bug with 'unique'? Don't get an error when 'nmax' is 1 less than the number of unique values












4















Have tested this on R 3.5.0.



set.seed(0)

x <- rexp(100)

length(unique(x))  ## 100



## this fails as I expect

unique(x, nmax = 98)

#Error in unique.default(x, nmax = 98) : hash table is full



## but how come does this succeed?

length(unique(x, nmax = 99))  ## 100





r vector unique







share|improve this question























  • Same behavior with function duplicated.

    – 李哲源
    Nov 21 '18 at 23:16











  • Why wrap only the second call in length? I think this would be more clear if you used length in both or neither case of calling unique with nmax of 98 & 99

    – arvi1000
    Nov 21 '18 at 23:22













  • This is the best I can offer. r.789695.n4.nabble.com/… nmax - 1 still returns the length of your vector, so I think it's correct about ignoring it.

    – Anonymous coward
    Nov 21 '18 at 23:27













  • @Anonymouscoward Thanks. Now factor has the same problem.

    – 李哲源
    Nov 21 '18 at 23:30











  • I guess anything that calls duplicated has the problem.

    – Anonymous coward
    Nov 21 '18 at 23:31
















4















Have tested this on R 3.5.0.



set.seed(0)

x <- rexp(100)

length(unique(x))  ## 100



## this fails as I expect

unique(x, nmax = 98)

#Error in unique.default(x, nmax = 98) : hash table is full



## but how come does this succeed?

length(unique(x, nmax = 99))  ## 100





r vector unique







share|improve this question























  • Same behavior with function duplicated.

    – 李哲源
    Nov 21 '18 at 23:16











  • Why wrap only the second call in length? I think this would be more clear if you used length in both or neither case of calling unique with nmax of 98 & 99

    – arvi1000
    Nov 21 '18 at 23:22













  • This is the best I can offer. r.789695.n4.nabble.com/… nmax - 1 still returns the length of your vector, so I think it's correct about ignoring it.

    – Anonymous coward
    Nov 21 '18 at 23:27













  • @Anonymouscoward Thanks. Now factor has the same problem.

    – 李哲源
    Nov 21 '18 at 23:30











  • I guess anything that calls duplicated has the problem.

    – Anonymous coward
    Nov 21 '18 at 23:31














4












4








4


1






Have tested this on R 3.5.0.



set.seed(0)

x <- rexp(100)

length(unique(x))  ## 100



## this fails as I expect

unique(x, nmax = 98)

#Error in unique.default(x, nmax = 98) : hash table is full



## but how come does this succeed?

length(unique(x, nmax = 99))  ## 100





r vector unique







share|improve this question














Have tested this on R 3.5.0.



set.seed(0)

x <- rexp(100)

length(unique(x))  ## 100



## this fails as I expect

unique(x, nmax = 98)

#Error in unique.default(x, nmax = 98) : hash table is full



## but how come does this succeed?

length(unique(x, nmax = 99))  ## 100





r vector unique




r vector unique






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 21 '18 at 23:10









李哲源李哲源

48.3k1496147




48.3k1496147













  • Same behavior with function duplicated.

    – 李哲源
    Nov 21 '18 at 23:16











  • Why wrap only the second call in length? I think this would be more clear if you used length in both or neither case of calling unique with nmax of 98 & 99

    – arvi1000
    Nov 21 '18 at 23:22













  • This is the best I can offer. r.789695.n4.nabble.com/… nmax - 1 still returns the length of your vector, so I think it's correct about ignoring it.

    – Anonymous coward
    Nov 21 '18 at 23:27













  • @Anonymouscoward Thanks. Now factor has the same problem.

    – 李哲源
    Nov 21 '18 at 23:30











  • I guess anything that calls duplicated has the problem.

    – Anonymous coward
    Nov 21 '18 at 23:31



















  • Same behavior with function duplicated.

    – 李哲源
    Nov 21 '18 at 23:16











  • Why wrap only the second call in length? I think this would be more clear if you used length in both or neither case of calling unique with nmax of 98 & 99

    – arvi1000
    Nov 21 '18 at 23:22













  • This is the best I can offer. r.789695.n4.nabble.com/… nmax - 1 still returns the length of your vector, so I think it's correct about ignoring it.

    – Anonymous coward
    Nov 21 '18 at 23:27













  • @Anonymouscoward Thanks. Now factor has the same problem.

    – 李哲源
    Nov 21 '18 at 23:30











  • I guess anything that calls duplicated has the problem.

    – Anonymous coward
    Nov 21 '18 at 23:31

















Same behavior with function duplicated.

– 李哲源
Nov 21 '18 at 23:16





Same behavior with function duplicated.

– 李哲源
Nov 21 '18 at 23:16













Why wrap only the second call in length? I think this would be more clear if you used length in both or neither case of calling unique with nmax of 98 & 99

– arvi1000
Nov 21 '18 at 23:22







Why wrap only the second call in length? I think this would be more clear if you used length in both or neither case of calling unique with nmax of 98 & 99

– arvi1000
Nov 21 '18 at 23:22















This is the best I can offer. r.789695.n4.nabble.com/… nmax - 1 still returns the length of your vector, so I think it's correct about ignoring it.

– Anonymous coward
Nov 21 '18 at 23:27







This is the best I can offer. r.789695.n4.nabble.com/… nmax - 1 still returns the length of your vector, so I think it's correct about ignoring it.

– Anonymous coward
Nov 21 '18 at 23:27















@Anonymouscoward Thanks. Now factor has the same problem.

– 李哲源
Nov 21 '18 at 23:30





@Anonymouscoward Thanks. Now factor has the same problem.

– 李哲源
Nov 21 '18 at 23:30













I guess anything that calls duplicated has the problem.

– Anonymous coward
Nov 21 '18 at 23:31





I guess anything that calls duplicated has the problem.

– Anonymous coward
Nov 21 '18 at 23:31












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