
1
Note also that the OP can use''.join('{:08b}'.format(i) for i in byte)on the original byte-array object. This is pretty similar: we take the byte-array apart, one byte at a time, and format each one using:08bto get an eight-bit zero-filled string representation, then join all the strings without whitespace.
– torek
Nov 22 '18 at 0:03
add a comment |
1
Note also that the OP can use''.join('{:08b}'.format(i) for i in byte)on the original byte-array object. This is pretty similar: we take the byte-array apart, one byte at a time, and format each one using:08bto get an eight-bit zero-filled string representation, then join all the strings without whitespace.
– torek
Nov 22 '18 at 0:03
1
1
Note also that the OP can use
''.join('{:08b}'.format(i) for i in byte) on the original byte-array object. This is pretty similar: we take the byte-array apart, one byte at a time, and format each one using :08b to get an eight-bit zero-filled string representation, then join all the strings without whitespace.– torek
Nov 22 '18 at 0:03
Note also that the OP can use
''.join('{:08b}'.format(i) for i in byte) on the original byte-array object. This is pretty similar: we take the byte-array apart, one byte at a time, and format each one using :08b to get an eight-bit zero-filled string representation, then join all the strings without whitespace.– torek
Nov 22 '18 at 0:03
add a comment |
you need your second bits to be s[8:16] (or just s[8:]) otherwise you get 0100000
you also need to convert you "bit string" back to an integer before thinking of it as a byte with int("0010101",2)
s = '1100001110100000'
value1 = bytearray([int(s[:8],2), # bits 0..7 (8 total)
int(s[8:],2)] # bits 8..15 (8 total)
)
print(value1.decode("utf8"))
answered Nov 21 '18 at 23:51
Joran BeasleyJoran Beasley
73.4k679120
add a comment |
you need your second bits to be s[8:16] (or just s[8:]) otherwise you get 0100000
you also need to convert you "bit string" back to an integer before thinking of it as a byte with int("0010101",2)
s = '1100001110100000'
value1 = bytearray([int(s[:8],2), # bits 0..7 (8 total)
int(s[8:],2)] # bits 8..15 (8 total)
)
print(value1.decode("utf8"))
answered Nov 21 '18 at 23:51
Joran BeasleyJoran Beasley
73.4k679120
add a comment |
you need your second bits to be s[8:16] (or just s[8:]) otherwise you get 0100000
you also need to convert you "bit string" back to an integer before thinking of it as a byte with int("0010101",2)
s = '1100001110100000'
value1 = bytearray([int(s[:8],2), # bits 0..7 (8 total)
int(s[8:],2)] # bits 8..15 (8 total)
)
print(value1.decode("utf8"))
answered Nov 21 '18 at 23:51
Joran BeasleyJoran Beasley
73.4k679120
you need your second bits to be s[8:16] (or just s[8:]) otherwise you get 0100000
you also need to convert you "bit string" back to an integer before thinking of it as a byte with int("0010101",2)
s = '1100001110100000'
value1 = bytearray([int(s[:8],2), # bits 0..7 (8 total)
int(s[8:],2)] # bits 8..15 (8 total)
)
print(value1.decode("utf8"))
answered Nov 21 '18 at 23:51
Joran BeasleyJoran Beasley
73.4k679120
answered Nov 21 '18 at 23:51
Joran BeasleyJoran Beasley
73.4k679120
answered Nov 21 '18 at 23:51
Joran BeasleyJoran Beasley
73.4k679120
answered Nov 21 '18 at 23:51
Joran BeasleyJoran Beasley
73.4k679120
73.4k679120
add a comment |
add a comment |
Convert the base-2 value back to an integer with int(s,2), convert that integer to a number of bytes (int.to_bytes) based on the original length divided by 8 and big-endian conversion to keep the bytes in the right order, then .decode() it (default in Python 3 is utf8):
>>> s = '1100001110100000'
>>> int(s,2)
50080
>>> int(s,2).to_bytes(len(s)//8,'big')
b'xc3xa0'
>>> int(s,2).to_bytes(len(s)//8,'big').decode()
'à'
answered Nov 22 '18 at 7:29
Mark TolonenMark Tolonen
94.2k12114176
add a comment |
Convert the base-2 value back to an integer with int(s,2), convert that integer to a number of bytes (int.to_bytes) based on the original length divided by 8 and big-endian conversion to keep the bytes in the right order, then .decode() it (default in Python 3 is utf8):
>>> s = '1100001110100000'
>>> int(s,2)
50080
>>> int(s,2).to_bytes(len(s)//8,'big')
b'xc3xa0'
>>> int(s,2).to_bytes(len(s)//8,'big').decode()
'à'
answered Nov 22 '18 at 7:29
Mark TolonenMark Tolonen
94.2k12114176
add a comment |
Convert the base-2 value back to an integer with int(s,2), convert that integer to a number of bytes (int.to_bytes) based on the original length divided by 8 and big-endian conversion to keep the bytes in the right order, then .decode() it (default in Python 3 is utf8):
>>> s = '1100001110100000'
>>> int(s,2)
50080
>>> int(s,2).to_bytes(len(s)//8,'big')
b'xc3xa0'
>>> int(s,2).to_bytes(len(s)//8,'big').decode()
'à'
answered Nov 22 '18 at 7:29
Mark TolonenMark Tolonen
94.2k12114176
Convert the base-2 value back to an integer with int(s,2), convert that integer to a number of bytes (int.to_bytes) based on the original length divided by 8 and big-endian conversion to keep the bytes in the right order, then .decode() it (default in Python 3 is utf8):
>>> s = '1100001110100000'
>>> int(s,2)
50080
>>> int(s,2).to_bytes(len(s)//8,'big')
b'xc3xa0'
>>> int(s,2).to_bytes(len(s)//8,'big').decode()
'à'
answered Nov 22 '18 at 7:29
Mark TolonenMark Tolonen
94.2k12114176
answered Nov 22 '18 at 7:29
Mark TolonenMark Tolonen
94.2k12114176
answered Nov 22 '18 at 7:29
Mark TolonenMark Tolonen
94.2k12114176
answered Nov 22 '18 at 7:29
Mark TolonenMark Tolonen
94.2k12114176
94.2k12114176
add a comment |
add a comment |
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